I understand your question and E=0.0693J is the maximum energy stored in the magnetic field during the collision, assuming that the carts never touch each other.
What is magnetic field?The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.Solution:to find the energy do as follows.
E=K 1 +K 2=0.5mv 12 +0.5mv 22 =0.5m(v 12+v 22 )
E=0.5(1.1)(0.323^2+(-0.147)^2)=0.0693J.E=0.5(1.1)(0.3232 +(−0.147)2)
E=0.0693J.
Hence, E=0.0693J is the maximum energy stored in the magnetic field during the collision, assuming that the carts never touch each other.
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The complete question is ;
10-kg carts on a low-friction track are rigged with magnets so that the carts repel each other when they approach each other. One cart has an initial velocity of +0.323 m/s, and the other has an initial velocity of -0.147 m/s.
What is the maximum energy stored in the magnetic field during the collision, assuming that the carts never touch each other?
what is the maximum horizontal force that can be applied to the lower block without the upper block slipping?
The maximum horizontal force that can be applied to the lower block without the upper block slipping is 4.7 N.
We know that, F net = m * a
Given that, mass of the first block = 0.5 kg
Mass of the lower block = 1 kg
The coefficient of friction between the bigger block and the table is 0.2.
The two blocks have 0.35 coefficient of friction.
The force between the table and the blocks is
F k = 1.5 * 9.8 * 0.20 = 2.94 N
The force between the two blocks is
F s = 0.5 * 9.8 * 0.35 = 1.1715 N
So, the maximum horizontal force is
1.715 = Fa - 2.94
Fa = 1.715 + 2.94 = 4.655 N = 4.7 N
Thus, the maximum horizontal force that can be applied to the lower block without the upper block slipping is 4.7 N.
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how much heat, in joules, does it take to raise the temperature of 225.0 g of water from 25.0°c to 100.0°c ?
The heat required to raise the temperature of 225.0 g of water from 25.0°c to 100.0°c is 70,537.5J
Heat = specific heat capacity of the substance × mass of the substance in grams × temperature difference
Let us rewrite the equation as
q=mcΔT
Where q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance and ΔT is the temperature difference.
m=225g
ΔT=100-25=72
c=4.18J/gC
Let us substitute the values.
q=225×75×4.18
q=70537.5J
What is specific heat capacity?
Specific heat capacity, or simply specific heat, refers to the heat capacity per unit mass of a pure substance. In other words, it is defined as the amount of heat needed to increase the temperature of 1kg of a material by 1K and is expressed in terms of J/kg·K or equivalently J/kg·°C.
How do you calculate the specific heat of water?
The specific heat capacity of water is 4.18 J/g/°C. We wish to determine the value of Q - the quantity of heat. To do so, we would use the equation Q = m•C•ΔT. The m and the C are known; the ΔT can be determined from the initial and final temperature.
Thus, the heat required is 70537.5J
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a 2kg ball rolls at a speed of 4m/s. if friction slows it down to 3m/s, how much work did it do?
The work done by friction in slowing down the ball from 4 m/s to 3 m/s is 7 J.
What is workdone?Work is said to be done whenever a body is moved by a force through a certain distance.
To calculate the work done by friction, in slowing down the ball, we use the formula below.
Formula:
W = m(u²-v²)/2........ Equation 1Where:
W = Work done by friction in slowing down the ballm = Mass of the ballv = Final speed of the ballu = Initial speed of the ballFrom the question,
Given:
m = 2 kgu = 4 m/sv = 3 m/sSubstitute these values into equation 1
W = 2(4²-3²)/2W = 2×7/2W = 7JHence, the work done by friction is 7 J.
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if a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion?
When the length of a simple pendulum, which oscillates with minimal amplitude, is doubled, the frequency of the oscillation stays the same.
What is the meaning of amplitude?
In physics, amplitude refers to the greatest displacement or distance that a spot on a vibration or wave can move relative to its equilibrium location. It is equal to the half-length of the vibration path.
What is the amplitude measured in?
The amplitude, which is measured in metric units (m), is the largest displacement that a medium's particles can experience from their average positions during the propagation of a wave. Meters are the SI unit of displacement. So, the amplitude unit in SI is the meter.
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The force of impact at 20 mph is what times that at 10 mph speeds
The force of impact at 20 mph is two times that at 10 mph speeds.
What is effect of force?An object can change its size or shape, begin moving, stop moving, accelerate, or decelerate as a result of a force acting on it. When two things contact, they exert pressures on one another that are identical in size but directed in the opposite direction.
The combined effect of all the forces acting on an object is known as the "resultant force," and it is the same as if only one force were to be operating on the object in that direction. To alter an object's velocity, the resulting force is necessary.
The force required for increasing speed 20 mph of an object of mass m at an interval of time t be = m×20/t.
The force required for increasing speed 10mph of an object of mass m at an interval of time t be = m×10/t.
Hence, the force of impact at 20 mph is two times that at 10 mph speeds.
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Why might a wine glass survive a fall onto a carpeted floor but not onto a concrete floor?.
A woman is driving at a velocity of 33.86 m/s at an angle of 23° What is the Y component of her velocity?
Answer:
The values are provided in question Velocity V = 12.72…
Explanation:
The velocity will equal v=12.72
At which reference point should your vehicle appear to intersect with the curb when parallel parking?
The reference point at which vehicle appear to intersect the curb is 2.22km.
To ensure that every parallel park is successfully completed, it is crucial to employ a structured technique and to practice it until a level of proficiency is attained. However, contrary to popular belief, it need not be completed in a single seamless maneuver.
During the maneuver, it is acceptable to advance and make adjustments as long as you do so safely and keep an eye on your surroundings at all times.
Utilizing reference points, a structured technique is applied. Whatever method is used to parallel park, using reference points will help new drivers complete this maneuver.
You should slightly pass the car you plan to park behind. The front of this car is aligned with the center of your passenger-side front window in reference point.
[tex]Reference=\frac{\pi }{\sqrt{2} }[/tex]
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a 6 kg box is pushed with a force of 41 n at the moment it starts to accelerate from rest across the carpet. calculate the coefficient of static friction between the box and the carpet.
The coefficient of static friction between the carpet and the box is found to be 0.68.
The mass of the box is 6 kg and a force f of 41 newton is applied at the moment it starts to accelerate from rest across the carpet. If the net force is f and the force of friction between the carpet and the box is Fr.
We can write,
f = Fr
We know, force of friction is given by,
Fr = uN
N is the normal that is equal to weight of body,
u is the coefficient of static friction between the carpet and the box.
Putting values,
f = uN
41 = u(6×10)
u = 41/60
u = 0.68
So, the coefficient of static friction is found to be 0.68.
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A skier starts from rest at the top of a hill that is inclined at 10.5° with the horizontal. The hillside is 200.0 m long, and the coefficient of friction between the snow and the skis is 0.075. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest? Show all of your work.
Answer:
2000
Explanation:
ddoes rest : add the components
for a constant force, suppose the duration of impact on an object is doubled. a. how much is the impulse increased? b. how much is the resulting change in momentum increased?
Momentum is force * time. Momentum is also a change of momentum. that's why,
power * time
=
change in dynamics
For constant force, doubling the collision time doubles the momentum, resulting in a doubling of the momentum change.
The change in momentum is equal to the product of the change in mass and velocity. The mass remains the same because it is a constant value. It is the change in velocity that causes the change in momentum. The change in momentum is denoted by the symbol Δp.
What is the formula for momentum change?
1) The change in momentum is equal to the product of the change in mass and velocity. ⇒ΔP=m.
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Answer:
Explanation:
Momentum is force * time. Momentum is also a change of momentum. that's why,
power * time
=
change in dynamics
On a planet whose radius is 1.2×1010m, the acceleration due to gravity at the surface of the planet is 15m/s2. What is the mass of the planet?plese help me
Refer to the photo taken.
Sport question:
Move used in many sports where the ball carrier keeps one foot planted on the ground but is allowed to rotate on that foot
Answer:
That move is called a pivot foot.
Explanation:
this photo shows apparatus used in an experiment in which materials thought to have been present on the early earth were sparked with energy. what have we learned from this type of experiment?
These experiments have shown that the building blocks of life form easily and naturally under conditions that existed on early Earth.
Who proposed the idea of the nebular hypothesis?
The generally accepted model for the formation of the solar system is called the nebular hypothesis. It takes all the different kinds of information and merges them into one hypothesis that seems to match all the observations. The theory was proposed by French mathematician Pierre Simon Laplace more than 200 years ago.
What is astrobiology and what type of research does it involve?
Astrobiology is the study of life within the universe. Astrobiologists study how life forms and develops, and where life can be found. Astrobiology involves the search for life outside Earth, the study of planets and moons within our Solar System, and the search for habitable planets around other stars.
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A 275-kg load is lifted 23.0 m vertically with an acceleration a=0.200 g by a single cable. Determine (a) the tension in the cable, (b) the net work done on the load, (c) the work done by the cable on the load, (d) the work done by gravity on the load, and (e) the final speed of the load assuming it started from rest.
Let's calculate T = 275 (-23.0 - 0.200) and T = -6380 N using the formulas T - W = m a, T = W + ma, and T = m (g + a). B) Network is weight work less stress work. W = F d, T-W d, m a d, (275- 0.200) 23, W = 270.4 J
The tension the net work done on the load?The tension formula is expressed as. T=mg+ma. where T is tension and g is the gravitational acceleration (9.8 m/s2). The load's mass is M = 275 kg, and its acceleration is a = 0.12 g. Let T represent the cable's tension. The load accelerates upwardly as well as being raised vertically. Because of this, according to Newton's laws, T = M ( g + a ) = 275 1.12 9.8 = 3018.4 N
Calculate the work done by gravity on the load, the work done by the cable on the load, and other factors.According to sign convention, the task that the cable has done W = F. d, W = F d cos 180, W = -285 22.0, W = 2.79 103 J The work done by the weight is up and the weight points down, therefore the angle is 180o. W = T d cos 0 W = 2838.6 22.0 W = 6.22 104 J d)
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An 893-kg (1974 lb) dragster, starting from rest, attains a speed of 25.8 m/s (57.8 mph) in 0.59 s.
(a) Find the average acceleration of the dragster during this time interval.
(b) What is the magnitude of the average net force on the dragster during this time?
(c) Assume that the driver has a mass of 68 kg. What horizontal force does the seat exert on the driver?
Hello,
I hope you and your family are doing well!
(a) To find the average acceleration of the dragster, we can use the equation:
average acceleration = (final velocity - initial velocity)/time interval
Plugging in the values from the problem, we get:
average acceleration = (25.8 m/s - 0 m/s)/0.59 s = 43.7 m/s^2
(b) The net force on an object is equal to its mass times its acceleration, so the net force on the dragster during this time interval is:
net force = 893 kg * 43.7 m/s^2 = 38,971 N
(c) To find the horizontal force the seat exerts on the driver, we can use the equation:
force = mass * acceleration
The acceleration of the driver is the same as the acceleration of the dragster, which we found to be 43.7 m/s^2. Plugging this value into the equation, we get:
force = 68 kg * 43.7 m/s^2 = 2970 N
So the seat exerts a force of 2970 N on the driver.
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A skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.
Time after jump | Weight | Air Resistance
1 sec | 500 N | 200 N
2 sec | 500 N | 300 N
3 sec | 500 N | 400 N
4 sec | 500 N | 500 N
Which statement best identifies her speed at each second?
a. The skydriver has the slowest speed at 2 seconds
b. The skydriver has the fastest speed at 4 seconds
c. The skydriver has the slowest speed at 1 second
d. The skydriver has the fastest speed at # seconds
The statement that best identifies her speed at each second is as follows: the sky driver has the fastest speed at 4 seconds (option B).
What is air resistance?Air resistance is the action of friction that slows something moving through air.
Air resistance is dependent on velocity, area, and shape of the object going through the air. Altitude, temperature, and humidity change air density and, consequently, its resistance.
The higher the speed and the bigger the area, the higher the resistance. As speed increases so too does the frequency of the collision of air molecules with the object. This results in an increase in air resistance.
Therefore, as the sky driver with a weight of 500N increases in air resistance, the speed also increases.
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how do we determine the amount of dark matter in elliptical galaxies? how do we determine the amount of dark matter in elliptical galaxies? we measure the range of speeds of collections of stars at different distances from the galactic center and determine how much mass is interior to their orbits. we count the number of stars in the galaxy and determine its volume, so that we can calculate the galaxy's density. we measure how fast the galaxy rotates as a whole. we measure the orbital velocities of star-forming gas clouds around the outer portions of the galaxy. we search for dark lanes of dust and black holes within the galaxy.
To determine the amount of dark matter in elliptical galaxies, we have to: B. Measure the speeds of stars at different radii from the galactic center and determine how much mass is interior to the orbit.
How to measure dark matter in elliptical galaxies?Dark matter is a type of matter in the universe that does not interact with electromagnetic force. So, unlike ordinary matter, it does not absorb, reflect, or emit light. One of three ways to determine the amount of dark matter in elliptical galaxies is by measuring the galaxy's radius and the average of stars' movement (stars' speed) of that galaxy. We also need to calculate the ratio of mass-to-light from there. This method of measurement is called dynamical mass.
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the length of the path traveled by light in a vacuum in 1/299,792,458th of a second
A vacuum is an area devoid of matter, also referred to as "free-space." Practically speaking, only partial vacuums are feasible.
What do you meant by vacuums?North Americans typically refer to this electrical device as a vacuum cleaner or just a vacuum, whereas Britons typically refer to it as a hoover.
Both terms can be inflected to become verbs such as vacuumed, vacuuming, hoovered, and hoovering. A vacuum is an area devoid of matter, also referred to as "free-space."
Practically speaking, only partial vacuums are feasible. A great bagless upright vacuum, a respectable cordless vacuum, and a simple (but effective!) robot vacuum are just a few of the several vacuums we suggest; they typically cost around $150. Since the middle of the 19th century, a British person has been referred to as a "Limey" (from lime or lemon) in slang.
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Why do excavators have broad steel track chain instead of normal wheels?
Answer:
Increase the pressure , hence decreasing the force acting on the ground
The block is pushed by an
outside force.
Is energy conserved or not?
Answer:yes
Explanation:
Maryam used the graduated cylinder to measure the volume of an unknown liquid in the physics lab the volume she measured was 46.0 mL then the teacher asked her to mix it with 1.20 mL of water (what is the value of the mixture in (L) )
The total volume of the liquid in the graduated cylinder in liters is 0.0472 L.
What is the total volume of the mixture?The total volume of the mixture is the sum of the volume of all the liquid in the cylinder.
Mathematically, the formula for the total volume of the liquid in the graduated cylinder is calculated as follows;
V ( total ) = volume of the liquid + volume of the water
The given parameters include the following;
The volume of the liquid in the graduated cylinder = 46 mL
The volume of water in the graduated cylinder = 1.2 mL
The total volume of the liquid in the graduated cylinder is calculated as;
V (total) = 46 mL + 1.2 mL
V (total) = 47.2 mL
The total volume of the liquid in the graduated cylinder in liters is calculated as;
V (total in liters) = 47.2 mL / 1000 = 0.0472 L
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The block slides down an inclined track to a infinite length flat surface. The block comes to a stop on its own. Is energy being conserved or not conserved?
Energy is conserved as the block slides down because kinetic energy is converted to heat energy.
Is energy conserved?We are looking at the principle of the conservation of energy. We know that the principle of the conservation of energy states that energy can neither be created nor destroyed but it can be converted from one form to another.
Now we know that the energy of the block would remain constant. Given the fact that energy is not created or destroyed, we can see that as the block is sliding down, the block would be loosing energy thus it would become slower. This is because of the fact that friction is working against the movement of the block and the energy that is lost is converted to heat.
Thus we can say that the energy is converted to heat as the the block is slowing down thus energy is conserved.
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Compare the magnitude of the electromagnetic and gravitational force between two electrons separated by a distance of 2.00 m. Assume the electrons have a mass of 9.11 × 10–31 kg and a charge of 1.61 × 10–19 C. Round to two decimal places. Fe = × 10–29 N Fg = × 10–71 N F Subscript e baseline over F Subscript g baseline.= × 1042
Two metal spheres with the same charge, q, are in contact and experience an electrostatic force of magnitude F. 2.3x10 N 66.
What connection can be seen between the mass of the items, their distance from one another, and the strength of the gravitational pull between them?A mass-bearing item will pull toward another mass-bearing object. The strength of the force is directly proportional to the masses of the two objects and inversely proportional to the square of their distances from one another.
How much do two electrons separated in space weigh in terms of electrostatic and gravitational forces?Consequently, the ratio of electric to gravitational force between two electrons is 4.17 1042.
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Twin sisters Paola and Maria have a slight difference in their handwriting. Paola slants her letters more than Maria does. Which of the following elements BEST describes the area in which their handwriting differs?
A.
mechanical
B.
physical
C.
style
D.
emotional
Answer:
C. Style
Explanation:
Because if your letters are slanted, it's not mechanical, is it? Neither is it emotional, since that's just not right. As for physical, how is your letters being slanted physical? Therefore, the best answer would be C. Style.
Brainliest, Please!A 5.5 Kg rock falling in air experience a force due to air resistance of 50N. What is the acceleration
Answer:
F1 = ma = 5.5 kg * 10 m/s² = 55 N (force acts downwards)
F2 = - 50 N (force acts upwards)
net force = 5 N (downwards)
F = ma
a = F/m
a = 5 / 5.5
a = 0.91 m/s²
Explanation:
Since the object is falling downwards, the air resistance acts upwards. We also have a force acting downwards since the rock experiences gravitational acceleration (the value of g above is 10 m/s² for the sake of easier calculation but you can also set it to be 9.81 m/s² which is the more accurate value). Since the air resistance and force due to gravity are acting in opposite directions and force is a vector, we have to put a minus in front of F1 or F2 (it doesn't matter which direction you chose to be the positive one) . Then we calculate the net force, aka the difference between F1 and F2. Finally, knowing the force and the mass, we can calculate the acceleration.
Marissa does 11.1 J of work to lower her window shade in her bedroom in 7 seconds. How powerful is Marissa?
Marissa does 11.1J of work in 7 seconds.
We know that, the expression of power,
P= W/t
Here, W is the work done and t is the time.
Substitute the required values to determine the value of the power of Marissa.
work done= 11.1 J
time taken = 7 seconds
Power = 11.1 / 7
Power = 1.58 W
Hence, Marissa is 1.58 W is powerful
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Three examples of physical changes are……?
Answer:Cutting, bending, dissolving, freezing, boiling, and melting
Explanation:
Please help! Will mark brainliest
Answer:
Runner B
Explanation:
its just displacement over change in time
When you drop a golf ball, why does it not bounce as high as the initial drop point
height? (hint: 2 reasons should be given)
There are two reasons why a golf ball does not bounce as high as the initial drop point height. First, when the golf ball hits the ground, it experiences a force of impact that causes it to deform slightly. This deformation dissipates some of the energy from the initial drop, reducing the height of the bounce.
Second, when the golf ball bounces, it experiences friction with the ground, which also dissipates some of the energy from the initial drop. This further reduces the height of the bounce. Together, these two factors explain why a golf ball does not bounce as high as its initial drop point height.