Use the periodic table to determine the electron configuration for aluminum (Al) and arsenic (As) in noble-gas notation.

Al:

Answers

Answer 1

Explanation:

2,8,3

don't know .............

.....how


Related Questions

La función de la levadura en quimica

Answers

Explanation:

las levaduras son pequeños organismos unicelulares que se alimentan de azúcares simples y los descomponen en dióxido de carbono, alcohol (etanol, específicamente), moléculas de sabor y energía. El proceso se conoce como fermentación.

The reduced coenzymes generated by the citric acid cycle donate electrons in a series of reactions called the electron transport chain. The energy from the electron transport chain is used for oxidative phosphorylation.
a) Which compounds donate electrons to the electron transport chain?
b) Which of the following is the final electron acceptor?
c) Which of the following are the final products of the electron transport chain and oxidative phosphorylation?
1. H20
2. NADH
3. NAD+
4. ATP
5. ADP
6. O2
7. FADH2
8. FAD

Answers

Answer:

a. NADH and FADH₂ donate electrons to the electron transport chain

b. Molecular oxygen, O₂, is the final electron acceptor

c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP

Explanation:

The citric cycle oxidize acetylCoA molecules to carbon dioxide and in the process produce the reduced coenzyme NADH and FADH₂. These reduced coenzymes then are able to donate their electrons to various complexes in the electron transport chain. The flow of these electrons through the electron transport chain is coupled to proton pumping out of the mitochondrial matrix into the intermembrane space. Ultimately, the energy of the proton motive force is used to drive synthesis of ATP from ADP and inorganic phospahte and the electrons are accepted by molecular oxygen to produce water. This process is known as oxidative phosphorylation.

Therefore, the answers to the given questions a, b and c are as follows:

a. NADH and FADH₂ donate electrons to the electron transport chain

b. Molecular oxygen, O₂, is the final electron acceptor

c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP

How is the enthalpy of reaction shown in this potential energy diagram?

Answers

Answer:

as the difference of the energy of the reactants and the energy of the products

In the given potential energy diagram, the energy of product at higher level and energy of reactant at lower level. The for this reaction will be positive. So, the enthalpy of reaction is defined as the difference of the energy of the reactants and the energy of the products.

I hope this helps!

Which of the following flows through ecosystems in one direction?

1. Water
2. Energy
3. Nitrogen
4. Carbon

Answers

Answer:

It is energy

Explanation:

Your welcome! :)

Energy flows in one direction in an ecosystem.

What is an ecosystem?

An ecosystem is a system which shows the interaction between the living organisms and the non-living part of their environment.

An ecosystem usually shows a flow of nutrient and energy

Nutrients are cycled in an ecosystem but energy flows in only one direction.

Therefore, in an ecosystem, energy flows in one direction.

Learn more about ecosystem at: https://brainly.com/question/15971107

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i need help, do you mind helping me?

Answers

The mole ratio is 2:19 or 1:9.5

A student sets up the following equation to convert a measurement.
(The stands for a number the student is going to calculate.)

Fill in the missing part of this equation.

Answers

Answer:

–0.13 Pa.m²

Explanation:

From the question given above, the following data were obtained:

Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²

Measurement (Pa.m²) =?

We can convert from Pa.mm² to Pa.m² by doing the following:

1 Pa.mm² = 1×10¯⁶ Pa.m²

Therefore,

–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²

–1.3×10⁵ Pa.mm² = –0.13 Pa.m²

Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².

The complete equation will be:

[tex](-1.3\times 10^5 Pa.mm^2)\times 10^{-6}=(-0.13) Pa.m^2[/tex]

Explanation:

Given:

The equation to convert a measurement:

[tex](-1.3\times 10^5 Pa.mm^2)\times ? = ? Pa.m^2[/tex]

To find:

The missing part of the equation.

Solution:

[tex](-1.3\times 10^5 Pa.mm^2)\times ? = ? Pa.m^2[/tex]

On LHS the unit is in [tex]Pa. mm^2[/tex] and RHS the unit is in [tex]Pa.m^2[/tex] which means that we have to convert [tex]mm^2[/tex] to [tex]m^2[/tex]

In 1 millimeter there are 0.001 meters.

[tex]1 mm = 0.001 m\\1 mm^2=0.000001 m^2=10^{-6} m^2[/tex]

So, the complete equation will be:

[tex](-1.3\times 10^5 Pa.mm^2)\times 10^{-6}=(-0.13) Pa.m^2[/tex]

Learn more about conversions here:

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The number of moles of Cu produced in this
reaction is

Answers

Answer:

the answer is 0.078

Explanation:

edge 2021

Answer:

The next answers are

4.96

Wax

oxygen

Calculated based on the chemical equation:

✔ theoretical yield

Measured directly:  

✔ experimental yield

Determined experimentally:  

✔ experimental yield

Determined using stoichiometry:  

✔ theoretical yield

BOTH

ALL OF THE ABOVE

using accurate measurements

using pure chemicals

performing the reaction under the most ideal conditions

Explanation:

Difference between sieving and filtration

Answers

my answer

Explanation:

Answer. Filtration is the method of separating a solid from a liquid. A sieve sets a threshold calibration through which all undersized materials pass through. Filtration differs from sieving, where separation occurs at a single perforated layer (a sieve).

It took 2.30 minutes using a current of 3.00 A to plate out all the copper from 0.300 L of a solution containing Cu2 . What was the original concentration of Cu2

Answers

Answer:

7.16 × 10⁻³ M

Explanation:

Let's consider the reduction reaction of copper during the electroplating.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We can calculate the moles of Cu²⁺ present in the solution using the following relations.

1 A = 1 C/s.1 min = 60 s.1 mole of electrons has a charge of 96486 C (Faraday's constant).1 mole of Cu²⁺ is reduced when 2 moles of electrons are gained.

The moles of Cu²⁺ reduced are:

[tex]2.30 min \times \frac{60s}{1min} \times \frac{3.00C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molCu^{2+} }{2mole^{-} } = 2.15 \times 10^{-3} molCu^{2+}[/tex]

[tex]2.15 \times 10^{-3} moles[/tex] of Cu²⁺ are in 0.300 L of solution.

[Cu²⁺] = 2.15 × 10⁻³ mol/0.300 L = 7.16 × 10⁻³ M

In the reaction represented by the equation: N2 + 3H2 → 2NH3, what is the conversion factor of nitrogen to ammonia? Explain by using law of definite proportion

Answers

Answer:

10/3

Explanation:

Hope this helps

Answer:

The compound formula for the ammonia is

N

H

3

. It is a colorless gas. It is the result of the chemical reaction between nitrogen and hydrogen gas. The chemical reaction between the gases is shown below:

N

2

+

3

H

2

2

N

H

3

help!! An atomic number of 4, an atomic mass of 8 and a charge of +1.

Answers

Answer:

berylium

Explanation:

atomic number 4 atomic mass 8 and charge +1

Rocks are classified as igneous, metamorphic, or sedimentary according to

Answers

Answer:

D. the minerals they contain

Hope this answer is right!!

Which answer choice shows the correct arrangement of electrons on the energy levels (shells)?
A. 8, 8, 8
B. 2, 8, 2
C. 2, 2, 8
D. 2, 8, 8

Answers

Explanation:

looks like c is the answer

A student is examining a chemical reaction the student notes that the reaction requires 7.14 kcal mol energy per biomlecule synthesized the reaction itself produces 21.42 kcal mol energy the sutdent argues this is enough energy to make 3 biomecules. What error has the student made in the analysis?

a. The studentiras not remembered the Second Law of Thermodynamics.
b. The students has not remembered the First Law of Thermodynamics.
c. The student has made a simple calculation error
d. The student has made a conversion error

Answers

C took the test on edg2022

What is the correct answer question

Answers

Answer:

B

Explanation:

what are the answers for these I did four through 10 but I think I got four through nine wrong because I mixed up the radius and the atomic radius but I’m not sure can you please tell me the answers I can send you a picture of my work as well!

Answers

Answer:

1) B

2) D

3) A

4) Ga

5) K

6)Po

7) Atomic size increases down the group

8) B<Al<Ga<In<Tl

9)Se<C<Ga

10) ionization energy is the energy required to remove electrons from the outermost shell of an atom.

Explanation:

In the periodic table, the properties of elements reoccur ''periodically'' throughout the table, hence the name 'periodic table'.

Ionization energy increases across the period hence the noble gas He has the highest ionization energy.

Since ionization energy increases across the period, group 1 elements possess the lowest ionization energy.

Since atomic size increases down the group and decreases across the period, gallium is smaller than indium, potassium is smaller than caesium, polonium is smaller than titanium and iodine is larger than bromine.

This explanation above justifies the order of increasing atomic radius of group 13 elements shown in answer number 8 above.

Since atomic size decreases across the period, the order of increasing atomic size shown in answer number 9 above is correct.

Ionization energy is the energy required to remove electrons from the outermost shell of an atom.

when 27 g of water absorbs 1,5000 joules of heat energy the temperature of the water is raised to 57.7 what is the initial temperature of the water

Answers

Answer:

The initial temperature of the water is -75.08 K.

Explanation:

Given that,

Mass of water, m = 27 g

Heat absorbed, Q = 1,5000 J

Final temperature of water, T₂ = 57.7 K

The specific heat of water is 4.184 J/​g-K

We know that,

[tex]Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_1=T_2-\dfrac{Q}{mc}[/tex]

Put all the values,

[tex]T_1=57.7-\dfrac{15000}{27\times 4.184 }\\\\=-75.08\ K[/tex]

So, the initial temperature of the water is -75.08 K.

Calculate the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm.

Answers

Answer: The frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is [tex]5.49 \times 10^{14} s^{-1}[/tex].

Explanation:

Given: Wavelength = 546 nm [tex](1 nm = 10^{-9} m)[/tex] = [tex]546 \times 10^{-9} m[/tex]

The relation between frequency and wavelength is as follows.

[tex]\nu = \frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = frequency

c = speed of light = [tex]3.0 \times 10^{8} m/s[/tex]

[tex]\lambda[/tex] = wavelength

Substitute the values into above formula as follows.

[tex]\nu = \frac{c}{\lambda}\\= \frac{3.0 \times 10^{8} m/s}{546 \times 10^{-9} m}\\= 5.49 \times 10^{14} s^{-1}[/tex]

Thus, we can conclude that the frequency of the green light emitted by a hydrogen atom with a wavelength of 546 nm is [tex]5.49 \times 10^{14} s^{-1}[/tex].

How many carbon dioxide molecules react to form one glucose molecule during photosynthesis

Answers

Answer:

6 molecules

Explanation:

Only three elements are present in the products of photosynthesis: oxygen, carbon, and hydrogen. These same elements are present in the reactants of photosynthesis. Notice that it takes six molecules of water and six molecules of carbon dioxide to make one molecule of glucose

Answer:

6 molecules of carbone dioxide.

identify the limiting reactant
1.4 g of CO2 and 2.2 g of KOH in the reaction: CO2 + 2KOH → K2CO3 + H20

Please show work, will give brainliest

Answers

Answer:

KOH is the limiting reactant

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to identify the required limiting reactant by calculating the moles of water vapor produced by each reactant, CO2 and KOH, as shown below:

[tex]1.4gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molH_2O}{1molCO_2}=0.0318mol H_2O\\\\2.2gKOH*\frac{1molKOH}{56.11gKOH}*\frac{1molH_2O}{2molKOH}=0.0196mol H_2O[/tex]

In such a way, since 2.2 grams of KOH yield the fewest moles of water vapor, we infer KOH is the limiting reactant.

Regards!

Reaction of 2,3-dimethyl-1-butene with HBr leads to an alkyl bromide, C6H13Br. On treatment of this alkyl bromide with KOH in methanol, elimination of HBr occurs and a hydrocarbon that is isomeric with the starting alkene is formed. What is the structure of this hydrocarbon, and how do you think it is formed from the alkyl bromide

Answers

Answer:

See explanation and image attached

Explanation:

The image attached shows the entire scheme of reactions mentioned in the question.

The first reaction is an addition reaction which yields a tertiary alkyl halide as shown in accordance with Markovnikov rule.

The second reaction is a dehydrohalogenation in which the base abstracts a proton from the alkyl halide followed by loss of a bromide ion to yield the corresponding alkene.

This alkene is an isomer of the starting material.

You have 4 litres of a 3.0 mol/L solution of NaCl in a chemical store room.
How many moles of NaCl are present?

Answers

Answer:

12

Explanation:

nNaCl= 4x3=12

A 10 M concentrated stock solution of NaCl was used to prepare 5 liters of diluted 1 M solution. Which of the following statements is true about the process used to achieve this required dilution?

The volume of stock solution used was less than 0.4 liters.
The volume of stock solution used was more than 5 liters.
The volume of the solvent used was less than 0.4 liters.
The volume of the solvent used was less than 5 liters.

Answers

Answer: D.) The volume of stock solution used was more than 5 liters

Explanation:

Answer:

b

Explanation:

i got it

Determine which intermolecular forces are the dominant (strongest) forces for a pure sample of each of the following molecules by placing the molecules into the correct bins.
Dispersion Forces; Dipole-Dipole Forces; Hydrogen Bonding Forces
Kr, H2O, CHCI3, HF, C2H6, HBr

Answers

Answer:

Kr- Dispersion Forces

H2O- Hydrogen Bonding

CHCI3- Dipole-Dipole Forces

HF- Hydrogen Bonding

C2H6- Dispersion Forces

HBr- Hydrogen Bonding Forces

Explanation:

Dispersion forces occurs in all substances. They are the dominant intermolecular interaction in all non polar substances such as C2H6 and Kr.

Hydrogen bonding occurs when hydrogen is bonded to a highly electronegative atom such as Cl, Br, O etc. It is the dominant intermolecular interaction in HF, HBr and H2O.

Dipole-Dipole interactions occur when a permanent dipole exists in a molecule such as in CHCI3

Iodide ion catalyzes the decomposition of hydrogen peroxide. The reaction is first-order in H2O2. What is the value of the rate constant, k, if the initial rate is 0.00842 mol/(L·s) and the initial concentration of H2O2 is 0.500 mol/L.

Answers

Answer:

0.01684 s⁻¹

Explanation:

In a first-order reaction, the rate is proportional to the concentration of only one reactant (raised by 1). In this case, the reactant is H₂O₂. Thus, the rate law is the following:

rate = k [H₂O₂]

We have the following data for the initial rate:

rate = 0.00842 mol/(L·s)

[H₂O₂] = 0.500 mol/L

So, we introduce the data in the expression for the rate law to calculate k:

k = rate/[H₂O₂] = (0.00842 mol/L·s)/0.500 mol/L = 0.01684 s⁻¹

85.4 g of chlorine reacts completely according to the following reaction: P4 (s) + 6 Cl2, (g) 4PC13 (I)
If 104 g of phosphorous trichloride is produced, what is the percent yield for this reaction?

please show work
will give brainliest

Answers

Explanation:

hope the picture make sense :)

PLEASE HELP ASAP‼️‼️
A
B
C
D

Answers

Answer:

Hey mate......

Explanation:

This is ur answer......

Option C is the correct answer.....

molecules in liquids are weaker than solids but stronger than gases......

Hope it helps!

Brainliest pls!

Follow me! :)

1 point
What is the correct balanced equation for the double displacement
reaction provided?
CaBr2+2NaOH???

a) CaBr2+2NaOH
>CaNa
+ BrOH

b) CaBr2
+ NaOH → Ca(OH)2
+NaBr

c) CaBr2 NaOH> CaBr2
+NaOH

d)CaBr2
+ 2NaOH
→ Ca(OH)2
+2NaBr

Option A
Option B
Option C
Option D

Answers

Answer:

Option D

Explanation:

A double displacement reaction is a type of reaction in which two reactants exchange ions to form two new compounds.

CaBr2 + 2NaOH → Ca(OH)2 + 2NaBr

Calcium Bromide + Sodium Hydroxide = Portlandite + Sodium Bromide

Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. CH2Br2 CH3NH2 LiF C3H8 CF4

Answers

Answer:

The given molecules are:

CH2Br2

CH3NH2

LiF

C3H8

CF4.

Which compound consists of the hydrogen bond as the strongest intermolecular force.

Explanation:

The hydrogen bond is the electrostatic force of attraction that exists between the covalently bonded H-atom of one molecule and a high electronegative atom (N, O, F) of another molecule.

For example, H-bonding in water is represented below:

Among the given molecules,

CH2Br2 does not have H-bond because there is no either N or O or F atom in it.

In LiF also there is no H-atom and no hydrogen bond.

C3H8 also does not have H-bond in it.

CF4 also does not have H-atom or hydrogen bond in it.

The answer is CH3NH2(methylamine).

It has an intermolecular hydrogen bond in it as shown in the attachment.

The dashed line represents the H-bond.

How is the enthalpy of reaction shown in this potential energy diagram

Answers

Answer:

In the given potential energy diagram, the energy of product at higher level and energy of reactant at lower level. The for this reaction will be positive. So, the enthalpy of reaction is defined as the difference of the energy of the reactants and the energy of the products.

Hope this is fine for you,,!

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