Mass does not change thus the object would have the same mass in ay planet or the moon.
What is the mass?
We need to look at the mass of the body as the quantity of matter that we can find in the body. This implies that the more of matter that we can find in a particular object, the more the mass of the object. It is also possible to define the mass as the quantity of the inertia in an object. These are the basic ways that the mass of the object could be considered or understood in this case.
We know that the mass of the object does not change. This is because the quantity of the matter that an object has is not going to change no matter where the object is found whether on the earth or in the moon.
Having said this, we can now agree that the mass of the object would stay the same both on earth and in the moon.
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We used a “dot” to represent the Sun’s location in the picture. Is this dot too small, too large or just the right size to represent the size of the Sun on the picture?
The dot used to represent the Sun’s location in the picture is too large to represent the size of the Sun on the picture.
1 cm = 10000 light-years
1 mm = 1000 light-years
Dot = 0.5 to 1 mm
Diameter of the Sun = 1.5 * [tex]10^{-7}[/tex] light-years = 1.5 * [tex]10^{-10}[/tex] mm
On comparing, the Sun should not be visible to a human eye in that picture. Even using an Electron microscope, we cannot spot the Sun according to the given scale.
A light-year is a measurement of distance. It is the distance travelled by light in one year.
Light speed = 300000 km / s = 9.46 * [tex]10^{12}[/tex] km / yr
1 light year = 9.46 * [tex]10^{12}[/tex] km
Diameter of sun = 1.39 * [tex]10^{6}[/tex] km
Therefore, the dot used to represent the Sun’s location in the picture is too large to represent the size of the Sun on the picture.
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calculate the net force acting on the box in the following. refer to the screenshot below.
Here the two force 3N and 3N acting on same direction, so
net force = 3N + 3N
= 6N
Forces that are balanced are those that are opposite in direction and equal in size, but here the equal forces acts in same direction so it is unbalanced
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⚠️Please help me!!!⚠️Vector V is 448 m long in a 224 direction. vector W is 336 m long in a 75.9 direction. Find the direction of their vector sum.
The magnitude of the vector sum of the two vectors V and W is determined as 240.84 m.
Resolution of the vectors in x and y axis
The given vector can be resolved into x and y axis as follows;
Vx = Vcosθ
Vx = 448cos(224)
Vx = -322.26
Vy = Vsinθ
Vy = 448 x sin224
Vy = -311.2
Wx = 336 x cos(75.9)
Wx = 81.86
Wy = 336 x sin75.9
Wy = 325.88
∑X = -322.26 + 81.86 = -240.4
∑Y = -311.2 + 325.88 = 14.68
Resultant vector
R = √[(-240.4)² + (14.68)²]
R = 240.84 m
What is vector?In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.
Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed, time, and mass are scalars, displacement, velocity, and acceleration are vector values.
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2 students push on a box in the same direction and a 3rd student pushes in the opposite direction. What is the net force on the box if each push with a force of 50 N?
The net force on the box after the applied force is 50N.
What is Force?A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces. As a vector quantity, a force has both magnitude and direction. Newton is the unit of measurement.
Additional units include dyne, pound-force, poundal, kip, and kilopond.
Deriving values from other quantities: F = ma (previously P = mf)
Force is an external agent that has the power to alter a body's resting or moving condition. It has a size and a movement. The direction of the force is referred to as the force's direction, and the application of force is the place at which the force is applied.
Original force of box = 0 N
Force applied by 2 student
Adding them because they are pushing it from the same side
50 N + 50 N
= 100N
Subtracting 50 N because the 3rd student is pushing the box from the opposite side
100N - 50N
= 50 N
The net force on the box after the applied force is 50N.
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A plastic rod is rubbed with wool, producing a distribution of positive and negative surplus charge that is concentrated in two locations on the rod and two on the wool. This distribution can be approximated as two pairs of small balls of charge as shown in The distance d is 30.0 mm, and the magnitude of the charge on each ball is 6.00 μC . The initial state of the system is the neutral rod and wool before the rubbing.
If 34.0 J of work went into thermal energy as the rod and wool heated up, how much work was done on the system?
The work that was done on the system is 326 J.
What is the work done in moving the charge?
The work done in moving the charge over the distance is calculated as follows;
W = Fr
W = (kq²)/r
where;
k is Coulomb's constantq is magnitude of the charger is the distance of the chargeW is the work doneF is the electric forceW = (9 x 10⁹) x (6 x 10⁻⁶)² / (30 x 10⁻³)
W = 360 J
The total work done on the system is calculated as follows;
Wt = Wc - We
where;
Wt is the total work doneWc is the work done in moving the chargeWe is the work that went into thermal energyWt = 360 J - 34 J
Wt = 326 J
Thus, we can conclude that the net work done on the system is obtained by subtracting the work done that went into thermal energy from the work done in moving the charge.
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A 44-kg child steps onto a scale and reads 430N.
A 44 kg child steps onto a scale and reads 430 N so the magnitude of the normal force acting on the child will be 430 N.
What is Normal Force?The normal force is a common force that is experienced when an object is placed on a surface and pushed against it. For instance, the normal force prevents a book from falling through a table when it is placed on one. The book is being pulled downward by gravity, but because it isn't truly falling, something must be pushing it upward. The normal force is what we refer to as. Normal refers to something that is perpendicular to the surface.
According to the question,
Normal Force=Weight of the person
= 430 N
So, the Magnitude of the normal force acting on the child will be 430 N.
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Riders on the power tower are launched skyward with an acceleration of 4g, after which they experience a period of free fall. what is a 60 kg rider's apparent weight during the launch?
The rider's apparent weight during the launch is 2940 N.
When the rider is rest, the forces acting on the skyward (y-direction) are mg towards earth and F_N opposite to mg. Total force will be,
F = F_N - mg
The mass of the rider is 60 kg. When riders are launched skyward with an acceleration of 4g, the force
F = ma = m*4g
F_N - mg = m*4g
F_N - 60*9.8 = 60*4*9.8
F_N - 588 = 2352
F_N = 2352 + 588 = 2940 N
The rider's apparent weight during the launch is 2940 N.
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The smooth ER differs from the rough ER in that:
A. The rough ER contains no ribosomes, the smooth ER contains ribosomes.
B. The smooth ER produces carbohydrates and lipids, rough ER produces proteins.
C. The smooth ER produces proteins, rough ER produces lipids.
D. The rough ER is the site of mRNA transcription, smooth ER is the site of protein translation.
What is the frequency of a wave if the velocity is 449.4 m/s and the wavelength is 8.4 meters?
We will have the following:
First, we remember:
[tex]\lambda=\frac{v}{f}[/tex]Then we will have:
[tex]\left(8.4m\right?)=\frac{\left(449.4m/s\right)}{f}\Rightarrow f=\frac{\left(449.4m/s\right)}{\left(8.4m\right)}[/tex][tex]\Rightarrow f=53.5Hz[/tex]So, the frequency of the wave is 53.5 Hz.
A steel cable carries a 3,000 lbs load which is descending with a speed of 12 ft/s. It slows
down uniformly and comes to a halt in 9ft. Compute the tension in the cable during this motion.
The tension in the cable during this motion will be 3750 lbs , when a steel cable carries a 3000 lbs load which is descending with a speed of 12 ft/s.
What is tension and what is speed , and how the tension is calculated out to be 3750 lbs?Tension is specifically the pulling force , when we either pull a rope or an object tension is in action.Here in this question, given 3000 lbs load and speed of 12 ft/s and speed is uniform .The halt is given out to be of 9 ft, for calculating the tension in the cable we will first change units, m = 3000 lbs= 1362 kg , final velocity = v= 12 ft/s = 3.66 m/s, distance= d= 9 ft = 2.745 m.Using the kinematics equation , v^2 = u^2 + 2as , 0^2 - 3.66 ^2 = 2a (2.745), a = -2.44 m/s^2.The tension is calculated by using the equation , mg-T = ma , which equals 3750 lbs.To know more about tension visit:
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explain why water comes out more slowly from a tap on the first floor than from a tap on the ground floor
Answer:
It is because of the pressure exerted by water. As the depth of water increases, the pressure also increases.
Explanation:
The same monochromatic light passes through the interface between two other unknown materials. This time the transmitted wave is observed to be farther from the normal to the interface than the incident wave. What can be said about these two materials and the light traveling through them?
Since the same monochromatic light passes through the interface between two other unknown materials. The option that can be said about these two materials and the light traveling through them is option B and C:
B)The second material through which the light propagates has a lower index of refraction.C)As the light passes into the second material, its speed increases.What is the monochromatic light above about?Regarding the question Snell's law tells us that light at an interface bends toward a more dense or higher index of refraction.
The second material has a lower index of refraction than the first material because the light is bending away from the normal since it is farther from the normal. As a result, for the second question, the second and third boxes are checked.
The refracted ray bends away from the normal to the interface when a light ray enters a material with a lower index of refraction and a higher wave speed, and it will look closer to the interface than the incident ray.
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See full question below
The same monochromatic light passes through the interface between two other unknown materials. This time the transmitted wave is observed to be farther from the normal to the interface than the incident wave. What can be said about these two materials and the light traveling through them?
A)The second material through which the light propagates has a higher index of refraction.
B)The second material through which the light propagates has a lower index of refraction.
C)As the light passes into the second material, its speed increases.
D)As the light passes into the second material, its speed decreases.
How will the electrical force between two charged particles change if thedistance between them is increased by 4 times the amount?
Given that the distance between the two charged particles is increased by 4 times the amout, let's determine how the electrical force between them will change.
The electrical force between two charged particles is determined by the formula:
[tex]F=k\frac{q_1q_2}{r^2}[/tex]Where:
k is the constant
q1 and q2 are the two charged particles
r is the distance between the particles
From the formula, we can see that the electrical force between them is inversely proportional to the the square of the distance between the charged particles.
Thus, in order to increase the electrical force, the distance must be decreased.
If the electrical force is changed by a factor of
As shown in the figure, a square insulating slab 5.0 mm thick measures 2.0 m ×
2.0 m. It has a charge of 8.0 × 10^-11 C distributed uniformly throughout its volume. Use Gauss’s law to determine the electric field at point P, which is located within the slab, 1.0 mm from the top face.
Assume P is far from the (front, back, left, and right) sides of the slab. (ε0 = 8.85 × 10^-12 C2/N ∙ m2)
The electric field at point P is mathematically given as
E=-6.69n-m^2/c
This is further explained below.
What is the electric field?Generally, the equation for magnetic Flux is mathematically given as
[tex]Flux $=\mathrm{E}.2 \mathrm{~A}\\=\mathrm{Q}_{\text { enc }} / \varepsilon_0$[/tex]
[tex]=\mathrm{E} 2 \mathrm{~A}\\\\=\mathrm{p} * \mathrm{Vol} / \varepsilon_0$[/tex]
[tex]=E 2\left(d x^* d y\right)\\\\=p^*\left(d x^* d y^* 2^* d z\right) / \varepsilon O$[/tex]
E=p^* d z /
Taking into account the fact that Let the permittivity of the slab is approximate:
[tex]$\varepsilon O=8.85^* 10^{\wedge}-12 \mathrm{~F} / \mathrm{m}$[/tex]
Distance from the origin to the point in question:
dz=0.0015m
Charge distribution over the slab is uniform:
[tex]&\mathrm{p}=\mathrm{Q} / \mathrm{vol}=\left(-7.9 * 10^{\wedge}-11\right) \mathrm{C} /\left(0.005^* 2 * 2\right) \mathrm{m}^{\wedge} 3 \\[/tex]
p=-3.95^* 10^-9
[tex]\mathrm{E}=\mathrm{p}^* \mathrm{dz} / \varepsilon 0\\\\=\left(3.95^* 10^{\wedge}-9 * .0015\right) / 8.85^* 10^{\wedge}^{-11} \\[/tex]
E=-6.69n-m^2/c
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An intergalactic spaceship arrives at a distant planet that rotates on its axis with a period of [tex]T=26 hours[/tex]. The mass of the planet is [tex]M=4.9*10^{25} kg[/tex]. The spaceship enters a circular orbit with an orbital period that is equal to the planet's period for the rotation about its axis, T.
A) Enter an expression for the radius of the spaceship's orbit.
(I tried [tex]R=(T^{2} GM/4pi^{2} )^{1/3}[/tex] but its says incorrect and that's all I've been able to find)
B) Calculate the orbital radius in meters.
The orbital period could be obtained from the question as 8.98 * 10^7 m.
What is the orbital period?We know that the solar system is composed of the sun and the planets. The planets are known to move around the sun in concentric circles. Following the heliocentric model of the solar system, the sun is at the center of the solar system at all times and all the other planets tend to move round the sun at a good distance that is appropriate for each.
Now we have that;
T = √4π^2r^3/GM
T = period of the orbit
r = radius of the orbit
G = gravitational constant
M = mass of the planet
Hence, we have;
R = ∛T^2GM/4π^2
R =∛ (26 * 60 * 60)^2 * 6.67 * 10^-11 * 4.9 * 10^25/ 4 * (3.142)^2
R = ∛2.86 * 10^25/39.49
R = 8.98 * 10^7 m
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The ship motion compared with which reference point?
Since the cruise ship makes its way from one island to another. The ship is in motion is compared with the reference point of option C. a lighthouse on a nearby island.
What is the motion of the cruise ship about?Sine the cruise ship from one Island is relocating, the lengthy duration by the passengers within the ship makes it simple to detect the ship motion.
The skipper is the only one who is aware of the ship's direction and speed. Even though the cargo loads are stable and related to the ship's course, we cannot take them into account when calculating the traveling distance of the ship.
Since it is in the sea and relatively close to it, the lighthouse on the island can be used to calculate the distance traveled by ships. Due to its stability, we can use it as a reference point in the water that can be seen from a great distance.
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A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?
A.
the passengers on the ship
B.
the captain of the ship
C.
a lighthouse on a nearby island
D.
the cargo inside the hull of the ship
help!!!!!!
Why are the accelerations due to gravitational force on the moon and the Earth different? Do you think you could shield a gravitational field in a vacuum?
The accelerations due to gravitational force on the moon and the Earth different due to difference in mass of its body and its radius. No, gravitational field cannot be shielded in a vacuum.
Acceleration due to gravity = Local gravitational field strength = g
g = G M / r²
G = Gravitational constant
M = Mass of the body
r = Radius of the body
G = 6.67 * [tex]10^{-11}[/tex] N m²
From the equation,
g ∝ M
g ∝ 1 / r²
Since the Earth is much bigger and heavier than moon, the acceleration due to gravity is much lesser in moon in comparison with Earth.
Therefore, the accelerations due to gravitational force on the moon and the Earth different due to difference in mass of its body and its radius. No, gravitational field cannot be shielded in a vacuum.
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6. What horizontal force is required to slide a 150 N crate with uniform motion across a
floor where the coefficient of kinetic friction is 0.20?
Horizontal force required to slide a 150 N crate with uniform motion across a floor where the coefficient of kinetic friction is 0.20 is calculated to be 30 N .
A force that is applied in parallel to the horizon is known as horizontal force. The force exerted on a body has two components, that is the horizontal component and a vertical component.
Two types of horizontal force are :
Static friction which is the maximum horizontal force that can be applied before an object starts to move. Kinetic friction which the horizontal force that acts in the opposite direction of the motion of an object.Given , force = 150 N
Coefficient of kinetic friction, μ = 0.20
Horizontal force, F = μmg
=0.20* 150
Horizontal force = 30 N
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module 2 question 15
What net external force is exerted on a 1000-kg artillery shell fired from a battleship if the shell is accelerated at 2.80 ✕ 104 m/s2? (Enter the magnitude.)
N
What is the magnitude of the force exerted on the ship by the artillery shell?
N
The net external force exerted on a 1000-kg artillery shell accelerated at 2.80 ✕ [tex]10^{4}[/tex] m / s² fired from a battleship is 2.8 * [tex]10^{7}[/tex] N. The magnitude of the force exerted on the ship by the artillery shell is - 2.8 * [tex]10^{7}[/tex] N.
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
a = Acceleration
m = 1000 kg
a = 2.80 ✕ [tex]10^{4}[/tex] m / s²
F = 1000 * 2.80 ✕ [tex]10^{4}[/tex]
F = 2.8 * [tex]10^{7}[/tex] N
This is the net external force exerted by the shell on the battleship.
According to Newton's third law of motion,
[tex]F_{BS}[/tex] = - [tex]F_{SB}[/tex]
[tex]F_{BS}[/tex] = Force exerted by the battleship on the shell
[tex]F_{SB}[/tex] = Force exerted by the shell on the battleship
[tex]F_{BS}[/tex] = 2.8 * [tex]10^{7}[/tex] N
[tex]F_{SB}[/tex] = - [tex]F_{BS}[/tex]
[tex]F_{SB}[/tex] = - 2.8 * [tex]10^{7}[/tex] N
Therefore,
The net external force exerted on the artillery shell = 2.8 * [tex]10^{7}[/tex] NThe magnitude of the force exerted on the ship by the artillery shell = - 2.8 * [tex]10^{7}[/tex] NTo know more about Newton's second law of motion
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If you dropped a ball on the surface of Katar, what rate would it accelerate toward the ground
Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or point travelling straight forward. Due to the constant change in direction, motion on a circle accelerates even while the speed is constant.
The rate at which an object's velocity changes in relation to time is known as acceleration. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
The formula a = v/t denotes acceleration (a), which is the product of the change in velocity (v) and the change in time (t). Using metres per second squared (m/s²), you can gauge how quickly velocity varies.
Acceleration due to gravity on earth = 9.8 m/s²
Therefore, the rate at which the ball will fall on the Katar is 9.8m/s²
Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity since it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.
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A young researcher wants to test how well extremophiles, organisms that thrive in extreme conditions, live in different environments. She will do this by putting extremophiles of different species into different solvents
Because of limited lab space, she can run only one sample at a time, and each sample must remain undisturbed for 7 days. To reduce the total time needed to process all samples, the researcher decides to use two acidic
solutions along with a control. The information below includes the extremophiles and the solvents the researcher will use in her tests.
Solvents
Species of
Extremophiles
T. prosperus
A. aceti
Based on the tables, how many days will all of the researcher's experiments take?
You may use the calculator.
OA. 7
OB. 21
OC. 49
OD. 84
A brierleyi
H. acidophilum
Name
hydrochloric acid
ascorbic acid
water
PH
1.3
4.2
7.0
It will take exactly 84 days with all the researcher's experiments , even after reducing the total time needed to process all samples.
What is an extremophile and how to take the samples and notice their living condition?As is explained in the question as well an extremophile is the kind of organism can better thrive or live in harsh or extreme conditions.Some examples of extremophilic species are polar bears living in extreme cold regions .Here in this question the researcher has taken two samples for reducing the time of results, in which one extremophile takes 7 days to grow.Taking two samples would count to 14 days for one extremophile , and the researcher in the question took 4 samples and three solvents.In the way total of 84 days would be required by the researchers to obtain the result of the change in the living environment of extremophilic species.To know more about extremophile visit:
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how are the layers of Earth connected and affected by each other?
Answer:
Each layer has a unique chemical composition, physical state, and can impact life on Earth's surface. Movement in the mantle caused by variations in heat from the core, cause the plates to shift, which can cause earthquakes and volcanic eruptions.
A piston releases 18 J of heat into its surroundings while expanding from0.0002 m2 to 0.0006 m at a constant pressure of 1.0 * 105 Pa. What are thecorrect values for heat and work for the piston?A. Q = -18 J, W = +40 JB. Q = +18 J, W = +40 JC. Q = +18 J, W = -40 JD. Q = -18 J, W = -40 J
It's important to know that when a system releases heat to the surroundings, the net value of heat is negative by convention, it's exothermic.
On the other hand, when a system does work then the work done is negative, that is, the system is exerting work.
Therefore, the correct answer is D.pls help, it's due tomorrow!
An electron travels 2.68 m in 6.11 × 10−8 s. How fast does it travel in cm/s? Answer in units of cm/s.
The speed (in cm/s) of the electron, given that it travels 2.68 m in 6.11×10⁻⁸ s is 4.39×10⁵ cm/s
How to determine the speedWe'll begin by defining speed. This is given below.
Speed is defined as the distance travelled per unit.
Speed = distance / time
With the above formula, we can obtain the speed of the electron. Details below
The following data were obtained from the question give above:
Distance = 2.68 m = 2.68 / 100 = 0.0268 cmTime = 6.11×10⁻⁸ sSpeed =?Speed = distance / time
Speed = 0.0268 cm / 6.11×10⁻⁸ s
Speed = 4.39×10⁵ cm/s
Therefore, the speed is 4.39×10⁵ cm/s
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What is the period of a wave traveling at a rate of .100 Hz?
The period of a wave traveling at a rate of 0.100 Hz is 10 seconds.
How to calculate period?Period in physics is the time required for one complete cycle of vibration to pass a given point. The period is denoted by T and is measured by seconds (s).
The period of a wave and the frequency are inversely related to one another i.e. as the frequency of a wave increases, the period of the wave decreases.
The time it takes for one complete vibration is called the period (T). For example, if the period of a vibration is 0.1 second (it means one vibration takes 0.1 second), the frequency of the vibration is 10 vibrations per second or 10 hertz
The relationship between them can be given in an equation as follows:
T = 1/f
According to this question, a wave is traveling at a rate of 0.100 Hz. The period can be calculated as follows:
T = 1/0.100
T = 10s
Therefore, the period of a wave traveling at a rate of 0.100 Hz is 10 seconds.
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A proton is at the origin and an electron is at the point x = 0.36 nm , y = 0.40 nm
Find the electric force on the proton.
The electric force on the proton is 7.9 x 10⁻²² N.
What is electric force?
Electric force is defined as the force between two charged objects. According Coulombs law, this force is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.
F = kq₁q₂/r²
where;
q₁ is charge of protonq₂ is charge of electronr is the distance between the chargesK is Coulomb's constantThe distance between the two charges is calculated as follows;
r = √(y² + x²)
r = √(0.36² + 0.4²)
r = 0.54 mm
F = (9 x 10⁹ x 1.6 x 10⁻¹⁹ x 1.6 x 10⁻¹⁹) / (0.54 x 10⁻³)²
F = 7.9 x 10⁻²² N
Thus we can conclude that a proton is at the origin and an electron is at the point x = 0.36 nm , y = 0.40 nm will experience a force of 7.9 x 10⁻²² N.
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A uniform plank of weight 200N and length 6m is supported by a rope if breaking tension in the rope is 400N How far can a boy of weight 400N walk towards the support
The distance the boy can walk to the support = Lm
Board force = Fb = 200 N
Rope breaking stress = Fr = 400 N
Distance to rope = Lr = 6 m
Boy = Fm = 400N
Distance to the center of gravity of the board = Lb = 3m
According to the balance rule:
All moments and forces on the board are 0,
= (Fr)(Lr) - (Fm)(Lm) - (Fb)(Lb) = 0
= (400)(6) - (400×Lm) - (200)(3) = 0
= 2400 - 600 = 400 × Lm
= 400× Lm = 1800
= Lm = 1800
400
= Lm = 4.5m.
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The maximum stress that a material can withstand before it breaks is called breaking stress or breaking stress. Also. Breaking stress is the maximum force that can be applied to a cross-sectional area of material so that it cannot withstand additional stress before it fails.
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An object travels 5m/s in 2 seconds. How far did it travel?
Answer:
3
Explanation:
because half I think is the answer
Answer:
10 m
Explanation:
5 m/s * 2 s = 10 meters ( see how the ' s ' cancels out?)
A woman is sitting at a bus stop when an ambulance with a siren wailing at 440 Hz approaches at 31.5 m/s (about 70 mph). Assume the speed of sound to be 343 m/s.
(a)
What frequency (in Hz) does the woman hear?
As the source moves toward the stationary observer, the frequency the woman will hear the sound from the siren will be 484.5 Hz
What is Doppler Effect ?Doppler effect is the frequency change due to the relative motion between a sound or light and an observer.
Given that a woman is sitting at a bus stop when an ambulance with a siren wailing at 440 Hz approaches at 31.5 m/s. If the speed of sound is to be 343 m/s, the frequency the woman hear the sound can be calculated by using the formula
Fo = FsC/(C - V)
Where
Fo = Frequency of the observerFs = frequency of the siren = 440 HzV = speed of the car = 31.5 m/sC = speed of the sound = 343 m/sSubstitute all the parameters into the formula
Fo = (440 × 343) / (343 - 31.5)
Fo = 150920 / 311.5
Fo = 484.5 Hz
Therefore, the woman will hear the sound from the siren at the frequency of 484.5 Hz
Learn more about Doppler Effect here: https://brainly.com/question/1330077
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What forces are at work on your body when skydiving
PLEASE HURRY DUE TODAY
Answer:
The physics behind skydiving involves the interaction between gravity and air resistance. When a skydiver jumps out of a plane he starts accelerating downwards, until he reaches terminal speed. This is the speed at which the drag from air resistance exactly balances the force of gravity pulling him down.