Karen the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or the other (not both). On Monday therewere 3 clients who did Plan A and 5 who did Plan B. On Tuesday there were 6 clients who did Plan A and 2 who did Plan B. Karen trained her Monday clients fora total of 10 hours and her Tuesday clients for a total of 10 hours. How long does each of the workout plans last?

Karen The Trainer Has Two Solo Workout Plans That She Offers Her Clients: Plan A And Plan B. Each Client

Answers

Answer 1

ive n

lan A

Plan B

Monday: 3 clients - Plan A

5 clients - Plan B

Total 10 hours

Tuesday

6 clients - Plan A

2 clients - Plan B

Total 10 hours

rocedure

Let's define a system of linear equations that represents the above problem.

A: Number of hours of workout in plan A

B: Number of hours of workout in plan B

[tex]\begin{gathered} 3A+5B=10 \\ 6A+2B=10 \end{gathered}[/tex]

The goal here is to solve

3A+5B=10 and

6A+2B=10 for the variables A and B.

The solutions to your equations are:

A = 5/4 hour

B = 5/4 hour


Related Questions

PLEASE HELP!!!!!!!!!!

Answers

[tex]\text{ \$9.50 +\$ 2.25 +w=14}[/tex]

Explanation

Step 1

et

w represents the cost of gift-wrapping.

then

Jessie spent a total of $14

total= 14

the cost for postage=$2.25

the cost of the gift( itself)=9.50

in words, the total is

the total cost is the cost of the gift plus the cost of the postage plus the cost of gift-wrapping

Now,replace

[tex]\begin{gathered} 14=\text{ \$9.50 +\$ 2.25 +w} \\ \text{reordering} \\ \text{ \$9.50 +\$ 2.25 +w=14} \end{gathered}[/tex]

1. Approximate using perfect squares.
<78 <
<√78<
<√78 <
So V78 is between
and

Answers

Answer:

8 and 9

Step-by-step explanation:

consider perfect squares either side of 78

64 < 78 < 81 , then

[tex]\sqrt{64}[/tex] < [tex]\sqrt{78}[/tex] < [tex]\sqrt{81}[/tex] , that is

8 < [tex]\sqrt{78}[/tex] < 9

someone in a car going past you at the speed of 41 m/s drops a small rock from a height of 1.6 m . How far from the point of the drop will the rock hit the ground? the acceleration due to gravity is 9.8 m/s^2​

Answers

Answer:

please mark my brain list answer

Answer:

s = ut + 1/2 at²

2.4 = 4.9t²

t = 0.70

distance = speed x time

d = 24 x 0.7

d = 16.8 m

Andy has $310 in his account. Each week, w, he withdraws $30 for his expenses. Which expression could be used if he wanted to find out how much money he had left after 8 weeks?
1) 310-8w
2) 280+30(w-1)
3) 310w-30
4) 280-30(w-1)

Answers

Hey you man what are you doing here go to there

D- 280-30(w-1)

EXPLANATION - we read the questions and create 310-30w as an equation, but we have to find another way that is equivalent to A B C or D. If you take D-280-30(w-1) and distribute to get 280-30w+30 then you have to combine like terms to get 310-30w.

Probability of distribution: Four children are born, and the number of boys is noted assume an equal chance of a boy or a girl for each birth

Answers

The subset's components can be listed in any order when combined.

The former two are both 15/16.

What is the difference between combinations and permutations?A set of elements can be divided into subsets in two different ways: by combination and by permutation. The subset's components can be listed in any order when combined. The components of the subset are listed in a permutation in a certain order. n distinct things permuted (when repetition is not allowed) Repetition when it is acceptable. When the objects are not distinct, permutation (Permutation of multi sets).

P(at least one boy) and then P(at least one Girl)

P(at least one boy and one girl)

If we assume P(girl) = P(boy) = 50%

The latter results from the 16 possible combinations.

noting only two of which are single sex.

So 14/16 = 7/8.

Therefore, the former two are both 15/16.

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[tex] \rm\sum_{n=2}^\infty \frac{(-1)^n}{n^2(n^2-1)} \binom{2n}{n}^{ - 1}\\ [/tex]
[tex]\:\:\:\:\:\:\:[/tex]​

Answers

Let

[tex]\displaystyle f(x) = \sum_{n=2}^\infty \frac{x^n}{n^2(n^2-1) \binom{2n}n}[/tex]

Differentiate and multiply by [tex]x[/tex].

[tex]\displaystyle xf'(x) = \sum_{n=2}^\infty \frac{x^n}{n(n^2-1) \binom{2n}n}[/tex]

Now differentiate twice.

[tex]\displaystyle x f''(x) + f'(x) = \sum_{n=2}^\infty \frac{x^{n-1}}{(n^2-1)\binom{2n}n}[/tex]

[tex]\displaystyle xf'''(x) + 2f''(x) = \sum_{n=2}^\infty \frac{x^{n-2}}{(n+1)\binom{2n}n}[/tex]

Multiply by [tex]x^3[/tex].

[tex]\displaystyle x^4 f'''(x) + 2x^3 f''(x) = \sum_{n=2}^\infty \frac{x^{n+1}}{(n+1)\binom{2n}n}[/tex]

Differentiate one last time and multiply by [tex]\frac1x[/tex].

[tex]\displaystyle x^3 f^{(4)}(x) + 6x^2 f'''(x) + 6x f''(x) = \sum_{n=2}^\infty \frac{x^{n-1}}{\binom{2n}n}[/tex]

Now integrate with the fundamental theorem of calculus, noting that [tex]f(0)=f'(0)=0[/tex] follows from our series definition. We do this twice and make use of the recurrence

[tex]I_n = \displaystyle \int_0^x y^n f^{(n+1)}(y) \, dy = x^n f^{(n)}(x) - n I_{n-1}[/tex]

Integrating once yields

[tex]\displaystyle x^3 f'''(x) + 3x^2 f''(x) = \sum_{n=2}^\infty \frac{x^n}{n \binom{2n}n}[/tex]

Multiply by [tex]\frac1x[/tex].

[tex]\displaystyle x^2 f'''(x) + 3x f''(x) = \sum_{n=2}^\infty \frac{x^{n-1}}{n \binom{2n}n}[/tex]

Integrating once more yields the ordinary differential equation

[tex]\displaystyle x^2 f''(x) + x f'(x) - f(x) = \sum_{n=2}^\infty \frac{x^n}{n^2 \binom{2n}n}[/tex]

and we recognize the right side as the series

[tex]\displaystyle \sum_{n=2}^\infty \frac{x^n}{n^2 \binom{2n}n} = 2\arcsin^2\left(\frac{\sqrt x}2\right) - \frac x2[/tex]

Solving the differential equation is quite doable with the variation of parameters method; we ultimately find

[tex]\displaystyle f(x) = \frac12 + \frac{7x}8 - \left(\frac1x+\frac12\right) \sqrt x \sqrt{4-x} \, \arcsin\left(\frac{\sqrt x}2\right) + 2 \left(\frac1x-1\right) \arcsin^2\left(\frac{\sqrt x}2\right)[/tex]

Recover the sum we want by letting [tex]x=-1[/tex]. Recall that

[tex]\arcsin(iz) = i \,\mathrm{arsinh}(z) = i\ln(z + \sqrt{1+z^2})[/tex]

Then we have the following equivalent results involving our old friend [tex]\phi[/tex].

[tex]\displaystyle f(-1) = -\frac38 - \frac{\sqrt5}2\, \mathrm{arsinh}\left(\frac12\right) + 4 \,\mathrm{arsinh}^2\left(\frac12\right) \\\\ f(-1) = -\frac38 - \frac{\sqrt5}2 \ln\left(\frac{1+\sqrt5}2\right) + 4 \ln^2\left(\frac{1+\sqrt5}2\right) \\\\ f(-1) = \boxed{-\frac38 - \left(\frac12 - \phi\right) \ln(\phi) + 4 \ln^2(\phi)}[/tex]

In AKLM, the measure of ZM=90°, ML = 55, KM = 48, and LK = 73. What ratiorepresents the cosecant of ZK?

Answers

Remember that

csc k=1/sin k

and

sin k=55/73

therefore

csc k=1/(55/73)

csc k=73/55

Which inequality correctly compares 118%, 0.34, and 2 1/5?

Answers

0.34 < 118% < two and one fifth

Answer:

ask your village people fowl

-3v-7v
What is the answer to this question

Answers

Answer:

-10v

Step-by-step explanation:

-3v - 7v

OR

(-3v)+(-7v)

= -10v

Answer:

the answer is -3v-7v= -10

Describe the transformation that shows Figure A is similar to Figure B. PLEASE HELP!!!

Answers

Answer:

C. the dilate with scale of 2

Step-by-step explanation:

when you dilate, a scale bigger than 1 means you enlarge the figure A

no other choices make figure a bigger to 'fit into' or be the same as figure B

so thus, the answer is C.

Answer:

C.

Step-by-step explanation:

as we can clearly see, when going from figure A to figure B every length and coordinate is doubled. that means a constant scale factor of 2 for all of that. but the angles and the general structure of the object remained the same (so, both are similar).

For two events A and B, P(A) = 0.60, P(B) = 0.40, and P(B|A) = 0.60. Find P(A|B).

Answers

The value of P(A|B) will be;

⇒ 0.6

What is mean by Probability?

The term probability refers to the likelihood of an event occurring.

Given that;

For the two events A and B;

⇒ P(A) = 0.60

⇒ P(B) = 0.40

And, P(B|A) = 0.60

Now,

Since, We know that;

⇒ P(A∪B) = P(A) + P(B) - P(A∩B)

Substitute all the values, we get;

⇒ P(A∪B) = 0.60 + 0.40 - P(A∩B)

And, P(A∩B) = P(A) P(B)

⇒  P(A∩B) = 0.60 × 0.40

⇒ P(A∩B) = 0.24

Hence,

⇒ P(A∪B) = 0.60 + 0.40 - P(A∩B)

⇒ P(A∪B) = 0.60 + 0.40 - 0.24

⇒ P(A∪B) = 0.76

Since, We know that the formula;

⇒  P(A|B) = P(A∩B) / P(B)

Substitute all the values we get;

⇒ P(A|B) = P(A∩B) / P(B)

⇒ P(A|B) = 0.24 / 0.40

⇒ P(A|B) = 0.6

Therefore,

The value of P(A|B) will be;

⇒ 0.6

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To find the actual discount, multiply the discount rate by the original amount 'x'. To find the sale price, subtract the actual discount from the original amount 'x' and equate this to given sale price. Solve the equation and find the original amount 'x'.

Answers

If the original price =$50

If we take $20 off, we have: $50-20 =$30

Next, taking 25% off of $30, we have:

Final Price = (100%-25%) of $30

=0.75 x 30

Final Price Final 0Price=$22.5

9

If we take $20 off, we have: $90-20 =$70

Next, taking 25% off of $70, we have:

Final Price = (100%-25%) of $70

=0.75 x 70

Final Price =$52.50

Need Help!!
Calculate the length x

Please explain to me on how to calculate this.

Answers

Answer: 55 cm

Step-by-step explanation:

a^2 + b^2 = c^2

X^2 + 48^2 = 73^2

X^2 + 2,304 = 5,329

X^2 = 3,025

X = 55

This is math… i swear please do not leave i have had 4 people leave me :(

Answers

B

1) To solve this question, we can write out two equations within this expression:

[tex]\begin{gathered} (x)30+(30-x)15=30(20) \\ 30x+450-15x=600 \\ 15x=600-450 \\ 15x=150 \\ \frac{15x}{15}=\frac{150}{15} \\ x=10 \end{gathered}[/tex]

So we can do it with 10L of that 30% solution.

2)Let's find the other volume, plugging into that x=10, since the whole volume of this new solution is 30L we can subtract from that 30L that 10L we have just found:

[tex]30-10=20l[/tex]

3) So we found 20l of the 15% solution.

Thus the answer is B

a) Find the function algebraically. Show yourwork!b) Where is the asymptote on the graph of thisfunction? Give as an equation.c) What is the domain and range of thisfunction?Domain:Range:

Answers

(a)

In order to find the function, let's use the ordered pair (-3, 8) in the given exponential function f(x).

So we have:

[tex]\begin{gathered} f(x)=a^x \\ \\ (-3,8)\colon \\ 8=a^{-3} \\ 2^3=(\frac{1}{a})^3 \\ 2=\frac{1}{a} \\ a=\frac{1}{2} \end{gathered}[/tex]

So the function is f(x) = (1/2)^x

(b)

The asymptote of this graph is y = 0, that is, the horizontal axis.

(c)

The domain is the values that x can assume, so the domain of this function is all real numbers, that is, (-infinity, infinity)

The range is the values that f(x) can assume, so the range of this function is y>0, that is, all positive numbers: (0, infinity)

Write the expression 12-2 in simplest form

Answers

Answer:

Is it 6-1?

Step-by-step explanation:

Answer: 6-1

Step-by-step explanation:

is simplest form

Choose the four expressions that are equivalent to 6^−2.

Answers

Answer:

y=-3/2x+4

Step-by-step explanation:

The expression 6⁻² can be written as -

6⁻² = 1/6²

6⁻² = 1/36

6⁻² = (1/6 x 1/6)

What is an expression? What is equation Modelling?

A mathematical expression is a combination of terms separated by mathematical operators. For example : 2x + 3y + 6. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have the following expression -

6⁻²

We can write the expression 6⁻² in the following possible ways -

6⁻² = 1/6²

6⁻² = 1/36

6⁻² = (1/6 x 1/6)

Therefore, the expression 6⁻² can be written as -

6⁻² = 1/6²

6⁻² = 1/36

6⁻² = (1/6 x 1/6)

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Solve the application involving geometry. If necessary, refer to the geometry formulas listed in the inside back cover of the text.
The measure of one angle is 11 times the measure of another. If the two angles are supplementary, find the measures of the angles.

Answers

One angle's measurement is 11 times that of another. if the two angles supplementary one another. The measure of the angles area one is 165° and other angle is 15°.

Given that,

One angle's measurement is 11 times that of another. if the two angles supplementary one another.

We have to determine the angles' measurements.

The word "supplementary" refers to two angles coming together to form a straight angle. It indicates that when two angles sum up to 180 degrees, they are said to be supplementary angles. If two angles complement one another

It has an acute angle on one side and an obtuse angle on the other.

The angles are both right angles.

So, It follows that A + B = 180°.

Angle A is 11 times angle B means

A=11B

We get,

11B+B=180

12B=180

B=180/12

B=15°

Then angle A is

A=11×15

A=165°

Therefore, The measure of the angles area one is 165° and other angle is 15°.

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Find the value of x.

Answers

I WILL USE THE REASONS VERTICAL OPPOSITE ANGLES AND CO-INTERIOR ANGLES

[tex]8x + 6 + 118 = 180 \\ 8x + 124 = 180 \\ 8x = 180 - 124 \\ 8x = 56 \\ \frac{8x}{8} = \frac{56}{8} \\ x = 7[/tex]

NOTE THAT DUE TO LACK OF LABELLING OF ANGLES IN THE DIAGRAM I COULDN'T GIVE YOU BRIEF EXPLANATION BUT I HOPE YOU UNDERSTAND.

Value of 0.3(1/4 - 1) + 0.35

Answers

The value of the expression is 0.125

Numerical expressions are sets of numbers that undergo mathematical operations with a pre-established order of operations. Numerical expressions are sets of numbers that undergo mathematical operations with a pre-established order of operations.

How to calculate the expression ?

The expression is

0.3(1/4 - 1) + 0.350.3(0.25-1) + 0.35

solve by using BODMAS0.3(-0.75) + 0.35= -0.225 + 0.35= 0.125

Hence the value of the expression is 0.125

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Parallelogram I is a scaled copy of parallelogram H.


What scale factor takes parallelogram H to parallelogram I?

Answers

1 ÷ 3 is the scale factor that takes parallelogram H to parallelogram I.

If Parallelogram I is a scaled replica of Parallelogram H, then perhaps the figure in which every length in the initial estimate is multiplied by the exact number.

Scale factor = size of new shape ÷ size of the old shape.

The magnification ratio of a parallelogram I is significantly 3 times that of parallelogram H this ratio could be only assumed when the data is not given.

The polygon will be reduced if the magnification ratio would be between 0 and 1. The picture will be magnified if the zoom ratio is larger than one.

The scale factor refers to the ratio of the old thing's scale to the new object's scale. Although the size of these ratios varies, they are useful.

Use negative magnification to enlarge the picture. Whenever the scale factor is negative, the value diverges from the scale.

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The complete question is -

Parallelogram I is a scaled copy of parallelogram H. What scale factor takes parallelogram H to parallelogram I in the image?

The scaling factor that transforms parallelogram H into parallelogram I is 1/3.

If Parallelogram I is a scaled-down version of Parallelogram H, then it might be the result of multiplying each length in the initial estimate by a precise value.

Scale factor is equal to new shape's size minus old shape's size.

A parallelogram I's magnification ratio is noticeably three times greater than a parallelogram H's. Only in cases where no data is provided may this ratio be assumed.

If the magnification ratio is in the range between 0 and 1, the polygon will be smaller. If the zoom ratio exceeds one, the image will be enlarged. The scale factor is the ratio of the scale of the old thing to the scale of the new thing.These ratios are helpful despite the fact that their sizes differ.

Enlarge the image by applying negative magnification. The value deviates from the scale whenever the scale factor is negative.

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pls help this is the last question and i have to get correct

Answers

The correct statements regarding sum and subtraction with negative numbers are given as follows:

The inequality p + q < 0 is possible because -5 + (-5) = -10.The inequality p - q > 0 is possible because -4 - (-5) = 1.The inequality p - q < 0 is possible because -5 - (-4) = -1.

How to add two negative numbers?

When two negative numbers are added, the result is negative, as we keep the signal and then add the absolute amounts of each value, for example:

-5 + (-5) = -(5 + 5) = -10.

Hence the fourth statement is correct, while the first and the third are not.

How to subtract two negative numbers?

When we subtract two negative numbers, we first transform the second number to positive, meaning that the result can be either positive or negative, as the result will take the signal of the higher value and their absolute amounts are subtracted.

Hence:

-4 - (-5) = -4 + 5 = (5 - 4) = 1.-5 - (-4) = -5 + 4 = -(5 - 4) = -1.

Hence the fifth and the sixth statements are correct.

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Solve the following compound inequality -24 ≤2x-10 ​

Answers

-24 ≤ 2x-10

⇒ -24 + 10 < 2x

⇒-14 < 2x

⇒ 2x < 14

x < 7

What is Inequality?An inequality in mathematics is a relation that compares two numbers or other mathematical expressions unequally. The majority of the time, size comparisons between two numbers on the number line are made. Different types of inequalities are represented by a variety of notations, including:The symbol a b indicates that and is smaller than b.When a > b is used, it indicates that and is bigger than b.a is not equivalent to b in any scenario. These relationships are referred to be stringent inequalities since either an or b is strictly bigger or less than the other. Equivalence is not considered.

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Help me with this question -_-

Answers

Answer: u≤29

Hope this helps! :)

You add 10 to each side so the answer is 29 is bigger and equal than to u

Write a general rule for multiplying

help please ​

Answers

All multiplications must also be the same if to add the number over and over again.(if 9* 5 was 45, then 9+9+9+9+9 must also be 45.

Answer: Any number multiplied by zero equals zero. 4x0=0

Decide whether perimeter or area should be considered when buying a frame needed around a door.

Answers

Step-by-step explanation:

yes its important because we need to know the measurements of the side

What is the rule for the pattern 1, 4, 7, 10,...?

A) Add 10
B) Multiply by 4
C) Add 3
D) Subtract 3

Answers

Answer:

C

Step-by-step explanation:

1+3=4

4+3=7

7+3=10

Wheras if you try to multiply by 4 it works on the first one, but 4×4=16 not 7. If you add 10 to 1 you get 11, which is not the next number. And if you subtract 1-3=-2, which is on the wrong side of 0.

C add three 1+3=4
Hope this helps

In one year a factory produced 11,650 gallons of lemonade 4,950 fewer gallons of ice tea than lemonade anf 3,500 fewer gallon of root beer than iced tea. How many gallons were produced in all

Answers

In a single year, factories create a total of 21550 gallons.

In both imperial and US customary units, the gallon is a unit of volume.A gallon is a unit of measurement for liquids that is equal to eight pints. In Britain, it is equal to about 4.546 litres. In America, it is equal to about 3.785 litres.

We have been given that

Lemonade = 11,650 gallons

Ice tea = 4,950 fewer than lemonade

Root beer = 3,500 fewer than Ice tea.

After calculating

Ice tea = 11,650 - 4,950

Ice tea = 6700 gallons

Root beer = 6700 - 3,500

Root beer = 3200 gallons

Total  factory produced in one year

= 11,650 + 6700 + 3200

Hence , 21550 gallons are total factory produced in one year.

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At the Olympic Games, a runner won the 26.2-mile marathon race in 2 hr 5min and 4 second. What was his average speed in mph and
km/h?

Answers

Answer:

The average speed of the runner is 12.7 mph and 20.4 km/h

Step-by-step explanation:

Identify all extrema of this function: f(x) = 2/(3x-5).
Select one:
A. Max:2.52; Min: 1.23
B. Max:0.19; Min: -2.31;
C. No extrema
D. Max: 3; Min: -2

Answers

The correct option C. No extrema, is obtained for the given function.

What is defined as the extrema of the function?The term extremum (plural extrema) refers to a value that is the minimum or maximum among all function values.When a function changes from increasing to decreasing, it reaches its relative maximum as well as relative minimum (relative extrema).The absolute extremum (as well as global extremum) of the a function in a specified interval is the point at which the function's maximum or minimum value is obtained. The interval given is frequently the domain of the function, as well as the absolute extremum is the point that corresponds to the highest or minimum value for the entire function.

For the given question;

The function is defined as ;

f(x) = 2/(3x-5)

First differentiate the function with respect to x using division rule.

f'(x) = -6/(3x - 5)²

Now, find the point of contraflexure for x by putting f'(x) equals to zero.

f'(x) = 0

-6/(3x - 5)² = 0

-6 = 0

But, -6 ≠ 0

As, x is getting eliminates, we don't have any point of contraflexure.

Thus,the will be no extrema for the given function.

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