Subtract these equations.

The corresponding values of expressions 1, 2,3,4 and 5 when evaluated are -2, -0.65, -7/48, 67 1/2 and 2 2/33

1. To evaluate (a-2b)^3 when a = -3 and b = - 1/2,  put a = -3 and b = - 1/2 into the expression (a-2b)^3:

(a-2b)^3 = ( -3 - 2(-1/2) )

              = (-3 + 1) = -2

2. To evaluate (jk - 1) ÷ j when j = -4 and k = -0.9, put  j = -4 and k = -0.9 into the expression (jk - 1) ÷ j:

(jk - 1) ÷ j = ( -4(-0.9) - 1) ÷ (-4)

              = (3.6 -1) ÷ (-4) = (2.6) ÷ (-4) = -0.65

3. To evaluate -|a+b| / 2-c when a =1 7/8 , b = -1 , and c = -4 , put b = -1 , and c = -4 into the expression -|a+b| / 2-c:

-|a+b| / 2-c  = -|1 7/8 + (-1)|/ 2 -(-4)

                  = -| 7/8 | / 6 = -7/48

4. To evaluate (w^2 / x - 3) ÷ 10 multiplied by z when w = -9 , x = 2.7 , and z= -2/5:

(w^2 / x - 3) ÷ 10z = ((-9)²/ 2.7 -3)  ÷ 10(-2/5)

                            = (81/(-0.3))  ÷  (-4) = -270/-4 = 67 1/2

5. To evaluate (2a - 1/3) ÷ b/15 when a = -2/5 and b = -8.25:

(2a - 1/3) ÷ b/15 = (2(-2/5) - 1/3) ÷ -8.25/15

                          = (-4/5 - 1/3) ÷ (-11/20) = -17/5 ÷ (-11/20) = 2 2/33

Therefore, the expressions 1, 2,3,4 and 5 evaluate to -2, -0.65, -7/48, 67 1/2 and 2 2/33 respectively

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The factor of the trinomial 9x² + 30x + 25 is (3x + 5).

When you factor a trinomial, you change an algebraic expression from a trinomial to a binomial. ax² + bx + c, where a and b are coefficients and c is a constant, is the general expression for a trinomial, which is a polynomial with three terms.

Given trinomial: 9x² + 30x + 25

Factoring the trinomial, we get

9x² + 30x + 25

9x² + 15x + 15x + 25

3x(3x + 5) + 5(3x + 5)

(3x + 5)²

Therefore, (3x + 5) is the factor of the given trinomial.

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Answer:

1, 7, 13, 19, 25, 31, 37, 43

Step-by-step explanation:

it is increasing by 6 each time so you add 6 three more times.

The non-real solutions of the polynomial expression are x = 2 + i√11 and x = 2 - i√11

The equation of the polynomial expression is given as:

x^4 – 7x^3 + 23x^2 – 29x – 60 = 0

Also, we have the following points

(-1, 0), (0, -60), (2.5, -60), (4, 0)

Write out the x-intercepts

(-1, 0) and (4, 0)

This means that

x = -1 and x = 4

So, we have

x + 1 = 0 and x - 4 = 0

Multiply

(x + 1)(x - 4) = 0

Divide the polynomial equation x^4 – 7x^3 + 23x^2 – 29x – 60 = 0 by (x + 1)(x - 4) = 0

Using a graphing calculator, we have

x^4 – 7x^3 + 23x^2 – 29x – 60/(x + 1)(x - 4) = x^2 - 4x + 15

So, we have

x^2 - 4x + 15

Next, we solve the quadratic expression using a quadratic formula

So, we have

x = (-b ± √(b² - 4ac))/2a

This gives

x = (4 ± √((-4)² - 4 * 1 * 15))/2 * 1

So, we have

x = (4 ± √-44)/2

This gives

x = (4 ± 2√-11)/2

Divide

x = 2 ± √-11

So, we have

x = 2 ± i√11

Split

x = 2 + i√11 and x = 2 - i√11

Hence, the non-real solutions are x = 2 + i√11 and x = 2 - i√11

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2.16 sec take to eat a human weighing 90kilograms.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

It takes 12 seconds the Dragon eat 500 Kg.

So, to eat 1 Kg the dragon takes

=12/500

=0.024 sec

Now, to eat 90 Kg it will take

=0.024 x 90

= 2.16 sec

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Answer:

approximately 19~20 shopper

Step-by-step explanation:

this case binomial distribution

X~B(n,p)

X: number of shoppers who spend less than 20$

n=28

p=0.7

use mean of binormal distribution E(X)=np

Answer)

E(x) =28*0.7=19.6

thus approximately 19~20 shopper

olution

Basically, the number of asymptotes will be the number of solutions the denominator of the function has

We are given the function

Solving the denominator

he answer is 3 vertical asymptotes

The method that she could use to measure an equivalent amount is to remove 25% from the measurement used.

From the information, the chef needs 3/4 of a cup of flour for her recipe, but her 1/4 cup measure is missing.

Therefore, the method that she could she use to measure an equivalent amount will be to subtract 25% from whatever value that she is using.

It should be noted that 3/4 to percentage will be:

= 3/4 × 100.

= 75%

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Answer:

congruent: a° and c°; d° and b°

Supplementary: c° and b°; a° and b°; a° and d°; c° and d°

Step-by-step explanation:

The subsets of the set {-3, 6}, which are proper subsets is the option;

A set is a model that represents a collection of mathematical objects such as numbers, lines, symbols, points, other sets, variables, or shapes.

In set theory, a set A is a subset of the set B if all the elements or members present in set A can be found in set B. Therefore, set B is said to contain set A or set A is contained in set B.

The above relationships can be expressed using examples as follows;

Let set A = {X, Y} and let set B = {X, Y, Z}, then set A is a subset of set B because the elements, X, Y, contained in set A, are also contained in set B,

Generally, the number of proper subsets of a set that contains n elements is [tex] {2}^{n} - 1[/tex]

Given that the subset of a set which is not a proper subset is the set of itself.

The given set is; {-3, 6}

The number of elements in the set, n = 2

Therefore;

The number of proper subsets = 2² - 1 = 3

All the subsets of {-3, 6} are therefore;

∅, {-3}, {6}

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Solution

The total number nof cookies in the bag is:

- Thus, we can write the probabilities of choosing any of the cookies are given as:

- Now, let us analyze Trey's random choices

Choice 1:

He chose a sugar cookie at first.

- Thus, the probability of this choice is

Choice 2:

- He chose an oatmeal cookie in the second choice.

- But he already had one cookie before this choice, thus, the total number of cookies is one less. That is, 23 not 24.

- Thus, the probability of choosing the oatmeal cookie is given as:

- Because these choices do not interfere with one another (i.e. they are mutually exclusive), we can apply the AND probability formula to calculate the probability that Treys chose a Sugar Cookie first, and then an Oatmeal cookie next.

- The AND probability is given as

- Thus, we can find the probability that Trey chooses Sugar Cookies first and Oatmeal Cookie next as follows:

Final Answer

The answer is

The weighted dollar amount of the savings account as per the an investment portfolio given is equal to $67.20.

As given in the question,

An investment portfolio is shown below.

Investment Amount Invested ROR

Savings Account $3,200     2.1%

Municipal Bond $4,900       4.5%

Preferred Stock  $940         10.5%    

Common Stock A $1,675     -3.5%

The weighted dollar amount of the savings account is equal to :

= 2.1% of $3200

=  ( 2.1 / 100)  × $3200

= ($6720) /100

= $ 67.20

Therefore,  the weighted dollar amount of the savings account  as per the an investment portfolio given is equal to $67.20.

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Answer:

There is no solution.

Step-by-step explanation:

The absolute value of a number is the distance between that number and zero. It doesn't deal with negative numbers. For example, if you were playing a board game and were told to move back 6 spaces, you would be moving -6 spaces, but 6 spaces away from where you were. Absolute value focuses on how far you moved from where you were. So, an absolute value can't be negative.

Answer:

30

Step-by-step explanation:

200/40=5

5x6=30

therefore there are 30 tickets you could get with 400$

hope this helped

have a great day ^^

Answer:

30 tickets

Explanation:

One ticket can be represented as variable t.

Using t, we can set up an equation (proportion) using the given information:

[tex]6t = \$ 40[/tex]

Then, we can multiply both sides of the equation (proportion) by something such that the number of dollars on the right side is $200.

[tex]6t \ = \ \$ 40 \\\times 5 \ \ \ \times 5[/tex]

[tex]30t = \$ 200[/tex]

So, we can get 30 tickets for $200.

Answer: I am 97% sure it's D

Step-by-step explanation:

Answer:

A and D (the top one and the bottom one)

Step-by-step explanation:

You do not multiply the exponents when the two terms are be multiplied. Instead, you add the exponents. For example, in the first problem, the terms being multiplied are [tex]5y^4[/tex] and [tex]2y^5[/tex]. The exponents are 4 and 5, and when you add them together, that is the exponent that y should carry in the answer.

Hope this helps you! May I please get a brainliest?

For $3.00, the pounds of bananas that can be bought are 2.

How to derive equation of line from graph using two point form?
A line's equation can take many different shapes in a two-dimensional coordinate plane. The point-slope form, slope-intercept form, and general or standard form of the equation of a line are the three most often used techniques.
The formula of two point form of a equation is given below:
Let (x₁, y₁) and (x₂, y₂) be the two points such that the equation of line passing through these two points is given by the formula:
(y-y₁)/(x-x₁) = (y₂-y₁)/(x₂-x₁) -- (i)
Rearranging (i), we get: y - y₁ = [(y₂-y₁)/(x₂-x₁)] (x-x₁) --(ii)

Given, the graph has y co-ordinate as cost in $ of bananas and the x co-ordinate as pounds in lb.
From graph in question, the two points that can be assumed are (0.5,0.75) and (3,4.5); thus using two point form we get the equation as:
y - 0.75 = [(4.5 - 0.75)/(3 - 0.5)] *(x - 0.5) ⇒ y - 0.75 = 1.5 (x - 0.5)
⇒ y - 0.75 = 1.5x - 0.75 ⇒ y = 1.5x ⇒ x = y/1.5 --(ii)
From (ii),
thus for y = 3, value of x will be x = 3/1.5 = 2

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From the diagram we notice that the angle of 55° is vertical opposite to angle 3, hence they are equal.

Also from the diagram we notice that angles 3 and 6 are alternate interior angles and since lines A and B are parallel then they are equal.

Finally angle 6 and angle 7 are vertical opposite, which means they are equal.

Therefore, the value of angle 7 is 55°

Answer:

Using the data under D1 and D2, calculate the cross elasticity of demand for golf at all three prices. (To do this, apply the midpoints approach to the cross elasticity of demand.) At $50, cross elasticity = -2.40 ± 0.05At $35, cross elasticity = -3.00 ± 0.05At $20, cross elasticity = -4.00 ± 0.05Is the cross elasticity the same at all three prices? No. Are movies and golf substitute goods, complementary goods, or independent goods? Complementary goods.b. Using the data under D2 and D3, calculate the income elasticity of demand for golf at all three prices. (To do this, apply the midpoints approach to the income elasticity of demand.) At $50, income elasticity of demand = 1.40 ± 0.05At $35, income elasticity of demand = 2.33 ± 0.05At $20, income elasticity of demand = 3.00 ± 0.05Is the income elasticity the same at all three prices? No. Is golf an inferior good? No, it is a normal good.

The required statement is given as the data tends to the normal good.

Statistics is the study of mathematics that deals with relations between comprehensive data.

Calculate the cross elasticity of demand for golf at each of the three prices using the information under D1 and D2.

At $50, the cross elasticity is equal to -2.40 ± 0.05;
At $35, it is - 3.00± 0.05;
At $20, it is - 4.00 ±0.05.
No golf and movies complementary, independent, or alternative goods complementing products b.

Calculate the income elasticity of demand for golf at each of the three prices using the information under D2 and D3.
At $50, the income elasticity of demand is equal to 1.40±0.05
At $35, it is 2.33± 0.05
At $20, it is 3.00± 0.05

Thus, the required statement is given as the data belong to the normal good.

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The graph has the horizontal tangent line at the the turning point(stationary point) And we know that at the turning point the gradient is 0. We can find the gradient of f(x0 by the first derivative. As  I said the gradient a the turning point is 0 meaning since f'(x) =m  and m=0 ∴f'(x)=0

[tex]f'(x)=4x-2\\0=4x-2\\4x=2\\\frac{4x}{4}=\frac{2}{4} \\x=\frac{1}{2}[/tex]

Now we know that in order to find the point where x = [tex]\frac{1}{2}[/tex]  we can substitute the value of x in the original equation

[tex]f(\frac{1}{2})=2(\frac{1}{2} )^{2} -2(\frac{1}{2} )-1\\f(\frac{1}{2} )=-\frac{3}{2}[/tex]

The answer is [tex](\frac{1}{2} ,-\frac{3}{2} )[/tex]

Hope I helped.

iven:

heere are given that the population in the year 2000 was 12000 and the growth rate is 7% per year.

xplanation:

ccording to the question:

For t =0 which is the year 2000:

For t = 1:

If we say r is the rate, then:

Then,

For t = 2:

And,

For t = 3:

Therefore our function should be:

(a):

he population function:

Now,

(b):

ccording to the question:

2008 is 8 year from year 2000:

Therefore, t = 8:

Then,

Put the value 8 for t into the function (a):

inal answer:

The ratio of 5 to 6 means that for every 5 girls on the track team there are 6 boys.

So, if there are n groups of 5 girls, there should be also n groups of 6 boys. Thus, we have the proportion:

Then, let's check each item to find out which one shows possible numbers of girls to boys on the track team.

A. 24 girls, 20 boys

B. 50 girls, 56 boys

C. 60 girls, 50 boys

D. 20 girls, 24 boys

Therefore, option D is correct.

The rocked was launched at an initial height of 325 meters

The equation of the function is given as

h ( t ) = − 4.9 t 2 + 226 t + 325 .

Rewrite the above equation properly

So, we have the following equation

h(t) = −4.9t^2 + 226t + 325

At the initial height of the launch, the time is 0

This is represented as

t = 0

Substitute the known values in the above equation

So, we have the following equation

h(0) = −4.9(0)^2 + 226(0) + 325

Evaluate the exponent in the above equation

So, we have the following equation

h(0) = −4.9(0) + 226(0) + 325

Evaluate the product in the above equation

So, we have the following equation

h(0) = 0 + 0 + 325

Evaluate the sum in the above equation

So, we have the following equation

h(0) = 325

Hence, the initial height of the launch is 325 meters

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Possible question

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.9 t 2 + 226 t + 325 .

Calculate the height of launch of the rocket

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

(a)

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (0, - 2) ← 2 points on the line

m = [tex]\frac{-2-0}{0-(-3)}[/tex] = [tex]\frac{-2}{0+3}[/tex] = - [tex]\frac{2}{3}[/tex]

(b)

the y- intercept is the point on the y- axis where the line crosses, that is

y- intercept c = - 2

(c)

y = - [tex]\frac{2}{3}[/tex] x - 2 ← equation of line

Answer: (a) only

Step-by-step explanation:

For there to be inverse proportion, the product of x and y must be constant.

The linear graphing of the given equation y = 3x - 3 is done by plotting a series of points and then tracing a line through them.

Given equation:

y = 3x - 3

Now we will graph this linear equation by plotting points.

We can select input values, evaluate the equation at these input values, and compute output values to determine the respective points. Coordinate pairs are created by the input and output values. The coordinate pairs are then plotted on a grid.

So, the points of the given linear equations are:

 x     y

-2    -9

-1     -6

0    -3

1      0

2     3

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: y = x² -14 x + 48[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

The values of x for which the curve cuts/touches the x - axis are roots of that particular polynomial.

So, the values of x, when y = 0 are the roots of the given quadratic function.

that is : x = 6 and x = 8

And it can be represented as :

[tex]\qquad \tt \rightarrow \: (x - h1)(x - h2)= 0[/tex]

[ h1 and h2 represents roots of the quadratic function ]

[tex]\qquad \tt \rightarrow \: (x - 6)(x - 8) = 0[/tex]

It can be further simplified as :

[tex]\qquad \tt \rightarrow \: {x}^{2} -8x - 6x + 48 = 0[/tex]

[tex]\qquad \tt \rightarrow \: x {}^{2} - 14x + 48 = 0[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞