Pls help me with the answer to question 3

Answer:

Step-by-step explanation:

Slope of line passing through (0, 3) and (3, -1) = (-1-3)/(3-0) = -4/3

Slope of any parallel to the line is also -4/3.

Point-slope equation for line of slope -4/3 that passes through (-3, 2):

y-2 = (-4/3)(x+3)

Answer:

1. (-2, 3) 7

2. (5, 8) 5

3. (-6, 1/2) 2/3

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where the center is at point (h, k) and the r is the radius. Find the values that would fit the numbers in parenthesis to find the center of the circle, and take the squareroot of the number on the right side of the equation to find the radius.

lmk if im wrong, hope this helps!

Answer:

The ball reached its maximum height of ([tex]11\ yards[/tex]) in ([tex]1\ second[/tex]).

Step-by-step explanation:

This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.

The first step in completing the square is to group the quadratic and linear term:

[tex]h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6[/tex]

Now factor out the coefficient of the quadratic term:

[tex]h(t)=-5(t^2 -2t) + 6[/tex]

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

[tex]h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6[/tex]

Now take the balancing term out of the parenthesis:

[tex]\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))[/tex]

Simplify:

[tex]h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11[/tex]

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

[tex](1, 11)[/tex]

Answer:

f(x)=

Step-by-step explanation:

Answer:

it should be 90 degrees

Step-by-step explanation:

...........................

Answer:

40%

Step-by-step explanation:

[tex]\frac{8}{20} = \frac{2}{5}[/tex]

[tex]\frac{2}{5} = 0.40[/tex]

0.40 = 40%

Answer:

≈£2412

Step-by-step explanation:

1800(0.05)^6

≈£2412

20+7x

just use the distributive property on 2(5+3x) then add x and 10

Answer:

28.3mm

Step-by-step explanation:

3(3)=9(pi)= 28.274...

Answer: 9[tex]\pi[/tex], or more specifically, 28.26, or even more specifically, 28.2643.

Explanation:

To find the area of a circle, you need to do r squared x pi. Since pi repeats randomly infinitely, we are going to simplify it to 3.14. 3 squared or 3 x 3 equals 9. 9 x 3.14 = 28.26. Therefore, the area of the quarter is 28.26. If you want to find the answer without simplifying pi, it is approximately 28.2643. You can also write it as 9[tex]\pi[/tex].

Hope this helps! If it did, please give brainliest! It would help a lot! Thanks! :D

Answer:Third Person Objective

Answer: (-3, -8) (0, 1) (-3, -8)

Step-by-step explanation:

So in the equation, y=3x+1, 1 is the y intercept (which is where the line goes through the y intercept, so graph a point at 0,1 (that also fills out the middle of the chart. 3 is the slope of the equation so then you have to use the slope and you will find 2, 7 as a point and -3, -8 as a point.

Hope that helps! :)

Answer:

it would be 66 I hope this helps.

Answer:

a

Step-by-step explanation:

Step-by-step explanation:

[tex]\tt{} \frac{ \sqrt[3]{60} }{ \sqrt[3]{36} } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5} }{ \sqrt[3]{3} } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5} }{ \sqrt[3]{3} } \times \frac{ \sqrt[3]{ {3}^{2} } }{ \sqrt[3]{ {3}^{2} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5} \sqrt[3]{ {3}^{2} } }{ \sqrt[3]{3} \sqrt[3]{ {3}^{2} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5 \times {3}^{2} } }{ \sqrt[3]{3 \times {3}^{2} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5 \times 9} }{ \sqrt[3]{ {3}^{3} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{45} }{3}[/tex]

[tex]\tt{}1.18563[/tex]

Answer:

yaaaaas i think it is c

Step-by-step explanation:

Answer:

Q is P reflected across the x-axis; only the signs of the y-coordinates of P and Q are different.

Step-by-step explanation:

Hope this helped :)

Answer:

1:2 is the ratio

Step-by-step explanation:

Answer:

-1/3

Step-by-step explanation:

-1/2 is the answer and try to don't lose points next time.

Answer:

3

Step-by-step explanation:

Use Pythagorean theorem

Base²+ altitude² = hypotenuse²

Base² + (√3)²   = (2√3)²

Base² + √3 *√3 = 2√3 *2√3

Base² + 3           = 4*3

Base² + 3           = 12

              Base²  = 12 - 3

              Base²  = 9

              Base    = [tex]\sqrt{9}=\sqrt{3*3} =3[/tex]

Answer:

600 cm³

Step-by-step explanation:

12 x 10 = 120

120 x 5 = 600

Answer:

volume is just defined as multplying all the sides and is alot different from surface area, so it would be 1/5x1/5x/14 which is 1/100

Step-by-step explanation:

Answer:

there are 6 faces

Step-by-step explanation:

there are 4 faces around and 1 on to and 1 on the bottom

Answer:

ΔDEG ≅ ΔFGE

Side-Angle-Side

Step-by-step explanation:

DG ║ EF  because DG⊥DE and GF⊥EF

∠DGE ≅ ∠FEG because alternate interior angles of parallel lines are congruent

so Side-Angle-Side proves congruency

Answer:

(a). and (b).

Step-by-step explanation:

Simplify Square Roots -

Find one perfect square and one imperfect square to multiply to the square root.

[tex] \sqrt{4 \times 10} = 2 \sqrt{10} [/tex]

[tex]40^{ \frac{1}{2} } = \sqrt[2]{(40) ^{1} } = \sqrt{40} [/tex]

[tex] \sqrt{40} \neq 4 \sqrt{10} [/tex]

[tex]160 ^{ \frac{1}{2} } = \sqrt[2]{160 ^{1} } = \sqrt{160} \neq \: \sqrt{40} [/tex]

[tex]5 \sqrt{8} \neq \: \sqrt{40} [/tex]

Answer:

(9, 2)

Step-by-step explanation:

What point divides the directed line segment ​ AB¯¯¯¯¯ ​ ⁢ into a 3:1 ratio?

coordinate plane with segment A B with A at (0, 2) and B at (12, 2)

(3, 2)

(4, 2)

(8, 2)

(9, 2)

Solution:

If point O(x, y) divides the line segment AB with endpoints A([tex]x_1,y_1[/tex]) and B([tex]x_2,y_2[/tex]) in the ratio n:m, the coordinates of O is:

[tex]x=\frac{n}{n+m} (x_2-x_1)+x_1\\\\y=\frac{n}{n+m} (y_2-y_1)+y_1[/tex]

Let us assume C(x, y) is the point that divides  segment A B with A at (0, 2) and B at (12, 2) in the ratio 3 : 1. Hence:

[tex]x=\frac{3}{3+1}(12-0)+0=\frac{3}{4}(12)=9 \\\\y=\frac{3}{3+1}(2-2)+2=\frac{3}{4}(0)+2=2[/tex]

Therefore the coordinate of point C is at (9, 2).