In 2014, the population of Arizona was approximately 5.23 x 10. if it’s land area

Answer:

80 degrees

Step-by-step explanation:

the angles in a triangle all add up to 180 degrees

Answer:

Let the third angle be [tex]{x°}[/tex]

Since the sum of all three angles of a triangle is 180°,

We have

40°+60°+[tex]{x}[/tex] = 180°

→ 100+[tex]{x}[/tex] = 180°

[tex]{x}[/tex] = 180-100 = 80°

The measure of the third angle is 80°

Answer:

[tex]k=-\frac{1}{42}[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

Given the equation [tex]y=14x+2[/tex], we can identify the slope (m) to be 14. This means that the slope of a perpendicular line would have to be [tex]-\frac{1}{14}[/tex] since that is its negative reciprocal.

In the equation [tex]y=k*3x+2[/tex], the slope would be 3k. 3k would be equal to [tex]-\frac{1}{14}[/tex]:

[tex]3k=-\frac{1}{14}[/tex]

Divide both sides by 3 to solve for k

[tex]k=-\frac{1}{42}[/tex]

I hope this helps!

Answer:

B

Step-by-step explanation:

the slope is 0

the y intercept is ( 0,4 )

here,

f(x)=x-4

then, f(-3.2)=(-3.2)-4

[ replace the value of x in the equation by -3.2]

therefore,f(-3.2)=-7.2 answer....

HOPE THIS HELPS YOU.HAVE A NICE DAY/NIGHT.....

9514 1404 393

Answer:

  (a)  f(-3.2) = -7

Step-by-step explanation:

The ceiling function returns the smallest integer greater than or equal to its argument value. For an argument of -3.2, the next larger integer is -3.

  [tex]f(-3.2)=\lceil -3.2\rceil-4=-3-4=\boxed{-7}[/tex]

Answer:

We know that:

H(x) = |1 - x^3|

and:

We want to write H(x) as  f( g(x) ) , such that for two functions:

So we want to find two functions f(x) and g(x) such that:

f( g(x) ) = |1 - x^3|

Where neither of these functions can be an identity function.

Let's define g(x) as:

g(x) = x^3 + 2

And f(x) as:

f(x) = | A - x|

Where A can be a real number, we need to find the value of A.

Then:

f(g(x)) = |A - g(x)|

and remember that g(x) = x^3 + 2

then:

f(g(x)) = |A - g(x)| = |A - x^3 - 2|

And this must be equal to:

|A - x^3 - 2| =  |1 - x^3|

Then:

A = 3

The functions are then:

f(x) = | 3 - x|

g(x) = x^3 + 2

And H(x) =  f( g(x) )

Answer:

[tex]area \: = \frac{165}{360} \times \pi {8}^{2} \\ = 92.1533845053 \\ = 92 \: in^{2} [/tex]

Use the following property below:

[tex] \large \boxed{ \sqrt[n]{a} \times \sqrt[n]{a} \times \sqrt[n]{a} = { (\sqrt[n]{a}) }^{3} }[/tex]

Therefore,

[tex] \large{ \sqrt[7]{x} \times \sqrt[7]{x} \times \sqrt[7]{x} = { (\sqrt[7]{x}) }^{3} }[/tex]

Then we use next property.

[tex] \large{ \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} } }[/tex]

Hence,

[tex] \large{ \sqrt[7]{ {x}^{3} } = {x}^{ \frac{3}{7} } }[/tex]

Answer

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: \: 1 \frac{1}{15} \:(or) \: 1.0667}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \frac{4}{5} \div \frac{3}{4} [/tex]

= [tex] \: \frac{4}{5} \times \frac{4}{3} [/tex]

= [tex] \: \frac{4 \times 4}{5 \times 3} [/tex]

= [tex] \: \frac{16}{15} [/tex]

= [tex] \: 1 \frac{1}{15} [/tex]

( OR )

= [tex] \: 1.0667[/tex]

[tex]\bold{ \green{ \star{ \orange{Mystique35\:♨}}}}⋆[/tex]

Step-by-step explanation:

[tex] \frac{4}{5} \div \frac{3}{4} \\ = \frac{4}{5} \times \frac{4}{3} \\ = \frac{16}{15} \\ thank \: you[/tex]

=====================================================

Explanation:

The double tickmarks show that segments DE and EB are the same length.

The diagram shows that DB = 16 cm long

We'll use these facts to find DE

DE+EB = DB

DE+DE = DB

2*DE = DB

DE = DB/2

DE = 16/2

DE = 8

-------------

Now let's focus on triangle DEC. We just found the horizontal leg is 8 units long. The vertical leg is EC which is unknown for now. We'll call it x. The hypotenuse is CD = 9

Use the pythagorean theorem to find x

a^2+b^2 = c^2

8^2+x^2 = 9^2

64+x^2 = 81

x^2 = 81 - 64

x^2 = 17

x = sqrt(17)

That makes EC to be exactly sqrt(17) units long.

If you follow those same steps for triangle ADE, then you'll find the missing length is AE = 6

---------------

So,

AC = AE+EC

AC = 6 + sqrt(17)

AC = 10.1231056256177

AC = 10.1 cm approximately

Answer:

7>h

Step-by-step explanation:

Answer:

prime factorization of 225 = 32•52.

Step-by-step explanation:

The number 225 is a composite number so, it is possible to factorize it. 225 can be divided by 1, by itself and at least by 3 and 5.

A composite number is a positive integer that has at least one positive divisor other than one or the number itself. In other words, a composite number is any integer greater than one that is not a prime number.

Answer:

Given function:

This is the third degree polynomial, so it has total 3 roots.

Lets factor it and find the roots:

The roots are:

It has highest degree 3 so 3 roots

Lets find

Roots are

Answer: 33.4

Step-by-step explanation:

Answer:

51, 104, and the next number of series is 185

Step-by-step explanation:

I hope this will help u

Answer:

the next number in the sequence should be 45

Answer:

7√2

Step-by-step explanation:

Leg of the right triangle = greater base - smallest base = 10- 3 = 7

Leg 2 = height = 7

x = [tex]\sqrt{7^2 + 7^2} = \sqrt{49 * 2} = 7\sqrt{2}[/tex]

Answer:

12 meters

20cm*60 = 1200cm = 12 meters

100cm = 1m btw

Answer:

C

Step-by-step explanation:

173.6 • 9= 1562.4

Answer:

You haven't given a picture of the graph dear.

The point (-3,-2) lies in the third quadrant.

Answer:

3 mi of fencing would be required to enclose this field.

Step-by-step explanation:

Here we are finding the perimeter of a field with given length and width.  We apply the perimeter formula P = 2L + 2W.  Substituting the given dimensions, we get:

P = 2(1 mi) + 2(0.5 mi), or

P = 2 mi + 1 mi = 3 mi

3 mi of fencing would be required to enclose this field.

Answer:

15840 feet of fencing = Perimeter = 15840ft

However, if fencing is 6ft or 10ft we need to divide by the length of each fence for panels.

See bold.

Step-by-step explanation:

6ft fencing = 5280/6 = 880 fences one length

880 x 2 = 1760 6ft fences 2 sides

0.5 x 1760 = 880

1760+ 880 = 2640 fences each 6ft

Total feet of fence = 2640 x 6 =15840 feet of fencing

Answer:

78 miles

Step-by-step explanation:

Given that:

Original length, L = 47 miles

Additional length (miles) added per day, = 1 mile

Representing as an equation :

L(D) = original length + additional length per day * number of days

Let, D = number of days

L(D) = 47 + D

Length after 31 days :

L(31) = 47 + 31

= 78 miles

Answer: it is a linear line

Step-by-step explanation:

They both together make 0

Answer:

3.6661

3.6661

A, Adding a constant does nothing to the standard deviation

Step-by-step explanation:

I'm gonna assume s=standard deviation

The standard deviation is just the square root of the second moment minus the first moment squared

Because we were not told otherwise I think it's pretty safe to assume that all events are equally likely

Let's start by calculating the first moment (AKA The mean)

1/5(8+16+14+8+16)= 12.4

Let's then find the second moment

1/5(8²+16²+14²+8²+16²)= 167.2

√(167.2-12.4²)=3.6661

b.

While I could just tell you that adding something to the standard deviation (and the variane as well) doesn't do anything let's calculate it for fun

same process

.2(16+24+22+16+24)= 20.4

.2(16²+24²+22²+16²+24²)=429.6

√(429.6-20.4²)= 3.6661

Answer:

[tex]Rate = -10[/tex]

Step-by-step explanation:

Given

The table

Required

The average rate if change over (4,6)

This is calculated as:

[tex]Rate = \frac{f(6) - f(4)}{6-4}[/tex]

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

From the table:

[tex]f(6) = -37[/tex]

[tex]f(4) = -17[/tex]

So:

[tex]Rate = \frac{-37 --17}{2}[/tex]

[tex]Rate = \frac{-37 +17}{2}[/tex]

[tex]Rate = \frac{-20}{2}[/tex]

[tex]Rate = -10[/tex]

Answer:

[tex]\sec A =\frac{\sqrt{13}}{3}[/tex]

Step-by-step explanation:

Given

[tex]\tan A = 2/3[/tex]

Required

[tex]\sec\ A[/tex]

First, we have:

[tex]\tan A = \frac{x}{y}[/tex]

Where

[tex]x \to oppo site\\[/tex]

[tex]y \to adja cent[/tex]

[tex]z \to hypotenuse[/tex]

So:

[tex]\tan A = \frac{x}{y} =\frac{2}{3}[/tex]

By comparison:

[tex]x = 2; y =3[/tex]

Using Pythagoras, we have:

[tex]z^2 = x^2 +y^2[/tex]

[tex]z^2 = 2^2 +3^2[/tex]

[tex]z^2 = 13[/tex]

[tex]z = \sqrt{13[/tex]

[tex]\sec A =\frac{z}{y}[/tex]

[tex]\sec A =\frac{\sqrt{13}}{3}[/tex]

Answer:

13km per day

Step-by-step explanation:

If this does not involve complex rules then we can calculate the rate just by dividing 52 with 4 which results 13km per day

Goodluck

Answer:

B

Step-by-step explanation:

LA = radius x 2 x pi x height = 6 x 2 x pi x 13 = 489.8 ft^2

Answer:

C(min) = 0.5*V  +  √V/1.256  $

Step-by-step explanation:

The volume of a circular cylinder is: V(c)  = π*r²*h    where r is the radius of the circumference of the base and h is the height

The cost of the can is = the cost of (base and top) + lateral cost

Base surface = top surface =  π*r²

Then cost of ( base + top ) is = (2* π*r² )*0,1

Lateral surface is  = 2*π*r*h

Then cost of lateral surface is:  (2*π*r*h)*0,5

Total cost C(t) = (2* π*r² )*0,1  +  (2*π*r*h)*0,5

V = π*r²*h

Total cost  as a function of (V >0 a parameter) and r then

h  =  V / π*r²

C(V,r)  =  (2* π*r² )*0,1  +  π*r*(V / π*r²)

C(V,r)  =  0.2*π*r²  + V*/r

Taking derivatives on both sides of the equation we get:

C´(V,r)  =  2*0.2*π*r  -  V/r²

C´(V,r)  =  0             0.4*π*r  - V/r  = 0

Solving for r

0.4*π*r² - V = 0      ⇒  1.256*r²  = V          r = √ V/ 1.256    cm

and  h  =  V /π *  (√ V/ 1.256)²

h =  1/ 1.256*π

h  =  0.254 cm

C(V,r)  =  0.2*π*r²  + V*/r

C(min) = 0.2*π* (√ V/ 1.256)²   +  V/ √ V/ 1.256

C(min) =  0.2*π*V/1.256  +   V/ √ V/ 1.256

C(min) = 0.5*V  +  √V/1.256  $

Answer:

Step-by-step explanation:

Answer:

- 0.125

Step-by-step explanation:

Given the equation :

(0.020(5/4) + 3 ((1/5) – (1/4)))

0.020(5/4) = 0.025

3((1/5) - (1/4)) = 3(1/5 - 1/4) = 3(-0.05) = - 0.15

0.025 + - 0.15 = 0.025 - 0.15 = - 0.125

Answer:

C 80 R36

Step-by-step explanation:

See attached image for explanation.