In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

Answers

Answer 1

Answer:

90,597 square inches

Step-by-step explanation:

In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

We solve using Heron's formula

A = √s(s -a)(s - b) (s - c)

s = a + b + c/2

a = 410 inches

b = 530 inches

c = 830 inches

Hence,

s = 410 + 530 + 830/2

s = 885

A = √885(885 - 410)(885 - 530)(885 - 830)

A = 90,597.030166557 square inches

Approximately = 90,597.0 square inches


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The next term is 8/3

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

The area (A) of a triangle is calculated as

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If t varies 1/s and t=2 when s=60 find the relationship between t and s, b, find the value of t when s=90 c, find s when t=2,1/2

Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

I do not understand this either lolll lolll

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EQ 3 = A

EQ 4= C

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Answers

Solution,
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take the common,
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Here,
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Answers

Answer:

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Answer:

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Answers

Answer:

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Answers

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Answers

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