Answer:
Ms French
Explanation:
1km is equal to 1000m so ms French biked further
Base your answers to questions 1 and 2 on
the diagram below, which represents a solid material
of uniform composition.
2.0 cm
Density = 2.7 g/cm³
-3.0 cm-
A) 32 g
4.4 g
L
2.0 cm-
W₂
1. The mass of this piece of material is approximately
B 0.23 g
9.3 g
Answer:
A. 32 g
Explanation:
Density = 2.7 g/cm3
Volume = 2 x 2 x 3 = 12 cm3
Mass = dV = 2.7 x 12 = 32.4 g or 32 g
Imagine that you have set up a genetic screen to identify e. Coli mutants that cannot metabolize the amino acid tryptophan for energy. Beginning with a master plate containing many colonies, you prepare replica plates on medium with glucose or tryptophan as the only energy source. You would look for colonies that _____.
Replica plates on medium with glucose or tryptophan as the only energy source. You would look for colonies that can grow only on the plates with glucose
How does the termination of transcription in E. coli relate to RNA hairpin turns?The turns, which separate the RNA transcript from the transcription bubble, are created by complementary base pairing. Genes that are constitutively expressed, or "housekeeping" genes, have the highest frequency of GbM, while genes with the most variable expression have the lowest frequency.
What transpires when an mRNA hairpin loop forms?During transcription, the mRNA strand develops a hairpin loop that separates the RNA polymerase from the DNA template strand. The sequences involved in this process are referred to as terminator sequences, and the process is known as rho-independent or intrinsic termination.
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A compound containing only c, h, and o, was extracted from the bark of the sassafras tree. the combustion of 72.3 mg produced 196 mg of co2 and 40.2 mg of h2o. the molar mass of the compound was 162 g/mol. determine its empirical and molecular formulas
The Empirical formula of the compound is C₅H₅O.
and molecular formula of the compound is C₁₀H₁₀O₂.
mass of C in the compound = (196g CO2)x (12.0 g C/44.0 g CO2) = 53.45g C
mass of H in compound = (40.2 g H2O) x (2.0 g H /18.0 g H2O) = 4.46 g H
mass of O in compound = 72.3 g total - 53.45 g C - 4.46 g H = 14.39 g O
now convert mass of each element to moles
53.45 g C x (1 mole C/12.0 g C) = 4.45 moles C
4.46 g H x (1 mole H/1.0 g H) = 4.46 moles H
14.39 O x (1 mole O/16.0 g O) = 0.899 moles O
Divide each by 0.899 to get C₅H₅O, which has a mass of 81 g
double that to get C₁₀H₁₀O₂ with mass of 162 g.
This is a "classic" example of a combustion analysis problem.
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A lava flow high in silicon is likely to flow?
High silica content lava flow is thick and viscous and does not flow easily.
Though lava rises upwards toward the surface, it is too thick to pass through the Earth's fissures and crevices. Pressure is increasing as the lava continues to surge upward.
Which lava contains more silica?The least dangerous process involved in volcanic eruptions is lava flow. The temperature, silica content, extrusion rate, and slope of the terrain are all factors that affect how far a lava flow travels. A lava flow with a high silica content or one that is chilly will not move very far. Such a flow would be extremely viscous (a high resistance to flow). Low silica content is characteristic of basalt flows like those in Hawaii, OR long-distance flow, and low viscosities.
A MAGMA COMPOSITION AND TYPES OF ROCK
There are various varieties of magmas, ranging from mafic magmas, which have high Fe and Mg contents and relatively little silica, to felsic magmas, which have low Fe and Mg contents and relatively high silica.
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A chargers particle is know as a
Answer:
A charged particle is called an ion.
A charged particle is called an ion.
Any atom or group of atoms that bears one or more positive charge is called cation and one or more negative charge is called anion.
A compound contains 19.3% Na, 26.9% S, and 53.8% O. its formula mass is 238g. what
The empirical formula of the compound, given it contains 19.3% Na, 26.9% S, and 53.8% O is NaSO₄
How to determine empirical formulaThe following paameters were obtained from the question:
Sodium (Na) = 19.3%Sulphur (S) = 26.9%Oxygen (O) = 53.8%Empirical formula =?The empirical formula of the compound can be obtained as follow:
Divide by their molar mass
Na = 19.3 / 23 = 0.839
S = 26.9 / 32 = 0.840
O = 53.8 / 16 = 3.3625
Divide by the smallest
Na = 0.839 / 0.839 = 1
S = 0.840 / 0.839 = 1
O = 3.3625 / 0.839 = 4
Thus, the empirical formula of the compound is NaSO₄
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Complete question:
A compound is 19.3% Na, 26.9% S, and 53.8% O. Its formula mass is 238 g/mol. What is the empirical formula? Show your work in a neat and logical manner.
1. The process occurring in the mantle that is thought to be the force behind plate
tectonics is an example of a(n)
a. Plate Boundary
b. Divergent Boundary
c. Normal Fault
d. Convection Current
Answer:
D
Explanation:
The heating, rising, cooling, and sinking cycles are called convection currents. 2. A version of this same process, occurring in the mantle, is thought to be the force behind plate tectonics. ... Scientists suggest that differences in density cause the hot, plastic-like rock to be forced upward toward the surface.
Electrons have a ___________ charge and are found in the area of an atom called _________ _____________.
Answer:
Electrons have a negative charge and are found in the area of an atom called Outer Shell
Electrons have a negative charge and are found in the area of an atom called electron shells.
how does temperature differ from thermal energy
How do plants recycle hydrogen during cellular respiration?(1 point) Responses The hydrogen in water is recycled as glucose. The hydrogen in water is recycled as glucose. The hydrogen in glucose is recycled as hydrogen gas. The hydrogen in glucose is recycled as hydrogen gas. The hydrogen in glucose is recycled as water. The hydrogen in glucose is recycled as water. The hydrogen in hydrogen gas is recycled as glucose. The hydrogen in hydrogen gas is recycled as glucose.
Plants recycle hydrogen during cellular respiration, as the hydrogen in glucose is recycled as water. The correct option is d.
What is cellular respiration?Food molecules are broken down into energy, water, and carbon dioxide during cellular respiration. In the presence of oxygen, cells respire. Multiple chemical cycles are involved in cell respiration.
In plants, cellular respiration occurs but in a minimum amount, and in this process the hydrogen in combines with oxygen and forms water.
Therefore, the correct option is d. The hydrogen in glucose is recycled as hydrogen gas.
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Answer: Plants recycle hydrogen during cellular respiration, as the hydrogen in glucose is recycled as water. The correct option is d.
Explanation: What is cellular respiration?
Food molecules are broken down into energy, water, and carbon dioxide during cellular respiration. In the presence of oxygen, cells respire. Multiple chemical cycles are involved in cell respiration.
In plants, cellular respiration occurs but in a minimum amount, and in this process the hydrogen in combines with oxygen and forms water.
Therefore, the correct option is d. The hydrogen in glucose is recycled as hydrogen gas.
In an experiment, a solution required 30. 05 g of nacl, 50. 0 g of , and 0. 4006 g of mgso4. Using the correct number of significant figures, what is the resulting mass?.
Using significant figures and rounding up, the resulting mass is 80.5 g.
When using addition or subtraction, the total number of significant figures is relevant. Instead, the last significant figure of every number is considered.
In 30.05, the last significant figure is 5, and it is in the hundredths. In 50.0, the last significant figure is 0, and it is in the tenths. Finally, in 0.4006, the last significant figure is 6, and it is in the ten thousandths. Of the three, the 0 from 50.0 is in the "highest" position, and so the last significant figure of the results should also be in the tenths.
If we add the numbers up, we get:
30.05 g + 50.0 g + 0.4006 = 80.4506 g
Because the last significant figure should be in the tenths, we are going to round up 4 to 5, because trailing numbers are greater than 0, so the final mass will be 80.5 g.
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Imagine that a researcher has developed a way to isolate thylakoids from chloroplasts and to make the ph of the thylakoid space acidic. If these isolated thylakoids are transferred to a ph8 solution in the dark, what might the researcher expect to observe?.
In the given condition where the thylakoids are isolated from the chloroplasts to make the pH of the thylakoid space acidic, the isolated thylakoid will form the ATP.
ATP is also referred to as Adenosine Triphosphate and is correctly called as the energy currency of the cell as it is responsible molecule for carrying the energy units in the cell. When the isolated thylakoids are made to transfer in the pH = 8 basic solution, then the acidic lumen of the chloroplast will be having a higher concentration of H⁺ ions. When they are placed in the basic solution then the H⁺ ions will move out because of the occurrence of concentration gradient which is higher in the lumen than the surrounding. The chloroplasts will now bear synthesis of ATP. Therefore, the isolated thylakoid is able to make ATP when the lumen is acidic, and the surroundings are made basic in nature.
Thus, the thylakoid which is isolated will bear the synthesis of ATP.
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364 Cal to kilowatt-hours
Express your answer using three significant figures.
Answer:
the answer is 0,000423
Explanation:
according to 3SF
A 118.0 g sample of a compound contains 72.0 g of C. 18.0 g of H, and 28.0 g of N.
Which of the following is the empirical formula of the compound?
The empirical formula of a sample of a compound that contains 72.0 g of C. 18.0 g of H, and 28.0 g of N is C₃H₉N.
How to calculate empirical formula?Empirical formula is the notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.
The empirical formula of a compound can be calculated as follows:
C = 72.0g
H = 18.0g
N = 28.0g
Next, we divide by the atomic mass of each element as follows:
C = 72.0g ÷ 12 = 6molH = 18.0g ÷ 1 = 18 molN = 28.0g ÷ 14 = 2molNext, we divide by the smallest mole as follows:
C = 6mol ÷ 2 = 3H = 18 mol ÷ 2 = 9N = 2mol ÷ 2 = 1The empirical ratio is 3:9:1, hence, the empirical formula of the compound is C₃H₉N.
The options to the incomplete question are as follows:
CH₄NC₃H₉NC₄H₉N₂C₅H₅NLearn more empirical formula at: https://brainly.com/question/14044066
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here are three main types of chemical reactions: precipitation, acid-base and oxidation- reduction. classify each of the following as precipitation, acid-base or oxidation-reduction.
Precipitation is any liquid or frozen water that forms in the atmosphere and falls back to the Earth.
Acid–base reaction, a type of chemical process typified by the exchange of one or more hydrogen ions, H+, between species that may be neutral
An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species.
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polypropylene has a density of 0.90 g/cm3. explain why 4 different-sized cylinders made out of this material would not be able to be used in this experiment (following the exact procedure you did) to find the density of the material
Polypropylene is considered as safe for use. The chemicals found in plastic products are proven to contribute to some cancers.
What drawbacks does polypropylene have?Its usage in high temperature applications is constrained by its high thermal expansion coefficient.
Heavily resistant to both aromatic and chlorinated solvents. It is vulnerable to UV damage.
It is well known for being challenging to paint because of its low bonding capabilities.
It is highly flammable.
Which applications of polypropylene are common?Plastic containers, component parts for machinery and equipment, and even fibers and textiles are only a few applications for polypropylene.
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Explain what happens to cloud mist as the number of "dry days” increases.
The cloud mist as the number of "dry days” increases and fewer precipitation events contributing to the annual total of cloud mist or the dry days has been increased.
What is the main procedure of formation of cyclones?The main procedure of formation of cyclones is that when hot moist air flows at the upper surface of the ocean it tries to move in upward direction due to which less amount of air is left at the surface of ocean and hence a lower air pressure is created in this area.
Surrounding air which is at higher air pressure try to push the low pressure air which rises the temperature of low pressure air and again this air moves upward leaving behind less air at the surface of the ocean.
When this high temperature and moist air moves in the upward direction it temperature decreases due to which clouds are formed . This combination of clouds and wind continuously grows and started spinning. When this combination of wind and clouds spin fast, that time an eye is formed at the center. At this center very low air pressure is there and air with high pressure flows down into this center.
Therefore, The cloud mist as the number of "dry days” increases and fewer precipitation events contributing to the annual total of cloud mist or the dry days has been increased.
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in the bohr model of the hydrogen atom, an electron in the lowest energy state follows a circular path at a distance of 5.29 ✕ 10−11 m from the proton. (a) show that the speed of the electron is 2.19 ✕ 106 m/s. (submit a file with a maximum size of 1 mb.)
According to the Bohr model, electrons orbit the nucleus at constant energies then the speed of the electron is I = 1.05 mA.
What is meant by Bohr model?The Bohr model, also known as the Rutherford-Bohr model, was first proposed by Niels Bohr and Ernest Rutherford in 1913 and describes an atomic system with an orbiting system of electrons and a small, dense nucleus that is similar to the Solar System in structure but is attracted by electrostatic forces rather than gravity.
Speed of electron = v = 2.19 × 1[tex]$$0^6[/tex] m/s
Radius of circular path = [tex]$\gamma[/tex] = 5.29 × 1[tex]0^{11}[/tex] m
The period of electron Pn its orbits is,
T = 2π[tex]\gamma[/tex] / V
To find the current represented by the orbiting electron
I (ΔQ/Δf) = |e|/T = |e|V /2πr
substitute the value in the above equation, we get
[tex]$I=\frac{\left(2.19 \times 10^6\right)\left(1.60 \times 10^{-19}\right)}{2(8.14)\left(5.29 \times 10^{-11}\right)} \\[/tex]
simplifying the equation, we get
I = 1.75 × 10-³ C/s
I = 1.05 mA
Therefore, the speed of the electron is I = 1.05 mA.
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In the first reaction of the citric acid cycle, oxaloacetate, which contains blank______ carbons, is combined with acetyl-coa, which contains blank______ carbons in its acetyl group, to produce citric acid, which contains blank______ carbons.
Citric acid, which has 6 carbons, is created by combining oxaloacetate, which has 4 carbons, with acetyl-CoA, which has 2 carbons in its acetyl group.
What is citric acid cycle and how it works?Citric acid cycle also called as TCA cycle , which starts with the condensation of acetyl group with oxaloacetic acid( OAA).Citrate synthase is an enzyme which catalyses the initial reaction of TCA cycle .Then the third step is isomerization which isomerizes citrate to isocitrate.The oxaloacetate contains 4 carbon which is combined with acetyl-coa which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.To know more about citric acid cycle visit:
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some scientists believe that life on earth began about 3.5 billion years ago. what do they base this belief on?
Because the oldest rocks with fossilized evidence of life on earth are at least 3.5 billion years old, life on earth must have started at least then.
How did life on Earth look like 3 billion years ago?According to a study, Earth may have been a "waterworld" without continents 3 billion years ago. Without any continents to divide the oceans, Earth may have been entirely submerged in water about 3 billion years ago, resembling a "waterworld." The 3.5 billion year old "stromatolites," which are hard structures made by microbes, also contain evidence of their presence. Stromatolites are produced when microbe-made sticky mats trap and organize sediments into layers. Even as the microbes disappear, minerals precipitate inside the layers, forming strong structures.
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In the first reaction of the citric acid cycle, oxaloacetate, which contains blank______ carbons, is combined with acetyl-coa, which contains blank______ carbons in its acetyl group, to produce citric acid, which contains blank______ carbons.
Oxaloacetate contains 4C and is combined with acetyl-CoA which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.
What is a citric acid cycle and how it works?The tricarboxylic acid (TCA) cycle, also known as the Krebs or citric acid cycle, is the main source of energy for cells and a crucial step in aerobic respiration. The cycle transforms the chemical energy of acetyl coenzyme A (acetyl CoA) into nicotinamide adenine dinucleotide's reducing force (NADH).
The citric acid cycle also called as TCA cycle starts with the condensation of the acetyl group with oxaloacetic acid( OAA).An enzyme called citrate synthase catalyses the first step of the TCA cycle.Then the third step is isomerization which isomerizes citrate to isocitrate.The oxaloacetate contains 4 carbon which is combined with acetyl-CoA which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.To know more about the citric acid cycle visit:
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how many moles Mg(OH)2 has in 0,05 kg from substance?
According to the data 0.855 moles Mg(OH)₂ has in 0.05 kg from substance.
How do you convert moles to mass?Add the number of moles to the substance's molecular weight. The molecular weight of a substance determines how many grams there are in a mole and provides a conversion factor from moles to grams for that specific substance. 1 mol H2O x 18.02 g/mol = 18.02 g, or 18.02 grams, is the mass of one mole of water.
Briefing:1 kg = 1000g
We can convert 0.05 kg to grams
0.05 * 1000 = 50 grams
Then Find moles of Mg(OH)₂
1 grams Mg(OH)₂ is equal to 0.0171 mole
Then 50 grams Mg(OH)₂ is :
50 * 0.0171 = 0.855 moles
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Which of these are elements?
Au, C, K, O
H₂O, CO₂, NaCl
Milk, Mud, Air
Answer:
Au, C, K, O
Explanation:
Au = Gold
C = Carbon
K = Potassium
O = Oxegen
H20 = Not an element on the periodic table
CO2 = Not an element on the periodic table
NaCl = Not an element on the periodic table
Milk = Not an element on the periodic table
Mud = Not an element on the periodic table
Air = Not an element on the periodic table
Hope this helps! :)
Explain the terms physical properties of metals Malleability and ductility, and how they used in daily life situation ?
Answer:
Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.
and For jewellery and ornaments, gold, platinum and silver are being used. For building purposes, iron and steel can be used. Iron and aluminium are used as utensils. The thermometer uses mercury and helps to monitor the temperature.
Explanation:
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if you want to use the quick transition dialog box to apply multiple dissolves to a series of cut point, how do you identify the cuts to which the dissolves will be applied?
Around the cuts you want the transition to appear on, add in and out points.
What does "transition dialog box" mean to you?You can build a transition from one state in the lifecycle to another state using the new Transition dialog box. You can additionally specify which roles are permitted to move the object through this transition by using this feature.
What does the scientific term dissolve mean?A solute in a gaseous, liquid, or solid phase can dissolve in a solvent to create a solution through the process of dissolution.
Solubility. The greatest concentration of a solute that may dissolve in a solvent at a specific temperature is known as solubility.
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7. Students are asked to develop a plan for separating Al,0 (s) from a mixture of powdered Fe₂O3(s) and powdered Al20 (s) using chemical reactions and laboratory techniques. The student recovered 5.5 g of Al2O3 (s) from a 10.0 g sample of the mixture. Calculate the percent of Al by mass in the mixture of the two powdered oxides. (The molar mass of Al2O3 is 101.96g mol-¹, and the molar mass of Fez0, is 159.70 g mol-¹.)
The percent of aluminum (Al) by mass in the given mixture of the two powdered oxides is 29%.
What is the mass percent formula?The mass percent formula can be expressed by mass of the each element in one mole of the compound. The mass percentage of each component can be calculated as:
Mass percentage = (Mass of an element 1 mole of the compound)/ (molar mass of compound) × 100
Given, the mass of the mixture of the oxides Al₂O₃ and Fe₂O₃ is equal to 10.0 g.
The mass of the Al₂O₃ recovered = 5.5 g
The number of moles of Al₂O₃ = 5.5/101.96 = 0.054 mol
One mole of Al₂O₃ has two moles of aluminum.
0.054 mol Al₂O₃ will have moles of aluminum = 0.054 × 2 = 0.108
The molar mass of the aluminum (Al) = 26.98g/mol
The mass of 0.108 mol of Al = 0.108 × 26.98 = 2.9 g
The percentage by mass of Al in mixture = (2.9/10) × 100 = 29%
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no2 no2 drop zone empty. scl6 scl6 drop zone empty. bef2 bef2 drop zone empty. more than eight valence electrons due to an expanded octet fewer than eight valence electrons due to an odd number of valence electrons fewer than eight valence electrons due to a shortage of valence electrons
NO₂ is the example of fewer than eight number of valence electrons due to an odd no. of valence electrons.
N , atomic no. is 7 = 2 , 5
O , atomic no. is 8 = 2, 6
SCl₆ is the example of more than eight valence electrons due to an expanded octet.
S , atomic no. is 16 = 2 , 8 , 6
Cl , atomic no. is 17 = 2 , 8 , 7
BeF₂ is the example of fewer than eight valence electrons due to shortage of valence electrons.
Be, atomic no. is 4 = 2, 2
F , atomic no. is 9 = 2 , 7
These are the examples of odd no. of electrons, expanded octet due to more valence electron and less than eight valence.
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sulfuric acid has many uses, making it the most produced chemical in the world (over 150 million tons a year). one of the steps in the manufacture of sulfuric acid is so2(g) 1/2 o2(g) equilibrium reaction arrow so3(g). a sealed flask at 627°c is loaded with 1.48 atm of so2 and 0.74 atm of o2. after reaction, the equilibrium pressure of so3 is found to be 1.10 atm. what is the value of kp for this reaction at 627°c?
The value of the equilibrium constant at 627 °C, based on equilibrium pressures, will be 44.1.
First, we write the balanced reaction equation:
2 SO₂(g) + O₂(g) → 2 SO₃ (g)
Based on the reaction equation, the expression for the equilibrium constant (Kp) will look like this:
[tex]K_{p} =\frac{(pSO_{3} )^{2} }{pO_{2}(pSO_{2} )^{2} }[/tex]
pSO₃ - partial pressure of sulfur(VI) oxide
pO₂ - partial pressure of oxygen
pSO₂ - partial pressure of sulfur(IV) oxide
To calculate Kp, we need the equilibrium pressures for all three gasses. We already know the pressure for sulfur(VI) oxide (1.10 atm), but we need to calculate it for oxygen and sulfur(IV) oxide as well.
Because the molar ratio of sulfur(IV) oxide and sulfur(VI) oxide is 1:1, that means that for the formation of 1.10 atm of sulfur(VI) oxide, 1.10 atm of sulfur(IV) oxide was expended, so the equilibrium pressure of SO₂ will be 1.48 atm - 1.10 atm = 0.38 atm.
We apply the same principle for oxygen, but because oxygen:sulfur(VI) oxide ratio is 1:2, only 1.10 atm / 2 = 0.55 atm of oxygen was expended for the formation of sulfur(VI) oxide, leaving us with the oxygen equilibrium pressure of 0.74 atm - 0.55 atm = 0.19 atm.
We plug these values into the expression above:
Kp = (1.10 atm)² / (0.19 atm * (0.38 atm)²) = 44.1
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Which statement best describes the air behind a cold front?The air is warm and dry.
The air is warm and dry.
The air is colder and drier.
The air is warmer and more humid.
The air is cold and filled with moisture.
The air behind a cold front is always cooler than the air in front of it.
The air behind a cold front is much colder and drier than the air in front of it. When a cold front passes the temperature can drop by more than 15 degrees in the first hour. Air masses behind a cold front can be cooler and drier than those in front of the front. When a cold front approaches, precipitation may occur just before or during the passage of the front.
Clear skies cooler temperatures and lower relative humidity behind the front are expected. The answer is the boundary between two different air masses where cold air is retreating and warm air is advancing. A front represents the boundary between two different air masses, such as warm and cold air. A cold front occurs when cold air turns into warm air.
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Answer: Question 1.: B. Question 2.: D. Question 3.: C. Question 4.: A.
ytrdsxcvbhjiuytrfdcvbnjuytfvfdvhgytrdfcvnb.
Answer:
Explanation:
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