Coal is burned to create steam, which is then used to generate electricity at coal-fired power stations. Under extreme pressure, the steam generated enters a turbine, which turns a generator to provide power. In order to restart the process, the steam is then cooled, condensed back into water, and fed back into the boiler.
For example, the Kingston Fossil Plant near Knoxville, Tennessee, uses coal to heat its boilers to around 1,000 degrees Fahrenheit in order to produce high-pressure steam as a practical illustration of this.
How is energy generated by burning coal?
Whether bituminous, subbituminous, or lignite, they are all burned in coal-fired power plants. The heat generated by coal combustion is utilized to turn water into high-pressure steam, which drives a turbine and generates electricity.
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calculate the de broglie wavelength of a 1.2-kg rock thrown with a speed of 6.0 m/s into a pond. is this wavelength similar to that of the water waves pro- duced? explain.
The de Broglie wavelength for a particle== 0.92 ×10⁻³⁴m.
de broglie wavelength is the wavelength associated with particle of mass m moving with velocity v.
p= h/ λ
where, p -is the momentum of the atom;
h- Planck's constant - 6.626×10⁻³⁴ m²kg s⁻¹
λ- wavelength;
Momentum can be expressed as
p=m×v
where , m is the mass of the particle;
v - the speed of the particle.
so,
λ = h/(m×v)
= ( 6.626×10⁻³⁴ m²kg s⁻¹)/(1.2kg × 6.0 m/s)
= (6.626×10⁻³⁴ m²kg s⁻¹)/7.2
= 0.92 ×10⁻³⁴ m
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Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The center of mass of the three mass system is at 83cm
Center of mass definition:A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component.
Given the mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
[tex]X_{CM}=\frac{Mx_{1}+m_{2}x_{2}+m_{3}x_{3}}{M+m_{2}+m_{3}}X_{CM}=\frac{0.5\times 0.5+1\times 0.5+3\times 1}{0.5+1+3}=\frac{3.75}{4.5}=0.83m = 83cm[/tex]
So the center of mass of the three mass system is at 83cm.
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a 615 n student standing on a scale in an elevator notices that the scale reads 645 n. from this information, the student knows that the elevator must be moving
Yes, it is true. The elevator moves upward because the acceleration is a positive number. If the acceleration is positive, the elevator will move higher.
Here, we can make use of Newton's second law of motion to find the acceleration.
Student mass equals 615/9.81, or 62.7.
The student's weight decreased and increased as a result on the scale.
ma = uarr F
645-615 = 62.7*a
a = 0.478m/s^2
The elevator moves upward because the acceleration is a positive number.
It is real.
The complete question is:
A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student knows that the elevator must be moving upward. True or false?
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6. why do the elements in the tubes have to have high voltage electricity run through them before the colored light is emitted? in other words, why don't the cold, un-energized tubes glow?
In order for the electrons to emit photons and leave the ground state, the heat produced by the electricity must be present.
Electron :The electron is a subatomic particle with a negative one elementary charge electric charge. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically thought to be elementary particles.
Photon :The electromagnetic force is carried by a photon, an elementary particle that is a quantum of the electromagnetic field and includes electromagnetic radiation like light and radio waves. Since photons have no mass, they always move at the 299792458 m/s speed of light in a vacuum.
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how do you apply newtons laws to solve problems?
Answer:
✨Hello mark as branlist Identify the physical principles involved by listing the givens and the quantities to be calculated
Explanation:
If a 0.5 kg pair of shoes weighs 0.3 N on Pluto, what is the strength of gravity on Pluto?
Answer:
0.2
Explanation:
0.5 - 0.3 = 0.2
ASAP what is the unit we use to measure mass
Answer:
mass is measured in kilograms
Please help will give brainiest!!!
Given the fact that the arrow is in motion, it the follows that the arrow possesses kinetic energy.
What is the kinetic energy?The kinetic energy is the energy that is possessed by a body by virtue of its motion. This is different form the potential energy of the body which is the energy that the body possesses as a result of the fact that the object is located at a particular position. These are actually the two kinds of mechanical energy that we have in the study of physics.
If we consider this matter closely, we would see that the arrow as shown is in motion. The arrow does posses a velocity and such the arrow is in motion. As long as we can see that the arrow is in motion, it the follows that the arrow as we can see does and in fact possesses the kinetic energy.
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a force in the negative direction of an x axis is applied for 24 ms to a 0.50 kg ball initially moving at 16 m/s in the positive direction of the axis. the force varies in magnitude, and the impulse has magnitude 32.4 n · s.
The force varies in magnitude is 1350 N.
We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by
P = m . v
where P is momentum, m is mass and v is velocity.
Momentum depends on the Impulse, where
ΔP = I
m (v2 - v1) = F . t
where I is impulse, F is force and t is time
From the question above, we know that:
m = 0.5 kg
t = 24 ms = 0.024 s
v1 = 16 m/s
I = 32.4 Ns
Find the force applied
I = F . t
32.4 = F . 0.024
F = 1350 N
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Pls help with the right answer and explanation to this question
Answer: Substance 3 is liquid at room temperature
Explanation: The common room temperature is assumed to be 20-22°C, we need to find the substance that will be in liquid state in that temperature.
For Substance 1, the boiling point is -195.975°C, and hence at room temperature, it would be in vapor phase and all liquid would have turned to gas.
For Substance 2, the boiling point is 3.85°C, and hence at room temperature, it would be in vapor phase and all liquid would have turned to gas in this case too.
For Substance 3, the boiling point is 77.85°C, and melting point is -108.15°C, hence at room temperature, it would be in liquid state.
For Substance 4, the melting point itself is 1800°C, due to which at room temperature it would be in solid state.
A vector is a way to represent magnitude and direction. Which one of the following vector pairs as equal in direction only?
explained image
a)one short and one longer arrow going towards each other
b)one short and one long arrow going in the same direction
c)one arrow going to the left the other facing down
d)two of the same size arrows going towards eachother
Select one:
a. A
b. B
c. C
d. D
B. The pairs of vectors equal in direction only are one short and one long arrow going in the same direction.
What is direction of a vector?
The direction of a vector can be defined as the measure of the angle it makes with a horizontal line.
The direction of a vector can also be described as the measure of the exact position on the x and y coordinate where a vector can be found.
When we describe the direction of vectors, we don't consider their size or magnitude, rather we focus on the angle of inclination of the vectors above the horizontal.
The magnitude of a vector is defined as the size of the vector.
Vectors pointing or going in the same direction have equal directions despite their size.
Vectors with equal size have the same magnitude despite their directions.
Thus, we can conclude that two vectors going in the same direction will have equal direction.
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Alex brings a bag of trail mix to school. He empties the bag and measures the total mass of the trail Then he separates the nuts, chocolate, and raisins into individual piles. He eats the chocolate and then measures the mass of the remaining two piles. He records his data in the table
What was the mass of the chocolate that Alex ate?
The mass of the chocolate from the table that we can find in the question is 11 grams.
What was the mass of the chocolate that Alex ate?
We can see that the table as it have been shown gives us both the total number of the trail mix that Alex has brought to the school as well as the various individual components of the trail mix that he has. Looking at this over view would be of a lot of help as we are trying to find out now the number of the mass of the chocolate that Alex ate.
We have the following information;
Mass of nuts = 24 grams
Mass of raisins = 10 grams
Mass of chocolate = unknown grams
We can now have;
Total mass = Mass of nuts + Mass of raisins + Mass of chocolate
Mass of chocolate = Total mass - (Mass of nuts + Mass of raisins)
Mass of chocolate = 45 - (10 + 24)
Mass of chocolate = 11 grams
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What is the radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s2 ?
The radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s² is 9 M m
g = G M / R²
g = Acceleration due to gravity
G = Gravitational constant
M = Mass
R = Radius
g = 4.9 m / s²
G = 6.67 * [tex]10^{-11}[/tex] m³ / kg s²
M = 5.97 * [tex]10^{24}[/tex] kg
R² = ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] ) / 4.9
R² = 81.3 * [tex]10^{12}[/tex].
R = 9 * [tex]10^{6}[/tex] m
R = 9 M m
Acceleration due to gravity is the acceleration produced by a planet. If an object is falling, it will gain some acceleration due to gravitational force.
Therefore, the radius of a planet is 9 M m
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How do particles of a gas differ from particles of a liquid when in the same container?
A. Gas particles are more spread out
B. Gas particles are closer together
C. Gas particles are smaller
D. Gas particles are larger
Answer:
I believe that it is A) they're more spread out
the density of mercury is 13.6g cm‐³. What do you understand by this statement?
Answer:
The relative density of mercury is 13.6, this means that mercury is 13.6 times as heavy as an equal volume of water.
two people are trying to push a refrigerator. one person is pushing at an angle that is parallel to the floor and 70° to the front plane of the refrigerator with a force of 400 n, and the other is pushing at an angle that is parallel to the floor and 110∘ to the front p
Answer: As friction force is less than the Resultant
force so they will be able to move the fridge
Explanation:
top view of fridge
Angle between forces B= 180- 70- (186-110 )
= 170 - 70 = 40 -
Resultant of forces .
R = 1 ( FOR + ( 82 ) 2 + 2 FIF2 COS B .
J (40B) " + ( 375 ) 2 + 2 x 400 * 375 x Cos 40 "
7 28 - 31 1 N .
() friction force = 600.
As friction force is less than the Resultant
force so they will be able to move the fridge
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There is 728.311N force acting on the front plane. while two individuals attempt to push a refrigerator. Pushing with a force of 400 N, one person is positioned with their back.
Angle between forces B= 180- 70- (186-110 )
= 170 - 70 = 40
R= [tex]\sqrt{(F1^{2} )+(F2^{2})+2F1F2cos\alpha }[/tex]
Here F1= 400
F2=375
alpha = 40
Resultant of forces .
728 . 31 1 N
friction force = 600.
friction force.
The refrigerator can be moved since the friction force is smaller than the resultant force.
Force's Definition. When an object interacts with another object, it experiences a push or pull that is known as a force. Every time two things interact, a force is applied to each of them.
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what is the velocity of an object that travels 100 km in 20 s
Answer: 100km/20s=5km/s
Explanation:because velocity is equal to distance ovet time
a ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the ball has a centripetal acceleration of magnitude 2g.
Since the chute is semicircular, the ball's velocity shortly before free fall at the top would be horizontal. Given that, starting velocity u=0 As a result, 2R is the distance from the chute's bottom.
We must first determine the speed at which the ball is moving at the top of the shop. Therefore, let's accelerate. Two G are equal to the centripetal acceleration.
In contrast, acceleration is equal to two B squared. Because of this, the speed is equal to two square. The square root of two G is the Rudolph centripetal acceleration times. It's calculated, that. Yeah. So now, mm hmm, mm hmm, we must calculate it.
Approximately 14 m/s and quite close to checkpoint 1 in meters per second. By dividing the object's velocity by the amount of time it takes to go from one location to another, the acceleration velocity can be calculated. Acceleration results from changes in the magnitude of velocity or direction.
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Luka Modric kicks the ball with a velocity of 367km/h at an angle of 45 degrees above the horizontal.
a) how long will the ball be in the air?
b) how far downfield will it land as it hits the back of the net?
c) how high did the ball go at its highest point over the Italian defense?
A. The time spent by the ball in the air is 14.7 s
B. The ball will land at 1060.47 m as it hits the net.
C. The maximum height reached by the ball is 265.12 m
A. How to determine the time
The time spent by the ball in the air can be obtained as follow:
Initial velocity (u) = 367 Km/h = 367 / 3.6 = 101.944 m/sAngle of projection (θ) = 45 °Acceleration due to gravity (g) = 9.8 m/s²Time (T) = ?T = 2uSineθ / g
T = [2 × 101.944 × Sine 45] / 9.8
T = 14.7 s
B. How to determin the distance
Initial velocity (u) = 367 Km/h = 367 / 3.6 = 101.944 m/sAngle of projection (θ) = 45 °Acceleration due to gravity (g) = 9.8 m/s²Range (R) =?R = u²Sine(2θ) / g
R = (101.944)² × Sine (2×45) / 9.8
R = 1060.47 m
C. How to determine the maximum height
The maximum height reached by the ball can be obtained as follow:
Initial velocity (u) = 367 Km/h = 367 / 3.6 = 101.944 m/sAngle of projection (θ) = 45 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?H = u²Sine²θ / 2g
H = [(101.944)² × (Sine 45)²] / (2 × 9.8)
H = 265.12 m
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if the frequency of a wave was 10 Hz and the speed was 5m/s, find its wavelength
Answer:
[tex]0.5\; {\rm m}[/tex].
Explanation:
The period [tex]T[/tex] of a wave is the reciprocal of its frequency [tex]f[/tex]. In other words, [tex]T = (1/f)[/tex]. Since the frequency of the wave in this question is [tex]f = 10\; {\rm Hz} = 10\; {\rm s^{-1}}[/tex], the period of this wave would be [tex]T = (1/f) = (1/10)\; {\rm s} = 0.1\; {\rm s}[/tex].
The wavelength of a wave is the distance its wavefront travels in one period [tex]T[/tex].
The period of this wave is [tex]T = 0.1\; {\rm s}[/tex]. At a speed of [tex]v = 5\; {\rm m\cdot s^{-1}}[/tex], it would have travelled a distance of [tex]v\, T = (0.1\; {\rm s})\, (5\; {\rm m\cdot s^{-1}}) = 0.5\; {\rm m}[/tex] within one period.
Has anyone else done this before??
if not i am still confused how to find difference between a radius and the accepted value can be expressed as the percent error. What is a percent error!? My radius was 3486.
The Percentage error is zero.
Formula :-
Percentage error = V₀ - Vᵃ/ V₀ × 100%
V₀ = observed value, given = 3486 km
Vᵃ = accepted value, given = 3486 km
Hence, there is no difference between observed value and accepted value. So the Percentage error is zero.
Percentage error compares an estimate to a correct price and expresses the distinction among them as a percentage. This statistic permits analysts to recognize the scale of the error relative to the real fee. it's also known as percent errors and % error.
Percentage error is the difference between a measured or experiment value and an frequent or known price, divided by way of the known price, accelerated by using 100%.
Percentage error tells you ways large your errors are while you measure some thing in an experiment. Smaller values imply which you are near the well-known or actual fee. for example, a 1% error means that you obtain very close to the familiar value, at the same time as 45% method that you had been quite an extended manner off from the authentic price.
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a car goes around a curve on a road that is banked at an angle of 32.6°. even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 20.8 m/s. what is the radius of the curve?
The radius of curve that a car goes around that is banked at an angle of 32.6° is 69 m
R = v² / g tan θ
R = Radius of the curve
v = Velocity
g = Acceleration due to gravity
θ = Banked angle
R = 20.8² / ( 9.8 * tan 32.6° )
R = 432.64 / ( 9.8 * 0.64 )
R = 432.64 / 6.27
R = 69 m
A banked surface is a surface that is sloped upwards on the outer side of a curve. In race car tracks, the banked angle is usually 12° to 36°.
Therefore, the radius of curve that a car goes around that is banked at an angle of 32.6° is 69 m
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This question is kinda tricky
The speed of the ball is "50.4 m/s"
The structure is 130 meters high.
64 meters across the horizontal
Gravity causes an acceleration of 9.8 m/s.
Using the equation of motion s = ut + (0.5at2) and presuming that air resistance is not taken into account, we first calculate how long it takes for the object to strike the ground.
where s = distance (height of the building)
initial speed is u. (which is 0 in this case )
Time t equals (130/4.9) where an is the gravitational acceleration (0 x t) + (0.5 x 9.8 x t2) = 130 4.9 x t2.
5.15 seconds = t
We now apply the equation Vy = Uy + at to get the speed before it touches the ground (0 in this case)
Vy = 0 + (9.8 x 5.15) (9.8 x 5.15) (9.8 x 5.15)
Vy = 50.4 m/s
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a line 3km north and 5km east what is the resultant??
Answer:
See below
Explanation:
Use pythag theorem
r^2 = 3^2 + 5^2
r = sqrt (34) = 5.83
angle = arctan (3/5) = 31 degrees north of east
Which statement accurately describes the relationship between force and
momentum?
A. As the density of an object decreases, its momentum decreases,
and it takes less force to change its motion.
B. As the mass of an object decreases, its momentum increases, and
it takes more force to change its motion.
C. As the mass of an object decreases, its momentum decreases,
and it takes less force to change its motion.
D. As the density of an object decreases, its momentum increases,
and it takes more force to change its motion.
Answer:
its c my brotha
because if the density decreases so will the mass less mass=less momentum
If the acceleration of a school bus over a given time interval is zero, how does the instantaneous velocity of that school bus at any instant during that interval compare to its average velocity over the interval?.
Both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.
What is instantaneous velocity?Instantaneous velocity is the rate of differential change of displacement with respect differential change in time. Mathematically -
v = dx/dt
Given is the acceleration of a school bus over a given time interval as zero.
For acceleration over a given time interval to be zero, it must be ensured that the the velocity of the object should remain constant. Mathematically-
a = (v - u)/(t₂ - t₁)
For acceleration [a] = 0, v = u. Therefore -
a = 0
The instantaneous velocity for zero acceleration between the time interval t₁ to t₂ will be equal to initial velocity only -
dx/dt = u
This will be the instantaneous velocity and is equal to (u) at any instant.
Now -
dx = u dt
Integrating both sides, we get -
∫dx = ∫u dt
x = ut
Therefore, the average velocity will be =
v(avg) = x/Δt = ut/Δt
Now -
t = Δt for any specific time interval. Therefore -
v(avg) = ut/t = u
This is the average velocity and it is equal to (u).
Therefore, both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.
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Max is golfing and he hits a ball 235 meters 15.9° west of north. From that location he hits the ball 29.5 meters 41.1° east of north. What is the final displacement vector for Max's golf ball?
The final displacement vector for Max's golf ball is d. 246 m, 29.1 degrees north of east.
displacement 1 = 235 m 15.9° west of north.
displacement2 = 29.5 meters 41.1° east of north.
resultant vector = [tex]\sqrt{235{^{2} + 29.5^{2} }[/tex]
= 246.84 m, 29.1 degrees north of east
A vector is an object that has both importance and direction. Geometrically, we are able to image a vector as a directed line section, whose duration is the importance of the vector, and with an arrow indicating the direction. The direction of the displacement vector is from its tail to its head.
Vector is a term that refers colloquially to a few quantities that can not be expressed via an unmarried variety, or to elements of a few vector spaces. Vectors are geometrical or physical portions that own both value and direction wherein the item is moving. The importance of a vector shows the length of the vector. it's far normally represented by means of an arrow pointing within the course of the vector.
Disclaimer:- your question is incomplete, please see below for the complete question.
Max is golfing and he hits a ball 235 meters 15.9° west of north. From that location, he hits the ball 29.5 meters 41.1° east of north. What is the final displacement vector for Max's golf ball?
a. 246 m, 29.1 degrees east of north
b. 252 m, 10.3 degrees west of north
c. 252 m, 10.3 degrees north of west
d. 246 m, 29.1 degrees north of east
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A spring has a spring constant of 15 N/cm. Which of the following hanging mass would produce an extension of 3.0 cm?
a. 4.5 kg
b. 5.0 kg
c. 200 g
d. 45 kg
The hanging mass that would produce an extension of 3.0cm is 4.5kg (option A).
How to calculate extension of a spring?The spring constant denoted by K is a measure of the stiffness of the spring. It is different for different springs and materials.
The larger the spring constant, the stiffer the spring and the more difficult it is to stretch.
The spring constant can be calculated using the following formula:
k = F/e
Where;
k = spring constant (Nm-¹)F = force (N)e = extension (cm)F = 15 × 3 = 45N
Since Force = mass × acceleration (10m/s²), the mass can be calculated as follows:
m = 45N ÷ 10m/s² = 4.5kg
Therefore, 4.5kg is the mass of the spring.
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a cd players operating speed is 1600 rad/s. if it starts from rest and has an acceleration of 400 rad/s, how long does it take to reach full speed
The time taken for the cd player to reach the full angular speed is 4 seconds.
What is the time of motion of the cd player?
The time of motion of the cd player is calculated by applying the following kinematic equation as shown below.
ωf = ωi + αt
where;
ωf is the final angular velocityωi is the initial angular velocityα is angular accelerationt is the time of motionSince the cd player started from rest, the initial angular velocity = 0
The time taken for the cd player to reach the full speed is calculated as follows;
1600 = 0 + 440t
1600 = 400t
t = 1600/400
t = 4 seconds
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A rocket travels 220 meters directly upward with an average acceleration of 14.7 meters per second squared.
How has the velocity of the rocket changed after 220 meters?
The change in the velocity of the rocket after 220 meters is 80.42 m/s.
What is the velocity of the rocket?
The change in the velocity of the rocket at the given time of motion is calculated as follows;
Apply the following kinematic equation to determine the velocity of the rocket.
v² = u² + 2as
where;
v is the final velocity of the rocketu is the initial velocity of the rocket = 0a is the acceleration of the rockets is the distance travelled by the rocketv² = 2as
v = √2as
v = √(2 x 14.7 x 220)
v = 80.42 m/s
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