If a Ferrari, with an initial velocity of 14m/s, accelerates at a rate of 60 m/s^2 for 4 seconds, what will its final velocity be

Answers

Answer 1

Answer:

254 m/s

Explanation:

(Vf-Vi) = at

(Vf-14)= 60 (4)

Vf = 254 m/s


Related Questions

HURRY I NEED IT NOW What is the density at 20oC of 12.0 milliliters of a liquid that has a mass of 4.05 grams?

0.338 g/mL

2.96 g/mL

16.1 g/mL

48.6 g/mL

Answers

Density is the mass per unit volume of any object. It is calculated by dividing the mass of an object by its volume. This is:

ρ = m/V

ρ = 4.05 g  / 12 mL

ρ = 0.3375 g/mL

ρ ≅ 0.338 g/mL

OPTION A

The diagram below shows a wave with its wavelength indicated in red.
wavelength

What will happen to the wave's frequency if its wavelength is made twice as long?

A. It will stay the same.

B. It will go to zero

C. It will double.

D. It will decrease

Answers

Answer:

answer is D.it will decrease

Answer:

D. It will decrease

Explanation: Study island ;)

The ball is pulled by a force called gravity. In what direction does gravity always pull the ball?​

Answers

Answer:

Gravity always pulls the ball toward the center of earth (the ground).

Explanation:

what that guy up there said^^

Buster Posey hits a pop-up straight up. The velocity of the baseball as it leaves the bat is 42.5 m/s. Determine (a) the total time the baseball is in the air, and (b) the maximum height the baseball reaches. Assume the baseball is caught at the same height above the ground as it was hit. Draw an image of the baseball for each 1 second of time it is traveling, for each image include a labeled velocity and acceleration vector.

Answers

Answer:

part a: 4.25s

part b: 180.625m

Explanation:

part a:

what we know: vi=42.5m/s

                          t=?

                          vf=0

                          g= -10m/s^2

----------------------------------------------------------

equation: vf-vi/g=t

plug in: -42.5m/s/ - 10m/s^2 = 4.25s

-----------------------------------------------------------

part b: 42.5m/s x(times) 4.25s = 180.625m

Which of the following represent an atom from period 3?WILL MARK BRAINLIEST

Answers

Answer:

First one

It has 3 orbital

The diagram first represents an atom from period three of the modern periodic table.

How many periods are there in the periodic table?

There are seven periods and 18 groups in the periodic table where each element is arranged on the basis of its increasing atomic number.

The atom represents in the diagram first is known as the sodium element. The atomic number of sodium is 11. Its electronic configuration is 2, 8, and 1. It requires three shells for the distribution of electrons. Apart from sodium, other members of period three include magnesium, aluminum, Silicon, Phosphorus, Sulfur, chlorine, and argon.

The diagram two represents an element of helium, while the diagram three represents an element of oxygen.

Therefore, the diagram first represents an atom from period three of the modern periodic table.

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If you wake up in the morning, go to school, go to the grocery store, and then return to the same place where you woke up, what is your displacement for the day

Answers

Answer:

0 I think

Explanation:

A penny is dropped from the 82nd Floor Observatory of the Empire State Building. The penny will fall for 8.1s before hitting the ground. 1. How far does the penny fall? 2. How fast is the penny going when it hits the ground?

Answers

Answer:

vf=79.38 m/s

y= 321.5 m

Explanation:

Free Fall Motion

A free-falling object falls under the exclusive influence of gravity. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

1.

The penny will fall for t=8.1 s before hitting the ground, thus the height from which it was dropped is:

[tex]\displaystyle y=\frac{9.8\cdot 8.1^2}{2}[/tex]

y= 321.5 m

2.

The final velocity is:

[tex]vf=9.8\cdot 8.1[/tex]

vf=79.38 m/s

What is its speed if it takes 0.5 seconds to cover the distance?

Answers

Answer:How far is the distance?

Explanation:

Se lanza verticalmente hacia arriba un proyectil y alcanza una altura máxima de 100 metros de altura. ¿Cuál fue la velocidad hacia arriba con la que fue lanzada?

Answers

Answer:

v =  44,3 m/s

Explanation:

La velocidad la podemos hallar usando la siguiente expresión:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]

En donde:

h: es la máxima altura = 100 m

[tex]v_{f}[/tex]: es la velocidad final = 0 (en la altura máxima)

[tex]v_{0}[/tex]: es la velocidad inicial =?

g: es la gravedad = 9,81 m/s²

Resolviendo la ecuación anterior para v₀, tenemos:

[tex] v_{0} = \sqrt{2gh} = \sqrt{2*9,81 m/s^{2}*100 m} = 44,3 m/s [/tex]

Entonces, el proyectil fue lanzado hacia arriba con una velocidad de 44,3 m/s.

Espero que te sea de utilidad!                      

As shown in the figure, a 2.00-kg block is held in place against the spring by a 50-N horizontal external force. The external force is removed, and the block is projected with a velocity v1 = 1.2 m/s at as it separates from the spring. The block descends a ramp and has a velocity v2 = 2.0 m/s at the bottom. The track is frictionless between points A and B. The block enters a rough section at B, extending to E. The coefficient of kinetic friction between the block and the rough surface is 0.30. The velocity of the block is v3 = 1.4 m/s at C. The block moves on to D, where it stops.

A) What is the total energy of the spring block system before the block descends down the ramp.

B) How high is the ramp?

C) How far did the block move from B to C?

D) How far did the block move from C to D?

E) What is the work done by friction on the block from B to D?

F) What is the Mechanical energy of the spring-block system at E?

G) How much was the spring compressed by the external force

H) What is the spring constant?

Answers

Answer:

Explanation:

A ) Total energy of spring block system at height = kinetic energy at the bottom

= 1/2 m V²

= .5 x 2 x 2²

= 4 J

B )

height of ramp be h

mgh = 1/2 m ( v₂² - v₁² )

2 x 9.8 x h = 2² - 1.2²

19.6 h = 4 - 1.44

h = .1306 m

13.06 cm

C ) If distance between B and C be x₁

work done by friction = reduction in kinetic energy

= μ mg x₁ = 1/2 m ( 2² - 1.4² )

.3 x 9.8 x₁ = 1.02

x₁ = 34.7 cm

D )

If distance between C and D be x₂

work done by friction = reduction in kinetic energy

= μ mg x₂ = 1/2 m ( 1.4² - 0 )

.3 x 9.8 x₂ = .98  

x₂ = 33.33 cm

E )

Total work done by friction

= 1/2 m v² - 0 , v = 2 m /s

= .5 x 2 x 2²

= 4 J .

F )

Mechanical energy of the system at E = 0

G ) 1/2 k x² = 1/2 m v²

kx = 50 N , where x is compression and k is spring constant

k²x² / 2k = 1/2 m v²

50² / k = 2 x 1.2²

k = 868.05 N / m

H ) kx = 50

x = 50 / k

= 50 / 868.05

= 5.76 cm .

A man paces 2m
east and 3m north
while on the phone.
The entire trip
takes 13s. What is
the man's distance,
displacement,
average speed, and
average velocity?
C
yo
of
S
shc
do
you
Us
be

Answers

Ndjsjisisoskskksieiwieiieie

PLEASE HELP ME ANSWER DUE SOON BRAINLIEST FOR WHOEVER

Answers

Answer:

1) mechanical

2) transverse

3) medium

4) longitudinal

Explanation:

A bullet is shot from a rifle with a speed of 3,015 feet per second. Assuming the billet moves at a constant velocity what is the time rescuers die the biller to strike a target 4,146 meters away

Answers

Answer:

Explanation:

Given

final speed v = 3015ft/s

initial speed = 0m/s

Distance S = 4146m/s

Required

Time

Using the equation of motion to get the time;

S = (v+u)/2 * t

since 1m = 3.28084ft'

4146m = 3.28084 * 4146 = 13,602.36264feet

13,602.36264 = 3015+0/2 * t

13,602.36264 = 1,507.5t

t = 13,602.36264/ 1,507.5

t = 9.023 secs

Hence it will take 9.023 seconds the rescuer die the biller to strike a target

When forces are balanced, what happens to the motion of the object?

Group of answer choices

Objects never have balanced forces.

Objects with balanced forces change motion.

Objects with balanced forces are able to change at will.

Objects with balanced forces remain unchanged.

Answers

Answer:

C-objects with balanced forces remain un changed

Explanation:

because the forces that act on the body cancel each other and the net force=0

A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42°. What is the force of
static friction acting on the box if box has a gravitational force of 112.1 N ?
0 70 N
O 80 N
O 75 N
O 85 N
Mark this and return
Save and Exit
Next
Submit

Answers

Answer:

The correct option is;

75 N

Explanation:

The given parameters are;

The angle of inclination of the ramp, θ = 42°

The gravitational force of the box = m × g = 112.1 N

Let [tex]F_f[/tex] represent the force of static friction acting on the box

Given that the box is at rest, we have

The component of the gravitational force acting along the inclined plane = The force of static friction acting on the box, [tex]F_f[/tex]

We have that the component of the gravitational force acting along the inclined plane = m × g × sin (θ) = [tex]F_f[/tex]

[tex]F_f[/tex] = m × g × sin (θ)

Substituting the values, gives;

[tex]F_f[/tex] = 112.1 × sin (42°) ≈ 75.0095409728

∴ The force of static friction acting on the box = [tex]F_f[/tex] ≈ 75 N

Answer:

C: 75N

Explanation:

Another name for semi-arid climate is

Answers

Answer: an steppe climate

Explanation:

Brady has extreme persistent worry and fear that impacts his daily life. How would this disorder be classified in the DSM-5? (2 points) Group of answer choices Anxiety Disorder Substance Use and Addictive Disorder Obsessive-Compulsive and Related Disorder Feeding and Eating Disorder

Answers

Answer:

Anxiety

Explanation:

Answer:

anxiety disorder

Explanation:

just took the quiz

If 4000J is used to move a charge through a potential difference of 0.078V, what is the charge?

Answers

Answer:

102564.103 C

Explanation:

From the question given above, the following data were obtained:

Energy (E) = 4000 J

Potential difference (V) = 0.078 V

Charge (Q) =?

Thus, we can obtain the charge as illustrated below:

E = ½QV

4000 = ½ × Q × 0.078

4000 = Q × 0.039

Divide both side by 4000

Q = 4000 / 0.039

Q = 102564.103 C

Thus, the charge is 102564.103 C.

Irene drops a clay ball at time t=0. The ball stops when it hits the ground. Which of the following graphs best shows the velocity v of the clay ball from when it is dropped until it hits the ground?

Answers

Answer:

Graph-

Explanation:

The graph best shows the velocity v of the clay ball from when it is dropped until it hits the ground is attached below.

What is velocity?

Velocity is the time rate of change of displacement. The displacement and velocity both are vector quantities. They represent magnitude and direction as well.

Irene drops a clay ball at time t=0. The ball stops when it hits the ground.

When the clay ball drops, only force acting is due to acceleration due to gravity.

The velocity of the clay ball decreases with the time.

Thus, the graph best shows the velocity v of the clay ball from when it is dropped until it hits the ground is attached.

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An aircraft is descending with a constant velocity of 480 kmh at an angle of 2.0 to the horizontal. What is the vertical component of the plane's velocity

Answers

Answer:

Vy = 4.65 m/s

Explanation:

Since, the airplane is descending at a rate of 480 km/h at an angle of 2° from horizontal. Therefore, its vertical component of velocity shall be given as follows:

Vy = V Sin θ

where,

Vy = Vertical Component of Velocity = ?

V = Velocity of Plane = (480 km/h)(1000 m/1 km)(1 h/3600 s) = 133.33 m/s

θ = Angle = 2°

Therefore,

Vy = (133.33 m/s)(Sin 2°)

Vy = 4.65 m/s

Which changes of state occur between solids and gases? Check all that apply.

vaporization
deposition
freezing
melting
sublimation

Answers

Answer:

deposition, sublimation

Explanation:

The changes of state occur between solids and gases during deposition and sublimation. The second and fifth option are correct.

What is sublimation?

The conversion of solid to gas and gas to solid directly, as in case of solid ice made of carbon di oxide.

The change of state means changing the phase of the matter with the change in temperature and pressure of the surrounding.

The vaporization change liquid to gas or solid to liquid and vice versa. Freezing is converting liquid to solid. Melting is converting from solid to liquid.

The rest phenomenon are deposition and sublimation in which phase change between solid and gas.

Thus,  second and fifth option are correct.

Learn more about sublimation.

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im a very dumb human being plz help

Answers

Answer:

so first is the clouds is presipitision then its  the ocean one and then dirt and then the mud then the gray part

Explanation:

Solve these two please its urgent, If i like your answer ill give brainly....

Answers

Answer: green car and red car

Explanation:

Answer:

it is white car for the first question and for the second it goes green slowest and white fastest red is in the middle

A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars combine.

Answers

Answer:

ok what is the question

Answer:

If the question is what is the magnitude of the final velocity of the combined cars ? Answer: 1.5 m/s

Explanation:

What the someone explain this to me

Answers

Answer:

the answer might be A and D if not sorry

Explanation:

Un bloque de 20kg de masa se desplaza horizontalmente en la dirección de eje X por acción de una fuerza horizontal variable F = 6x, donde F se mide en Newton y "x" en metros. Si se desprecia el rozamiento determine: a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x=+10m hasta la posición x=+20m b) La rapidez del bloque en la posición x=+20m, si su rapidez en la posición x=+10m fue √10 m/s.

Answers

Answer:

a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.

b) La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.

Explanation:

a) El trabajo expermentado por el bloque ([tex]W[/tex]), medido en joules, es definida por la siguiente ecuación integral:

[tex]W = \int\limits^{x_{max}}_ {x_{min}} F(x) \, dx[/tex] (1)

Donde:

[tex]x_{min}[/tex], [tex]x_{max}[/tex] - Posiciones mínima y máxima del bloque, medidos en metros.

[tex]F(x)[/tex] - Fuerza horizontal aplicada al bloque, medida en newtons.

Si conocemos que [tex]F(x) = 6\cdot x[/tex], [tex]x_{min} = 10\,m[/tex] y [tex]x_{max} = 20\,m[/tex], entonces el trabajo realizado por esta fuerza es:

[tex]W = \int\limits^{20\,m}_{10\,m} {6\cdot x} \, dx[/tex] (2)

[tex]W = 6\int\limits^{20\,m}_{10\,m} x\, dx[/tex]

[tex]W = 3\cdot x^{2}\left|\limits_{10\,m}^{20\,m}[/tex]

[tex]W = 3\cdot [(20\,m)^{2}-(10\,m)^{2}][/tex]

[tex]W = 900\,J[/tex]

El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.

b) La rapidez final del bloque se determina mediante de Teorema del Trabajo y la Energía, es decir:

[tex]W = K_{f}-K_{o}[/tex] (3)

Donde son [tex]K_{o}[/tex], [tex]K_{f}[/tex] las energías cinéticas traslacionales inicial y final, medidos en joules.

Al aplicar la definición de energía cinética traslacional, expandimos y simplificamos la ecuación como sigue:

[tex]W = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (4)

Donde:

[tex]m[/tex] - Masa del bloque, medido en kilogramos.

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Rapideces inicial y final del bloque, medidos en metros por segundo.

[tex]\frac{2\cdot W}{m} = v_{f}^{2}-v_{o}^{2}[/tex]

[tex]v_{f} = \sqrt{\frac{2\cdot W}{m}+v_{o}^{2}}[/tex]

Si conocemos que [tex]W = 900\,J[/tex], [tex]m = 20\,kg[/tex] y [tex]v_{o} = \sqrt{10}\,\frac{m}{s}[/tex], entonces la rapidez final del bloque es:

[tex]v_{f} = \sqrt{\frac{900\,J}{2\cdot (20\,kg)}+10\,\frac{m^{2}}{s^{2}} }[/tex]

[tex]v_{f} \approx 5.701\,\frac{m}{s}[/tex]

La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.

Frank has a liquid. It has a mass of 6 g and a volume of 9 ml. What is its density?

Answers

1/3
Because density is mass/volume

Please help me out! This is a big question!
True or false?
Because of the Doppler effect, as an observer and source move closer the pitch of the sound from the source gets higher; if the observer and source are moving farther apart the pitch will sound lower to the observer.

Answers

Answer:

true

Explanation:

I just had a test on this

Answer:

true

Explanation:

cause it is

She wants to travel back to Madison by train. The distance from Chicago to Madison is 147 miles and takes 2.47 hours. If she makes no stops, what is her average speed?

Answers

Answer:

59.51 mph.

Explanation:

The following data were obtained from the question:

Distance (d) = 147 miles

Time (t) = 2.47 hours.

Speed (S) =?

Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed (S) = Distance (d) / time (t)

S = d/t

With the above formula, we can obtain the speed of the girl as illustrated below:

Distance (d) = 147 miles

Time (t) = 2.47 hours.

Speed (S) =?

S = d/t

S = 147 miles / 2.47 hours.

S = 59.51 miles per hour (mph)

Thus, the speed of the girl is 59.51 mph.

A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy
is loaded into it. The roller coaster starts from rest at point A which is 25 m above
point B. If the track near to point B is in the shape of a circle with a radius of 15 m,
and the cart is moving at 22 m/s at point B, what centripetal acceleration does the
cart experience at that point?

Answers

Answer:

32 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of cart = 120 Kg

Radius (r) = 15 m

Velocity (v) = 22 m/s

Centripetal acceleration (a) =?

The centripetal acceleration experienced by the cart can be obtained as illustrated below:

a = v²/r

a = 22² / 15

a = 484 / 15

a = 32.27 ≈ 32 m/s²

Thus, the centripetal acceleration experienced by the cart is approximately 32 m/s².

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