What is the biggest difference between exponential functions and other functions you have learned about up to this point?

Answer:

27 is the answer

Step-by-step explanation:

Answer:

Yes 2*35.625

Step-by-step explanation:

Just divide by two and now you have dimensions for a rug that has an area of 71.25

Yes, Is it possible for the rug to have an area of 71.25 square feet.

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

We have to given that;

A rug weaver wants to create a large rectangular rug.

Now, From the figure;

Area (S) = (8 + x) (9 - x)

            = - x² + x + 72

            = - (x² - x + 1/4) + 1/4 + 72

           = - (x - 1/2)² + 72.25

Hence,

S (max) = 72.25 square feet

And, 72.25 > 71.25

Thus, Is it possible for the rug to have an area of 71.25 square feet.

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Complete question is shown in figure.

The mass of the 2D plate is 20.067 kg, with a moment of 5.742 kg.m about the y-axis. The x-coordinate of the center of mass of the 2D plate is 0.286 m. The mass of the 3D body is 62.137 kg, with a moment of 39.748 kg.m about the y-axis. The x-coordinate of the center of mass of the 3D body is 0.640 m.

To determine the center of mass of the 2D shape bounded by the lines y = ±1.3x between x = 0 to 2.1, we need to calculate the mass, moment, and x-coordinate of the center of mass.

1) Mass of the 2D plate:

The area of the 2D shape can be calculated by finding the difference in the areas under the two lines y = ±1.3x between x = 0 and x = 2.1.

Area = ∫(1.3x)dx - ∫(-1.3x)dx

     = ∫1.3xdx + ∫1.3xdx

     = 2 * ∫1.3xdx

     = 2 * [0.65x²] between x = 0 and x = 2.1

     = 2 * (0.65 * (2.1)²)

     = 2 * (0.65 * 4.41)

     = 2 * 2.8665

     = 5.733

Mass = Area * Density

     = 5.733 * 3.5

     ≈ 20.067 kg

Therefore, the mass of the 2D plate is approximately 20.067 kg.

2) Moment of the 2D plate about the y-axis:

The moment of the 2D shape about the y-axis is given by the integral of the product of the y-coordinate and the area element.

Moment = ∫(y * dA)

      = ∫(±1.3x * dA)

      = 2 * ∫(1.3x * dA) between x = 0 and x = 2.1

      = 2 * 1.3 * ∫(x * dA) between x = 0 and x = 2.1

      = 2 * 1.3 * ∫(x * dx)

      = 2 * 1.3 * [0.5x²] between x = 0 and x = 2.1

      = 2 * 1.3 * (0.5 * (2.1)²)

      = 2 * 1.3 * (0.5 * 4.41)

      = 2 * 1.3 * 2.205

      = 5.742 kg.m

Therefore, the moment of the 2D plate about the y-axis is 5.742 kg.m.

3) x-coordinate of the center of mass of the 2D plate:

The x-coordinate of the center of mass of the 2D shape can be calculated using the formula:

x-coordinate = Moment / Mass

x-coordinate = 5.742 kg.m / 20.067 kg

            ≈ 0.286 m

Therefore, the x-coordinate of the center of mass of the 2D plate is approximately 0.286 m.

For the 3D body created by rotating the same lines about the x-axis:

1) Mass of the 3D body:

The volume of the 3D body can be calculated by finding the difference in the volumes between the two shapes obtained by rotating y = ±1.3x about the x-axis between x = 0 and x = 2.1.

Volume = π * ∫(1.3x)^2 dx - π * ∫(-1.3x)^2 dx

      = π * ∫1.69x^2 dx - π * ∫1.69x^2 dx

      =

2 * π * ∫1.69x² dx

      = 2 * π * [0.5633x³] between x = 0 and x = 2.1

      = 2 * π * (0.5633 * (2.1)³)

      = 2 * π * (0.5633 * 9.261)

      = 2 * π * 5.2167

      ≈ 32.703 m³

Mass = Volume * Density

     = 32.703 * 1.9

     ≈ 62.137 kg

Therefore, the mass of the 3D body is approximately 62.137 kg.

2) Moment of the 3D body about the y-axis:

The moment of the 3D body about the y-axis can be calculated similarly to the 2D plate but considering the additional dimension.

Moment = ∫(x * dV)

      = π * ∫(x * (1.3x)² dx) - π * ∫(x * (-1.3x)^2 dx)

      = 2 * π * ∫(1.3x³ dx)

      = 2 * π * [0.325x⁴] between x = 0 and x = 2.1

      = 2 * π * (0.325 * (2.1)⁴)

      = 2 * π * (0.325 * 19.4481)

      = 2 * π * 6.3252

      ≈ 39.748 kg.m

Therefore, the moment of the 3D body about the y-axis is approximately 39.748 kg.m.

3) x-coordinate of the center of mass of the 3D body:

The x-coordinate of the center of mass of the 3D body can be calculated using the formula:

x-coordinate = Moment / Mass

x-coordinate = 39.748 kg.m / 62.137 kg

            ≈ 0.640 m

Therefore, the x-coordinate of the center of mass of the 3D body is approximately 0.640 m.

To summarize the answers:

a) Mass of the 2D plate: 20.067 kg

b) Moment of the 2D plate about the y-axis: 5.742 kg.m

c) x-coordinate of the center of mass of the 2D plate: 0.286 m

d) Mass of the 3D body: 62.137 kg

e) Moment of the 3D body about the y-axis: 39.748 kg.m

f) x-coordinate of the center of mass of the 3D body: 0.640 m

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The account was open for 3 years. This duration was determined by calculating the time using the formula for simple interest based on the initial principal, interest rate, and the amount of interest earned.

To determine the length of time the account was open, we can use the formula for simple interest:

Interest = Principal * Rate * Time

Given that Tom opened the account with $600, the annual interest rate was 2%, and he received $36 in interest, we can set up the equation:

36 = 600 * 0.02 * Time

Simplifying the equation:

36 = 12 * Time

Dividing both sides by 12:

Time = 3

Therefore, the account was open for 3 years.

In conclusion, Tom's savings account was open for 3 years, as calculated using the simple interest formula.

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Answer:6

Step-by-step explanation:

To solve the differential equation y" + xy' + 2y = 0 using power series, we assume a power series representation for the solution and derive a recurrence relation for the coefficients. The first eight nonzero terms can be found by solving the recurrence relation.

To solve the differential equation y" + xy' + 2y = 0 using power series around x₁ = 0, we can assume a power series representation for the solution:

y(x) = ∑(n=0 to ∞) aₙxⁿ

Let's substitute this power series representation into the given differential equation and find the recurrence relation for the coefficients aₙ.

Differentiating y(x) with respect to x:

y'(x) = ∑(n=0 to ∞) aₙn xⁿ⁻¹

y''(x) = ∑(n=0 to ∞) aₙn(n-1) xⁿ⁻²

Substituting these expressions into the differential equation:

∑(n=0 to ∞) aₙn(n-1) xⁿ⁻² + x ∑(n=0 to ∞) aₙn xⁿ⁻¹ + 2∑(n=0 to ∞) aₙxⁿ = 0

Now, we can rearrange and collect like terms based on the powers of x:

∑(n=0 to ∞) [aₙn(n-1) xⁿ⁻² + aₙn xⁿ⁺¹ + 2aₙxⁿ] = 0

Since this equation must hold for all values of x, each coefficient of xⁿ must be zero. Therefore, we get the following recurrence relation for the coefficients:

aₙ(n-1)(n-2) + aₙ₋₁(n-1) + 2aₙ = 0

Simplifying the recurrence relation:

aₙ(n² - 3n + 2) + aₙ₋₁(n-1) = 0

Now, we can start finding the first few nonzero terms of the power series solution by using the recurrence relation.

First term (n=0):

a₀(0² - 3(0) + 2) + a₋₁(-1) = 0

a₀ + a₋₁ = 0

Second term (n=1):

a₁(1² - 3(1) + 2) + a₀(1-1) = 0

a₁ - a₀ = 0

From the first and second terms, we find a₀ = a₁ and a₋₁ = -a₀.

Third term (n=2):

a₂(2² - 3(2) + 2) + a₁(2-1) = 0

a₂ - 3a₁ = 0

a₂ - 3a₀ = 0

Fourth term (n=3):

a₃(3² - 3(3) + 2) + a₂(3-1) = 0

a₃ - 6a₂ = 0

a₃ - 6a₀ = 0

Continuing this process, we can find the values of a₄, a₅, a₆, and so on, using the recurrence relation.

By solving the recurrence relation for each term, we can determine the first eight nonzero terms of the power series solution to the differential equation y" + xy' + 2y = 0.

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Answer:

x = - 2

Step-by-step explanation:

The axis of symmetry passes through the vertex, is a vertical line with equation equal to the x- coordinate of the vertex, that is

equation of axis of symmetry is x = 1

The zeros are equidistant from the axis of symmetry, on either side

x = 4 is a zero and is 3 units to the right of x = 1, so

3 units to the left of x = 1 is 1 - 3 = - 2

The other zero is therefore x = - 2

Answer:

3

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

9×[tex]\frac{1}{3}[/tex]

9×1/1×3=

[tex]\frac{9}{3}[/tex]÷3=

3!!!!

Answer:

$412.35

Step-by-step explanation:

Answer: $412.35

Step-by-step explanation:

$137.45 x 3 = $412.35 for the total that the bake sale raised.

Given : jason wants to create a box with the same volume as the one shown

To find : measurements of width and height .

Solution :

Volume of given box

=> 6 * 2 * 3

=36

length to be 4 inches .

lwh = 36

=> 4 wh = 36

=> wh = 9

9 = 1 * 9

9 = 3 * 3

Width and Height can be 3 inches each or 1 and 9 inches

A1) To find the intersection of the two equations, we can solve for one variable in terms of the other and substitute that equation into the other equation.

Starting with the first equation:

4x - 3y = 6

Solving for y:

-3y = -4x + 6

y = (4/3)x - 2

Now let's look at the second equation:

-2x + (3/2)y - 3 = 0

Solving for y:

(3/2)y = 2x + 3

y = (4/3)x + 2

Now we have two expressions for y:

y = (4/3)x - 2  and y = (4/3)x + 2

These lines have different y-intercepts and the same slope, so they are not parallel and must intersect at some point.

Setting the two expressions equal to each other:

(4/3)x - 2 = (4/3)x + 2

Subtracting (4/3)x from both sides:

-2 = 2

This is a contradiction, so there is no solution.

Answer: none

A2)

To find the intersection of the two equations, we can again solve for one variable in terms of the other and substitute that equation into the other equation.

Starting with the first equation:

x - 4y = -5

Solving for y:

-4y = -x - 5

y = (1/4)x + (5/4)

Now let's look at the second equation:

3x - 2y = 15

Solving for y:

-2y = -3x + 15

y = (3/2)x - 7.5

Now we have two expressions for y:

y = (1/4)x + (5/4)  and y = (3/2)x - 7.5

Setting the two expressions equal to each other:

(1/4)x + (5/4) = (3/2)x - 7.5

Subtracting (1/4)x and adding 7.5 to both sides:

(11/4) = (5/2)x

Multiplying both sides by 2/5:

x = 22/20 = 11/10

Now we can substitute this value of x into either equation to find y:

y = (1/4)(11/10) + (5/4) = (11/40) + (50/40) = 61/40

Answer: (11/10, 61/40)

A3)

Starting with the first equation:

4x + y = 9

Solving for y:

y = -4x + 9

Now let's look at the second equation:

2x - 3y = 22

Solving for y:

-3y = -2x + 22

y = (2/3)x - (22/3)

Now we have two expressions for y:

y = -4x + 9  and y = (2/3)x - (22/3)

Setting the two expressions equal to each other:

-4x + 9 = (2/3)x - (22/3)

Adding 4x and (22/3) to both sides:

33/3 = (14/3)x

Multiplying both sides by 3/14:

x = 9/14

Now we can substitute this value of x into either equation to find y:

y = -4(9/14) + 9 = -18/7

Answer: (9/14, -18/7)

A4)

Starting with the first equation:

-6x + 9y = 9

Solving for y:

9y = 6x + 9

y = (2/3)x + 1

Now let's look at the second equation:

2x - 3y = 6

Solving for y:

-3y = -2x + 6

y = (2/3)x - 2

Now we have two expressions for y:

y = (2/3)x + 1  and y = (2/3)x - 2

Setting the two expressions equal to each other:

(2/3)x + 1 = (2/3)x - 2

Adding -2/3x and -1 to both sides:

0 = -3A1)

To find the intersection of the two equations, we can solve for one variable in terms of the other and substitute that equation into the other equation.

Starting with the first equation:

4x - 3y = 6

Solving for y:

-3y = -4x + 6

y = (4/3)x - 2

Now let's look at the second equation:

-2x + (3/2)y - 3 = 0

Solving for y:

(3/2)y = 2x + 3

y = (4/3)x + 2

Now we have two expressions for y:

y = (4/3)x - 2  and y = (4/3)x + 2

These lines have different y-intercepts and the same slope, so they are not parallel and must intersect at some point.

Setting the two expressions equal to each other:

(4/3)x - 2 = (4/3)x + 2

Subtracting (4/3)x from both sides:

-2 = 2

This is a contradiction, so there is no solution.

Answer: none

A2)

To find the intersection of the two equations, we can again solve for one variable in terms of the other and substitute that equation into the other equation.

Starting with the first equation:

x - 4y = -5

Solving for y:

-4y = -x - 5

y = (1/4)x + (5/4)

Now let's look at the second equation:

3x - 2y = 15

Solving for y:

-2y = -3x + 15

y = (3/2)x - 7.5

Now we have two expressions for y:

y = (1/4)x + (5/4)  and y = (3/2)x - 7.5

Setting the two expressions equal to each other:

(1/4)x + (5/4) = (3/2)x - 7.5

Subtracting (1/4)x and adding 7.5 to both sides:

(11/4) = (5/2)x

Multiplying both sides by 2/5:

x = 22/20 = 11/10

Now we can substitute this value of x into either equation to find y:

y = (1/4)(11/10) + (5/4) = (11/40) + (50/40) = 61/40

Answer: (11/10, 61/40)

A3)

Starting with the first equation:

4x + y = 9

Solving for y:

y = -4x + 9

Now let's look at the second equation:

2x - 3y = 22

Solving for y:

-3y = -2x + 22

y = (2/3)x - (22/3)

Now we have two expressions for y:

y = -4x + 9  and y = (2/3)x - (22/3)

Setting the two expressions equal to each other:

-4x + 9 = (2/3)x - (22/3)

Adding 4x and (22/3) to both sides:

33/3 = (14/3)x

Multiplying both sides by 3/14:

x = 9/14

Now we can substitute this value of x into either equation to find y:

y = -4(9/14) + 9 = -18/7

Answer: (9/14, -18/7)

A4)

Starting with the first equation:

-6x + 9y = 9

Solving for y:

9y = 6x + 9

y = (2/3)x + 1

Now let's look at the second equation:

2x - 3y = 6

Solving for y:

-3y = -2x + 6

y = (2/3)x - 2

Now we have two expressions for y:

y = (2/3)x + 1  and y = (2/3)x - 2

Setting the two expressions equal to each other:

(2/3)x + 1 = (2/3)x - 2

Adding -2/3x and -1 to both sides: 0 = -3

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The maximum period of the LFSR with the given characteristic polynomial is 63.

To draw the diagram of a Linear Feedback Shift Register (LFSR) with a characteristic polynomial of [tex]x^6 + x^5 + x^3 + x^2 + 1,[/tex] we need to represent the shift register stages and the feedback connections.

The characteristic polynomial tells us the feedback taps in the LFSR. In this case, the feedback taps are at positions 6, 5, 3, 2, and 0 (the coefficients of the polynomial with non-zero exponents).

In the diagram, D1 represents the output of the first stage (bit), D2 represents the output of the second stage, and so on. The arrows represent the shift direction, with the feedback connections shown by the lines connecting the output of specific stages to the feedback taps.

Now, let's determine the maximum period of the LFSR with this characteristic polynomial. The maximum period of an LFSR is given by [tex]2^N - 1,[/tex] where N is the number of stages in the shift register.

In this case, there are 6 stages, so the maximum period is [tex]2^6 - 1 = 63.[/tex]

Therefore, the maximum period of the LFSR with the given characteristic polynomial is 63.

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Answer:

a=7

Step-by-step explanation:

4(2a-3) = 2(3a+1)

8a-12 = 6a+2

2a-12=2

2a=14

a=7

Answer:

(D) 112,800

Step-by-step explanation:

75%x150,400= 112,800

112,800 use the headache medicine.

Answer:

option D

Step-by-step explanation:

Out of 4 , 3 use headache medicine . So the fraction is 3/4 .

Total number of people in city = 150,400 .

So ,

⇒ n = 3/4 × Population

⇒ n = 3/4 × 150,400

⇒ n = 112,800

Answer:

3

Step-by-step explanation:

I hope this answer has helped you

The value of expression x - 9, if x = 12 is 3, so the correct option is 4.

A mathematical expression is made up of a statement, at least one arithmetic operation, and at least two integers or variables.

Given:

x - 9 and x = 12

Put the value of x in the expression as shown below,

x - 9 = 12 - 9

x - 9 = 3

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Trigonometric functions are the ratio of different sides of a triangle. The ratios sin∠m, cos∠m, and Tan∠m are 0.758, 0.6522, and 1.1624.

The trigonometric function gives the ratio of different sides of a right-angle triangle.

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}[/tex]

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

As it is given that the base of the triangle for the ∠m is Mk(15 units), the perpendicular is KL(4√19), and the hypotenuse is 23. Now, the trigonometric ratios can be written as,

Sine

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\\rm Sin (\angle m)=\dfrac{KL}{ML}\\\\\\\rm Sin (\angle m)=\dfrac{4\sqrt{19}}{23}\\\\\\\rm Sin (\angle m)=0.758069\approx 0.758[/tex]

Cosine

[tex]\rm Cos\theta=\dfrac{Base}{Hypotenuse}\\\\\\\rm Cos(\angle m)=\dfrac{MK}{ML}\\\\\\\rm Cos(\angle m)=\dfrac{15}{23}\\\\\\\rm Cos (\angle m)=0.65217\approx 0.6522[/tex]

Tangent

[tex]\rm Tan\theta=\dfrac{Perpendicular}{Base}\\\\\\\rm Tan(\angle m)=\dfrac{KL}{MK}\\\\\\\rm Tan(\angle m)=\dfrac{4\sqrt{19}}{15}\\\\\\\rm Tan(\angle m)=1.16237\approx 1.1624[/tex]

Hence, the ratios sin m, cos m, and tan m are 0.758, 0.6522, and 1.1624.

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The joint probability, Prob(V1 < 0.5, V2 < 0.3), of two uniformly distributed variables V1 and V2, modelled using a Gaussian copula with a correlation coefficient of ρ = 0.5.

Given that V1 and V2 are uniformly distributed between 0.2 and 0.8, we need to transform these variables to standard normal variables before calculating the joint probability. The Gaussian copula is commonly used for this purpose.

The transformation from the uniform distribution to the standard normal distribution can be achieved using the inverse of the cumulative distribution function (CDF) of the standard normal distribution. Let Φ denote the CDF of the standard normal distribution. The transformed variables, denoted as U1 and U2, can be calculated as follows:

U1 = Φ^(-1)(V1)

U2 = Φ^(-1)(V2)

Since the correlation coefficient between U1 and U2 is ρ = 0.5, we can calculate the joint probability using the bivariate normal distribution function with mean 0, standard deviation 1, and correlation coefficient 0.5. Let Φ2 denote the cumulative bivariate normal distribution function.

[tex]Prob(V1 < 0.5, V2 < 0.3) = Prob(U1 < Φ^(-1)(0.5), U2 < Φ^(-1)(0.3))[/tex]

[tex]= Φ2(Φ^(-1)(0.5), Φ^(-1)(0.3); ρ = 0.5)[/tex]

By evaluating the bivariate normal distribution function at the given values, we can obtain the joint probability.

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To write down the joint probability Prob(V1 < 0.5, V2 < 0.3) in terms of the cumulative bivariate normal distribution function, we need to utilize the properties of the Gaussian copula and the correlation coefficient.

The area of the triangle with vertices: Q(2,-1,1), R(3,-2,-2), S(5,1,-1) is 6.5 square units.

To find the area of the triangle with vertices: Q(2,-1,1), R(3,-2,-2), S(5,1,-1), we can use the formula Area of triangle = 1/2 * |(x2-x1) (y3-y1)-(x3-x1)(y2-y1)|

where, x1, y1, x2, y2, x3 and y3 are the coordinates of the given triangle Q(2,-1,1)

corresponds to x1=2, y1=-1R(3,-2,-2)

corresponds to x2=3, y2=-2S(5,1,-1)

corresponds to x3=5, y3=1

We can substitute these values in the above formula to get Area of triangle = 1/2 * |(x2-x1) (y3-y1)-(x3-x1)(y2-y1)|= 1/2 * |(3-2)(1-(-1)) - (5-2)(-2-(-1))|    = 1/2 * |-4 - 9|    = 1/2 * 13    = 6.5

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Answer:

B. $27,000

Step-by-step explanation:

So 55,000 = 2x + 1,000

Simply for x

55,000 = 2x + 1,000

54,000 = 2x

x = 27,000

Answer 2.05

Step-by-step explanation: hope this helps

Answer:

The answer is;

box A:3/2

box B:2/3

Answer:

2:36

Step-by-step explanation:

i don't know for my answer

Answer:

π

Step-by-step explanation:

S = rФ

Arc length = radius x theta

S = (3)([tex]\frac{\pi }{3}[/tex]) = [tex]\pi[/tex]

Answer:

5.59 times per second.

Step-by-step explanation:

Direct variation is in the form:

[tex]y=kx[/tex]

Where k is the constant of variation.

Inverse variation is in the form:

[tex]\displaystyle y=\frac{k}{x}[/tex]

In the given problem, the frequency of a vibrating guitar string varies inversely  as its length. In other words, using f for frequency and l for length:

[tex]\displaystyle f=\frac{k}{\ell}[/tex]

We can solve for the constant of variation. We know that the frequency f is 4.3 when the length is 0.65 meters long. Thus:

[tex]\displaystyle 4.3=\frac{k}{0.65}[/tex]

Solve for k:

[tex]k=4.3(0.65)=2.795[/tex]

So, our equation becomes:

[tex]\displaystyle f=\frac{2.795}{\ell}[/tex]

Then when the length is 0.5 meters, the frequency will be:

[tex]\displaystyle f=\frac{2.795}{.5}=5.59\text{ times per second.}[/tex]

Answer:

answer is a . x²-8x+16=32

x²-8x=32-16

1.An orthonormal basis for W is False.

2.If x is not in a subspace W, projw(x) is not zero then x True.

3.The QR factorization columns of Q form an orthonormal basis for the column space of A True.

An orthogonal set in a vector space necessarily mean that it is orthonormal are the vectors orthogonal to each other, but they unit length if {V1, V2, V3} is an orthogonal set in W, that the vectors are mutually orthogonal, but they may not have unit length {V1, V2, V3} assumed to be an orthonormal basis for W.

The projection of a vector x onto a subspace W, denoted as projW(x), is defined as the closest vector in W to x. If x is not in W, then the projection of x onto W will not be zero a nonzero vector in the subspace W that is closest to x.

In a QR factorization of a matrix A, where A has linearly independent columns, the matrix Q consists of orthonormal columns. The columns of Q form an orthonormal basis for the column space of A.

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this is example

So, first we need to write the given ratio as fraction,

= 8/18

= (8 × 2)/(18 × 2)

= 16/36

= 16 : 36 (one equivalent ratio),

So, 16 : 36 is an equivalent ratio of 8 : 18.

Now we will find another equivalent ratio of 8 : 18 by using division.

Similarly, first we need to write the given ratio as fraction,

= 8/18

= (8 ÷ 2)/(18 ÷ 2)

= 4/9

= 4 : 9 (another equivalent ratio)

So, 4 : 9 is an equivalent ratio of 8 : 18.

Therefore, the two equivalent ratios of 8 : 18 are 16 : 36 and 4 : 9.

2. Frame two equivalent ratios of 4 : 5.

Solution:

To find two equivalent ratios of 4 : 5 we need to apply multiplication method only to get the answer in integer form.

First we need to write the given ratio as fraction,

= 4/5

= (4 × 2)/(5 × 2)

= 8/10

= 8 : 10 is one equivalent ratio,

Similarly again, we need to write the given ratio 4 : 5 as fraction to get another equivalent ratio;

= 4/5

= (4 × 3)/(5 × 3)

= 12/15 is another equivalent ratio

Therefore, the two equivalent ratios of 4 : 5 are 8 : 10 and 12 : 15.

Note: In this question we can’t apply division method to get the answer in integer form because the G.C.F. of 4 and 5 is 1. That means, 4 and 5 cannot be divisible by any other number except 1.

The two equivalent ratios of 5:8:4 are 8: 10 and 12: 15.

The fraction is defined as the division of the whole part into an equal number of parts. In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

First, we need to write the given ratio as a fraction,

F= 8/18

F= (8 × 2)/(18 × 2)

F= 16/36

F= 16 : 36 (one equivalent ratio),

16: 36 is an equivalent ratio of 8: 18.

Find another equivalent ratio of 8: 18 by using division. Similarly, first, we need to write the given ratio as a fraction,

F= 8/18

F= (8 ÷ 2)/(18 ÷ 2)

F= 4/9

F= 4 : 9 (another equivalent ratio)

4: 9 is an equivalent ratio of 8: 18.

Therefore, the two equivalent ratios of 5:8:4 are 16: 36 and 4: 9.

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