Simplify: 3-2
A. -9
B. -6
C.1/9
D.1/6​

Simplify: 3-2 A. -9 B. -6 C.1/9 D.1/6

Answers

Answer 1

Answer:

1/9

Step-by-step explanation:

3 ^ -2

The negative in the exponent means to bring it to the denominator

1/ 3^2

1/9

Answer 2

Answer:

C. 1/9

Step-by-step explanation:


Related Questions

Express 5 cm in metre and kilometre.in decimals........................

Answers

Answer:

0.05 metre

5×10^5 kilometer

1.9685

Which Triangles are Congruent and Explain Why.

Answers

Answer:

D

Step-by-step explanation:

because I remember doing this before

HELP PLS +10 BRAINLY POINTS (SHOW WORK PLS)

Answers

Hi there!

[tex]\large\boxed{\text{System G.}}[/tex]

For a system to have an infinite number of solutions, both expressions must be equal. We can go through each system and determine this:

F:

x + 2 = y

4 = 2y - x

If we rearrange so that both are in the same format, we get:

x + 2 = y

x + 4 = 2y

These cannot be equal, so they do not have infinite solutions.

G:

2y + 6 = 4x

-3 = y - 2x

Rearrange:

2y + 6 = 4x

-y - 3 = -2x

We can try to make the bottom equation look like the top equation by multiplying all terms by -2. We get:

2y + 6 = 4x. This is the same as the top, so G has infinite solutions.

Just to be sure, we can go through the others:

H:

y + 3 = 2x

4x = 2y - 3

Rearrange:

y + 3 = 2x

2y - 3 = 4x. Cannot be equal to the other equation.

J:

y = 2x - 5

y = 2x - 2. Not equal.

The correct answer is G.

Simplify the expression


2(6x + 3)

Answers

12x + 6 because 2 times 6 is 12 and 2 times 3 is 6

The confidence interval is pretty wide and leaves a lot of uncertainty over the proportion of UCI students who live on campus. With the goal to estimate a narrower 95% confidence interval, what is a simple change to this study that you could suggest for the next time that a similar survey is conducted

Answers

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Researchers must increase the response rate to achieve a narrower confidence interval. Because we see that the trust gap is inverse to sample size. We must increase data in estimating a narrower 95-percent trust range. Since the sample has increased, its error margin has decreased, this reduces the width of the trust interval.

Ignore the instructions if you know how to do it in a different way & please check answer!
~Rules~
a. NO LINKS/FILES
b. NO SILLY ANSWER
c. SHOW WORK/EXPLAIN HOW YOU GOT IT
If you follow all the rules I will give Brainliest.
~Hocus Pocus

Answers

Answer:

8ft is the diameter so the radius would be half of that, so it's 4ft. Now substitute

[tex]\pi4 {}^{2} [/tex]

now solve 4^2=16 now multiply it by 3.14 (pi). 16×3.14= 50.24

Find the sum of the first five terms of the geometric series 50 + 25 + 12.5 +

Answers

The answer for this question is 6.25

What is the surface area of the cylinder with height 4 in and radius 5 in? Round your answer to the nearest thousandth .

Answers

Answer: 282.743 in2

Step-by-step explanation:

: If Newton Manufacturers has an accounts receivable turnover of 4.8 times and net sales of $7,812,379, what would its receivables be?

Answers

Answer:

$1,627,579

Step-by-step explanation:

Given that

The account receivable turnover is 4.8 times

And, the net sales is $7,812,379

We need to find out the receivable

So as we know that

accounts receivable turnover = net sales ÷ average accounts receivables

Therefore the accounts receivables is

= ($7,812,379 ÷ 4.8)

= $1,627,578.96

= $1,627,579

Luci and her friends go out to lunch and receive a bill
for their meals that reads $56.80. They added a 20%
tip to their bill before tax was calculated. Tax is 8%.
How much money did they leave in total, including tax
and tip? Round to the nearest cent. Show your work.

Answers

Answer:

$72.70

Step-by-step explanation:

bill was $56.80

tip was 20% so was 56.80/ 5( because 5 of 20% will make 100%)= $11.36

tax was 8% so was 56.80*8/100= $4.54

total money paid

56.80+4.54+11.36 = 72.70

NO LINKS!!! NOT AN ASSESSMENT OR TEST!!!! NOT MULTIPLE CHOICE!!

a. Sketch a graph to model Seattle's cost structure over the domain [0, 42,000]. Be sure to label the axes and any endpoints where the graph breaks.


b. Describe the function over each part of its domain. State whether it is constant, increasing or decreasing, and state the slope over each part. ​

Answers

Part (a)

The graph is shown below. It's a piecewise function composed of 3 parts: Two flat horizontal segments and a decreasing segment.

Note the use of open holes at points C and E. They tell the reader that the specific point is not part of the function. For example, point C at (8000,0.75) is an open hole since the second piece has x = 8000 excluded. In other words, the domain for the second piece is [tex]8,000 < x \le 20,000[/tex] which says to exclude 8000 but to include 20,000.

============================================================

Part (b)

The flat parts are due to the two first pieces being constant functions. Regardless of what x is on those portions, the cost per unit stays the same. We see that the cost starts off at 35 cents per unit (green segment), then it jumps to 75 cents per unit (blue segment).

So far the costs have been constant, but once we get to the red curve portion, then the costs decrease as x increases. Note that 1/(200,000) = 0.000005 which means the costs are decreasing by 0.000005 dollars per unit. Let's multiply that by 10,000 to get 10,000*0.000005 = 0.05

So for the red portion, the costs are decreasing by $0.05 per 10,000 units, or they are decreasing by 5 cents per 10,000 units. When x > 20000, the lowest we can get the cost is at 62 cents per unit. This is when production is at max capacity (42,000 units).

If you wanted the cost per unit to be as small as possible, and x didn't have to be larger than 20 thousand, then you'd stick to the green line. However, the drawback here is that you can only produce at max 8000 units.

Answer:

Person above was super helpful!

Step-by-step explanation:

what is the vertex of y=ax^2+c

Answers

9514 1404 393

Answer:

  (0, c)

Step-by-step explanation:

Compare the given equation to the vertex form equation ...

  y = a(x -h)^2 +k . . . .  quadratic with vertex (h, k)

You have ...

  y = ax^2 +c

Matching these forms, we see that h=0, and k=c. Then the vertex is ...

  (h, k) = (0, c)

What is the volume of the given picture below? ( HELP PLEASE )

Answers

It's 904.78.

The formula for the volume of a sphere is 4/3(pi)r^3. The diameter is 12. Half it to get the radius, which is 6. Plug 6 into the formula. The result is 904.77868.

Soren solves the quadratic equation x^2 + 8x – 9 = 0 using the quadratic formula. In which step did Soren make an error?

Answers

Answer:

step 3 didn't divide by 2

Step-by-step explanation:

in step

[tex] \frac{ - 8 + \sqrt{100} }{2} = \frac{ - 8 + 10}{2} = 1 \\ \frac{ - 8 - \sqrt{100} }{2} = \frac{ - 8 - 10}{2} = - 9[/tex]

The probability that the number on the card is a perfect square is

Answers

From 2 to 101 , the perfect square numbers are ,

4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 , 100 .

Total number of possible outcomes = 100.

Total number of favourable outcomes = 9 .

Hence ,

→ P ( of getting perfect square ) = 9/100

Can someone help me

Answers

Answer:

y= (-6/5)x -2

Step-by-step explanation:

y=mx+b , where m is the slope, and b is the y -intercept

the y -intercept is where the line intersects the y-axis so b = -2

the slope m= y(rise) /x(run)  = 6/-5 = -6/5 ( to find the slope you have to know how to get from any point on the line to another point on the same line; start at point (0,-2) go up 6(y-rise) and to the left 5(x-run) at point (-5,4))

y= (-6/5)x -2

FIND THE MISSING SIDE LENGTHS!!!!!

Answers

Step-by-step explanation:

tan 30°= root 3/ 3

r²=x² + y²

r²= 4root3 ² + 12²

r²= 48 +144

r²= 192

ŕ= 8root3

so the bottom is 12...

the other side is 4root3

[tex]4 \sqrt{3} [/tex]

and hypotenuse is 8root3

[tex]8 \sqrt{3} [/tex]

Element X is a radioactive isotope such that every 24 years, its mass decreases by
half. Given that the initial mass of a sample of Element X is 70 grams, how long
would it be until the mass of the sample reached 61 grams, to the nearest tenth of a
year?

Answers

Answer:

Step-by-step explanation:

We get to use the simple version of the half life equation:

[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where N is the amount of radioactive element left after a specific number of years,

N0 is the initial amount of the element,

t is the number of years (our unknown), and

H is the Half life of the element. For us,

N is 61

N0 is 70,

t is unknown,

H is 24 years. Filling in:

[tex]61=70(.5)^{\frac{t}{24}[/tex]. We begin by dividing both sides by 70 to get:

[tex].8714285=(.5)^{\frac{t}{24}[/tex] and then take the natural log of both sides:

[tex]ln(.8714285=ln(.5)^{\frac{t}{24}[/tex] which allows us to bring down the exponent to the front on the right side:

[tex]ln(.8714285)=\frac{t}{24}ln(.5)[/tex]. We divide both sides by ln(.5) to get:

[tex].1985457976=\frac{t}{24}[/tex] and then multiply both sides by 24 to get:

t = 4.8 years

Researchers from a large community college in California are interested in understanding the demographics of students enrolled in their online classes. The researchers collected the following data for the 2014/2015 school year.

Male Female Total
Online Only 2,000 7,000 9,000
Online and in the class only 8,000 1,000 9,000
Total 10,000 8,000 18,000

What does the data suggest about the relationship between sex and enrollment?

a. Females are more likely to enroll in Online Only courses than males.
b. Females are more likely to enroll in Online and In Class courses than males
c. There are more females enrolled at the community college than males.
d. Females are equally likely as males to enroll in an Online Only course.

Answers

Answer:

a. Females are more likely to enroll in Online Only courses than males.

Step-by-step explanation:

From the data, we have that:

There are 9,000 students that are online only, of which 2,000 are male and 7,000 are female.

There are 9,000 students that are Online and in the class only, of which 8,000 are male and 1,000 are female.

In total, there are 18,000 students, of which 10,000 are male and 8,000 are female.

a. Females are more likely to enroll in Online Only courses than males.

True, 7,000 females compared to 2,000 males in online only courses. This option is the answer to this question.

b. Females are more likely to enroll in Online and In Class courses than males

False, in online and in the class courses, there are 8,000 males and 1,000 females, so females are less likely.

c. There are more females enrolled at the community college than males.

False, there are 10,000 males and 8,000 females.

d. Females are equally likely as males to enroll in an Online Only course.

False, there are 7,000 females compared to 2,000 males in online only courses, so they are more likely, and not equally likely.

The expression 4c - 3 is equal to _ when c = -2

Answers

Answer:

-11

Step-by-step explanation:

let f(c) = 4c - 3

f(-2) = 4(-2) - 3 = -8 -3 = -11

Answer:

-11

Step-by-step explanation:

4c - 3

c = -2

4(-2) - 3

-8 - 3

-11

4c - 3 = -11 when c = -2

Hi plz help, if you can ill mark you 5 starz! :)

Answers

Answer:

Step-by-step explanation:

Part A= 59.11

Part B: i think is B

I hope this helps :))

Answer:

Step-by-step explanation:

Part A : 59.11

Part B: the answer is B. You keep the same amount of decimal places in the problem in your product. we had 2 so we have 2 decimal places in 5911 ---> 591.1 --->59.11

solve the equation s - 12 equals 20
ASAP pls​

Answers

Answer:

s = 32

Step-by-step explanation:

s - 12 = 20

s (- 12 + 12) = 20 + 12

s = 32

Step-by-step explanation:

s-12=20

s=20+12

s=32

Hope it helps.

The probability that a tennis set will go to a tiebreaker is 16%. In 220 randomly selected tennis sets, what is the mean and the standard deviation of the number of tiebreakers

Answers

Answer:

The mean number of tiebreakers is of 35.2 and the standard deviation is of 5.44.

Step-by-step explanation:

For each set, there are only two possible outcomes. Either it goes to a tiebreak, or it does not. The probability of a set going to a tiebreak is independent of any other set, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

The probability that a tennis set will go to a tiebreaker is 16%.

This means that [tex]p = 0.16[/tex]

220 randomly selected tennis sets

This means that [tex]n = 220[/tex]

What is the mean and the standard deviation of the number of tiebreakers?

[tex]E(X) = np = 220*0.16 = 35.2[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{220*0.16*0.84} = 5.44[/tex]

The mean number of tiebreakers is of 35.2 and the standard deviation is of 5.44.


Helpp
Based on the histogram above, which of the following statements must be true

Answers

Answer:

b

Step-by-step explanation:

because the price of money is maximum 2,500

Find the 9th term of the geometric sequence 5, -25, 125, ...

Answers

Answer:  1,953,125

This is one single value and it is just a bit under 2 million.

Or more accurately, it's a bit over 1.9 million.

===========================================================

Explanation:

a = 5 = first termr = -5 = common ratio

Note that dividing any term by its previous term gets us the common ratio

r = term2/term1 = -25/5 = -5r = term3/term2 = 125/(-5) = -5

The r value must stay the same the entire time, or else the sequence isn't geometric.

The nth term of any geometric sequence is a*(r)^(n-1). With the 'a' and 'r' values we found, we update that to 5(-5)^(n-1)

-----------------

To verify that is the correct nth term expression, plug in various values of n to compare it with the given sequence.

If we tried n = 2 for instance, then we find the 2nd term is

5(-5)^(n-1) = 5(-5)^(2-1) = -25

which matches what your teacher gave you. I'll let you verify the other terms.

-----------------

The last thing we need to do is plug in n = 9 and simplify

5(-5)^(n-1)

5(-5)^(9-1)

5(-5)^8

5(390625)

1,953,125  this is one single value (rather than 3 separate values)

In a viral pool test it is known that in a group of five (5) people, exactly one (1) will test positive. If they are tested one by one in random order for confirmation, what is the probability that only two (2) tests are needed?

Answers

Answer:

[tex]\frac{4}{20}[/tex] or 0.2 or 20%

Step-by-step explanation:

For only two tests to be needed this means that the first test would need to come back as negative and the second test would be to come back as positive. Therefore, to find the probability of this happening we first need to find the probability of each individual test and multiply them together.

The first test needs to come back negative, there are four negative individuals out of the total 5 that are in the group. Therefore, the probability of the first test is 4/5.

Now we remove the individual that has just been tested and we are left with 4 total subjects in the group, of which only 1 is positive. Therefore, the probability of the second test is 1/4. Now we need to multiply these two probabilities together to get the probability of only needing two tests.

[tex]\frac{4 * 1}{5 * 4} = \frac{4}{20}[/tex] or 0.2 or 20%

GUYS QUICK! what is the surface area of a sphere that has a radius of 5 cm

Answers

Answer:

100 pi cm^2

or approximately 314 cm^2

Step-by-step explanation:

The surface area of a sphere is given by

SA = 4 pi r^2

The radius is 5

SA = 4 *pi * 5^2

SA = 4*pi(25

SA = 100 pi cm^2

If pi is 3.14

SA = 100 *3.14 = 314 cm^2

Answer:

[tex]\large\fbox{\underline{Surfαcє αrєα σf sphєrє ís 314 cm ².}}[/tex]

Step-by-step explanation:◈ Gívєn ◈

☞ Rαdíus σf sphєrє = 5 cm

◈ Tσ FínD ◈

☞ Surfαcє αrєα σf sphєrє

◈ Fσrmulα nєєdєd ◈

☞ Surfαcє αrєα σf sphєrє = 4 π r ²

◈ Sσlutíσn ◈

usíng thє fσrmulα

surfαcє αrєα σf sphєrє = 4 π r ²

suвstítutє thє vαluєs

surfαcє αrєα σf sphєrє = 4 × 3.14 × ( 5×5 ) cm ²

mutíplчíng thє vαluєs

surfαcє αrєα σf sphєrє = 100 cm² × 3.14

Hєncє , Surfαcє αrєα σf sphєrє ís 314cm ².

–––––––––☆–––––––––

A survey of 1100 adults from a certain region​ asked, "If purchasing a used car made certain upgrades or features more​ affordable, what would be your preferred luxury​ upgrade?" The results indicated that 49​% of the females and 41​% of the males answered window tinting. The sample sizes of males and females were not provided. Suppose that of 600 ​females, 294 reported window tinting as their preferred luxury upgrade of​choice, while of 500 ​males, 205 reported window tinting as their preferred luxury upgrade of choice. Complete parts​ (a) through​ (d) below.
a. Is there evidence of a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade at the 0.05
level of​ significance?
b. State the null and alternative​hypotheses, where π1 is the population proportion of females who said they prefer window tinting as a luxury upgrade and π2 is the population proportion of males who said they prefer window tinting as a luxury upgrade.

Answers

Answer:

a) The p-value of the test is 0.0076 < 0.05, which means that there is evidence of a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade at the 0.05.

b) The null hypothesis is [tex]H_0: \pi_1 - \pi_2 = 0[/tex] and the alternate hypothesis is [tex]H_1: \pi_1 - \pi_2 \neq 0[/tex].

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Females:

49% from a sample of 600. So

[tex]\pi_1 = 0.49, s_{\pi_1} = \sqrt{\frac{0.49*0.51}{600}} = 0.0204[/tex]

Males:

41% from a sample of 500. So

[tex]\pi_2 = 0.41, s_{\pi_2} = \sqrt{\frac{0.41*0.59}{500}} = 0.022[/tex]

Test if there is a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade.

From here, question b can already be answered.

At the null hypothesis we test if there is no difference, that is, the subtraction of the proportions is 0. So

[tex]H_0: \pi_1 - \pi_2 = 0[/tex]

At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the proportions is different of 0. So

[tex]H_1: \pi_1 - \pi_2 \neq 0[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

From the two samples:

[tex]X = \pi_1 - \pi_2 = 0.49 - 0.41 = 0.08[/tex]

[tex]s = \sqrt{s_{\pi_1}^2 + s_{\pi_2}^2} = \sqrt{0.0204^2 + 0.022^2} = 0.03[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{0.08 - 0}{0.03}[/tex]

[tex]z = 2.67[/tex]

Question a:

P-value of the test and decision:

The p-value of the test is the probability that the sample proportion differs from 0 by at least 0.08, which is P(|Z| > 2.670, which is 2 multiplied by the p-value of Z = -2.67.

Looking at the z-table, Z = -2.67 has a p-value of 0.0038.

2*0.0038 = 0.0076

The p-value of the test is 0.0076 < 0.05, which means that there is evidence of a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade at the 0.05.

1. Which of these is an infinite arithmetic sequence?
O {691, 632, 573, 514}
O {232, 354, 476, 598, ...}
O {845, 169, 33.8, 6.76, ...}
O {724, -362, 181, -90.5}

Answers

Answer: Choice B

Each time we're adding 122 to each term to get the next term

232+122 = 354354+122 = 476476+122 = 598

This goes on forever because of the three dots, hence the set is infinitely large.

We say that the common difference is 122. Subtracting any two adjacent terms gets us this value. Eg: 354-232 = 122.

How far does the barnacle travel in one revolution of the water wheel?

m

Answers

Answer:

2pi

Step-by-step explanation:

Right on edg assignment

Other Questions
assume a company uses the weighted average method in its processing costing august 1 balance 62000 and materials 310,000 consisted of 6000 units with 40500 in materials during august 48000 units were installed into production consisted of 8000 units that were 100% with respect to mateirals the materials cost included in the refining departement ending work in process inventory is closest to A gymnasium floor is being covered by square shock-absorbing tiles. The new tiles are 2 inches larger in length and width than the old tiles. The new flooring will require only 600 tiles. What is the length of a side of one of the new shock-absorbing tiles Mga isyu tungkol sa kawalan ng paggalang sa dignidad at sekswaliadad what is science and important of science Every closed circuit has an electric current, voltage, and ___________..Fill in the blank The Gagliarda began with a bold and lively alr, and as he played the opening bars, he heard behind him a creaking of the wicker chair. Thesound was a perfectly familiar one--as of some person placing a hand on elther arm of the chalr preparatory to lowering himself into it, followedby another as of the same person being leisurely seated. But for the tones of the violin, all was silent, and the creaking of the chair was strangelydistinct. The illusion was so complete that my brother stopped playing suddenly, and turned round expecting that some late friend of his hadslipped in unawares, being attracted by the sound of the violin, or that Mr. Gaskell himself had returned. With the cessation of the music anabsolute stillness fell upon all; the light of the single candle scarcely reached the darker corners of the room, but fell directly on the wicker chairand showed it to be perfectly empty. Half amused, half vexed with himself at having without reason interrupted his music, my brother returned tothe Gagliarda, but some impulse Induced him to light the candles in the sconces, which gave an Illumination more adequate to the occasion. TheGagliarda and the last movement, a Minuetto, were finished, and John closed the book, Intending, as it was now late, to seek his bed. As he shutthe pages a creaking of the wicker chalr again attracted his attention, and he heard distinctly sounds such as would be made by a person raisinghimself from a sitting posture. This time, being less surprised, he could more aptly considerthe probable causes of such a circumstance, andeasily arrived at the conclusion that there must be in the wicker chair osiers responsive to certain notes of the violin, as panes of glass in churchwindows are observed to vibrate in sympathy with certain tones of the organ. 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