Suppose that Hubble's constant were H0 = 51 km/s/Mly (which is not its actual value). What would the approximate age of the universe be in that case?

Answer:

Explanation:

Given,

As we know,

Kinetic Energy,

Therefore ,

Kinetic energy of the object is,

[tex] = \frac{1}{2} \times 12 \: kg \times 10 \: m {s}^{ - 1} \times 10 \: m {s}^{ - 1} [/tex]

= (6 × 10 × 10) J [As 'J' stands for 'joule']

= 600 J (Ans)

The magnitude of the induced electric field is (RdB/dt)/4

The induced electric field is gotten from

-∫E.dl = dФ/dt where E = induced electric field, dl = path length vector, Ф = magnetic flux through cylindrical region = AB where A = area of magnetic flux = πR² where R = radius of cylindrical region and B = magnetic field.

So, -∫E.dl = dФ/dt

-∫E.dl = dAB/dt

-∫Edlcos0 = AdB/dt (where E.dl = Edlcos0 = Edl since E and dl are parallel to each other.)

So -∫Edl = πR²dB/dt

-E∫dl = πR²dB/dt (∫dl = 2πr since the integral is the circumference of the path)

-E(2πr) = πR²dB/dt (we integrate dl from r = 0 to 2R)

-E2π(2R - 0) = πR²dB/dt

-E4πR= πR²dB/dt

E = πR²dB/dt ÷ 4πR

E = -(RdB/dt)/4

So, the magnitude of the induced electric field is (RdB/dt)/4

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Answer:

a) 1 m/s²

b) -1 m/s²

c) 0 m/s² (constant speed, not accelerating)

Explanation:

A

delta speed = 10 - 0

delta time = 10 - 0

delta speed / delta time = 10/10

delta speed / delta time = 1

B

ds = 5 - 10

dt = 15 - 10

ds / dt = -5 / 5

ds / dt = -1

C

ds = 5 - 5

dt = 25 - 15

ds / dt = 0 / 10

ds / dt = 0

The average acceleration of A, B, and C will be 1 m/s², -1 m/s², and 0 m/s².

An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.

There are different types of acceleration :

Average acceleration is defined as the average change in velocity with respect to the average change in time.

SI unit is m/s² and it is vector quantity.

According to the question,

For A, Acceleration= (v₁-v₀)/(t₁-t₀)

⇒10-0/10-0

= 1 m/s².

For B, Acceleration= (v₃-v₂)/(t₃-t₂)

⇒5-10/15-10

= -1 m/s²

For C, Acceleration will be constant because change in velocity is constant, this is the case of uniform motion, so its acceleration is also going to be constant (as per the definition of acceleration change in velocity ratio change in time).

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Answer:

  170/179 A ≈ 949.7 mA

Explanation:

Finding equivalent impedance of a bridge network can be simplified by converting one end of it from a Δ to a Y configuration. The equivalent resistance in the Y connection is the product of the two resistors connected to that node, divided by the sum of all three resistors.

Considering the left side of the top two branches, the equivalent Y network values are ...

  (10)(15)/(10+15+25) = 150/50 = 3 . . . ohms

connected to the right-end node

  (25)(10)/50 = 5 . . . ohms

connected to the top-center node, and ...

  (25)(15)/50 = 7.5 . . . ohms

connected to the center node of the middle branch.

__

Then the top two branches of this circuit have an equivalent impedance equal to 3 ohms in series with the parallel combination of (5+20) ohms and (7.5+10) ohms. That value is ...

  3 + (25)(17.5)/(25 +17.5) = 226/27 ≈ 13.294 . . . ohms

This, in turn, is in series with the 2.5 ohms in the bottom branch, bringing the total circuit resistance to about 15.794 ohms, or 537/34 ohms.

The total source current is then ...

  I = V/R = (15 v)/(537/34 Ω) = 170/179 A ≈ 0.9497 A

_____

Alternate solutions

Alternatively, you can write and solve three node or loop equations for this circuit. For example, the equations for CCW loop currents, with I1 as the bottom loop, could be written in augmented matrix form as ...

  [tex]\left[\begin{array}{ccc|c}27.5&-10&-15&-15\\-10&55&-25&0\\-15&-25&50&0\end{array}\right][/tex]

The result is the same.

Answer:

O present a topic in your own words

Explanation:

Plagiarism is using someone else's words or work without giving them proper credit. Presenting a topic in your own words means you are not copying anyone.

Answer:

present a topic in your own words

Explanation:

Answer:

True

Explanation:

Answer:

Row A is correct

Explanation:

both conduction and convection require mass to complete any heat transfer. A vacuum contains no mass

Answer: Terrestrial biomes are based on land, while aquatic biomes include both ocean and freshwater biomes.

Explanation:

Explanation:

static electricity draws energy

Answer:

Acceleration due to gravity on a certain planet = 4 m/s²

Explanation:

According to the question,

Weight = 30 N

Mass = 7.5 kg

Let acceleration due to gravity be 'a'

Formula:

Weight = Mass × Acceleration due to gravity

30 = 7.5 × a

a = 30/7.5

a = 4 m/s²

Answer:

B. is your answer

Explanation:

Have a good day

Sincerly, lipor

Short, difficult activities that push your body are called anaerobic activities.  Option b is correct

They are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles. Examples include weightlifting or sprinting.

Short, difficult activities that push your body are called anaerobic activity. Anaerobic activities are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles, such as weightlifting or sprinting. These activities help build muscle strength and improve power and speed.

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Answer:

Explanation:

Explanation:

Characteristics of Force:

Forces are due to an interaction of at least two objects. It may change the state of motion of an object. It may change the shape of an object. Forces applied on an object in the same direction add to one another and the resultant is in the same direction.

Answer:

5scs

Explanation:

phones fall fast so i guessed

Answer:

(a) f' = 878 Hz

(b) f' = 735 Hz

Explanation:

Answer:

i dont know need points

Explanation:

Answer:

newtons per coulomb

Answer:

0.2seconds

Explanation:

Speed=distance/time

15.5m/s=3.00m/x seconds

x=3/15.5

x=0.1935

x=0.2sec

hope this helped

Answer:

1. C

2. True

3. D

4. True

Explanation:

While distance refers to “how much land an object has traversed throughout its journey,” displacement measures “how far an object is out of place.” In this post, let's look at the difference between distance and displacement. Thus, option C is correct.

Displacement and distance are two distinct ideas. The total distance travelled is larger than the displacement between those two points if an object changes direction while travelling.

Distance is the length of any path connecting any two places. Displacement is the straight-line distance between any two points when calculated along the shortest route.

Therefore, The direction is ignored when calculating distance. The direction is accounted for in the displacement calculation.

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Answer:

False

Explanation:

This is because the work is the same so the force won't change

Answer:

Explanation:

KE = ½Iω²

ΚΕ = ½(mL²/3)ω²

ΚΕ = ½(0.63(0.82²)/3)4.2²

ΚΕ = 1.24541928

KE = 1.2 J

Answer:

P = 120,000,000

Explanation:

P = m.v

m = (20,000.1000)= 20,000,000kg

v = 0.6 m/s

p = (20,000,000)(0.6)

p = 120,000,000 kg⋅m/s

Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

From the question,

We are to calculate the power each student would have to climb the flight of stairs.

Power can be calculated using the formula

[tex]P = \frac{F \times d}{t}[/tex]

Where

P is Power

F is the force

d is the distance

and t is the time

NOTE: The weight of the students represent the force

F = 700 N

d = 4 m

t = 6 s

∴ [tex]P = \frac{700 \times 4}{6}[/tex]

P = 467 W

F = 650 N

d = 4 m

t = 6 s

∴ [tex]P = \frac{650 \times 4}{6}[/tex]

P = 433 W

Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

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Newton's laws allow to find the result for the movement of the basketballl:

Newton's laws establish the relationship between the forces on objects:

Let's apply these principles to the ball's motion diagram.

The two vertical forces are in the opposite direction, one is due to the weight of the body and the other is the attraction of the earth to the support of the ball, they are of equal magnitude, not their action-reaction force and reluctant because it is applied to the same body

       In conclusion we can say that the ball is on the ground.

The two horizontal forces are in the opposite direction, the thrust force is greater than the friction therefore using Newton's second law the ball must be accelerating in the direction of the thrust force.

       In conclusion we can say that the ball is accelerating in the direction of the pushing force.

In conclusion using Newton's laws we can find the result for the motion of the basketball:

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The characteristics of the scalar product allows to find the angle between the two vectors is:

The scalar product is the product between two vectors whose result is a scalar.

            A . B = |A|  |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

            i.i = j.j = 1

            i.j = 0

            A . B = (4 i - 4j). * -5 i + 7j)

            A . B = - 4 5 - 4 7

            A. B = -48

We look for the modulus of each vector.

           |A| = [tex]\sqrt{x^2 +y^2 }[/tex]

           |A| = [tex]\sqrt{4^2 + 4^2}[/tex]  

           |A| = 4 √2

          |B| = [tex]\sqrt{5^2 +7^2}[/tex]

          |B| = 8.60

We substitute.

            -48 = 4√2  8.60  cos θ

            -48 = 48.66 cos θ

            θ = cos⁻¹   [tex]\frac{-48}{48.664}[/tex]  

            θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

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Divide total meters by meters per second:

800 m / 18 m/s = 44.4 seconds

Answer: 44.4

Answer:

The answer is 15. Step by step is you times 80 by 65 and then you divided by 2 and you call your teacher

Answer:

whats the question...............

Explanation:

In Physics, energy can be defined as the ability and capacity to do work by an object or physical body.

In Physics, energy can be defined as the ability to do work. Thus, energy must be possessed or transferred to a physical object (body) before it can be used in doing a work or heating a system.

Generally, there are two (2) main types of energy and these are;

For example, you require a sufficient amount of energy to move a crate of egg across a given distance.

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Answer:. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... All forms of energy are associated with motion.

Explanation:. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... All forms of energy are associated with motion.

Let m₁ and m₂ be the masses of the two objects, and v₁ and v₂ their initial velocities. So

m₁ = 30.0 g = 0.0300 kg

m₂ = 13.0 g = 0.0130 kg

v₁ = + 20.5 cm/s = 0.205 m/s

v₂ = + 15.0 cm/s = 0.150 m/s

and we want to find v₁' and v₂', the final velocities of either object after their collision.

Momentum is conserved throughout the objects' collision, so that

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

where v₁' and v₂' are the first and second object's velocities after the collision.

Kinetic energy is also conserved, so that

1/2 m₁v₁² + 1/2 m₂v₂² = 1/2 m₁(v₁')² + 1/2 m₂(v₂')²

or

m₁v₁² + m₂v₂² = m₁(v₁')² + m₂(v₂')²

From the first equation (omitting units), we have

0.0300 • 0.205 + 0.0130 • 0.150 = 0.0300 v₁' + 0.0130 v₂'

0.0810 = 0.0300 v₁' + 0.0130 v₂'

81 = 30 v₁' + 13 v₂'

From the second equation,

0.0300 • 0.205² + 0.0130 • 0.150² = 0.0300 (v₁')² + 0.0130 (v₂')²

0.00155 ≈ 0.0300 (v₁')² + 0.0130 (v₂')²

1.55 ≈ 30 (v₁')² + 13 (v₂')²

Solving both equations simultaneously gives two solutions, one of which corresponds to the initial conditions. The other yields

v₁' ≈ + 0.172 m/s

and

v₂' ≈ + 0.227 m/s

Answer:

False.

Explanation: