The conjugate of (2+i)²/3+i, in the form of a+ib, is
13/2 + i(25/2)
13/10 + i(-15/2)
13/10 +(-9/10)
13/10+(9/10)​

Answers

Answer 1

Given that

(2+i)²/(3+i)

On multiplying both numerator and the denominator with (3-i) then

⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]

⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]

⇛ [(2+i)²(3-i)]/[(3²-i²)

⇛ [(2+i)²(3-i)]/(9-i²)

⇛ [(2+i)²(3-i)]/[9-(-1)]

Since ,i² = -1

⇛ [(2+i)²(3-i)]/(9+1)

⇛ [(2+i)²(3-i)]/10

⇛ [{2²+i²+2(2)(i)}(3-i)]/10

⇛ (4+i²+4i)(3-i)/10

⇛ (4-1+4i)(3-i)/10

⇛ (3+4i)(3-i)/10

⇛ (9-3i+12i-4i²)/10

⇛ (9+9i-4(-1))/10

Since, i² = -1

⇛(9+9i+4)/10

⇛(13+9i)/10

⇛ (13/10)+ i (9/10)

We know that

The conjugate of a+ib is a-ib

So,

The conjugate of (13/10)+ i (9/10) is

(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)

Answer:-The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)

Additional comment:

The conjugate of a+ib is a-ib and i = -1(a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².

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Step-by-step explanation:

a)

p

(

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+

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red marble

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b)

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o

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e

r

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d)

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=

p

(

Blue marbles

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+

p

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even numbers

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p

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blue marbles and even numbers

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p

(

Blue marbles

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=

8

14

p

(

even numbers

)

=

7

14

p

(

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=

8

14

+

7

14

4

14

p

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What is Probability in Math? - Definition & Overview

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Chapter 24 / Lesson 7

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