the shape below has been made up of a football that has been unstitched and laid flat. what is the size of angle x?

Using the empirical rule, approximately 22 data points would be expected to fall within ± 1 standard deviation of the mean from a sample of 32. Therefore, the correct option is option 1.

Using the empirical rule, we need to determine approximately how many data points would fall within ± 1 standard deviation of the mean from a sample of 32.

The empirical rule states that for a normal distribution:

1. Approximately 68% of the data falls within ± 1 standard deviation of the mean.

2. Approximately 95% of the data falls within ± 2 standard deviations of the mean.

3. Approximately 99.7% of the data falls within ± 3 standard deviations of the mean.

Since you asked about ± 1 standard deviation, we will focus on the first point. We have a sample of 32 data points, and we want to know how many of these data points fall within ± 1 standard deviation of the mean.

To find this, we can use the percentage provided by the empirical rule (68%) and multiply it by the total number of data points in the sample (32).

0.68 * 32 = 21.76

Since we cannot have a fraction of a data point, we can round the result to the nearest whole number.

Approximately 22 data points would fall within ± 1 standard deviation of the mean from a sample of 32, according to the empirical rule which corresponds to option 1.

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The domain and range of the graphs shown above include the following:

Domain: [2, ∞]                 Domain: [-∞, ∞]

Range: [1, ∞]                    Range: [-2, ∞]

Domain: [-∞, ∞]                 Domain: [1, ∞]

Range: [-∞, ∞]                   Range: [-∞, 2]

In Mathematics and Geometry, a domain refers to the set of all real numbers (x-values) for which a particular function (equation) is defined.

In Mathematics and Geometry, the horizontal portion of any graph is used to represent all domain values and they are both read and written from smaller to larger numerical values, which simply means from the left of any graph to the right.

By critically observing the graphs shown in the image attached above, we can reasonably and logically deduce the following domain and range for graph 1:

Domain = [2, ∞].

Range = [1, ∞] or y ≥ 1

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Step-by-step explanation:

Equilateral triangle: All sides are equal in length. Isosceles triangle: Two sides are equal in length. Scalene triangle: All sides have different lengths.

(a) The slope of the line is 1021. This means that for each year since 2000, the forest loss increases by an average of 1021 square kilometers per year.

(b) If we measured forest loss in meters per year, we need to convert the units from square kilometers to square meters. Since there are 100 square meters in a square kilometer, the slope would be 1021 x 100 = 102,100. Therefore, the slope would be 102,100 meters per year.

(c) If we measured forest loss in thousands of square kilometers per year, we need to divide the slope by 1000 to convert from square kilometers to thousands of square kilometers. The slope would be 1021/1000 = 1.021. Therefore, the slope would be 1.021 thousands of square kilometers per year, or 1.021 million square kilometers per year.

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The two-way frequency table is:

 | Hip Hop (H) | Pop (P) | Total

Likes Hip Hop (H)     | 110 | 50 | 160

Dislikes Hip Hop (D) | 170 | 80 | 250

Total                          | 280 | 130 | 410

We have,

Based on the survey results, we can organize the data in a two-way table. Let's denote "Hip Hop" as H and "Pop" as P:

          | Hip Hop (H) | Pop (P) | Total

Likes Hip Hop (H)     | 110 | 50 | 160

Dislikes Hip Hop (D) | 170 | 80 | 250

Total                          | 280 | 130 | 410

In the table:

The top row represents the students who like hip-hop music (H).

The bottom row represents the students who dislike hip-hop music (D).

The left column represents the students who like pop music (P).

The right column represents the students who dislike pop music.

The total count for each category is given in the "Total" row and column.

The marginal frequencies (totals) are as follows:

Total students who like hip-hop music (H): 280

Total students who dislike hip-hop music (D): 130

Total students who like pop music (P): 160

Total students who dislike pop music: 250

Overall total students surveyed: 410

Thus,

The two-way table is given above.

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Σan represents the sum of terms an in a sequence indexed by n. It is a concise way to express the total sum of the sequence, starting from a specified initial value of n and adding up to a specified final value.

The symbol Σ, pronounced as "sigma," is used to represent the summation notation in mathematics. When we write Σan, it means we are summing up the terms of a sequence (an) starting from a specified initial value of n and continuing up to a specified final value.

To explain further, let's consider an example. Suppose we have a sequence (an) given by a1, a2, a3, ..., an. The summation Σan represents the sum of these terms:

Σan = a1 + a2 + a3 + ... + an.

The value of n can vary depending on the context or the problem at hand. It could be a fixed value, or it could be a variable that ranges over a certain set of values. The notation allows us to express the sum of a potentially infinite number of terms by indicating the pattern of the terms and the range of values for n.

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Main Answer:The GCD of p(x) = x^3 - 6x^2 + 14x - 15 and q(x) = x^3 - 8x^2 + 21x - 18 is d(x) = 2x^2 - 7x + 3, and the corresponding polynomials a(x) and b(x) are a(x) = 1 and b(x) = -1, respectively.

Supporting Question and Answer:

How can we find the greatest common divisor (GCD) of two polynomials and determine the corresponding polynomials that satisfy the Bézout's identity?

To find the GCD of two polynomials and determine the polynomials that satisfy Bézout's identity, we can use the Euclidean algorithm for polynomials. This algorithm involves performing polynomial divisions to obtain remainders until the remainder becomes zero. The last nonzero remainder obtained is the GCD of the two polynomials. The coefficients obtained during the divisions allow us to express the GCD as a linear combination of the original polynomials, satisfying Bézout's identity.

Body of the Solution: To find the greatest common divisor (GCD) of polynomials p(x) and q(x), as well as the polynomials a(x) and b(x) such that a(x)p(x) + b(x)q(x) = d(x), we can use the Euclidean algorithm for polynomials.

Given p(x) = x^3 - 6x^2 + 14x - 15 and q(x) = x^3 - 8x^2 + 21x - 18, we can proceed as follows:

Step 1: Divide p(x) by q(x) to find the remainder.

Dividing p(x) by q(x), we have:

x^3 - 6x^2 + 14x - 15 = (x^3 - 8x^2 + 21x - 18)(1) + (2x^2 - 7x + 3)

Step 2: Set q(x) as the new dividend and the remainder as the new divisor. Now, set q(x) = (x^3 - 8x^2 + 21x - 18) and the remainder (2x^2 - 7x + 3) as the new p(x).

Step 3: Repeat the division until the remainder becomes zero. Continuing the process, we have: x^3 - 8x^2 + 21x - 18 = (2x^2 - 7x + 3)(x - 3) + (0)

Since the remainder is zero, we stop the process.

Step 4: Determine the GCD.The last nonzero remainder obtained in the previous step is the GCD of p(x) and q(x). In this case, it is

d(x) = 2x^2 - 7x + 3.

Step 5: Find the polynomials a(x) and b(x). To find a(x) and b(x), we work backwards using the equations obtained during the divisions: From the first division:

2x^2 - 7x + 3 = p(x) - (x^3 - 8x^2 + 21x - 18)(1)

Rearranging the terms, we have:

p(x) - q(x)(1) = 2x^2 - 7x + 3

Therefore, a(x) = 1 and b(x) = -1.

Final Answer:Hence, a(x) = 1 and b(x) = -1.

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The GCD of p(x) = x^3 - 6x^2 + 14x - 15 and q(x) = x^3 - 8x^2 + 21x - 18 is d(x) = 2x^2 - 7x + 3, and the corresponding polynomials a(x) and b(x) are a(x) = 1 and b(x) = -1, respectively.

Supporting Question and Answer:

How can we find the greatest common divisor (GCD) of two polynomials and determine the corresponding polynomials that satisfy the Bézout's identity?

To find the GCD of two polynomials and determine the polynomials that satisfy Bézout's identity, we can use the Euclidean algorithm for polynomials. This algorithm involves performing polynomial divisions to obtain remainders until the remainder becomes zero. The last nonzero remainder obtained is the GCD of the two polynomials. The coefficients obtained during the divisions allow us to express the GCD as a linear combination of the original polynomials, satisfying Bézout's identity.

Body of the Solution: To find the greatest common divisor (GCD) of polynomials p(x) and q(x), as well as the polynomials a(x) and b(x) such that a(x)p(x) + b(x)q(x) = d(x), we can use the Euclidean algorithm for polynomials.

Given p(x) = x^3 - 6x^2 + 14x - 15 and q(x) = x^3 - 8x^2 + 21x - 18, we can proceed as follows:

Step 1: Divide p(x) by q(x) to find the remainder.

Dividing p(x) by q(x), we have:

x^3 - 6x^2 + 14x - 15 = (x^3 - 8x^2 + 21x - 18)(1) + (2x^2 - 7x + 3)

Step 2: Set q(x) as the new dividend and the remainder as the new divisor. Now, set q(x) = (x^3 - 8x^2 + 21x - 18) and the remainder (2x^2 - 7x + 3) as the new p(x).

Step 3: Repeat the division until the remainder becomes zero. Continuing the process, we have: x^3 - 8x^2 + 21x - 18 = (2x^2 - 7x + 3)(x - 3) + (0)

Since the remainder is zero, we stop the process.

Step 4: Determine the GCD.The last nonzero remainder obtained in the previous step is the GCD of p(x) and q(x). In this case, it is

d(x) = 2x^2 - 7x + 3.

Step 5: Find the polynomials a(x) and b(x). To find a(x) and b(x), we work backwards using the equations obtained during the divisions: From the first division:

2x^2 - 7x + 3 = p(x) - (x^3 - 8x^2 + 21x - 18)(1)

Rearranging the terms, we have:

p(x) - q(x)(1) = 2x^2 - 7x + 3

Therefore, a(x) = 1 and b(x) = -1.

Hence, a(x) = 1 and b(x) = -1.

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Answer:

-1/2, 1/2, -1, -2, 2

Step-by-step explanation:

a_1 = 2

a_2 = -1

a_n+2 = a_n+1/a_n

a_3 = a_2/a_1 = -1/2

a_4 = a_3/a_2 = -1/2 / (-1) = 1/2

a_5 = a_4/a_3 = 1/2 / (-1/2) = -1

a_6 = a_5/a_4 = -1 / (1/2) = -2

a_7 = a_6/a_5 = -2 / (-1) = 2

a_8 = a_7/a_6 = 2/(-2) = -1

a_9 = a_8/a_7 = -1/2

etc.

Check the picture below.

The Balmer series is a set of spectral lines in the visible region of the electromagnetic spectrum that are emitted by excited hydrogen atoms. The theoretical wavelengths of the Balmer series lines can be calculated using the Balmer-Rydberg equation:

1/λ = R_H (1/2² - 1/n²)

where λ is the wavelength of the emitted photon, R_H is the Rydberg constant for hydrogen, and n is an integer representing the energy level of the hydrogen atom.

For the Balmer series, n always starts at 2, so the equation can be simplified to:

1/λ = R_H (1/4 - 1/n²)

The Rydberg constant for hydrogen is given by:

R_H = 1.0974 x 10^7 m^-1

Therefore, the theoretical wavelength of the Balmer series lines can be calculated using the equation:

λ = (1/R_H) * (1/(1/4 - 1/n²))

where n is an integer from 3 to infinity.

In this lab, we can use the Balmer-Rydberg equation to calculate the theoretical wavelength values of the Balmer series lines and compare them to the experimental values obtained from the spectral lines observed in the lab.

The value of R given in the equation you provided is the Rydberg constant for hydrogen, which is equal to 1.0974 x 10^7 m^-1.

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To approximate the surface area of one slipcover for Davea's topiaries, we need more information regarding the shape and dimensions of the topiaries.

To calculate the surface area of a slipcover, we need information about the shape and dimensions of the topiary. Depending on the specific shape, whether it is a cone, cylinder, or other geometric form, the surface area formula will differ. For example, if the topiary is a cone, the surface area formula would involve the radius and slant height of the cone. If it is a cylinder, the surface area formula would involve the radius and height of the cylinder. Without these details, it is impossible to provide an accurate estimate of the surface area of the slipcover. However, in general, the slipcover would cover the entire surface of the topiary, excluding the base, to provide adequate protection against frost.

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The graph of the function f(x)=log5(x) can be stretched vertically by multiplying the output of the function by 8.

This can be represented as 8f(x)=8log5(x). Similarly, the function can be shifted to the right by 4 units by replacing x with x-4, resulting in f(x-4)=log5(x-4). Finally, the function can be shifted up by 2 units by adding 2 to the output of the function, resulting in f(x)+2=log5(x)+2. Combining all of these transformations, we get the new function g(x)=8log5(x-4)+2. This function will have the same basic shape as the original function, but will be vertically stretched, shifted to the right, and shifted up. The horizontal asymptote of the function will still be y=0, and the x-intercept will be at x=1. The vertical asymptote will also be at x=0, but the graph will be shifted to the right by 4 units.

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To find a numerical approximation for P(W - E[W] < 0.01), where W = X1 + ... + X20 - (Y1 + ... + Y20) and Xi, Yi are independent random variables uniformly distributed in the unit interval [0, 1], we can use simulation methods such as Monte Carlo simulation.

Monte Carlo simulation involves generating a large number of random samples and using these samples to estimate probabilities. In this case, we can simulate the random variables Xi and Yi, calculate W for each simulation, and count the number of times W - E[W] is less than 0.01. Dividing this count by the total number of simulations gives us an approximation for P(W - E[W] < 0.01).

To perform the simulation, we generate 20 random numbers from a uniform distribution for each Xi and Yi, calculate W for each simulation by summing the Xi values and subtracting the Yi values, and then compare W - E[W] to 0.01. By repeating this process a large number of times (e.g., 10,000 simulations), we can estimate the probability.

By running the Monte Carlo simulation and calculating the ratio of simulations where W - E[W] < 0.01 to the total number of simulations, we obtain a numerical approximation for P(W - E[W] < 0.01).

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Answer: Logistic regression is a very popular, statistically sound, probability-based classification algorithm that employs supervised learning.

Given that the absolute value of the price elasticity of demand for Good X is 0.5, this indicates that the demand for Good X is inelastic. Now, let's analyze the effect of a 10 percent decrease in the price of Good X.

1. Calculate the percentage change in quantity demanded: Multiply the price elasticity of demand (0.5) by the percentage change in price (-10%).
  0.5 * (-10%) = -5%

2. Since the result is negative, this implies that the quantity demanded will increase by 5% due to the 10% decrease in price. This corresponds to option (b) in your list.

3. To determine the effect on revenues, we'll consider both the price and quantity changes. The price decreased by 10%, and the quantity demanded increased by 5%.

4. Calculate the new revenue: Initial revenue (100%) + price change (-10%) + quantity change (5%) = 95% of the initial revenue.

This means that there will be a 5% increase in revenues from the sale of Good X after the price decrease, which corresponds to option (c) in your list. So, the correct answer is (b) A 5% increase in the quantity demanded of Good X, and (c) A 5% increase in revenues from the sale of Good X.

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The canonical representative of [tex]4^2^4^1[/tex] mod 385 is equal to 4.

To compute the remainders using Fermat's Little Theorem, we need to know that it states: If p is a prime number and a is any integer not divisible by p, then [tex]a^(^p^-^1^)[/tex]≡ 1 (mod p).

Now, let's apply the Chinese Remainder Theorem to find the canonical representative of 4^241 mod 385:

We have the following congruences:

[tex]4^2^4^1[/tex] ≡ 4 (mod 5)

[tex]4^2^4^1[/tex] ≡ 4 (mod 7)

[tex]4^2^4^1[/tex] ≡ 4 (mod 11)

Using the Chinese Remainder Theorem, we can combine these congruences to find the canonical representative modulo 385:

Let x be the canonical representative of [tex]4^2^4^1[/tex] mod 385.

We have:

x ≡ 4 (mod 5)

x ≡ 4 (mod 7)

x ≡ 4 (mod 11)

By solving this system of congruences, we find that x = 4.

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Set the right-hand side equal to zero to obtain the related homogeneous equation:

y'' − y' − 2y = 0

r2 - r - 2 = 0 is the characteristic equation.

The result of factoring this equation is (r - 2)(r + 1) = 0

The roots are therefore r = 2 and r = -1.

The homogeneous equation's general solution is the following:

y_h(t) equals c1*e(2t) plus c2*e(-t).

We need to identify a specific solution in order to discover the nonhomogeneous equation's general solution. The approach of indeterminate coefficients can be used to infer a form for a specific solution. We can speculate on a specific solution of the following kind because the polynomial on the right-hand side of the equation is of degree 2.

At2 + Bt + C = y_p(t)

Taking y_p(t)'s first and second derivatives, we obtain:

y_p'(t) equals 2At + B

y_p''(t) = 2A

When these expressions are substituted into the initial differential equation, we obtain:

-6t + 10t2 = 2A - (2At + B) - 2(At2 + Bt + C)

When we condense and group related terms, we get:

-6t + 10t2 = (-2A)t2 + (-2B-2A)t + (2A-B-2C)t

When like terms' coefficients are equated, we obtain:

-2A = 10, -2B - 2A = -6, 2A - B - 2C = 0

If we solve for A, B, and C, we obtain:

A = -5, B = 4, C = -11/4

The specific solution is thus:

y_p(t) = -5t^2 + 4t - 11/4

As a result, the following is the nonhomogeneous equation's general solution:

c1*e(2t) + c2*e(-t) - 5t2 + 4t - 11/4 are equivalent to y(t) = y_h(t) + y_p(t).

where the initial circumstances define the constants c1 and c2.

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Answer:

geometric

Step-by-step explanation:

1x9=9

9x9=81

Widget Town is now a monopoly. It can raise its prices to earn a larger profit.

The situation described is known as a monopoly, where Widget Town becomes the sole producer of widgets in the market.

As a monopoly, Widget Town can take advantage of its position by raising prices to earn a larger profit. With no competition, customers have limited alternatives and may have to accept higher prices.

However, it's important to note that this can lead to reduced consumer choice and potential negative consequences.

It is not advisable for Widget Town to split into two firms to increase competition, as the situation described explicitly states that it is now the last remaining widget producer.

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The explicit definition of the given geometric sequence is a(n) = 909 (4/3)ⁿ⁻¹.

Given is a geometric sequence,

a(n) = 909, if n = 1

a(n) = 4/3 a(n-1) if n > 1

The explicit formula for a geometric sequence is,

a(n) = a(1) rⁿ⁻¹

Here a(1) is the first term and r is the common ratio.

Here, a(1) = 909

r = a(2) / a(1) = 4/3 × 909 / 909 = 4/3

Explicit formula is,

a(n) = 909 (4/3)ⁿ⁻¹

Hence the required definition is a(n) = 909 (4/3)ⁿ⁻¹.

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The Gaussian random variable using that the probabilities are, (a) P(X > 4) = 0.9332 (b) P(|X| < 22) = 1.0000 (c) P(4 < X < 16) = 0.6827 (d) P(X > 19 | X > 10) = 0.2525 (e) The pdf of Y = (2X + 5) is fY(y) = (1/12√(2π)) * exp(-(y-25)^2 / 288) (f) The value of a such that P(X > 1) = 0.10 is a = 16.83.

(a) To find P(X > 4), we standardize the value and use the z-table to find the corresponding probability. P(X > 4) is equivalent to P(Z > (4 - 10)/6) = P(Z > -1) = 0.9332.

(b) P(|X| < 22) represents the probability that the absolute value of X is less than 22. Since the standard deviation of X is 6, this probability is equal to 1.0000 since the range [-22, 22] is much wider than the range covered by X.

(c) To find P(4 < X < 16), we standardize the values and calculate the area under the curve between the corresponding z-scores. P(4 < X < 16) is equivalent to P((-6/6) < Z < (6/6)) = P(-1 < Z < 1) = 0.6827.

(d) P(X > 19 | X > 10) represents the probability that X is greater than 19, given that X is already greater than 10. This is equivalent to P(X > 19) / P(X > 10). We calculate P(X > 19) using the z-score and find P(X > 19) = P(Z > (19 - 10)/6) = P(Z > 1.5) = 0.0668. P(X > 10) can be calculated similarly as P(Z > 0) = 0.5. Therefore, P(X > 19 | X > 10) = 0.0668 / 0.5 = 0.2525.

(e) To find the pdf of Y = (2X + 5), we can use the transformation technique. We substitute y = (2x + 5) into the pdf of X, and perform the necessary calculations to obtain the pdf of Y: fY(y) = (1/12√(2π)) * exp(-(y-25)^2 / 288).

(f) To find the value of a such that P(X > 1) = 0.10, we can use the standardization process. P(X > 1) is equivalent to P(Z > (1 - 10)/6) = P(Z > -1.5). Using the z-table, we find that P(Z > -1.5) = 0.9332. To obtain a probability of 0.10, we need to find the z-score that corresponds to P(Z > z) = 0.10. From the z-table, this z-score is approximately -1.28. We can then solve for a using the standardization formula: (a - 10)/6 = -1.28. Solving for a gives a ≈ 16.83.

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When a class interval is expressed as 100 up to 200, it means that the data is grouped into intervals or ranges, and the first interval starts at 100 while the last interval ends at 200.

When dealing with large sets of data, it is often more convenient to group the data into intervals or classes. Each interval is a range of values, and the frequency of data falling within that range is recorded. The class interval "100 up to 200" means that the first interval starts at 100, and the range continues up to but does not include 200.

This means that the first interval will include all values greater than or equal to 100 and less than 200. The exact size of the interval (i.e., the width) is not specified in this expression, so it could be any value that covers the range between 100 and 200.

For example, the interval could be 100-199, 100-199.99, or any other width that covers the specified range.

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The average number of repairmen present at any given time in the auto shop can be calculated using Little's Law, which states that the average number of entities in a system is equal to the average arrival rate multiplied by the average time spent in the system. In this case, the average arrival rate is 10 cars per day, and the average time spent in the system (technician working on a car) is 7 days. Therefore, the average number of repairmen present at any given time is:

Average number of repairmen = Average arrival rate * Average time spent = 10 cars/day * 7 days = 70 repairmen

The state space diagram of the Continuous-Time Markov Chain (CTMC) for this scenario can be represented as follows:

State 0: No cars in the system

State 1: 1 car being repaired

State 2: 2 cars being repaired

...

State 80: 80 cars being repaired (maximum capacity)

The transitions between states are determined by the arrivals and departures of cars. Each arrival increases the state by 1, and each departure decreases the state by 1.

The probability that the car shop has to turn away customers due to the lack of repairmen available can be determined by calculating the probability of the system being at the maximum capacity (80 cars being repaired). This can be calculated using the formula for the steady-state probability distribution of a CTMC. Without further information about the arrival and departure rates, it is not possible to provide an exact probability.

To ensure that the probability of turning away customers is less than 1%, the auto shop would need to recruit enough repairmen to increase the maximum capacity of the system. This would depend on the arrival and departure rates, and a detailed analysis would be required to determine the exact number of repairmen needed.

If the turned away cars are kept on a waiting list instead of being rejected, the waiting time for a car to be repaired would depend on the number of cars in the system and the rate at which repairs are completed. To ensure that the waiting time for a car is less than 2 days, the auto shop would need to recruit enough repairmen to reduce the average time spent in the system to less than 2 days. The exact number of repairmen required would depend on the arrival rate of cars and the rate at which repairs are completed, and a detailed analysis would be necessary to determine the specific number.

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Answer:

a)40°

b)25°

c)50°

d)82°

e)137°

Step-by-step explanation:

angles in triangles always add to 180°

if there is a square in the triangle this means the angle is 90°

a)180°-80°-60°=40°

b)180°-75°-80°=25°

c)180°-40°-90°=50°

d)180°-51°-47°=82°

e)180°-18°-25°=137°

If events A and B are mutually exclusive with probabilities P(A) = 0.4 and P(B) = 0.5, respectively, then the probability of their intersection, P(A ∩ B), is equal to zero.

If events A and B are mutually exclusive, it means that they cannot occur simultaneously. In other words, if event A happens, event B cannot happen, and vice versa. Mathematically, this can be represented as:

P(A ∩ B) = 0

The probability of the intersection of mutually exclusive events is always zero because there is no overlap between the events.

In the given scenario, the probability of event A is 0.4 (P(A) = 0.4) and the probability of event B is 0.5 (P(B) = 0.5). Since events A and B are mutually exclusive, we know that P(A ∩ B) = 0.

Therefore, the probability of the intersection of events A and B, denoted as P(A ∩ B), is equal to zero.

This result makes sense intuitively because if two events are mutually exclusive, they cannot occur at the same time. So the probability of both events happening together is zero.

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The circle has a radius of 4 units.

Let the circle's radius be $r$ and its centre be $(a,b)$.

The circle's centre must be on the line $x=a$ that passes through $(0,2)$ perpendicular to the $y$-axis since the circle is tangent to the $y$-axis at $(0,2)$.

We may formulate an equation involving the distance between $(8,0)$ and $(a,b)$, which is equal to the radius $r$, because the circle passes through $(8,0)$. The distance formula gives us:

$\sqrt{(a-8)^2+b^2}=r$

We know that $a$ is the distance between the centre and the $y$-axis, which is equal to the radius $r$, because the centre is on the line $x=a$.

As a result, we have:

$a=r$

This can be used to solve the previous equation for:

$\sqrt{(r-8)^2+b^2}=r$

Squaring both sides of the equation, we get:

$(r-8)^2+b^2=r^2$

Simplifying, we get:

$r^2-16r+64+b^2=r^2$

$b^2=16r-64$

Since $(0,2)$ lies on the circle, we have:

$(0-a)^2+(2-b)^2=r^2$

Substituting $a=r$ and simplifying, we get:

$r^2-4r+4+b^2=r^2$

$b^2=4r-4$

Now we have two equations involving $r$ and $b^2$, which we can solve simultaneously. Substituting $b^2=16r-64$ from the first equation into the second equation, we get:

$16r-64=4r-4$

Solving for $r$, we get:

$r=4$

Therefore, we know radius of this circle will be 4 units.

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The equation y = 30 - 2.5x best models the relationship shown in the following scatterplot: C. scatterplot C.

In Mathematics and Statistics, there are different characteristics that are used for determining the line of best fit on a scatter plot and these include the following:

By critically observing the scatter plots using the aforementioned characteristics, we can reasonably infer and logically deduce that scatterplot C best models the relationship given by y = 30 - 2.5x because the data points would be equally divided on both sides of the line with a negative slope of -2.5 and a y-intercept of 30.

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Answer:

-13

Step-by-step explanation:

(9 - 15 + 12 - 19)

= 9 - 15 + 12 - 19

= -6 + 12 - 19

= 6 - 19

= -13

Answer:

4 yards

Step-by-step explanation:

The volume of a rectangular prism is length*width*height.

Let's set the missing height as "x".

Then, we find this equation:9*10*x=360

90x=360

x=4

Therefore, the height of this rectangular prism is 4 yards.

Feel free to tell me if I did anything wrong! :)

The statements that must be true about the figure are

AB is bisected by EF,CD is bisected by AB, AE = 1/2 AB, EF = 1/2 ED,

FD = EB.

AB is bisected by EF: This statement is true because point E is the midpoint of AB, meaning it divides AB into two equal parts, and EF is a line connecting the midpoints of the sides. Therefore, EF bisects AB.

CD is bisected by AB: This statement is also true because point F is the midpoint of CD, meaning it divides CD into two equal parts, and AB is a line connecting the midpoints of the sides. Therefore, AB bisects CD.

AE = 1/2 AB: This statement is true because E is the midpoint of AB, which means AE and EB are equal in length. Since E is the midpoint, AE is half the length of AB.

EF = 1/2 ED: This statement is true because F is the midpoint of CD, and EF is a line connecting the midpoints of the sides. Therefore, EF is half the length of CD, and ED is twice the length of EF.

FD = EB: This statement is true because F is the midpoint of CD, meaning FD and EB are equal in length.

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