Solve the equation below for x. 100 = 25e3 In4 O A. 4 B. 3 e O C. X=In4 - 3 c In100 3. In25 O D.

Answer:

a)Figure C

b) Figure A, B, and C

c)Figure B and C

Step-by-step explanation:

Note squares are rectangles

Answer: (7,11)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Find The Edge Of The Cube Whose Leteral Surface Area Is 36cm^2

LSA of cube = x^2 + x^2 + x^2 + x^2 = 4x^2

so

4x^2 = 36

x^2 = 9

x = 3

-------------------------------

check

4 * 3^2 =

4 * 9 =

36

the answer is good

Answer: 3 cm

Step-by-step explanation:

The domain and range of this function f(x) = 4(∛8)ˣ are: A. {x| x is a real number}; {y| y > 0}.

A function simply refers to a mathematical expression which is used to define and represent the relationship that exists between two or more variables. This ultimately implies that, a function is typically used for uniquely mapping an input variable to an output variable.

In this scenario, the function f(x) = 4(∛8)ˣ represents an exponential function. Generally speaking, an exponential function is defined by the set of all real numbers on the x-axis.

Additionally, the value of four (4) is greater than zero (0) and as such the range defined by the set of all real numbers on the y-axis that are greater than zero (0).

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Answer:

A. {x| x is a real number}; {y| y > 0}

Step-by-step explanation:

on edge

The equation of line is =1/2 x+1/2 .

A line equation is a straightforward mathematical formula that uses the slope, x-intercept, and y-intercept of the line to describe the relationship between the points on the line.

The formula for a straight line is y=mx+c where c is the height at which the line intersects the y-axis, often known as the y-intercept, and m is the gradient.

In order to put the equation in y-intercept (y=mx+b) form and determine the equation of a graphed line, first determine the slope and y-intercept. The slope is the ratio of the y-to-x change.

y=mx+b

According to graph, points are (-1,0) and (1,1)

Hence we get –m+b=0 and m+b=1

On solving m = ½ and b = ½

The equation of line is =1/2 x+1/2 .

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The domain of the function f(x)=1/(x-3) will be all the real numbers except 3.

The domain of the function is defined as the set of all the possible values of the function. The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x).

A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

Given function is f(x)=1/(x-3). The domain of the function will be all the real numbers. But at x = 3 the value of the function does not exist.

Therefore, the domain of the function f(x)=1/(x-3) will be all the real numbers except 3.

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Answer:

No.

The square root of any number can never be negative/ -1

Answer:

ABC

Step-by-step explanation:

BECAUSE THEY ARE OPPOSITE

Answer:

x = 12, y = 60

Step-by-step explanation:

We have parallel lines, so alternate interior angles are congruent.

6x + 3 = 75

6x = 72

x = 12

The interior angles of a triangle add up to 180 degrees.

45 + 75 + y = 180

120 + y = 180

y = 60

Answer:

[tex]x=\dfrac{-3+\sqrt{37}}{2}, \quad x=\dfrac{-3-\sqrt{37}}{2}[/tex]

Step-by-step explanation:

Given quadratic equation:

[tex]x^2+3x-7=0[/tex]

Step 1

When completing the square for a quadratic equation in the form [tex]ax^2+bx+c=0[/tex] the first step is to move the constant to the right side of the equation:

[tex]\implies x^2+3x-7+7=0+7[/tex]

[tex]\implies x^2+3x=7[/tex]

Step 2

Add the square of half the coefficient of the term in x to both sides to form a perfect square trinomial on the left side:

[tex]\implies x^2+3x+\left(\dfrac{3}{2}\right)^2=7+\left(\dfrac{3}{2}\right)^2[/tex]

Simplify:

[tex]\implies x^2+3x+\left(\dfrac{3^2}{2^2}\right)=7+\left(\dfrac{3^2}{2^2}\right)[/tex]

[tex]\implies x^2+3x+\dfrac{9}{4}=7+\dfrac{9}{4}[/tex]

[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{28}{4}+\dfrac{9}{4}[/tex]

[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{28+9}{4}[/tex]

[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{37}{4}[/tex]

Step 3

Factor the perfect square trinomial on the left side:

[tex]\implies \left(x+\dfrac{3}{2}\right)^2=\dfrac{37}{4}[/tex]

Step 4

Square root both sides:

[tex]\implies \sqrt{\left(x+\dfrac{3}{2}\right)^2}=\sqrt{\dfrac{37}{4}}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{37}}{\sqrt{4}}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{37}}{2}[/tex]

Step 5

Subtract ³/₂ from both sides:

[tex]\implies x+\dfrac{3}{2}-\dfrac{3}{2}=-\dfrac{3}{2}\pm\dfrac{\sqrt{37}}{2}[/tex]

[tex]\implies x=-\dfrac{3}{2}\pm\dfrac{\sqrt{37}}{2}[/tex]

[tex]\implies x=\dfrac{-3\pm\sqrt{37}}{2}[/tex]

Therefore, the solutions of the given quadratic equation are:

[tex]x=\dfrac{-3+\sqrt{37}}{2}, \quad x=\dfrac{-3-\sqrt{37}}{2}[/tex]

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Answer:

i d k

Step-by-step explanation:

Answer: down here

Step-by-step explanation:

4−50

5−Y

6−150

​

Factor the expressions that are not already factored.

−46=−2×23

−144=−2

4

×3

2

Identify all the factors and their highest power in all expressions. Multiply the highest powers of these factors to get the least common multiple.

3312(Y−5)

Expand the expression.

3312Y−16560

The measure of the third angle in the triangle is 152°.

It should be noted that a triangle has three sides and the sum of the total angles is 180°.

In this case, two of the angles in a triangle measure 20° and 8°. The third angle will be:

= 180° - (20° + 8°)

= 180° - 28°

= 152°

The angle is 152°.

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The equivalent expression for [tex](3.7)^{-5}*(3.7)^{9}[/tex] is [tex](3.7)^{4}[/tex].

This is a question of exponents and powers.

Exponents

The exponent of a number says how many times to use the number in a multiplication. In [tex]8^2[/tex] the "2" says to use 8 twice in a multiplication, so [tex]8^2[/tex] = 8 × 8 = 64.

Here, 2 is the exponent or power and 8 is the argument.

We can use exponents when we have to deal with very large numbers.

For example:-

The distance between the Earth and the Sun is measured to be 149,600,000 Km.

To write it in simple terms we will write,

[tex]1.496 * 10^8[/tex] km.

We know that:-

[tex]a^b*a^c=a^{b+c}[/tex]

Here,

a = 3.7,

b = -5 and,

c = 9

Hence, we can write,

[tex](3.7)^{-5}*(3.7)^{9}=(3.7)^{-5+9}=(3.7)^{4}[/tex].

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Answer: R(8,1)

Step-by-step explanation:

[tex]\displaystyle\\M(9,2)\ \ \ \ S(10,3)\ \ \ \ R(x,y)=?\\\\M_x=\frac{R_x+S_x}{2} \\\\\Rightarrow\ 9=\frac{x+10}{2\\\\}[/tex]

Multiply both parts of the equation by 2:

[tex]9(2)=x+10\\18=x+10\\18-10=x+10-10\\8=x[/tex]

[tex]\displaystyle\\M_y=\frac{R_y+S_y}{2} \\2=\frac{y+3}{2}[/tex]

Multiply both parts of the equation by 2:

[tex]2(2)=y+3\\4=y+3\\4-3=y+3-3\\1=y[/tex]

⇒   R(8,1)

Answer: 3/2

Step-by-step explanation:

The scale factor is the same as the ratio of the length of a side of the image to the length of the corresponding side in the preimage.

We know that Y'X'=3 and YX=2, so the scale factor is 3/2.

Answer:

T: (-10,1)

S: (-10,-4)

U: (-5,1)

V:  (-5,-4)

Step-by-step explanation:

Translation means moving the object. Subtract 4 from each x value and add 1 to each y value.

Answer:

T' = (-10, 1)

S' = (-10, -4)

U' = (-5, 1)

V' = (-5, 4)

Step-by-step explanation:

      To do this, we will take each coordinate point, subtract four units from the x-value, and add one unit to the y-value.

T = (-6, 0) ➜ (-6 - 4, 0 + 1) ➜ T' = (-10, 1)

S = (-6, -5) ➜ (-6 - 4, -5 + 1) ➜ S' = (-10, -4)

U = (-1, 0) ➜ (-1 - 4, 0 + 1) ➜ U' = (-5, 1)

V = (-1, -5) ➜ (-1 - 4, -5 + 1) ➜ V' = (-5, 4)

Answer: The decrease in price is $64, and the sale price is $192.

Step-by-step explanation:

0.25 * $256 = $64

$256 - $64 = $192

Answer: x = -9

Step-by-step explanation:1

Combine like terms

2 Add the numbers

3 Rearrange terms

4 Subtract 14 from both sides

5 Simplify

6 Add x to both sides

7 Simplify

8 Divide both sides by the same factor

9 Simplify

If this helped you please consider marking this as the Brainliest Answer, if i make it to 10, I can be promoted to an expert. Thank you!

Answer:

x= -9

Step-by-step explanation:

Simplify  3x+14 -6x to -3x +14

Simplify 25−x+7  to  32−x32−x.

Add 3x3x to both sides.

Simplify  32−x+3x32−x+3x  to  32+2x32+2x.

Divide both sides by 22.

Simplify  18/2 to  99.

x=−9 is your final answer

Annual cost to operate farm B well with cost of natural gas $2.50 per 1,000 cubic feet and uses of 10000cubic feet of natural gas per year is $25.

As given,

Farm A:

Cost of natural gas per 1,000 cubic feet=$2.50

Farm B:

Uses of natural gas per year = 10000cubic feet

Cost of natural gas of farm B is same as farm A

Cost of natural gas per 1,000 cubic feet=$2.50

⇒1cubic feet=2.50/1000

Annual cost to operate 200ft well that uses 10000 cubic feet natural gas

10000 cubic feet=(2.50 ×10000)/1000

                             =$25

Therefore, annual cost to operate farm B well with cost of natural gas $2.50 per 1,000 cubic feet and uses of 10000cubic feet of natural gas per year is $25.

The complete question is:

Farm A has a 100 ft well that uses 7,000 cubic feet of natural gas per year. If the cost of natural gas for farm A is $2.50 per 1,000 cubic feet. And farm B has a 200 ft well that uses 10000 cubic feet of natural gas per year. if the cost of natural gas is the same a farm A, what is the annual cost to operate this well?

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Option C correctly represents the function.

For the given question;

From the definition of the function, two values in the domain can not have the same image, thus option a and b are incorrect.

Only option c correctly described the function, as for every value of out put there is only one input.

Thus, option c correctly described the function.

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Answer:

a: -$4

b:45

Step-by-step explanation:

First, you just divide the total amount lost by the number of shares. because it is a loss it's going to be a negative number. For the second one, you want the total so you are going to multiply 45 by 9 and because it's an increase, the answer is a positive number.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textsf{Question \#1 reads \boxed{\downarrow}}[/tex]

[tex]\large\text{Ivanna owns \underline{6 shares} of a certain stock. Yesterday the total value of}\\\large\text{her shares went down by \underline{24 dollars}. \boxed{\text{What was the change in value}}}\\\large\text{\boxed{\text{for each share}} ?}[/tex]

[tex]\huge\textsf{What should the equation look like?}[/tex]

[tex]\mathsf{\dfrac{24}{6} = change\ in\ value\ for\ each \ share}}[/tex]

[tex]\huge\textsf{How are we going to solve for the answer?}[/tex]

[tex]\mathsf{\dfrac{24\ dollars}{6\ certain \ stock} = change\ in\ value\ for\ each \ share}}[/tex]

[tex]\mathsf{24\ dollars \ \div\ 6\ certain\ stock\ = change\ in\ value\ for\ each \ share}[/tex]

[tex]\mathsf{4 = change\ in\ value\ for\ each \ share}}[/tex]

[tex]\huge\textsf{So, what s the answer to the question?}[/tex]

[tex]\large\text{Therefore, your answer should be: \boxed{\mathsf{4\ dollars}}}\large\checkmark[/tex]

[tex]\huge\textsf{Question \#2 reads \boxed{\downarrow}}[/tex]

[tex]\large\text{A private club grew by \underline{9 members} each week for \underline{45 weeks}. \boxed{\text {What}}}\\\large\boxed{\text{was the total change in the clubs size}} \large\text{ ?}}[/tex]

[tex]\huge\textsf{What should the equation look like?}[/tex]

[tex]\mathsf{\dfrac{45\ weeks}{9\ members} = total\ change\ in \ the\ clubs \ size}[/tex]

[tex]\huge\textsf{How are we going to solve for the answer?}[/tex]

[tex]\mathsf{\dfrac{45\ weeks}{9\ members} = total\ change\ in \ the\ clubs \ size}[/tex]

[tex]\mathsf{45\ weeks\ \div \ 9\ members = total\ change\ in\ the\ clubs\ size}[/tex]

[tex]\mathsf{5 = total\ change\ in\ the\ clubs\ size}[/tex]

[tex]\huge\textsf{So, what s the answer to the question?}[/tex]
[tex]\large\text{Therefore, your answer should be: \boxed{\mathsf{5\ members}}}\large\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

The multiplication of polynomials (3x² - 5x + 7) and (2x² - 5x + 7) is:

6x^4 - 25x³ + 60x² - 70x + 49

In this question, we have been given two polynomials 3x² - 5x + 7 and 2x² - 5x + 7

We need to multiply given polynomials.

(3x² - 5x + 7) × (2x² - 5x + 7)                          ............(Given polynomials)

= 3x²(2x² - 5x + 7) - 5x(2x² - 5x + 7) + 7(2x² - 5x + 7)      ..........(Distribute)

= 6x^4 - 15x³ + 21x² - 10x³ + 25x² - 35x + 14x² - 35x + 49     .....(Simplify)

= 6x^4 - 15x³ - 10x³ + 21x² + 25x² + 14x² - 35x -35x + 49

= 6x^4 - 25x³ + 60x² - 70x + 49

Therefore, the multiplication of polynomials (3x² - 5x + 7) and (2x² - 5x + 7) is 6x^4 - 25x³ + 60x² - 70x + 49

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The length of the sides of equilateral triangles are as follows

5cm,  15m , 8cm , 300m , 12m , 90mm .  

The whole length of a shape's boundary is referred to in geometry as the perimeter of the shape. By multiplying the lengths of all the sides and edges that surround an object, the perimeter may be calculated. It is measured in measures of length that are linear, such as centimeters, meters, inches, or feet. A regular polygon's sides are all the same length, as far as we know.

Therefore,

A regular polygon's perimeter is equal to the product of all of its sides, which is equal to the number of sides divided by the length of a side.

The measurement of a shape's length along its outline is known as its perimeter. Simple addition of the lengths of the object's edges serves as the perimeter measurement method.

The perimeter of an equilateral triangle

= 3a      where a is each side

So,

(a) P = 15 cm

3a = 15

a = 5

each side = 5 cm

(b) 45 m

3a = 45

a = 15 m

each side = 15 m

(c) 24 m

3a = 24

a = 8 cm

each side =  8 cm

(d) 900 m

3a = 900

a = 300 m

each side = 300 m

(e) 36 cm

3a = 36

a = 12 cm

each side = 12 cm

(f) 270 mm

3a = 270

a = 90 mm

each side = 90 mm

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Yes, because all linear equations have graphs that are straight lines. This statement explains Roxanne is correct.

The first order of equations is linear equations. For lines in the coordinate system, linear equations are defined. A linear equation in one variable is one in which there is a homogeneous variable of degree 1 (one variable) in the equation.

There may be several variables in a linear equation. Linear equations with two variables, and so forth, are what the equation is known as if it has two variables. When the unknown values are replaced for those produced by the solutions of linear equations, the equation is proved to be true. There is just one answer when there is just one variable.

Hence the correct option is A

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Answer:

The original price of the watch was 260pounds

Step-by-step explanation:

let the reduced price be x

(100%-15%)/100 of x=221

85x/100=221

85x=22100

there fore x=260pounds

The missing numbers in the third level can be 10, 6 and 18

On the first level of the number tower, we have

First level = 40

On the second level, we have

Second level = 16 and 24

The numbers on the third level of the number tower are missing.

However, these numbers must add up to the sum of 16, while the other must add up to 24

So, we can make use of

10, 6 and 18

This is because

10 + 6 + 6 + 18 = 40

Here, we have

2x + y = 14 and x + 2y = 16

Multiply 2x + y = 14 by 2

4x + 2y = 28

Subtract x + 2y = 16 from 4x + 2y = 28

4x - x + 2y - 2y = 28 - 16

Evaluate

3x = 12

Divide

x = 4

Also, we have 2x + y = 14

This gives

y = 14 - 2x

y = 14 - 2 x 4

y = 6

So, the values of x and y for 2x + y = 14 and x + 2y = 16 are 4 and 6, respectively

This has the same step as part (b)

In (b), we have

x = 4

Which gives

2x + y = 14

Make y the subject

y = 14 - 2x

Substitute 4 for x

y = 14 - 2 x 4

Evaluate

y = 6

Hence, the values of x and y for 2x + y = 14 and x + 2y = 16 are 4 and 6, respectively

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The ratio of the short leg to the hypotenuse in the right triangle is 1 : 2. the correct option is D. 1 : 2

From the question, we are to determine the ratio of the short leg to the hypotenuse in the given right triangle

Given an equilateral triangle with side lengths 2 units each and interior angle 60° each as shown in the diagram below. If the triangle is divided into 2 equal right triangles as shown in the given diagram, the length of the hypotenuse will be 2 units, the length of the short leg will be 1 unit, and the length of the long leg will be √3 units.

Thus,

The ratio of the short leg to the hypotenuse will be

1 unit / 2 units

= 1 : 2

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Solving for f

Adjacent angles of a parallelogram are supplementary, so (f+30)+72=180. It follows that f=78.

Solving for g

Opposite sides of a parallelogram are congruent, so 25=8g-3. It follows that g=3.5.