Taking into account definition of percent yield, the percent yield of the reaction if 3.35 g of N₂H₄ reacts with excess oxygen and produces 0.350 L of N₂ is 13.82%.
Reaction stoichiometryIn first place, the balanced reaction is:
N₂H₄ + O₂ → N₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
N₂H₄: 1 moleO₂: 1 moleN₂: 1 moleH₂O: 2 molesThe molar mass of the compounds is:
N₂H₄: 32 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
N₂H₄: 1 mole ×32 g/mole= 32 gramsO₂: 1 mole ×32 g/mole= 32 gramsN₂: 1 mole ×28 g/mole= 28 gramsH₂O: 2 moles ×18 g/mole= 36 gramsIdeal gas lawThe pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas. Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
percent yield= (actual yield÷ theoretical yield)× 100%
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
Actual yield of N₂In this case, you know:
P= 1 atmV= 0.350 LT= 295 KR= 0.082 [tex]\frac{atmL}{molK}[/tex]n= ?Replacing in the ideal gas law:
1 atm×0.350 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K
Solving:
n= (1 atm×0.350 L) ÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 295 K)
n= 0.01447 moles
Finally, the actual yield of N₂ is 0.01447 moles.
Theoretical yield of N₂Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 1 mole of N₂, 3.35 grams of N₂H₄ form how many moles of N₂?
moles of N₂= (3.35 grams of N₂H₄× 1 moles of N₂)÷ 32 grams of N₂H₄
moles of N₂= 0.1047 moles
Finally, the theoretical yield of N₂ is 0.1047 moles.
Percent yield for the reaction in this caseIn this case, you know:
actual yield= 0.01447 molestheorical yield= 0.1047 molesReplacing in the definition of percent yield:
percent yield= (actual yield÷ theoretical yield)× 100%
Solving:
percent yield= (0.01447 moles÷ 0.1047 moles)× 100%
percent yield= 13.82%
Finally, the percent yield for the reaction is 13.82%.
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Sierra Charter School:
Part 3 Directions: Watch the video: How to calculate Oxidation Numbers Intro Video and take notes throughout the video here and from those notes, write a summary.
An oxidation number is a number assigned to an atom that allows chemists to keep track of how many electrons are available for transfer and whether a particular reactant is being oxidized or reduced in a reaction.
Determine if the substance in question is an element. An unbonded free atom always has an oxidation number of 0. An oxidation number is a number assigned to a compound or element to indicate the number of electrons that have been lost or gained. A negative number indicates that an electron was gained and a positive number indicates that an electron was lost.
Determine if the substance in question is an ion. Aeon has an oxidation number corresponding to the charge. This applies to both ions that are not bonded to other elements and ions, which are part of the ionic compound. The oxidation number explains the ability of elements or compounds that provides or obtain electrons during a chemical reaction.
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an empty graduated cylinder weighs 26.145 g when the cylinder contains 48.3 of an unknown liquid it weighs 65.055 g. what is the density of the unknown liquid? put answer in correct significant figures
The density of the unknown liquid 1.88kg/m³
The density of a liquid is a measure of how heavy it is for the amount measured and if you weigh equal amounts or volumes of two different liquids, the liquid that weighs more is more dense and if a liquid that is less dense than water is gently added to the surface of the water, it will float on the water
Here given data is cylinder weighs 26.145 g and when the cylinder contains 48.3 of an unknown liquid and it weighs 65.055 g then we have to find density of the unknown liquid = ?
So density = mass/volume
cylinder weighs + liquid weighs = 91.2g
Density = 91.2g/48.3
Density = 1.88kg/m³
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Why does adding elements such as carbon to flexible metals make the material stronger?
Answer: Carbon strengthens iron by distorting its crystal lattice. This distortion is similar in effect to work hardening.
A 500 kg car is traveling Northbound towards Rosamond at a rate of 30 m/s. A 2000kg truck is traveling southbound toward LA at 25 m/s. What is the net momentum if North is the positive direction?
The net momentum if North is the positive direction is 20,000Kgm/s.
What is momentum?Momentum can simply be defined as the product of the mass of a particle and its velocity.
Momentum is a vector quantity that possesses a magnitude and a direction.
The Formula of momentum is given below:
Momentum, p = m * v
where;
m is the mass and v is the velocity of the body.
S.I. unit of momentum is kgm/s.
We have the given data as follows:
m1 = 500 kg
v1 = 30 m/s
m2 = 200 kg
v2= 25 m/s
Momentum = m1v1 + m2v2
= (500 * 30) + (200 * 25)
= 15000 + 5000
= 20,000 kgm/s
Momentum = 20,000Kgm/s.
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what is the ionic equation for Ba(ClO4)2(aq)+K2SO4(aq)⟶BaSO4(s)+2KClO4(aq)?
What is the empirical formula of a substance that contains 0.250 mol of carbon, 0.500 mol of hydrogen, and 0.250 mol of oxygen?
The empirical formula of the compound is CH₂O.
What is the empirical formula of the compound?The empirical formula of a compound is the simplest formula of a compound showing the elements in the compound combined in their simplest mole ratios.
The empirical formula is determined from the simplest whole number mole ratio in which the elements in the compound combine.
The empirical formula of the compound is calculated below as follows:
mole of carbon = 0.250
mole of hydrogen = 0.50
moles of oxygen = 0.250
Diving by the smallest ratio to convert to whole number ratios
mole ratio of carbon to hydrogen to oxygen will be:
C = 0.25 / 0.25 = 1
H = 0.50 / 0.25 = 2
O = 0.25 / 0.25 = 1
Empirical formula = CH₂O
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helppppppppppddjeoeps
Answer:
D.) mole, 6.022 x 10²³
Explanation:
Avogadro's Number is a ratio which states that there are 6.022 x 10²³ particles per every one mole.
A certain reaction has an activation energy of 36.11 kJ/mol.
At what Kelvin temperature will the reaction proceed 4.50
times faster than it did at 315 K?
Kelvin temperature will the reaction proceed 4.50 times faster than it did at 315 K is 293K
Temperature is the degree of hotness or coldness of an object
Here given data is certain reaction has an activation energy of 36.11 kJ/mol and reaction proceed 4.50 times faster than it did at 315 K and we have to find kelvin temperature = ?
Then, we have to use the arrhenius equation and set k1 = 1 and k2 = 4.50 because rate = k[A] so as long as concentration of reactants doesn't vary, rate is proportional to k
ln (k₂/k₁) = Ea/R(1/T₁ - 1/T₂)
k₂ = 4.50
k₁ = 1
Ea = 36.11 J/mole
R = 8.314 J/mol⁻k
T ₁= 315 K
T₂ = ?
ln(4.50/1) = 36.11/8.314 (1/314 - 1/T₂)
1.50 = 4.343 (1/315 - 1/T₂)
1.50 = 0.013 - 4.343/T₂
-1.48 = - 4.343/T₂
T₂ = 293 K
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I need help understanding this is not a test but study material
Explanation:
The law of conservation of mass:
In a chemical reaction, the mass is neither created nor destroyed. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.
------------------
According to this task, the statement that demonstrates the law of conservation of mass is:
Answer: there are 10 aluminum (Al) atoms represented on each side of the equation.
How many grams of copper(II) chloride are needed to produce 42.8 g copper(II) phosphate in the presence of excess sodium phosphate?
Taking into account the reaction stoichiometry, 45.35 grams of copper(II) chloride are needed to produce 42.8 g copper(II) phosphate in the presence of excess sodium phosphate.
Reaction stoichiometryIn first place, the balanced reaction is:
3 CuCl₂ + 2 Na₃PO₄ → Cu₃(PO₄)₂ + 6 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CuCl₂: 3 molesNa₃PO₄: 2 molesCu₃(PO₄)₂: 1 moleNaCl: 6 molesThe molar mass of the compounds is:
CuCl₂: 134.44 g/moleNa₃PO₄: 164 g/moleCu₃(PO₄)₂: 380.62 g/moleNaCl: 58.44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
CuCl₂: 3 moles ×134.44 g/mole= 403.32 gramsNa₃PO₄: 2 moles ×164 g/mole= 328 gramsCu₃(PO₄)₂: 1 mole ×380.62 g/mole= 380.62 gramsNaCl: 6 moles ×58.44 g/mole= 350.64 gramsMass of CuCl₂ requiredThe following rule of three can be applied: if by reaction stoichiometry 380.62 grams of Cu₃(PO₄)₂ are produced by 403.32 grams of CuCl₂, 42.8 grams of Cu₃(PO₄)₂ are produced by how much mass of CuCl₂?
mass of CuCl₂= (42.8 grams of Cu₃(PO₄)₂× 403.32 grams of CuCl₂) ÷380.62 grams of Cu₃(PO₄)₂
mass of CuCl₂= 45.35 grams
Finally, 45.35 grams of CuCl₂ is required to produce 42.8 g copper(II) phosphate.
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which species has 18 electrons
Answer:
Argon - Ar has 18 electrons
An ion that has 18 electrons is a potassium ion.
Hope this helps!
Explanation:
Using the equations
-
N₂ (g) + 3 H2 (g) → 2 NH3 (g) AH = -91.8 kJ/mol
C(s) + 2 H₂ (g) → CH4 (g) AH° = -74.9 kJ/mol
H₂ (g) + 2 C(s) + N₂ (g) → 2 HCN (g) AH° = 270.3 kJ/mol
Determine the enthalpy (in kJ/mol) for the reaction
CH4 (g) + NH3 (g) → HCN (g) + 3 H₂ (g).
According to the given data The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol.
What is enthalpy ?Enthalpy is a characteristic or state function which resembles energy; it has the same dimensions as energy and is thus measured in joules or ergs. The value of enthalpy is entirely determined by the temperature, pressure, and content of the system, not on the history.
Briefing:Calculate the change in enthalpy for the reaction
CH₄(g) + NH₃(g) → HCN(g) +3H₂(g)
From the given reactions
Reaction 1: N₂(g) + 3H₂(g) → 2NH₃(g) Change in enthalpy: -91.8 kJ/mol
Reaction 2: C(s, graphite) + 2H₂(g) → CH₄(g) Change in enthalpy: -74.9 kJ/mol
Reaction 3: H₂(g) +2C(s, graphite) +N₂(g) → 2HCN (g) Change in enthalpy: +270.3 kJ/mol
Reactions 1 and 2 to get reaction 4 and 5 respectively
Reaction 4: 2NH₃(g) → N₂(g) + 3H₂(g) ΔHo : 91.8 kJ/mol
Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol
Now, multiply reactions 4 and 3 by half (1/2) to get 6 and 7 respectively
Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol
Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN (g) ΔHo : +135.15 kJ/mol
Now,
Add reactions 5, 6, and 7 together
Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol
Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol
Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN(g) ΔHo : +135.15 kJ/mol
----------------------------------------------------------------------------------------------------------
CH₄(g) + NH₃(g) → HCN(g) + 3H₂(g) ΔH rxn = 255.95 kJ/mol
The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol
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How many moles of silver are present in a silver spoon that has a mass of 12.86 g?
You do not need to type your units into the answer box. Please report your answer with three places after the decimal, and do not use scientific notation.
The number of moles of silver present in a silver spoon that has a mass of 12.86g is 0.12 moles.
How to calculate number of moles?The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
The mass of a substance is the quantity of matter which a body contains, irrespective of its bulk or volume.
The mole of a substance is the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities e.g. atoms, molecules.
moles = mass ÷ molar mass
According to this question, silver spoon has a mass of 12.86g. The number of moles can be calculated as follows:
Molar mass of silver (Ag): 107.8682g/mol
moles = 12.86g ÷ 107.8682g/mol
moles = 0.12 moles
Therefore, 0.12 moles of silver are present in the silver spoon.
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i need help with chemistry equation
From the mole ratio and the masses of reactants:
The maximum amount in grams of ammonia (NH₃ ) that can be formed is 2.83 gThe formula of the limiting reagent is N₂.The amount of the excess reagent that remains after the reaction is complete is 3.65 grams.What is the maximum amount of the product that can be formed?The maximum amount of the product that can be formed is calculated from the equation of reaction as follows:
3H₂ (g) + N₂ (g) ---> NH₃ (g)The mole ratio of hydrogen to nitrogen is 3 : 1
From the given data:
4.67 grams of hydrogen gas are allowed to react with 4.67 grams of nitrogen.
The moles of the reactants is determined as follows:
Moles of hydrogen = 4.65/2 = 2.325 moles
Moles of nitrogen = 4.67/28 = 0.1667 moles
Hence, the limiting reagent is nitrogen while the excess reagent is hydrogen.
The maximum moles of ammonia (NH₃ ) that can be formed = 0.1667 moles.
mass of ammonia formed = 0.1667 * 17 grams
mass of ammonia formed = 2.83 g
The moles of the excess reagent remaining after the reaction is complete = 2.325 - (0.1667 * 3) = 1.825
moles of the excess reagent remaining = 1.835 moles
mass of the excess reagent remaining = 1.825 * 2
mass of the excess reagent remaining = 3.65 grams
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Cl₂(g) + F₂(g) 2CIF(g)
Draw Lewis structures for all reactant and product molecules.
Lewis structures for all reactant and product molecules and the show the bonding relationship between atoms of a molecule and the lone pairs of electrons in the molecule
Lewis structure for the reactants and product molecules can be drawn by following the octet rule and considering covalent bonding between the bonded atoms
Here given reaction is
Cl₂(g) + F₂(g) → 2CIF(g)
And lewis structure of reactant means Cl₂(g) + F₂(g) in Cl₂(g) one chlrine has three lone pair attached and another clorine also three lone pair attached whereas F₂(g) also has three pair of lone pair are attached and product means CIF(g) has Cl has three lone pair and F also has three lone pair attached
Lewis structures for all reactant and product molecules are given below
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Which of the following is an example of water in a liquid state?
A. ice
B. Steam
C. Snow
D. Rain
How many molecules are contained in a 4.30-g sample of dimethylmercury?
The number of molecules contained in a 4.30-g sample of dimethylmercury is 1.12 × 10²² molecules.
How to calculate number of molecules?The number of molecules of a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number as follows:
no of molecules = no of moles × 6.02 × 10²³
According to this question, 4.30-g sample of dimethylmercury (C₂H₆Hg) is given. The molar mass of C₂H₆Hg is 230.659 g/mol.
no of moles of dimethyl mercury = 4.3g ÷ 230.659 g/mol = 0.0186 moles
no of molecules of dimethyl mercury = 0.0186 moles × 6.02 × 10²³
no of molecules = 1.12 × 10²² molecules
Therefore, the number of molecules in 4.3g of C₂H₆Hg is calculated to be 1.12 × 10²² molecules.
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Is this the right answer to this question....?
Which of these is an example of active transport?
A: Transport of Na+ from a place of low concentration to a place of higher concentration
Transport of Na+ from a place of low concentration to a place of higher concentration. This is the right answer.
The sodium-potassium pump is the most common and well-known example of active transport. At the cell membrane, the sodium-potassium pump moves 3 sodium ions out of the cell and two potassium ions into the cell per ATP. Examples of active transport include the uptake of glucose in the human intestine and the uptake of minerals and ions into the root hair cells of plants.
One of the greatest examples of active transport is the movement of calcium ions out of cardiomyocytes. Cells secrete proteins such as enzymes, antibodies, and various other peptide hormones. Amino acids are transported across the intestinal mucosa of the human intestine. The movement of ions or molecules across cell membranes to regions of a higher concentration is assisted by enzymes and requires energy.
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balance the equation c3h8o3+o2- co2+h2o
Balanced equation of C3H8O3 + O2 = CO2 + H2O is 2C3H8O3 + 7O2 → 6CO2 + 8H2O
How To Balance C3H8O3 + O2 = CO2 + H2O ?
Balance the equation C3H8O3 + O2 = CO2 + H2O using the algebraic method.
Label Each Compound With a VariableaC3H8O3 + bO2 = cCO2 + dH2O
Create a System of EquationsC: 3a + 0b = 1c + 0d
H: 8a + 0b = 0c + 2d
O: 3a + 2b = 2c + 1d
Use substitution, gauss elimination3a - 1c = 0
8a - 2d = 0
3a + 2b - 2c - 1d = 0
Simplify the result to get the lowest, whole integer values.a = 2 (C3H8O3)
b = 7 (O2)
c = 6 (CO2)
d = 8 (H2O)
Substitute Coefficients and Verify Result2C3H8O3 + 7O2 = 6CO2 + 8H2O
Reactants Products
C 6 6
H 16 16
O 20 20
Since there is an equal number of each element in the reactants and products of 2C3H8O3 + 7O2 = 6CO2 + 8H2O, the equation is balanced.
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Of the chemical formulas MgO, Br₂, Ne, and CO₂,
which represents both an element and a molecule?
Explain your answer.
Br2 represents both an element and a molecule.
A molecule is defined as a group of atoms bonded together. An element is defined as a substance that cannot be chemically broken down further into simpler substances. Br2 is only bromine and it is two bromine atoms boned together to form a molecule.
"Nitric acid forms in the atmosphere through the following balanced reaction:
4NO(g) + 3O2(g) + 2H20 and excess oxygen gas, what is the percent yield for hte reaction?
The percent yield of the reaction is calculated as follows:
Percent yield = actual yield/ theoretical yield * 100 %
The percent yield of the reaction is less than 100%.
What is the percent yield of a given reaction?The percent yield of a reaction is the ratio of the actual yield of a reaction and the theoretical yield of the reaction.
Mathematically:
Percent yield = actual yield/ theoretical yield * 100 %The percent yield of any reaction is never 100& percent because no reaction actually goes to completion forming exactly all the product that is expected.
Considering the give reaction of the formation of nitric acid in the atmosphere:
The equation of the reaction is:
4 NO (g) + 3 O₂ (g) + 2 H₂0 (g) ---> 4 HNO₃ + excess oxygen.
The percent yield will require the actual yield and the theoretical yield in order to be calculated.
For example, if the actual yield is 12 g and the theoretical yield is 15 g, percent yield = 12/15 * 100%
Percent yield = 80%
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Arrange these acids according to their expected pKą values. (Highest to lowest)
CH₂CH₂COOH
CI2CHCOOH
CICH₂COOH
CICH₂CH₂COOH
i need help with chemistry equation
Answer:
12.1 grams and 77.8%
Explanation:
(Note: in this answer, sig figs are rounded in the end, not along the way) The molar ratio of calcium sulfate to calcium hydroxide is 1:1
there are 6.56 grams of calcium hydroxide, so the number of moles is the number of grams / the molar mass, which is (6.56 grams) / (74.093 g/mole)
=0.08854 moles of calcium hydroxide
Theoretically, 0.08854 moles of calcium hydroxide would make 0.08854 moles of calcium sulfate.
To find the number of grams of calcium sulfate, multiply the number of moles by the molar mass, which is .08854 * 136.14 = 12.054 grams, or
12.05 grams
The percentage yield of calcium sulfate is just the actual yield / predicted yield, which is 9.37/12.05 which is 0.7776, or 77.8%
Which of the following statements is NOT true concerning the decomposition of a simple binarycompound?A) The products are unpredictable.B)The products are the constituent elements.C)Energy is usually required.D)The reactant could be an ionic or a molecular compound.E) The reactant is a single substance
Step 1 -
A decomposition reaction is a reaction in which a compound is decomposed, i.e., we usually heat a substance thus forming new substances, such as gaseous substances.
Generally speaking, a decomposition reaction will involve only one reactant: the substance to be decomposed.
[tex]\text{reactant}\to\text{ product 1 + product 2 + }\ldots[/tex]Step 2 - Examples of decomposition reactions
Let's take a closer look at some examples:
[tex]\begin{gathered} ZnCO_3\to ZnO+CO_2 \\ 2Al_2O_3\to4Al+3O_2 \\ H_2CO_3\to H_2O_{}+CO_2 \\ NH_4NO_3\to N_2O+2H_2O \end{gathered}[/tex]We can already state some conclusions:
a) The products are not always the same. They depend on the reactant. Therefore, they are not always predictable.
b) The reactant can be an ionic compound (such as ZnCO3) but also a covalent compound (such as H2CO3).
c) The reactant does not decompose into its constituent elements.
Step 3 - Finding the wrong answer
Therefore, the only wrong answer is item b), the products are the constituent elements.
To test the effectiveness of a new nutrient supplement one group of identical mice is given the supplement and the other group is not given any thing .which is the most complete list of the parts of the
experiment presented in this scenario.
The most complete list of the parts of the experiment presented in this scenario include:
Dependent variableExperimental groupControl group.What is Experiment?This refers to the procedures which are performed in other to support or refute a hypothesis. It is also used to ascertain the authenticity of the claim by other people such as scientists etc who review it.
In the scenario given, we were told that the group of identical mice is given the supplement and the other group is not given any thing which means that the control group is the one which wasn't given anything while the ones who were given something is the experimental group.
The dependent variable is the supplement which was given to the mice and is therefore the reason why option B was chosen as the correct choice.
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Following the procedure of this experiment, you determined that your 1.000g sample of a fruit drink powder contained 6.04E-5 moles of acidic protons. Of these acidic protons, 2.00E-5 moles were due to VC. The rest were due to an acid H2B in the sample. Calculate: a) Moles of acidic protons due to H2B in the fruit drink sample b) Moles of H2B in the fruit drink sample
a.) 4.04E-5 moles of acidic protons
b.) 2.02E-5 mole of H2B in the fruit drink
What are protons?A proton can be defined as a stable subatomic particle with symbol p , H⁺, or ¹H⁺ that has a positive electric charge of +1 e elementary charge.
The mole with its symbol mol, is the unit of amount of substance in the International System of Units. The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object or sample.
The formula for the number of moles formula is expressed as follows;
Number of moles = Mass of substance / Mass of one mole.
n = m/M
from the given above, we have that
mass of sample = 1.00g
a.) Moles of acidic protons due to H2B in the fruit drink sample will be
6.04E-5 moles of acidic protons - 2.00E-5 moles were due to VC
= 4.04E-5 moles of acidic protons.
b.) Moles of H2B in the fruit drink sample = 2.02E-5 mole of H2B in the fruit drink
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A chemist reacts 10.5 g of Ag with 7.5 g of s in the reaction from the previous question what is the percent yield of a chemist actually obtains 9.8 g of ag2s
If 10.5 g of Ag and 7.5 g of S are reacted and 9.8 g of [tex]Ag_2S[/tex] is obtained, the percent yield of the reaction would be 81.4%
Percent yieldAg and S react to form [tex]Ag_2S[/tex] as follows:
[tex]2Ag + S -- > Ag_2S[/tex]
The mole ratio of Ag to S is 2:1.
10.5 g of Ag = 10.5/108
= 0.0972 moles
7.5 g of S = 7.5/32
= 0.2344 moles
In other words, Ag is limiting in availability.
The mole ratio of Ag to [tex]Ag_2S[/tex] = 2:1
0.0972 Ag is equivalent to 0.0972/2 = 0.0486 moles of [tex]Ag_2S[/tex]
0.0486 moles [tex]Ag_2S[/tex] weighs = 0.0486 x 247.8
= 12.04 grams
percent yield of [tex]Ag_2S[/tex] = 9.8/12.04 x 100%
= 81.4%
The percent yield of [tex]Ag_2S[/tex] that the chemist actually obtained is 81.4%.
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What electrons participate in chemical bonding?
Answer:
valence electrons
Explanation:
they are the electrons that are in the outermost shell
A 9.6 g object is placed in a graduatedcylinder displacing the volume from 10.0 mLto 13.2 mL.The volume of this object is 3.2 mL.What is its density in g/mL?Round your answer to the appropriatenumber of significant figures.[?] g/mL
ANSWER
T
EXPLANATION
Given that;
The mass of the object is 9.6 grams
The volume of the object is 3.2mL
Follow the steps below to find the density of the object
[tex]\text{ Density = }\frac{\text{ mass}}{\text{ volume}}[/tex]Substitute the given data into the formula above
Convert the volume of the object to cm^3
Recall, that 1mL is equivalent to 1cm^3
Hence, 3.2mL is 3.2 cm^3
[tex]\begin{gathered} \text{ Density= }\frac{\text{ 9.6}}{\text{ 3.2}} \\ \text{ Density = 3.00g/cm}^3 \end{gathered}[/tex]Therefore, the density of the object is 3.00 g/mL
Balance the following Equation:
A LI₂CO3 (s) + B HCI (aq) -> C LICI (aq) + D H₂O (1) + E CO₂ (g)
a) A = 1; B = 1; C = 1; D = 1; E = 1
b) A= 1; B = 1; C = 2, D = 1; E = 1
c) A= 1, B2, C = 2; D = 1; E = 1
d) A=2; B = 1;, C = 1; D = 2; E = 1
Answer:
C is the answer
Explanation:
Li2CO3 + HCl - - - - - - -> LiCl + H2O + CO2
Li. Li. H. Li. H. H. C
C Cl. Cl. O. O. O
O. O. O
2 Li ------>1Li so we put 2 in front LiCl on the right side to make 2Li---->2Li.
1H------->2H so we put 2 in front HCl on left side to make
Li2CO3 + 2HCl - - - - - - -> 2LiCl + H2O + CO2