The velocity of the ship heading due north at 9.00 m/s relative to the water has a velocity of 10 m / s relative to the earth.
Let S represent ship, W represent water and E represent Earth.
[tex]V_{SW}[/tex] = 9 m / s N
[tex]V_{WE}[/tex] = 1.52 m / s NE
Resolving [tex]V_{OE}[/tex] into its x and y components.
cos θ = Adjacent side / Hypotenuse
cos 40° = [tex]V_{OE}_{x}[/tex] / [tex]V_{OE}[/tex]
[tex]V_{WE}_{x}[/tex] = 0.77 * 1.52
[tex]V_{WE}_{x}[/tex] = 1.17 m / s
sin θ = Opposite side / Hypotenuse
sin 40° = [tex]V_{OE}_{y}[/tex] / [tex]V_{OE}[/tex]
[tex]V_{WE}_{y}[/tex] = 0.64 * 1.52
[tex]V_{WE}_{y}[/tex] = 0.97 m / s
[tex]V_{SE}[/tex] = [tex]V_{SW}[/tex] + [tex]V_{WE}[/tex]
[tex]V_{X}[/tex] = [tex]V_{SW}_{x}[/tex] + [tex]V_{WE}_{x}[/tex]
[tex]V_{X}[/tex] = 0 + 1.17
[tex]V_{X}[/tex] = 1.17 m / s
[tex]V_{Y}[/tex] = [tex]V_{SW}_{y}[/tex] + [tex]V_{WE}_{y}[/tex]
[tex]V_{Y}[/tex] = 9 + 0.97
[tex]V_{Y}[/tex] = 9.97 m / s
R = √ [tex]V_{X}[/tex]² + [tex]V_{Y}[/tex]²
R = √ 1.17² + 9.97²
R = √ 1.37 + 99.4
R = √ 100.77
R = 10 m / s
Therefore, the velocity of the ship relative to the earth is 10 m / s
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Which change to this process would shift the equilibrium to produce the
maximum possible amount of SO3?
2SO2 +022SO3 + energy
A. Removing the O₂ as it forms
B. Removing the SO3 as it forms
C. Increasing the temperature
D. Decreasing the pressure
B
The change to this process would shift the equilibrium to produce the maximum possible amount of SO3 is Decreasing the pressure. Option D.
Increasing the temperature shifts the equilibrium to the right with higher vapor concentrations, but keeping the system at this elevated temperature restores equilibrium. You can predict how given stress or change in conditions will affect equilibrium.
Sulfur trioxide formation is very slow at low temperatures. Increasing the temperature increases the speed at which equilibrium is reached. Decreasing the concentration of the reactants shifts the equilibrium to the left and produces less product. As the product concentration decreases the equilibrium shifts to the right producing more products.
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Answer: B
Explanation:
a roller coaster car rapidly picks up speed as it rolls down a slope. as it starts doown the slope. its speed is 4 m/s. but 3 secondes later ,at the bottom of the slope. its speed is 22 m/s what is the avrege acceleration?
The average acceleration is 6 [tex]m/s^{2}[/tex]
Given
Initial Velocity of the roller coaster (U) = 4 m/s
Final velocity of the roller coaster (V) = 22 m/s
Time taken (t) = 3 seconds
According to the second law of motion,
Acceleration is the rate of change of velocity per unit change in time taken.
Therefore,
a = [tex]\frac{v-u}{t}[/tex]
a = [tex]\frac{22-4}{3}[/tex]
a = 6 [tex]m/s^{2}[/tex]
Hence the acceleration after 3 seconds is 6 [tex]m/s^{2}[/tex]
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The diagram above represents the forces exerted on a box that a child is holding. FN represents the force applied by the child’s hand, and Fg represents the weight of the box. The child begins to raise the box with increasing speed. Which of the following claims is correct about force Fh that is exerted by the box on the child’s hand as the box is being raised?
Answer:
Fh=FN, where FN is larger as the box is being raised than when it was being held is correct.
Explanation:
A kangaroo jumps up with an initial velocity of 36 feet persecond from the ground (assume its starting height is 0 feet).Use the vertical motion model, h-16t2 + ut + s, where vis the initial velocity in feet per second and s is the height infeet, to calculate the amount of time the kangaroo is in the airbefore it hits the ground again. Round your answer to thenearest tenth if necessary.Time in air:seconds
Given
Initial velocity:
36 ft/s
Initial height:
0 ft
Vertical motion model:
h(t) = -16t^2 + ut + s
v = initial velocity
s = is the height
Procedure
We are going to use the model provided for the vertical motion.
[tex]\begin{gathered} h(t)=-16t^2+36t+0 \\ h(t)=-16t^2+36t \end{gathered}[/tex]We know that at the maximum height the final velocity is 0.
Then we will use the following expression to calculate the maximum height:
[tex]\begin{gathered} v^2_f=v^2_o-2ah_{\max } \\ 0=v^2_o-2ah_{\max } \\ 2ah_{\max }=v^2_o \\ h_{\max }=\frac{v^2_o}{2a} \\ h_{\max }=\frac{(36ft/s)^2}{2\cdot32ft/s^2} \\ h_{\max }=20.25\text{ ft} \end{gathered}[/tex]Now for time:
[tex]\begin{gathered} 20.25=-16t^2+36t \\ 16t^2-36t+20.25=0 \end{gathered}[/tex]Solving for t,
[tex]\begin{gathered} t_1=2.25 \\ t_2=0 \end{gathered}[/tex]The total time the kangaroo takes in the air is 2.3s.
As Rain passes a classroom, they hear the instructor say, "An early school of thought in psychological science that was influenced by Charles Darwin's work was that of . . . ." Which school of thought was the instructor MOST likely describing?
Please choose the correct answer from the following choices, and then select the submit answer button.
Answer choices
A: functionalism
B: structuralist
C: humanist
D: psychoanalytic
The school of thought in which the instructor is most likely describing is functionalism and is denoted as option A.
What is Functionalism?This is referred to as a theory which is based on the doctrine of all aspects of a society and touches the mental states.
This type of theory also believes that institutions perform positive functions and so on. Darwin was a scientist who was involved in putting in positive efforts in the science field due to the skills which were developed and was solved many problems which is therefore the reason why Functionalism was chosen as the correct choice.
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A box weighing 150 N is being pushed with constant velocity across a horizontal surface. If the force of friction between the box and the surface is 135 N, what is the coefficient of friction? Explain all of your work!!
brainliest answer for the best reply.
Answer:
uK=.9
Explanation:
friction=Fn(uK)
friction=135
Fn=150
135/150=.9
As a sample of water is heated, the energy is used to overcome the attractions between the molecules so that they begin to move past one another. Then, the kinetic energy of its molecules increases. Which sections of the heating curve illustrate this process? A.A followed by CB.C followed by BC.B followed by CD.A followed by B
Given that as the sample of water is heated, the kinetic energy of its molecules increases.
Let's determine the sections of the heating curve which illustrates this process.
At point A, we can see the temperature of the water at 0 degrees, then as the temperature increases, the water molecules absorb more energy.
But as the phase changes, the temperature remains constant.
Since section A shows constant temerature, while section B also indicates constant temperature, we can sat section A followed by section B shows this process.
The sections which show as the energy overcome the attractions between molecules so that they begin to mover past one another can be said to be Section A followed by Section B
ANSWER:
D. A followed by B.
What is the total amount of heat needed to change 31g of silver at 0.0°C to 1°C? The specific heat of silver is 0.129 J/g∙°C
Explanation
o solve this , we need to use the formula:
[tex]\begin{gathered} Q=m*c*(T_f-T_0) \\ where \\ m\text{ is the mass measured in kg} \\ c\text{ is the specific heat of silver=0.129 J/\degree C} \\ T_f\text{ and T}_o\text{ are the final and initial temperatures} \end{gathered}[/tex]so
Step 1
) Let
[tex]mass=31\text{ gr}[/tex]so, we need to convert from grams to kilograms ,to do that, divide the amount in grams by 1000
so
[tex]mass_{kg}=\frac{31}{1000}=0.031\text{ kg}[/tex]and
[tex]\begin{gathered} T_f=\text{1\degree C} \\ T_0=0°\text{ C} \end{gathered}[/tex]b) now, replace in the formula
[tex]\begin{gathered} Q=mc(T_{f}-T_{0}) \\ Q=0.031gr*0.129\frac{J}{g°C}(1°C-0°C) \\ Q=0.003999\text{ Joules} \end{gathered}[/tex]so, the answer is 0.003999 Joules
hope this helps you
A runner can maintain a constant acceleration of 1.1 m/s^2 for 8.5 seconds. What distance could the runner cover in that time if starting from rest.
The distance which this runner can cover in that time (8.5 seconds) if it starts from rest is equal to 39.7375 meters.
How to determine the distance?In order to determine the distance which this runner can cover in that time if it starts from rest, we would apply the second equation of motion. Mathematically, the second equation of motion is given by:
S = ut + ½at²
Where:
S represents the distance covered.t represents the time.u represents the initial velocity.a represents the acceleration.Note: Initial velocity is equal to zero (0) since the runner starts from rest.
Substituting the given parameters into the formula, we have;
Distance, S = 0(8.5) + ½ × (1.1 × 8.5²)
Distance, S = ½ × (1.1 × 72.25)
Distance, S = 79.475/2
Distance, S = 39.7375 meters.
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A puck of mass m = 0.095 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless string of length L = 0.69 m. The puck makes one revolution every t = 0.45 s.
Part (b) The string breaks suddenly. How fast, in meters per second, does the puck move away?
The speed in meters per second if the string breaks suddenly is 9.6 m/s.
What is the angular speed?The angular speed is the speed of an object that is moving along a circular path. In this case, we have a puck of mass m = 0.095 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless string of length L = 0.69 m. The puck makes one revolution every t = 0.45 s.
Let us recall that in order to find the angular speed as is required by the question "how fast in meters per second, does the puck move away?" we have to get the angle turned as well as the time taken.
We are told here that the angle turned is one revolution or 2π radians and the time from the question is 0.45 s. Thus the speed is gotten from;
ω = θ/t
ω = 2π radians/0.45 s
ω = 13.96 rad/s
But v = rω
v = 13.96 rad/s * 0.69 m
v = 9.6 m/s
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Calculate how much energy is transferred as useful energy in the following:
A plant that transforms 0.5% of the 200 J of light energy transferred from the Sun.
The formula that connects energy transferred, power, and time, as well as the formula that helps you calculate energy transferred, are as follows: Power multiplied by time equals transferred energy. For example, the energy-saving lamp's efficiency is 75 100 = 0.75. (or 75 per cent). This means that 75% of the electrical energy supplied is converted into light energy (25 per cent is transferred as heat energy).
What exactly is light energy?Light energy is a type of electromagnetic radiation that the human eye can perceive. Photons are the particles that make up light, and they are like tiny packets of energy. The Sun is the closest star to Earth and emits light energy.Light is defined as electromagnetic radiation visible to the human eye with wavelengths ranging from 380 to 750 nm.One type of radiant energy is light. Sunshine is radiant energy that provides the fuel and warmth that allow life to exist on Earth. Thermal energy, also known as heat, is the energy released by the movement of atoms and molecules in a substance. Heat builds up as these particles move faster.Light energy travels in the form of rays, which are emitted from the light source. Most light energy waves are invisible to the human eye and have different wave frequencies than visible light. Photons are the particles that carry light waves.To learn more about light energy refer to:
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a skateboarder starts moving 8 m/s and accelerate at 6 m/s2 to reach a speed 10 m/s at the bottom of rail how long is the rail
The length of the rail is 3 m.
What is the length of the rail?
The length of the rail is determined by calculating the distance travelled by the skateboarder.
v² = u² + 2as
where;
v is the final velocity of the skateboarderu is the initial velocity of the skateboardera is the acceleration of the skateboarders is the distance travelled10² = 8² + 2(6)s
100 = 64 + 12s
36 = 12s
s = 36/12
s = 3 m
Thus, the length of the rail is equal to the distance travelled by the skateboarder.
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11. What is the final velocity of a boat that accelerates at 3 m/s² for twelve seconds if it started with a
velocity of 4 m/s?
20 m/s is the final velocity of a boat that accelerates at 3 m/s² for twelve seconds if it started with a velocity of 4 m/s.
What is velocity and example?The speed at which that moves in a direction is known as its velocity. as the velocity of a car driving north on a road or even the pace at which a rocket takes off. Because the velocity vector was scalar, its integrand magnitude will always equal the motion's velocity.
Briefing:Using the first equation of motion
V = U + at
where V = Final Velocity
U = Initial Velocity
a = Acceleration
t = Time
V = 4 + 3*12
V = 40 m/s.
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a girl pushes a light snow shovel at a uniform velocity across a sidewalk. if the handle of the shovel in inclined 55 degress to the horizontal and she pushes the handle with a force of 100 N. what is the force of friction? what is the coefficeint of friction.
Answer:
0.565
Explanation:
mary cassatt has manipulated light and color in in the loge to emphasize the
Mary Cassatt has manipulated light and color in in the loge to emphasize the Division between male and female species.
The soft, blinking lighting fixtures of fireflies aren't just lovely—they'll additionally play a function in growing new species. A brand new observe suggests that the use of mild-up powers for courtship makes species break up off from every other at a faster tempo, presenting some of the clearest proof yet that the conflict to find mates shapes the range of life.
Males are extra colourful or ornamented than women in most, however no longer all, chook species. know-how this phenomenon calls for a primary draw close of the evolutionary forces that shape the conduct and morphology of people and species. Charles Darwin evolved plenty of the idea that allows explain this.
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You need to move a 20 kg box along a horizontal floor at an acceleration of 1.4m/s? by pulling
on a rope attached to the box. How much force do you need if you
a) Apply the force horizontally?
b) Apply the force at 30° above the horizontal?
c)
Apply the force at 30° below the horizontal?
The magnitude of the force in each case is;
a) 28 N
b) 14 N
c) -14 N
What is force ?In physics, we know that force is a vector quantity. The force is a push or a pull and it must have direction thus we would see that the magnitude of the force would tend to differ in any direction that we would have to consider in the problem above. Hence, we shall now try to see the work that is done in each of the cases that involves the box as have been shown in the question that we can see above.
a) If the force have been applied horizontally, then the work that is done is the product of the mass, the acceleration of the body
F = ma = 20 Kg * 1.4m/s^2 = 28 N
b) If the force is 30° above the horizontal then it has a vertical direction we have;
F = ma sin 30°
F = 20 Kg * 1.4m/s^2 * sin 30° = 14 N
C) Now we have the negative vertical direction thus;
F = 20 Kg * 1.4m/s^2 * (-sin 30° ) = -14 N
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The displacement
of a particle from a
reference point at any instant is given
by s = 31² 4t + 5, where s is in
metres and t is time in seconds.
Calculate the average velocity of the
particle in the time interval between 3
s and 5 s, and its instantaneous
velocity at 4 s.
The average velocity of the particle in the time interval between 3 s and 5 s is 28 m / s. The instantaneous velocity at 4 s is 28 m / s.
Average velocity = ( s2 - s1 ) / ( t2 - t1 )
s = 3t² + 4t + 5
At t = 3s,
s1 = 3 ( 3 )² + 4 ( 3 ) + 5
s1 = 27 + 12 + 5
s1 = 44 m
At t = 5 s,
s2 = 3 ( 5 )² + 4 ( 5 ) + 5
s2 = 75 + 20 + 5
s2 = 100 m
Average velocity = ( 100 - 44 ) / ( 5 - 3 )
Average velocity = 28 m / s
At t = 4 s, the instantaneous velocity,
v ( t ) = ds / dt
v ( t ) = d ( 3t² + 4t + 5 ) / dt
v ( t ) = 6t + 4
v ( 4 ) = 6 ( 4 ) + 4
v ( 4 ) = 28 m / s
Therefore,
The average velocity of the particle = 28 m / s. The instantaneous velocity = 28 m / s.To know more about Instantaneous velocity
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A dog walks 14 meters to the east and then 20 meters back
to the west.
For this motion, what is the distance moved?
Dis ance (m) =
What is the magnitude and direction of the
displacement?
Magnitude (m) =
Dir'n =
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The distance is 34m , magnitude of the displacement is 6m and direction of displacement is towards west.
As per question, a dog walks 14 meters to the east and then 20 meters back to the west.
The distance moved for this motion is given below,
Distance = 14 + 20 m = 34m
The magnitude of the displacement and its direction are given below:
Displacement = 14 - 20 m = - 6m
negative sign indicates that the direction of displacement is towards west.
Magnitude of the displacement = 6m
Thus, the distance is 34m ,direction of displacement is towards west and magnitude of the displacement is 6m.
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Try to represent this phenomenon as a chain of causes and effects in a labeled diagram in
the space below:
1. Pressure sensors in your shoulder are deformed for an extended amount of time.
2. These send signals to neurons that are attached under the skin.
3. These neurons relay signals through axons to other neurons until the signal reaches
your brain.
4. You decide you should rollover.
5. Your brain sends a signal to motor neurons that relay it to other motor neurons
through axons until the signal reaches your leg muscles.
6.
The cells that make up the muscle tissue in your leg muscles contract in response to
the signal they receive.
7. This leads to your legs moving, which is what pushes your body around so that you
roll over.
system
sed dots
This phenomenon is reflex action.
Reflex action is a surprising and involuntary response to stimuli. It helps organisms to quick adapt to an damaging condition that could have the potential to cause physical damage or maybe loss of life. Pulling our palms away right now after touching a hot or cold object is a traditional example of a reflex movement.
There are two reflexes, true reflexes, and bad reflexes. Proper reflexes assist with exercising, sports, and ordinary bodily activities such as driving, crossing the street, and working, however terrible reflexes can lead to damage and harm.
In a reflex action, the brain performs no element. The spinal cord, which reacts with out thinking about how to reply to stimuli, is in rate of those automated moves. It elicits no meaningful response inside the mind.
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An object has a velocity (4.04 m/s)i + (-4.96 m/s)j + (4.44 m/s)k. In a time of 3.84 s its velocity becomes (-3.75 m/s)i + (0.00 m/s)j + (4.44 m/s)k. If the mass of the object is 2.97 kg, what is the magnitude of the net force on the object, in N, during the 3.84 s? Assume the acceleration is constant.
The magnitude of the net force on the object is 7.15 N.
What is the resultant velocity of the object?The resultant velocity of the object is calculated as follows;
|v| = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)² ]
where;
x₂ is final velocity in x directionx₁ is initial velocity in x directiony₂ is final velocity in y directiony₁ is initial velocity in y directionz₂ is final velocity in z directionz₁ is initial velocity in z direction|v| = √[(-3.75 - 4.04)² + (0 - -4.96)² + (4.44 - 4.44)² ]
|v| = 9.24 m/s
The net force experienced by the object is calculated as follows;
F = ma
F = (mv)/t
F = (2.97 kg x 9.24 m/s) / (3.84 s)
F = 7.15 N
Thus, we can conclude that the object will experience a net force of 7.15 N.
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[tex]what \:is\: \: coefficient \: of \: kinetic \: friction \: equal \: to \: ?[/tex]
The coefficient of kinetic friction is equal to μ = F/N.
What is kinetic friction coefficient?The coefficient of kinetic friction (fr), which is a numerical value, is obtained by dividing the resistive force of friction (Fr) by the normal or perpendicular force (N) pushing the objects together.
What makes the difference between the kinetic and static coefficients of friction?Static friction prevents the box from moving on its own; this friction must be overcome by an opposing force powerful enough to cause the box to move. Kinetic friction, sometimes referred to as dynamic friction, is a force that resists the relative movement of surfaces when they are in motion.
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A 200 lb crate hangs at the end of a rope. Find its acceleration when the tension in the rope is 250lbs
Answer:
5. A 200 lbs crate hangs at the end of a rope. Find its acceleration when the tension in the rope is 250 lbs. (a, = 8 ft/s2) 6. An 1800 lbs car is drawn vertically up a mine shaft, accelerating at a rate of 20 ft/s?. Determine the tension in the cable that will produce this acceleration. (F= = 2925 lbs) 7. A steel cable carries a 3,000 lbs load which is descending with a speed of 12 ft/s. It slows down uniformly and comes to a halt in 9ft. Compute the tension in the cable during this motion. (F, = 3,750 lbs)
Explanation:
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You return the person tennis serve and hit a smashing winner into the corner of the backcourt. Your racket hits the tennis ball with a force of 50N
and a duration of 0.2 s. The mass of the ball is 0.5 kg. What was the velocity of the ball?
F = ma
Therefore:
F = m(v/t)
- The force is 50 N
- The mass is 0.5 kg
- Time is 0.2 seconds
50 = 0.5(v/0.2)
Solve for v and you get the velocity of the ball after it leaves the racket.
Velocity = 20 m/s
3 pts. A 500-g particle moving along the x-axis experiences the force shown in the figure. The particle’s velocity is 2.0 m/s at x = 0 m. For each part, give your answer in m/s to 2 significant figures.
(a) The velocity of the particle at position x = 1 m is 3.74 m/s.
(b) The velocity of the particle at position x = 2 m is 6.63 m/s.
(c) The velocity of the particle at position x = 3 m is 9.7 m/s.
What is force constant?The force constant or spring constant of a spring is the measure of stiffness of a spring.
The force constant of the spring is the slope of the graph and it is calculated as follows;
k = F/x
k = ΔF/Δx
where;
ΔF is change in forceΔx is change in extension of the springk = (15 N - 10 N) / (3m - 2m)
k = 5 N/m
The speed of the particle at each position is determined by applying the principle of conservation of energy as follows;
ΔK.E = ΔU
where;
ΔK.E is change in kinetic energy of the particleΔU is change in potential energy of the particle¹/₂m(v² - u²) = ¹/₂k(x₂² - x₁²)
m(v² - u²) = k(x₂² - x₁²)
v² - u² = k(x₂² - x₁²) / m
v² = k(x₂² - x₁²)/m + u²
v = √[ k(x₂² - x₁²)/m + u²]
where;
v is the final velocity of the particleu is the initial velocity of the particle = 2 m/sk is spring constantm is mass of the particle = 500 g =0.5 kgx₁ is the initial position of the particle = 0 mFor x = 1 m
v = √[5 (1² - 0²)/0.5 + 2²]
v = 3.74 m/s
For x = 2 m
v = √[5 (2² - 0²)/0.5 + 2²]
v = 6.63 m/s
For x = 3 m
v = √[5 (3² - 0²)/0.5 + 2²]
v = 9.7 m/s
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In the first movement of Beethoven's piano sonata No. 12, the theme is heard first followed by 2 different variations of it.
A. True
B. False, the theme is heard first followed by three different variations of it.
C. False, the theme is heard first followed by four different variations of it.
All choices offered are false.
The theme is heard first, followed by FIVE different variations of it.
===> 5
The maximum amount of pulling force a truck can apply when driving on
concrete is 10,560 N. If the coefficient of static friction between a trailer and
concrete is 0.8, what is the heaviest that the trailer can be and still be pulled
by the truck?
The truck needs to draw the trailer with 13200 N of force at its maximum capacity.
What Does Static Friction Mean?Every physical object has a small amount of "stickiness," which is where friction gets its power. Where two surfaces touch, there will be some resistance to motion in that direction. When two surfaces are stationary in relation to one another, there is static friction. Because static friction creates resistance, a certain amount of force must be exerted to get objects moving. There won't be any movement at all if the force applied to one of the surfaces does not surpass the static friction force.
Let the weight of the truck be W . reaction force R = W
Maximum frictional force = μ R
= .8 x W
So for movement of truck
Pulling force = frictional force
10560 = .8W
W = 13200 N
weight of heaviest truck required = 13200 N .
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Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]
The vertical component of the acceleration of a projectile remains constant during the entire trajectory of the projectile is True or False
True because the vertical acceleration of a projectile is the acceleration due to gravity which is either 9.8 m/s/s or -9.8 m/s/s depending on perspective.
Sanjay uses 225 N of force to move a wheelbarrow 18 m at a velocity of 1.8 m/s. What was the amount of power used?
The amount of power used by Sanjay when he uses a force of 225 N to move a wheelbarrow 18 m at a velocity of 1.8 m/s is 405 N
What is power?
Power can be defined as the product of force and velocity.
To calculate the amount of power used by Sanjay, we use the formula below.
Formula:
P = FV........... Equation 1Where:
P = PowerF = ForceV = Velocity.From the question,
Given:
F = 225 NV = 1.8 m/sSubstitiute these values into equation 1
P = 225×1.8P = 405 NHence, the amount of power is 405 N.
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Which object has a weight of about 22.5 N?
The object with a mass of 2.3 kg that is the rock will have a weight of 22.5 N.
W = m * g
W = Weight
m = Mass
g = Acceleration due to gravity
g = 9.8 m / s²
For the book,
m = 1.1 kg
W = 1.1 * 9.8
W = 10.78 N
For the Box,
m = 4.5 kg
W = 4.5 * 9.8
W = 44.1 N
For the Rock,
m = 2.3 kg
W = 2.3 * 9.8
W = 22.5 N
Therefore, the object that has a weight of about 22.5 N is the rock
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