PLEASE HELPP!!!
(look at the picture)
Answer:
I believe the answer is trench.
Explanation:
Hope this helps! <3
Answer:
B. Fault
Explanation:
Please correct me if I’m wrong
(it’s either b or c)
A boy throws a ball with a velocity of 30m/s.Find the total tome elapsed between throwing and catching the ball
(take g=10m/s2)
Answer:
x=45.92m
Explanation:
It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.
V^2=U^2+2*a*x
V=0 (as it is at max height)
U=30ms^-1 (initial speed)
a=-g /-9.8ms^-2 (as it is moving against gravity)
x is the variable you want to calculate (height)
0=30^2+2*(-9.8)*x
x=-30^2/2*-9.8
x=45.92m
With these questions it's best to just memorise the suvat equations and either draw or imagine the actions involved, that was you can tell what piece of given information translates to which variable. For example; I know that I am looking for max height, so when a ball is at its highest point, it can't be moving up anymore (thus V = 0). I also know that it is moving upwards against gravity, so gravity will be decelerating the ball (therefore a=-g). In a paper, it may as for assumptions with this question, a good answer would be no air resistance or movement due to any other external forces. I hope I helped :)
Answer:
By applying the law of conservation of energy, we can write the following equation.
Gain in potential energy =loss in kinetic energy.
mgh = 1/2(mu^2)
Where, the symbols represent usual quantities.
Hence, h = u^2/2g = 30^2/2x10 = 900/20
= 45 m
Hence, the maximum height attained is 45 m.
Alternative method:
v^2 = u^2 +2gh
0 = 30^2 +2(-10)h, at the highest point v=0
20h = 900
h = 900/20 = 45 m
help me for 11 point pls
Answer:
B
Explanation:
Hope this helps. :)
If a pair of shoes with a mass of 0.5 kg weigh 0.3 N, what is the strength of
gravity on Pluto? (Include units in your answer) *
Answer:
The strength of gravity on Pluto is 0.6 m/s²
Explanation:
The given mass of the shoe = 0.5 kg
The weight of the shoe (on Pluto), W = 0.3 N
Therefore, given that weight, W = Mass × The acceleration due to gravity, We have;
The strength of gravity = The force gravity applies to each unit of mass = The acceleration due to gravity (in m/s²)
The weight of the shoe, W = The mass of the shoe × The strength of gravity on Pluto
Substituting the known values, gives;
0.3 = 0.5 × The strength of gravity on Pluto
∴ The strength of gravity on Pluto = 0.6 m/s².
15. Use the chemical equation below to determine how many moles of ammonia
(NH) will be produced from 4 moles of nitrogen gas (N). Assume that there is enough H, for all of the N, to be converted to NH.
N2 + 3H2 + 2NH
8 moles
2 moles
3 moles
4 moles
Answer:
I'm not really sure but I think it is
four
A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?
Answer:
Explanation:
The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.
A weightlifter takes 0.5s to raise a barbell with 2 free-weights from the ground to a height of 0.9m. If each free-weight has a mass of 30kg and the barbell has a mass of 20kg, calculate how much power the weightlifter produces when lifting the barbell?
Answer:
P = 1412.82 [Watt]
Explanation:
First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.
[tex]m=30+30+20\\m= 80 [kg][/tex]
Weight is now defined as the product of mass by gravitational acceleration.
[tex]w=m*g[/tex]
where:
m = mass = 80 [kg]
g = gravity acceleration = 9.81 [m/s²]
[tex]w=80*9.81\\w=784.8[N][/tex]
Now using the product of the weight by the distance traveled we can calculate the work.
[tex]W=w*d[/tex]
where:
W = work [J]
w = weight = 784.8 [N]
d = distance = 0.9 [m]
[tex]W=784.8*0.9\\W=706.41[J][/tex]
And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.
[tex]P=W/t\\P=706.41/0.5\\P=1412.82[W][/tex]
Block on inclined plane experience a force due to gravity of 300N straight down. If the slope is inclined at 67.8°to the horizontal. What is the component of the force due to gravity perpendicular and parallel to the slope?
Answer:
The component of the force due to gravity perpendicular and parallel to the slope is 113.4 N and 277.8 N respectively.
Explanation:
Force is any cause capable of modifying the state of motion or rest of a body or of producing a deformation in it. Any force can be decomposed into two vectors, so that the sum of both vectors matches the vector before decomposing. The decomposition of a force into its components can be done in any direction.
Taking into account the simple trigonometric relations, such as sine, cosine and tangent, the value of their components and the value of the angle of application, then the parallel and perpendicular components will be:
Fparallel = F*sinα =300 N*sin 67.8° =300 N*0.926⇒ Fparallel =277.8 N Fperpendicular = F*cosα = 300 N*cos 67.8° = 300 N*0.378 ⇒ Fperpendicular= 113.4 NThe component of the force due to gravity perpendicular and parallel to the slope is 113.4 N and 277.8 N respectively.
An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?
Answer:
You need to put the diagrams. repost and include the diagrams
Please help asdfghjkll=
Answer:
Oh god
i have nooooo idea
Solid solutions containing two or more metal are commonly called alloys. True or false
Answer:
True
Explanation:
An alloy is a combination of metals or metals combined with one or more other elements. For example, combining the metallic elements gold and copper produces red gold, gold and silver becomes white gold, and silver combined with copper produces sterling silver.
Answer:
this is true
Explanation:
yes yes true
What is the mass of an object that accelerates at 5 m/s2 when pushed with 100 N?
Answer:
the answer is 20g
Explanation:
Data:
acceleration:5m/s2
force:100N
mass:?
solution:
force: mass*acceleration
mass: force divided by acceleration
mass:100/5
mass:20g
or another way of solving it is
force: mass*acceleration
100:mass*5
100/5 : mass
20g:mass
Definition of distance travelled?
Answer:
distance traveled is a total length of the path traveled between two positions.
how big is the universe?
sorry this is so random
Answer:
Explanation: 46 billion light years I think
Aww I wanted brainliest:( be doggo, doggo sad :(
Explain why the potential differences across each bulb do not add to the battery’s voltage, when the switch is closed.
Answer:
This is due to the gap in between the switch. So the applied energy is not converted to current even though the resistance is still there. Hence voltage will be there, where you applied it
Explanation:
A 200-gram baseball traveling at 48 m/s is hit by a bat and rebounds in the opposite direction at 52 m/s. Find the average force of the bat on the ball if the time of contact is 2.0x10-3 s.
Answer:
400N
Explanation:
Given the following parameters
Mass m = 200g = 0.2kg
initial velocity u = 48m/s
Final velocity v = 52m/s
Time t = 2.0x10-3 s.
Impulse is expressed as I = Ft = m(v-u)
Ft = m(v-u)
F = m(v-u)/t
Substitute the given values into the formula
F = 0.2(52-48)/0.002
F = 0.2(4)/0.002
F = 0.8/0.002
F = 400N
Hence the average force of the bat on the ball is 400N
A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the net force on the ball during acceleration?
Answer:
acceleration = v-u /t
30- 20/5
= 10/5 = 2m/sec²
Force = mass * acceleration
Force = 0.1 * 2
Force = 0.2 Newton
Answer:
I hope the above pic will help you
I will always help you understanding your assingments
have a great day #Captainpower:)
A fish swimming at a rate of .6 m/s notices a huge shark. Three seconds later, the fish is swimming at a speed of 3 m/s. What is the fish's acceleration?
0.8 m/s/s
-0.8 m/s/s
12.5 m/s/s
-12.5 m/s/s
Answer:
C
Explanation:
???
i think
i) The energy stored in wound watch spring is
a) K.E
b) P.E
c) Heat Energy
d) Chemical Energy
Answer:
Springs when non compressed has potential energy.
Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates for twice as long as Jim. Describe the final speed of Joe compared to Jim.
Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Answer the following
1) A piece of gold weighis 240 g and has a volume of 20 cm^3. Find the density of gold.
2) What is the perpendicular distance between the force and the turning point if a force
of 25 N produces a moment of force of 12.5 Nm
pls answer fast I will mark as brainlist
Answer:
1. 12 g/cm³
2. 0.5 m
Explanation:
1.
The weight of the gold is 240 g
The volume is 20 cm³
Density = Mass/ volume
Density = 240 / 20 = 12 g/cm³
2.
The formula for moment of a force is ;
Force * distance perpendicular between force and the turning point of force
Given that the moment of force is 12.5 Nm and force is 25 N then the perpendicular distance between the force and the turning point will be;
12.5 = 25 * d
12.5/25 = d
0.5 = d
d= 0.5 m
what is 0.94kg divided by 2.4n
Answer:
0.39166666666
Explanation:
The temperature of rock located 1,000 kilometers below the Earth's surface is about a. 200 C b.2,100 C c.2,800 C d.3,200 C
The temperature of the rock located at 1,000 km below the earth' surface has been 3200 degree Celsius. Thus, option D is correct.
The temperature at the earth's surface has been found to be nearly 0 degree Celsius. According to the geology of the earth, the temperature has been increased to 1500 degree Celsius by digging 100 km below the earth surface.
Thus, the temperature at 100 km from earth surface has been 1500 degree Celsius.
On moving down from 100 km, there has been a rise in temperature, and at the mouth of the mantle at 1000 km, the temperature has been approximately 3500 degree Celsius.
Thus the temperature that has been near about 3500 degree Celsius is 3200 degree Celsius. Thus, the temperature of the rock at 1000 km below the earth surface has been 3200 degree Celsius. Thus, option D is correct.
For more information about the temperature of earth, refer to the link:
https://brainly.com/question/893891
How much work is required to lift a 500 kg block 12 m? (Show work)
The required work done will be "6000 kg-m".
Work and energy:Work would be defined as an object's displacement whenever a force would be exerted to that as well, whereas energy is defined as the capacity to accomplish the work.
This then exists throughout a variety of forms, including potential, kinetic, biochemical, thermodynamic, nuclear, as well as direct current.
According to the question,
Mass, m = 500 kg
Distance, d = 12 m
We know the formula,
→ Work = Force x Distance
or,
→ W = F x D
By substituting the given values in the above formula, we get
= [tex]500\times 12[/tex]
= [tex]6000[/tex] kg-m
Thus the above answer is correct.
Find out more information about work done here:
https://brainly.com/question/25573309
A wagon having a mass of 42 kg is accelerated across a level road at 1.50 m/s2. What net force acts on the wagon horizontally?
Answer:
The net force acting on the wagon is 63 N
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass (m) is:
F = m.a
Where (a) is the acceleration of the object.
The wagon has a mass of m=42 Kg is accelerated at [tex]a=1.5\ m/s^2[/tex]. The net force is:
F = 42*1.5
F = 63 N
The net force acting on the wagon is 63 N
In May 1990 the French TGV train traveled the distance from Paris to Lille, France (127 miles) in 0.819 hours. What was the speed of the TGV in m/s
Answer:
v=69.32 m/s
Explanation:
you have to transfer the distance from mile to meters (from miles to meters multiply by 1609)
so d=204387 m
you have to transfer the time from hour to second (from hour to second multiply by 3600)
so t=2948.4 s
the rule says v=d/t=204387/2948.4= 69.32 m/s
The TGV train has a speed of 69.306 meters per second.
Let suppose that TGV train is travelling at uniform velocity, then we can be calculated its speed by means of the following kinematic equation:
[tex]v = \frac{x}{t}[/tex] (1)
Where:
[tex]v[/tex] - Speed, in meters per second.[tex]x[/tex] - Distance travelled by the train, in meters.[tex]t[/tex] - Time, in seconds.Now we proceed to convert both distance and time in terms of fundamental units:
Distance:
[tex]x = 127\,mi \times 1609\,\frac{m}{mi}[/tex]
[tex]x = 204343\,m[/tex]
Time:
[tex]t = 0.819\,h \times 3600\,\frac{s}{h}[/tex]
[tex]t = 2948.4\,s[/tex]
If we know that [tex]x = 204343\,m[/tex] and [tex]t = 2948.4\,s[/tex], then the speed of the TGV train is:
[tex]v = \frac{204343\,m}{2948.4\,s}[/tex]
[tex]v = 69.306\,\frac{m}{s}[/tex]
The TGV train has a speed of 69.306 meters per second.
We kindly invite you to check this question about kinematics: https://brainly.com/question/24468164
the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equator option d increase from pole to equator which is the answer
Answer:
D. Increases from pole to equator
Explanation:
I majored in Science
for an object in free fall, calculate the rate of change of the velocity from the first to the 100th second (metric units).
Answer:
The rate of change of velocity is 9.81 m/[tex]s^2[/tex].
Explanation:
By using the equation of motion, the velocity of any object in free fall at any instant, [tex]v=u+gt[/tex]
Where u (constant) is the initial velocity,
[tex]g=9.81 m/s^2[/tex] is the acceleration due to gravity,
v= velocity at time t.
To get the rate of change of velocity, differentiating the velocity, v, with respect to time, as
[tex]\frac {dv}{dt}=\frac{d}{dt}(u+gt) \\\\=\frac{d}{dt}u +\frac{d}{dt}(gt) \\\\=0+g\\\\=g[/tex]
[tex]\Rightarrow \frac{dv}{dt}=9.81 m/s^2[/tex]
Hence, the rate of change of velocity is 9.81 m/[tex]s^2[/tex].
A container with a mass of 5 kg is lifted to a height of 8 m. How much work is done by the gravitational force
Answer:
work done=392J
Explanation:
work done =Mgh
DATA
M=5kg
g= 9.8
h=8m
W=Mgh
W=5*9.8*8
W=392J
The work done by the gravitational force is equal to -400 J.
What is gravitational force?The gravitational force can be described as a force that attracts a body towards the center of the earth or any physical object that has mass. Every object has mass and exerts a gravitational pull on another object with mass.
Given, the mass of the container, m = 5 Kg
The height from the ground level, h = 8 m
The work done can be calculated by using the below-mentioned formula:
[tex]W = m\times g\times h[/tex]
Where g is the gravitational acceleration.
As the container is lifted in the upward direction therefore the value of the g will be negative.
Substitute the values of m, g, and h in the above formula:
W = 5 × (-10) × 8
W = -400 J.
The negative sign shows that the work is done against the gravitational force.
Therefore, the work done by the gravitational force is equal to -400 J.
Learn more about gravitational force, here:
brainly.com/question/24783651
#SPJ6
how the number of batteries and the number of coils of wire affect the strength of an electromagnet.