The graph of g(x) resembles the graph of f(x) = x2, but it has been changed.
Which of these is the equation of g(x)?

The Graph Of G(x) Resembles The Graph Of F(x) = X2, But It Has Been Changed.Which Of These Is The Equation

Answers

Answer 1

Answer:

B. g(x)=x²-3 b is my answer


Related Questions

Write down the name of each of these shapes
A)
B)
C)
D)

Answers

Answer:

a - Right angled triangle

b - Parallelogram

c - Square

d - kite

Step-by-step explanation:

Hope this helps

Goodluck

These are the names of each of these shapes;

1. Right-angled triangle

2. Parallelogram

3. Square

4. kite

What is the right angle triangle?

A right-angled triangle is a triangle, that has one of its interior angles equal to 90 degrees or anyone angle is a right angle.

A parallelogram is a quadrilateral with two pairs of parallel sides.

The opposite sides of a parallelogram are equal in length and the opposite angles are equal in measure.

A square is a four-sided polygon that has all sides equal in length and the measure of the angles is 90 degrees.

A kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides that are adjacent to each other.

These are the names of each of these shapes;

1. Right-angled triangle

2. Parallelogram

3. Square

4. kite

Learn more about parallelogram here;

https://brainly.com/question/12906753

#SPJ2

Ryder is building a workbench.
The top of the workbench is a rectangular piece of plywood that is 6.25 feet long and 1.83 feet wide.

Part A
Round the length and width to the nearest whole number.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6 + 6 + 2 + 2 = 16
B. 6 × 2 = 12
C. 7 + 7 + 2 + 2 = 18
D. 7 × 2 = 14

Part B
Round the length and width to the nearest tenth.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6.2 + 6.2 + 1.8 + 1.8 = 16
B. 6.2 × 1.8 = 11.16
C. 6.3 + 6.3 + 1.8 + 1.8 = 16.2
D. 6.3 × 1.8 = 11.34

Answers

so the ryder is building a workbench and the top of the workbench is a rectangular piece

Drag each pair of rates to the correct location on the table.
Identify the pairs of rates as equivalent or not equivalent.
and and and and and 10 and

PLS PLS PLSS HELP ME OUT

Answers

Answer:

36/6 and 6/1 is equivalent

20/5 and 3/1 is not equivalent

18/3 and 9/1 is not equivalent

35/7 and 5/1 is equivalent

32/4 and 8/1 is equivalent

100/10 and 5/1 is not equivalent.

Step-by-step explanation:

36 divided by 6 is 6.

20 divided by 5 is 4.

18 divided by 3 is 6.

35 divers by 7 is 5.

32 divided by 4 is 8.

100 divided by 10 is 10.

NEED HELP ON THIS ASAP PLZ!!​

Answers

Tan=opp/adj

Tan37=opp/13

X=13tan37

Answer:

x = 9.7

Step-by-step explanation:

tan θ = opposite side / adjacent side

tan 37° = x / 13

multiply 13 on each side

13 × tan 37° = 13 × x /13

13 × tan 37° = x

Rewrite

x = 13 × tan 37°

multiply, we get

x = 13 × 0.75355..

x = 9.79620265

Round nearest tenth = 9.7

Please help.

60
41
49
30

Answers

Answer: [tex]30^{\circ}[/tex]

Step-by-step explanation:

[tex]\cos x=\frac{13}{15}\\\\x=\cos^{-1} \left(\frac{13}{15} \right)\\\\x \approx 30^{\circ}[/tex]

Which expression can be used to determine the length of segment ZY?

On a coordinate plane, triangle X Y Z has points (3, 1), (3, 4), (negative 5, 1).

Answers

Answer:

The length of segment ZY is of [tex]\sqrt{73}[/tex] units.

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

In this question:

Point Z has coordinates (-5,1)

Pount Y has coordinates (3,4).

The length of segment ZY is the distance between points Z and Y. Thus

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]D = \sqrt{(-5-3)^2+(1-4)^2}[/tex]

[tex]D = \sqrt{8^2+3^2}[/tex]

[tex]D = \sqrt{73}[/tex]

The length of segment ZY is of [tex]\sqrt{73}[/tex] units.

Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

cot x sec4x = cot x + 2 tan x + tan3x





(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x





1 + sec2x sin2x = sec2x





sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x





- tan2x + sec2x = 1

Answers

Answer:

Step-by-step explanation:

1)

[tex]cot x sec^4 x = cotx + 2tanx + tan^3 x[/tex]

[tex]RHS =[/tex]

           [tex]=\frac{cosx}{sinx} + 2 \frac{sinx }{cosx} + \frac{sin^3x }{cos^3x}\\\\[/tex]

          [tex]= \frac{cosx(cos^3x) + 2sinx(sinx \ cos^2x ) + sin^3x(sinx)}{sinx \ cos^3x}\\\\[/tex]        [tex][\ taking LCM \ ][/tex]

         [tex]=\frac{cos^4x + 2sin^2xcos^2x +sin^4x }{sinx cos^3x}[/tex]

         [tex]= \frac{(sin^2 x + cos^2x)^2 }{sin x \ cos^3 x}[/tex]                        [tex][ \ a^4 + 2a^2b^2 + b^4 = (a^2 + b^2 ) ^2 \ ][/tex]

        [tex]= \frac{1}{sinx \ cos^3 x}\\\\= \frac{1 \times cosx}{sinx \times cos^3x \times cosx}[/tex]                    [tex][ \ multiplying\ and \ dividing \ by \ cosx \ ][/tex]

        [tex]= \frac{cosx}{sinx} \times \frac{1}{cos^4x}\\\\=cot x \ sec^4 x[/tex]

        [tex]= LHS[/tex]

2)

[tex]sin x \ ( tanx \ cosx - cotx \ cosx) = 1 - 2cos^2x[/tex]

[tex]LHS =[/tex]

        [tex]=sinx( [ \frac{sinx}{cosx} \times cosx)] - [ \frac{cosx}{sinx}\times cosx] )\\\\= sinx (sinx - \frac{cos^2x}{sinx})\\\\=sin^2x - cos^2 x\\\\=(1 - cos^2x ) -cos^2 x[/tex] [tex][ \ sin^2x = 1 -cos^2 x \ ][/tex]

        [tex]= 1 -cos^2x - cos^2 x \\\\= 1 - 2cos^2x \\\\=RHS[/tex]

3)

[tex]1 + sec^2x \ sin^2x = sec^2 x[/tex]

[tex]LHS =[/tex]

       [tex]= 1 +sec^2x \sin^2x \\\\= 1 + (\frac{1}{cos^2x} \times sin^2x )\\\\= 1 + \frac{sin^2 x}{cos^2x}\\\\= 1 + tan^2x \\\\= sec^2 x\\\\=RHS[/tex]

4)

[tex]\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} = 2 \ cosec x[/tex]

[tex]LHS =[/tex]

[tex]=\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} \\\\= \frac{sinx(1 +cosx)}{(1-cosx)(1+cosx)} + \frac{sinx(1-cox)}{(1+cosx)(1-cosx)}\\\\= \frac{sinx +sinx\ cosx}{(1 - cos^2x)} + \frac{sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{sinx + sinx \ cosx + sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{2sinx}{sin^2x}\\\\=\frac{2}{sinx}\\\\=2 cosec\ x\\\\=RHS[/tex]

5)

[tex]- tan^2 + sec^2 x = 1\\\\[/tex]

        [tex]sin^2 x + cos^2 x = 1\\\\\frac{sin^2x }{cos^2x} + \frac{cos^2x}{cos^x} = \frac{1}{cos^2x}\\\\tan^2x + 1 = sec^2x \\\\1 = sec^2 - tan^2x \\\\-tan^2x + sec^2 x = 1[/tex]                

Amie collects data on the fuel efficiency, in miles per gallon, and the mass, in kilograms, of
several different cars. She creates a scatter plot and determines that the line of the best fit for
the scatter plot has the equation y = 43.28 -0.011x, where y is the fuel efficiency, in miles per
gallon, and x is the mass, in kilograms. Based on this model, which of the following statements
is true?
O For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 0.4 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car increases by about 1.1 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car increases by about 0.4 miles
per gallon

Answers

Answer:

For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.

Step-by-step explanation:

Fuel efficiency after x kg in mass:

y = 43.28 -0.011x

Thus, the slope is of -0.011 per x kg.

Increase of 100:

When x = 100, as the slope is negative, the efficiency will decay by:

-0.011*100 = -1.1

Decay of 1.1 miles per gallon, so the answer is:

For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.

If x = 35°, which two lines can be proven parallel?

a)n and o
b)l and m
c)n and l
d)m and o

Answers

Answer:

a) n and o

Step-by-step explanation:

by the concept of corresponding angles, angles that are equal when a line intersects 2 parallel lines .

l is the line that intersects n and o, and since x = 35, theyre corresponding angles resulting in n and o being parallel

Answer:

a) n and o

Step-by-step explanation:

Corresponding angles

a farmer employs 12 men to harvest his crops.they take 9 boys to do the job.if he had employed 8 men,how ling would it have taken.​

Answers

Answer:

it needs more information

NO LINKS!!!

What is the volume of this solid?​

Answers

220 cubic units.

Answer:

Solution given:

for small cylinder

r=1

and for large cylinder

R=5+1=6

height for both [h]=2

Now

Volume of solid=πR²h-πr²h=πh(R²-r²)

=3.14*2(6²-1²)=219.8 =220 units ³.

Small cylinder is r=1

Large cylinder is R= 5+1 =6

Height (h) =2

Volume of solid,

→ πR²h-πr²h

→ πh(R²-r²)

→ 3.14 × 2(6²-1²)

→ 219.8

→ 220 cubic units

Solve the system of equations Y=-2x+5 and y=x^2+3x+9

Answers

I think

x= -4, -1 and y=13, 8

(-4, 13) and (-1, 8)

Simplify the following expression.

29.718 - 29.63

Answers

Answer:

0.088 is the answer...

Find the center and foci of the ellipse:
16x2 + 25y2 – 64x – 50y - 311 = 0

Answers

Answer:

You should first make sure you explain what exactly is the question, before delete others answers.‍♀️‍♀️

Step-by-step explanation:

a musician believes that listening to classical music affects mood determine if two-tailed or one-tailed​

Answers

Answer:

I think one tailed correct me if im wrong

Can someone please help ASAP!!

Answers

Step-by-step explanation:

you need to find:

uw:

uv:

vw= 8(already known)

Measure of W= 35

Measure of u= 90

measure of v= 180-90+35= 55

finding uv:

sin(35)= uv/8

0.57=uv/8

4.56=uv

finding uw:

sin(55)= uw/8

0.82= uw/8

6.56= uw

Help me plsssssssssss

Answers

the answer is B :)) (second one)

I am trying to graph y=2x-7

Answers

Step-by-step explanation:

The given equation is :

y = 2x-7

We will first find the points,

x  0 , , 3.5, 1 , 2 , 3

y -7 , 0, -5, -3, -1

The graph of the above equation is as follows :

It is a linear equation.

ASAP PLZ PLZ PLZ PLZZZZZZ

Answers

Answer:x=( y-p-mq)/m

Step-by-step explanation:

y-p=m(x-q)

x-q= y-p/m

x=y-p/m=q= y-p+mq/m

x= y-p+mq/m

Igor is in high school and got a part time job with every paycheck he has decide 10%will go to short term savings 20%to long term savings and the rest he will use for his current expenses and spending .

Answers

What is his salary amount?

what is the common difference of the following sequence? 4.3,5,7,9,11___
5.16,19,22,25__​

Answers

Answer:

Step-by-step explanation:

4). Given sequence → 3, 5, 7, 9, 11........

    Common difference of an arithmetic sequence is defined by,

    Common difference = Successive term - previous term

                                       = 2nd term - 1st term

                                       = 5 - 3

                                       = 2

5). Given sequence → 16, 19, 22, 25........

    Common difference of an arithmetic sequence = Second term - first term

                                                                                    = 19 - 16

                                                                                     = 3

help me :) which this question plzzzz !!

Answers

I believe its <ABF =<EDJ

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

Answers

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].

Now we will solve this expression with the help of law of exponents.

[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]

           [tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]

           [tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]

           [tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]

           [tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]

                [tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]

                [tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]

               [tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

r − ns × 12


for n = 2, r = 9, and s = 3.

Answers

Answer:

-63

Step-by-step explanation:

9 - (2×3) × 12

9 - (6 × 12)

9 - 72

= -63

Answer:

-63

Step-by-step explanation:

r − ns × 12

Let n = 2, r = 9, and s = 3

9 - (2)*3 * 12

Multiply first

9 - 72

-63

Assume the sample is a random sample from a distribution that is reasonably normally distributed and we are doing inference for a sample mean. Find endpoints of a t-distribution with 0.005 beyond them in each tail if the sample has size n

Answers

Answer:

The correct answer is "2.660".

Step-by-step explanation:

Given that,

Sample size,

n = 61

t-distribution with,

t = 0.005

Now,

The degree of freedom will be:

= [tex]n-1[/tex]

= [tex]61-1[/tex]

= [tex]60[/tex]

hence,

⇒ [tex]t,df=t_{0.005}, 60[/tex]

           [tex]=2.660[/tex]

Geometry help pls and thank you :)


What is the area of this triangle?



Enter your answer in the box.

(answer) units²

Answers

Answer:

12

Step-by-step explanation:

bh/2

base is 8

height is 3

24/2

12

Answer:

12

Step-by-step explanation:

The formula to find the area of a triangle is the following,

[tex]A=\frac{b*h}{2}[/tex]

Where (b) and (h) are the base and height of the triangle. In this situation, one can see that the base (CB) equals (8) units. One can attain this number by counting the boxes between point (C) and point (B). The height is (3). This number is the distance from the point (A) to the side (CB). Substitute these values into the formula and solve for the area.

[tex]A=\frac{b*h}{2}[/tex]

Substitute,

[tex]A=\frac{8*3}{2}[/tex]

Simplify,

[tex]A=\frac{8*3}{2}\\\\A=\frac{24}{2}\\\\A=12[/tex]

Demonstrate 528 divide by 4 using 10 blocks and the scaffolding method

Answers

534 -238
63838-36383
Answer 5

3x+2y=4 and -2x+2y=24

Answers

Answer:

1x= 28

y= v7vub8b9nf7v6v

Describe the shape that would result from a horizontal slice of the figure below.
PLEASE ANSWER FAST ILL MARK BRAINLEIST.!!!

Answers

Answer:

A triangular prism and a trapezoidal prism, if I understand the question

Step-by-step explanation:

There wound be a trapezoid and a triangle if you cut it horizontally. If you mean vertically, it would be a right triangular prism

(PLEASE HELP I JUST WANNA KNOW HOW TO DO IT WILL GIVE REWARDS.) Show all work to solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.

square root of the quantity x minus 2 end quantity plus 8 equals x

Answers

Hope my answer helps uh ✌️

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