PLEASE HELP! thxssss
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Answer:

(C) 40m/s

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

Answer:

Resultant force = [tex]\sqrt{91}[/tex]N

Explanation:

Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]

Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]

Rf = [tex]\sqrt{36+25+30}[/tex]

Rf = [tex]\sqrt{91}[/tex]

doesn't look right though...

The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given parameters:

Two forces are 6 N and 5N.

Angle between them is 60 degree.

So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N =  = 9.54 N.

Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°)  } = 33⁰.

Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

To find more about force, refer the link:

https://brainly.com/question/13191643

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Answer: False

Explanation:

Answer:

roddy i guess?

Explanation:

Answer:

Dababy and Roddy Ricch. Jason's songs use to be fire years back but now....not so much.

Explanation:

Answer:

4.04 seconds

Explanation:

In order to solve this problem, we must keep in mind that the initial 2.00 seconds at which the fuel is exhausted does not signal when the rocket reaches its maximum height.

From this moment on, the rocket has a downward acceleration of 9.8 m/s² but it still has an upwards velocity, which we will calculate. This upwards velocity keeps the rocket moving up for a certain period of time, which we will also calculate.

For this problem, let's set the upwards direction to be positive and the downwards direction to be negative.

To find the time that the rocket takes to reach its maximum height, we are going to use the initial 2.00 seconds and find the additional seconds it takes to reach a final vertical velocity of 0 m/s. This represents the time at which the rocket stops moving and heads in the downwards direction, which takes place after the rocket has reached its maximum height.

The time in the air of an object in projectile motion can be found using this equation, derived from one of the constant acceleration kinematic equations.

Time in the air (projectile motion):

Solve for [tex]v_i[/tex] by plugging in 2.00 seconds for t, 30 degrees for theta, and 20.0 m/s² for acceleration, since this is not a constant acceleration problem.

Multiply sin(30) and 2 together.

Multiply 20 to both sides of the equation.

Now we know that the initial velocity of the rocket is 40 m/s. We need to solve for the vertical component of the rocket's velocity in order to solve for the additional time it took after the 2.00 seconds to reach its maximum height.

Vertical component:

The vertical component of the velocity vector is 20 m/s.

Now, in order to solve for the additional seconds that the rocket took to reach its maximum height, let's use one of the kinematic constant acceleration equations that uses the variables [tex]v_f[/tex], [tex]v_i[/tex], [tex]a[/tex], and [tex]t[/tex].

Since we are trying to solve for time, we need to use this equation in terms of the vertical direction, aka the y-direction. Time is the same in either case.

The final vertical velocity of this rocket is 0 m/s at the top, or its maximum height. We found that the vertical component, aka the rocket's initial vertical velocity, is 20 m/s. The acceleration is given to us: -9.8 m/s² (since it's falling downwards, the acceleration must be negative because we already established this in the beginning).

We are trying to solve for time t. Substitute the known values into the equation.

Subtract 20 from both sides of the equation.

Divide both sides of the equation by -9.8.

Now we can take this time and add it to the initial 2.00 seconds of the rocket. This time we just solved for is the time after these initial seconds that the rocket kept going upwards, since its initial vertical velocity was not 0 m/s yet.

The time that the rocket takes to reach its maximum height is 4.04 seconds.

Answer:

4.04 second is your answer hope it help you........

The effort must move 8•0

Answer:

A

Explanation:

In  scenario A the two objects have the least gravitational force between them.

Gravitational force is defined as the force which one mass exert on the other mass separated by finite distance. Mathematically gravitational force is directly proportional to product of mass and inversely proportional to square of distance between them.

Force between two mass,

F = Gmm/r²

Given question, to find when have the least gravitational force between two masses so from option A we see there separation distance is maximum 1.5 m and mass product is less than option B.

So least gravitational force when masses are 12 kg and separation distance is 1.5 meter.

To learn more about gravitational force refer to the link:

brainly.com/question/12528243

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Answer:

As she raises the height of the ramp, the speed of the toy car decreases.

Explanation:

Speed is the ratio of the distance traveled by an object to the time taken.

i.e speed = [tex]\frac{distance}{time}[/tex]

From the given question, it would be observed that:

i. when the height of the ramp was 10 cm, the car traveled 5 meters.

ii. when the height of the ramp was increased to 13 cm, the car traveled 6 meters.

Therefore, an increase in the height of the ramp causes a decrease in the speed of the toy car so that the distance traveled per unit time increases. Showing that there is an inverse relationship between the height of the ramp and the speed of the toy car.

Answer:

The initial velocity of the ball is 28.714 m/s

Explanation:

Given;

time of flight of the ball, t = 2.93 s

acceleration due to gravity, g = 9.8 m/s²

initial velocity of the ball, u = ?

The initial velocity of the ball is given by;

v = u + (-g)t

where;

v is the final speed of the ball at the given time, = 0

g is negative because of upward motion

0 = u -gt

u = gt

u = (9.8 x 2.93)

u = 28.714 m/s

Therefore, the initial velocity of the ball is 28.714 m/s

Answer:

Feeling's.

Explanation:

Nobody can measure the feeling of a person or love , etc

Write each force in component form:

v ₁ : 50 N due east   →   (50 N) i

v ₂ : 80 N at N 45° E   →   (80 N) (cos(45°) i + sin(45°) j ) ≈ (56.5 N) (i + j )

The resultant force is the sum of these two vectors:

r = v ₁ + v ₂ ≈ (106.5 N) i + (56.5 N) j

Its magnitude is

|| r || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N

and has direction θ such that

tan(θ) = (56.5 N) / (106.5 N)   →   θ ≈ 28.0°

i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive x-axis.)

Answer:here you goo

Explanation:

A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.

Answer:

Minerals are naturally occuring solid while rocks are naturally occuring substances consist of aggregate minerals clumped together with other materials

Answer:

2.5 km/30min

Explanation:

Divide 5 by 2 because 30  min is half of 1 hour. when you do that you get 2.5

Answer:

I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.

Explanation:

19km in 30mins

1 hour is twice of 30 mins.

Twice the time means twice the distance.

therefore 2(19km) in 2(30 mins)

19km in 30mins = 38km/hour

Explanation:

Power is the rate at which work is done. It is expressed as:

     Power  = [tex]\frac{work done}{time taken}[/tex]  

To find the power of the man climbing the ladder, we must know the work he is doing and the duration of the work done.

 Work done  = force x distance

  Since he climbs,

           Force  = weight  = mg (mass x acceleration due to gravity)

    distance  = height = h

Power  = [tex]\frac{mgh}{t}[/tex]

t is the time

    If we know these parameters, we can find the power.

Answer:

it is an upside-down image but the brain realizes it and corrects it in its orientation so we see it in right direction.

Answer:

The lens of the eye is a convex lens. The image that it forms on the retina is upside down.

Explanation:

The eye makes an image, but it is upside down, the brain corrects the image and turns it right side up

Answer:

A stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

Explanation:

In more simple terms, an electron is a negatively charged subatomic particle.

Hope that helps :)

Answer:

An electron is a particle with negative charge that can be found in the atom, along with neutrons and protons

Answer:

0.61°

Explanation:

Since the box move at constant velocity, it means there is no acceleration then we can say it has a balanced force system.

Pulling force= resistance force

From the formula for pulling force,

F(x)= Fcos(θ)

= 425×cos(35.2)

=347N

The force exerted downward at an angle of 35.2° below the horizontal= Fsin(θ)= 425sin(35.2)

=425×0.567=245N

Resistance force= (325N+ 245N) (α)= 570N(α)

We can now equates the pulling force to resistance force

570 (α)= 347N

(α)= 347/570

= 0.61

Given :

Initial pressure, [tex]P_i=200\ kPa[/tex].

Initial volume, [tex]V_i= 4\ m^3[/tex].

Final volume, [tex]V_f = 2 \ m^3[/tex].

To Find :

Final pressure, [tex]P_f[/tex].

Solution :

We know, at constant temperature :

[tex]P_iV_i=P_fV_f\\\\P_f=\dfrac{P_iV_i}{V_f}\\\\P_f=\dfrac{200\times 4}{2}\\\\P_f=400\ kPa[/tex]

Therefore, new pressure is 400 kPa.

Hence, this is the required solution.

Answer:

C.

Explanation:

Answer:

Havent seen this one before but the explanation should help you out :)

Explanation:

There are only three atomic bonds.

Ionic bonding.

Covalent bonding.

Metallic bonding.

Answer:

Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral.  (I'm sorry if that wasn't helpful)

Explanation:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 142 × 7

We have the final answer as

Hace this helps you

Answer:  D.   500 J

=========================================================

Explanation:

To find the amount of work done, we multiply the force by displacement

work = force*displacement

work = (100 N)*(5 m)

work = (100*5) Nm

work = 500 J

In this case, "Nm" refers to "Newton meters" and not "nanometers"

1 newton meter is equal to 1 joule

Answer:

1010 m

Explanation:

The following data were obtained from the question:

Height (h) of cliff = 500 m

Horizontal velocity (u) = 100 m/s

Horizontal distance (s) =?

Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:

Height (h) of cliff = 500 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

500 = ½ × 9.8 × t²

500 = 4.9 × t²

Divide both side by 4.9

t² = 500/4.9

Take the square root of both side

t = √(500/4.9)

t = 10.1 s

Finally, we shall determine the horizontal distance travelled by the cannon ball.

This can be obtained by using the following formula (s = ut) as illustrated below:

Horizontal velocity (u) = 100 m/s

Time (t) = 10.1 s

Horizontal distance (s) =?

s = ut

s = 100 × 10.1

s = 1010 m

Thus, the cannon ball was launched 1010 m away from the cliff.

Answer:

100°c = 373.15 K

100°C=212°F

Explanation:

To convert Celsius to Kelvin, we need the following equation.

°C + 273.15 = K

100°C + 273.15 = K

373.15 = K

Therefore, 100°c = 373.15 K

F = 9/5C + 32

   =9/5(100)+32

  = (180) + 32

  = 212°

Therefore,

100°C=212°F