The manager of an amusement park is setting the price of a wookend admission to the
park based on a summer membership of $78. Sho wants the summer membership to bo
$12 loss than 3 times the cost of a wookend pass to the park. Which equation can the
amusement park manager use to find, x, the cost of the wookend admission?


I NEED THIS ANSWER RNN
PLEASEEEEEE 30 points 30 points 30 points

Answer:

the answer of this question is......

I think 134

but I can't explain that

I'm so sorry

:-/

Answer:

141

Step-by-step explanation:

This is a seven-sided pentagon. We can find the total sum of all the angles in the pentagon first.

Sum of angles in a pentagon = (7-2) × 180

                                                = 5 × 180

                                                = 900

∠B = 900 - 148 - 90 - 142 - 130 - 129 - 120

     = 141

Remember:

Formula of sum of angles in pentagon = (n-2) × 180 where n is the number of sides the pentagon has. Hope this helps :)

Answer:

dy/dx

= d/dx [2x² + 5x - 3]

= 4x + 5.

Hence at x = 1, dy/dx = 4(1) + 5 = 9.

The slope of the tangent is 9.

d/dx (3/x)

= d/dx (3x^-1)

= 3 * d/dx (x^-1)

= 3 * [-1 * x^(-2)]

= -3/x².

Answer:

This was on my test

Step-by-step explanation:

lol

Answer:

-1/3

Step-by-step explanation: it goes downwards from left to right so it is a negative and to reach the next line below it, it went to the right 3 units.

Therefore it is -1/3 :)

Answer:

Step-by-step explanation:

Given: i. AB||DE

          ii. AC≅DC

Prove: ΔABC≅ΔDEC

From the two triangles, it can be observed that;

m<BAC≅m<EDC (alternate angles)

m<ABC≅m<DEC (alternate angles)

m<BCA≅m<ECD (vertically opposite angles)

m<BAC + m<ABC + m<BCA = m<EDC + m<DEC + m<ECD = [tex]180^{o}[/tex] (sum of angles in a triangle)

Since the three angles of the triangles are congruent respectively, then;

ΔABC≅ΔDEC (AAA congruence property)

Answer:

78

Step-by-step explanation:

[tex]\bold{\sqrt{a-b+c}=3 }[/tex]

[tex]\bold{(\sqrt{a-b+c)}^2=3^2 }[/tex]

[tex]\bold{ a-b+c=9 }[/tex]

[tex]\bold{ a=9+b-c }[/tex]

Answer:

the first step in solving an equation with a variable on each sides is to get the variable on one side. This is done by reversing the addition or subtraction of one of the terms with the variable.

Step-by-step explanation:

Answer:

The correct answer is,

Answer: I think it is 25.5ft

Answer:

[tex]\mathrm{Domain\:of\:}\:\frac{x-1}{x+3}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<-3\quad \mathrm{or}\quad \:x>-3\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-3\right)\cup \left(-3,\:\infty \:\right)\end{bmatrix}[/tex]

Therefore, the 4th option i.e. (−∞, −3) (−3, ∞) is the correct answer.

Step-by-step explanation:

Given the expression

[tex]f\left(x\right)=\frac{x-1}{x+3}[/tex]

We know that the domain is the set of all the input or argument values for which is the function is real and defined.

From the given expression, we need to make sure the denominator of a rational function can be anything but 0, because 0 would make the function undefined.

Thus, we need to find undefined points such as:

x+3 = 0

x = -3

Therefore, the function domain must be:

x < -3 or x > -3

In other words,

[tex]\mathrm{Domain\:of\:}\:\frac{x-1}{x+3}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<-3\quad \mathrm{or}\quad \:x>-3\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-3\right)\cup \left(-3,\:\infty \:\right)\end{bmatrix}[/tex]

Therefore, the 4th option i.e. (−∞, −3) (−3, ∞) is the correct answer.

Answer:

y = 2x - 3.5

Step-by-step explanation:

2x² + 2y = 4x + 2x² - 7

2y = 4x + 2x² - 7 - 2x²

2y = 4x - 7

y = (4x - 7) / 2

y = 2x - 3.5

2x² + 2y = 4x + 2x² - 7

4x + 2y = 4x + 2x² - 7

4x + 2y = 4x + 4x - 7

4x+2y=8x-7

2y = 4x - 7

Answer:

x equals 3 so multiply 3x3 and it will give you 9 and add that to 6 and you get 15. x equals 3 for the one that equals 5.

Answer:

3x + 16 = 15

3x = 15-16

3x = -1

x = -1/3

Answer:

[tex]0.6x - 0.1x = 7 + 5 \\ 0.5x = 12 \\ x = \frac{12}{0.5} = 24[/tex]

Answer:

[tex]\mathrm{A.\:}x+2y=a[/tex]

Step-by-step explanation:

In standard form [tex]ax+by=c[/tex], any point the line passes through will make the inequality true. We can simply use any point given to find the equation of the line:

We can write the following system of equations from two points from the table:

[tex]\begin{cases}d\cdot3a+e\cdot(-a)=f\cdot a\\d\cdot5a+e\cdot(-2a)=f\cdot a\end{cases}[/tex]

Solving, we get:

For [tex]a \notin 0[/tex],

[tex]d=1,\\e=2,\\f=1[/tex]

Therefore, our equation is:

[tex]dx+ey=fa,\\1x+2y=1a,\\\fbox{$x+2y=a$}[/tex].

Answer:

321%

Step-by-step explanation:

hope I helped Kkkkkkkk

Answer:

The value of x = 65.4°

Step-by-step explanation:

Given

hypotenuse = 12

To determine

The value of ∠x = ?

Using the trigonometric ratio

cos x = adjacent / hypotenuse

here:

substituting adjacent = 5, hypotenuse = 12 in the formula

cos x = adjacent / hypotenuse

cos x = 5 / 12

x = arccos (5/12)

x = 65.4°

Therefore, the value of x = 65.4°

Answer:

The answer is 65.3 to the nearest tenth

Step-by-step explanation:

You'll use the Pythagoras theorem to find the unknown side first

then you'll use the sin rule to solve for x

Answer:

0+2+-4=-2

Step-by-step explanation:

Answer:

the answer is C

Step-by-step explanation:

hope this helps you

.82×23.7=19.434

Answer:

D

Step-by-step explanation:

step 1: Simplify 82/100 to its simplest form to by two to get 41/50

Step 2: multiply 41 by 23.7

41×23.7= 1971.7

Step 3: Divide 1971.7÷50=19.434

to the nearest hundredths =

19.4

Answer:

Ah I see it's the same it's a little more complex but I can do this as well.

But I can't type bcoz it will make it slow

so I'll write for this.ß

Answer:

[tex]k>-3[/tex]

Step-by-step explanation:

We have the equation:

[tex]-3x^2-6x+k=0[/tex]

Where a = -3, b = -6, and c = k.

And we want to determine values of k such that the equation will have real, unequal roots.

In order for a quadratic equation to have real, unequal roots, the discriminant must be a real number greater than 0. Therefore:

[tex]b^2-4ac>0[/tex]

Substitute:

[tex](-6)^2-4(-3)(k)>0[/tex]

Simplify:

[tex]36+12k>0[/tex]

Solve for k:

[tex]12k > -36[/tex]

[tex]k>-3[/tex]

So, for all k greater than -3, our quadratic equation will have two real, unequal roots.

Notes:

If k is equal to -3, then we have two equal roots.

And if k is less than -3, then we have two complex roots.

Answer:

=106

Step-by-step explanation:

PMDAS

First thing you do is the parenthesis

6+4(5)^2

then the exponent

6+4(25)

then multiply

6+100

then add

106

Hope this helps (:

Answer:

150

Step-by-step explanation:

First do what is in the parenthesis:

(2+3)

(6)

Then exponents:

[tex](6)^{2}[/tex]

(36)

Then Multiplication:

4(36)

144

Then Add:

144+6

150

Answer:

240

Step-by-step explanation:

-8(10×-3)

(10×3)=30

30×-8=240

Answer:

[tex]y=-x+15[/tex]

Step-by-step explanation:

Slope-intercept form is written as [tex]y=mx+b[/tex] where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept.

Any line perpendicular to a given line with slope [tex]m[/tex] has a slope of [tex]-\frac{1}{m}[/tex]. Therefore, the slope of a line perpendicular to [tex]y=x+12[/tex] is [tex]-\frac{1}{1}=-1[/tex].

We can now plug the coordinate it passes through into our slope-intercept form equation to solve for the y-intercept:

[tex]3=-1(12)+b,\\b=15[/tex]

Therefore, the equation of the line that is perpendicular to [tex]y=x+12[/tex] and passes through the coordinates [tex](12,3)[/tex] is [tex]\fbox{$y=-x+15$}[/tex].