Answer:
50m
Explanation:im just smart thank me later
The range is 80 meter and the stone is 4.04 second in air.
What is projectile?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
Given that: maximum height obtained by the projectile; H = 20 m.
Let initial velocity = u
For maximum range:
H = u²/4g
u = √(4gH) = 28 m/s
and the range of the projectile = u²/g = 4H = 4 ×20 m = 80 m.
Total time of flight = √2· u/g = √2 ×28/9.8 = 4.04 second.
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g Calculate the electric potential at the center of the square with a side of 1 meter, formed by the four charged particles.
Answer:
The potential at the center of square due to four identical charges each at the corner is 5.09 q x [tex]10^1^0[/tex] Volts, where q is the charge.
Explanation:
From the question it is given that
side of square = a = 1 m
let the charge of each square is q
potential at center due to 1 charge is V = [tex]\frac{q}{4\pi \epsilon r}[/tex] , where
[tex]\epsilon[/tex] is electrical permittivity of space
r is the distance between charge and point.
since the charge is present at at the corner so the distance between charge and point is the half the length of diagonal of square.
⇒ distance between charge and point = r =[tex]\frac{a}{\sqrt{2}}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] = 0.707 m
thus, V= [tex]\frac{q}{4\pi \epsilon r}[/tex] , on substituting the respected values of r = 0.707m and [tex]\frac{1}{4\pi \epsilon}[/tex] = 9 x [tex]10^9[/tex] we get,
V = 1.272 q x [tex]10^1^0[/tex] V
thus potential due to all 4 charges is
V = 1.272 q x [tex]10^1^0[/tex] x 4 = 5.09 q x [tex]10^1^0[/tex] Volts
what causes sound to have low pitch
A.Sound Wave with high frequency.
B.sound wave with low frequency.
C.sound wave with large amplitude
D.sound wave with small amplitude
Estimate the net force needed to accelerate a 1000-kg car at 3m/s/s from rest.
FILL IN THE BLANKS.
If this force acts on this car for 4 seconds, then the car will increase its speed by ————————- m/s a second each second reaching a final speed of ————————- m/s. The distance traveled during this motion is ——————- meters.
Answer:
First Blank. 30,000
Second Blank. 12,000
Third Blank. 20.0
Explanation:
A crate is pulled 7 m across a smooth surface. The tension in the rope pulling the crate is 40 N. If the work on the crate is 247 J, what is the angle the rope makes with the horizontal
Answer:
61.9°
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
Hence the angle that the rope makes with the horizontal is 61.9°
What is the speed of a commercial jet which travels form New York to Los Angeles (4800) in 6 hours
Answer:
[tex]Speed = 800km}/hr[/tex]
Explanation:
Given
[tex]Distance = 4800km[/tex]
[tex]Time = 6hr[/tex]
Required
Determine the speed of the jet
The speed is calculated as:
[tex]Speed = \frac{Distance}{Time}[/tex]
Substitute 4800 km for Distance and 6hr for Time
[tex]Speed = \frac{4800km}{6hr}[/tex]
[tex]Speed = 800km}/hr[/tex]
Hence, the speed of the commercial jet is 800km/hr
A horizontal force of 5.0-N accelerates a 4.0-kg mass, from rest, at a rate of 0.50 m/s^2 in the positive direction. What friction force acts on the mass
Answer:
3N
Explanation:
The frictional force always acts directly opposite to the force of motion, that is it opposes motion. According to the Newton second law of motion:
Sum of horizontal forces = 0
Hence:
5N - 4(0.5) - F = 0
5 - 2 = F
F = 3N
the earth is broken into smaller subsystems including the atmosphere the biosphere and the hydrosphere true or false
Answer:
true
Explanation:
these are not the only parts of the atmosphere, i dont know the full list but i know these arent the only parts
A wrench is accidentally dropped at the top of an elevator shaft in a tall building. (a) How many meters does the wrench fall in 1.5s
Answer:
11.25m
Explanation:
[tex]s = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times 1.5 + \frac{1}{2} \times 10 \times {1.5}^{2} \\ = 5 \times 2.25 \\ = 11.25[/tex]
A zone plate is found to give series of images of a point source on its axis. If the strongest and the second strongest images are at distances of 0.30m and 0.06 m respectively from the zone plate (both from the same side remote from the source), calculate the distance of the source from the zone plate, principal focal length and the radius of the second zone. Assume λ = 6 x 10-7m.
You are sending waves down a spring. You send a small amplitude wave down the spring. Then you
send a large amplitude wave. The large amplitude wave is...
A.slower than the low amplitude wave
B.the same speed as the low amplitude wave
C.faster than the low amplitude wave
Answer:
a is the correct answer hope it will help you
Calculate, for the judge, how fast you were going in miles per hour when you ran the red light because it appeared Doppler-shifted green to you. Take red light to have a wavelength of 650 nm and green to have a wavelength of 550 nm.
Answer:
The doppler effect equation is:
[tex]f' = \frac{v +v0}{v - vs}*f[/tex]
In the equation we have frequencies, but then we have the wavelengths of the lights, remember the relation:
v = f*λ
then:
f = v/λ
and v is the speed of light, then:
f = c/λ
where:
f' is the observed frequency, in this case, is equal to f = (3*10^17nm/s)/550 nm
f is the real frequency, in this case, is (3*10^17nm/s)/650 nm
vs is the speed of the source, in this case, the source is not moving, then vs = 0 m/s.
v is the speed of the wave, in this case, is equal to the speed of light, v = 3*10^8 m/s
v0 is your speed, this is what we want to find.
Replacing those quantities in the equation, we get:
(3*10^17nm/s)/550 = (3*10^8 m/s + v0)/(3*10^8 m/s)*(3*10^17nm/s)/650 nm
(650nm)/(550nm) = (3*10^8 m/s + v0)/(3*10^8 m/s)
1.182*(3*10^8 m/s) = (3*10^8 m/s + v0)
1.182*(3*10^8 m/s) - (3*10^8 m/s) = v0 = 54,600,000 m/s
So your speed was 54,600,000 m/s, which is a lot.
Four charges of equal magnitude, q = +1 uC, are placed at the four corners of a square with a side length of 1 meter located in the xy-plane. A small ball with a known charge +2 uC and an unknown mass is placed 2 meters above the center of the square (so along the z-axis).
Required:
a. What is the total force on the small ball from the four charges?
b. If the ball is in equilibrium where it was placed and we assume standard earth gravity, 9.8 m/s^2, what must the mass of the ball be?
Answer:
a) F _total = 15.08 10⁻³ N , b) m = 1,539 10⁻³ kg
Explanation:
a) To solve this problem we can use Coulomb's law to find the force created by each charge
F =[tex]k \frac{\ q_{1} q_{2} }{r_{12}^{2} }[/tex]
and the total force is
F = F₁₅ + F₂₅ + F₃₅ + F₄₅
The bold are vectros, In the exercise they indicate the charges
q₁ = q₂= q₃ = q₄ = 1 10⁻⁶ C
q₅ = 2 10⁻⁶ C
Let's set a reference system where the sphere is on the z axis and the other charges on the xy plane, let's write the coordinates of card charge
sphere (subscript 5)
x₅ = 0
y₅ = 0
z₅ = 2 m
charge 1
x = 0.5 m
y = 0.5 m
z = 0
charge 2
x = -0.5 m
y = 0.5 m
z = 0
charge 3
x = -0.5 m
y = -0.5 m
z = 0
charge 4
x = 0.5 m
y = -0.5 m
z = 0
With these values we can calculate the distance between each charge and the sphere
charge 1 and sphere
r₁₅² = (x₅ -x₁)² + (y₅ - y₁)² + (z₅ -z₁)²
substitute
r₁₅² = (0- 0.5)² + (0 - 0.5)² + (2 -0)²
r₁₅² = 0.5² + 0.5² + 2²
r₁₅² = 4.5
we can see that for the other charges the result is the same since being squared always gives positive
r₁₅ = r₂₅ = r₃₅ = r₄₅
the force created by the card charge on the sphere is the projection on the Z axis of the total force
Let's find the angle with respect to the Z axis
tan φ = r / z
where r is the magnitude of the vector in the xy plane
r = [tex]\sqrt{0.5^{2} + 0.5^{2} }[/tex]
r = 0.7071 m
φ = tan⁻¹ r / z
φ = tan⁻¹ (0.7071 / 2)
φ = 19.5
consequently the total force is
F_total = 4 F cos 19.5
F _total = [tex]4 \frac{k \ q_{1} q_{5} }{r_{15}^{2}}[/tex] cos 19.5
let's calculate
F_toal = 4 9 10⁹ 1 10⁻⁶ 2 10⁻⁶ /4.5 cos 19.5
F _total = 15.08 10⁻³ N
b) For this part indicate that the sphere is in equilibrium with the weight
F_total - W = 0
W = mg
F_total = mg
m = F_total / g
m = 15.08 10³ / 9.8
m = 1,539 10⁻³ kg
How can land that was formerly used as dumps, mines, or factory sites be.
rehabilitated?
Answer:
clear out the junk, and plant some stuff
Explanation:
clear out all of the nasties, unless it is biodegradable, or you could get some mushrooms to break everything down, then you can go and plant some stuff or do whatever. You could turn it into a playground, park, whatever.
Please help me and thank you
Answer:
536.56 m/s
Explanation:
We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:
Mass (m) of Porsche = 1361 kg
Velocity (v) of Porsche = 26.82 m/s
Momentum of Porsche =?
Momentum = mass × velocity
Momentum = 1361 × 26.82
Momentum of Porsche = 36502.02 Kgm/s
Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:
Your Mass = 68.03 kg
Your Momentum = Momentum of Porsche = 36502.02 Kgm/s
Your velocity =?
Momentum = mass × velocity
36502.02 = 68.03 × velocity
Divide both side by 68.03
Velocity = 36502.02 / 68.03
Velocity = 536.56 m/s
Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.
What happens to the dewpoint temperature of a decreasing mass of air?
Answer:What happens to the dew point temperature of a descending mass of air? As air sinks, it becomes warmer. (Warmer air expands and can hold more water, therefore the dew point may increase.) ... The hot water causes condensation of water vapor as it touches the cooler mirror.
Explanation:
I will give 20 points and brainliest
Space exploration can lead to money going to U.S.
businesses and universities.
What are two things NASA might hire U.S. businesses and universities to do?
A. Teach people to read
B. Research new ideas
C. Build complex equipment
D. Improve athletic teams
Answer:
b and c
Explanation:
NASA might hire U.S. businesses and universities to do: Research new ideas, build complex equipment. Hence, option (b) and (c) are correct.
What is Space exploration?Astronomy and space technology are used in space exploration to learn more about the universe. While astronomers use telescopes to explore the universe, both unmanned robotic space missions and human spaceflight also participate in the physical exploration of space. One of the main sources of space science, like its traditional form astronomy, is space exploration.
Although astronomy, or the study of celestial objects, has existed since the beginning of trustworthy written history, it wasn't until the mid-20th century that the possibility of physical space exploration became a reality.
Space exploration can lead to money going to U.S. businesses and universities. Hence, NASA might hire U.S. businesses and universities to do: Research new ideas, build complex equipment.
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A/An _____ is described as a device used to store electrical energy, usually two conductors separated by an insulator.
Answer: A capacitor.
Explanation:
The capacitor is a passive element that is used in electronics to store electrical energy maintaining an electrical field. The simpler case of a capacitor is the parallel plates capacitor.
It consists of two parallel metal plates separated by a distance D, in this case, the air between the plates works as a dielectric, as the plates do not touch each other and are separated by a dielectric, the charge is stored in the surface plates.
There are a lot of other types of capacitors, the most used in actuality may be the cylindrical one, where instead of parallel plates, it uses two concentric cylinders, and the space between the cylinders is filled with a dielectric/insulator.
Why is 1/2kx^2=gym not a linear equation
Need help ASAP please helppp
Answer:
2.3 newtons of force
Explanation:
Divide the weight by the speed of the bike
( I will give a brainliest )
What must be changed, temperature or heat energy, during condensation?
Answer:
The answer is temperature lol
Explanation:
:)
Imagine that you were having a conversation with a behaviorist and an ethologist. What would you say to help them meet in the middle of the nature/nurture debate?
Answer:my points back
Explanation:
During conversations with behaviorists and ethologists, it is mandatory to have a speech of interest to meet in the middle of the debate.
What do mean by conversation?The mode of communicating any topic or an issue to others by means of a set of words and speeches is known as a conversation.
In order to meet in the middle of the conversation, one needs to be deliverable with topics related to the domain of interest. Here the domain of interest means anything that is related to the profession.
For example, a behaviorist's role is to create plans for managing the behaviors of students. Similarly, an ethologist is a scientist, who studies animal behaviors. So, one to talk only related to their professional kinds of stuff for sake of clear understanding.
Thus, we can conclude that during conversations with behaviorists and ethologists, it is mandatory to have a speech of interest to meet in the middle of the debate.
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if a train has 1,450 kg of momentum and is traveling at 40 m/s ¿what is the mass of tren?
Help plis I have this wrong
Answer:
P=mv
1x450,200=m40
m= 36,255kg
Find the height from which you would have to drop a ball so that it would have a speed of 7.4 m/s just before it hits the ground.
Answer:
s = 2.79 m
Explanation:
Given that,
A ball have a speed of 7.4 m/s just before it hits the ground.
Initial velocity of the ball was 0 (at rest)
We need to find the height from where the ball was dropped. It means we need to find the distance covered by it. Let it is h.
Using the third equation of motion to find it as follows :
[tex]v^2-u^2=2as\\\\s=\dfrac{v^2}{2g}\\\\s=\dfrac{(7.4)^2}{2\times 9.8}\\\\s=2.79\ m[/tex]
So, the ball is dropped from a height of 2.79 m.
The height from which you would have to drop a ball so that it would have a speed of 7.4 m/s just before it hits the ground is 2.79m
Equation of motionsAccording to the third equation of motion;
[tex]v^2=u^2+2as[/tex]
where;
v is the final velocity = 7.4m/s
Initial velocity = 0m/s
s is the distance
a = g= 9.8m/s²
Substitute the values into the formula to have:
[tex]7.4^2=0^2+2(9.8)s\\54.76 + 19.6s\\s=\frac{54.76}{19.6}\\ s=2.79m[/tex]
Hence the height from which you would have to drop a ball so that it would have a speed of 7.4 m/s just before it hits the ground is 2.79m
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PLZ HELP ASAP
With number 10 above
Answer:
P = 1500 Watt
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force.
Being F the magnitude of the force vector and s the distance, the work is calculated as:
W=F.s
Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.
The power can be calculated as:
[tex]\displaystyle P=\frac {W}{t}[/tex]
Where W is the work and t is the time.
The force to be considered is the weight of the mass of m=100 kg, [tex]g= 10\ m/s^2[/tex]:
F = 100 * 10 = 1000 N
The distance is s=3 m, thus the work done by the weight lifter is:
W = 1000 N * 3 m
W = 3000 J
Finally, the power is:
[tex]\displaystyle P=\frac {3000}{2}[/tex]
P = 1500 Watt
If a ball with a momentum of 40 kgm/s has a velocity of 2 m/s, what is its mass?
momentum (m)=40
velocity (v)=2
now,
momentum (m)=m×v
40=m×2
m=40÷2
m=20kg
what is instaneous velocity means explain it pls
Answer:
Simply, it's just the velocity at a given moment in time.
Explanation:
Instantaneous velocity is basically just short for the velocity of something at any given time. To give an example, let's say I wind up a toy car and set him to go forward for 10 seconds, and 5 seconds in, I freeze time. The speed of the car at that moment is the instantaneous velocity.
Help pleaseeee need the answers ASAP
Answer:
- 670 kg.m/s
Explanation:
Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s
An ostrich with a mass of 141 kg is running to the right with a velocity of 13m/s. Find the momentum of the ostrich. Answer in units of Kg.m/s
Answer:
1833 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 141 × 13
We have the final answer as
1833 kg.m/sHope this helps you
Deshaun Watson launches a football at a speed of 24.7 ms and an angle of 33° above the horizontal How far down
the football field does the football land? What is the max height the football reaches during flight?
Show work
Answer:
9.23m
Explanation:
Max height = u²sin²theta/2g
u is the speed = 34.7m/s
theta is the angle of elevation = 33°
g is the acceleration due to gravity = 9.8m/s²
Substitute into the formula
Max height = 24.7²sin²33/2(9.8)
Max height = 610.09sin²33/2(9.8)
Max height = 610.09(0.29663)/19.6
Max height = 180.97/19.6
Max Height = 9.23m
Hence the max height the football reaches during flight is 9.23m
Q2) A Ferrari moves at 240 km/h for 1.2 h. How far it will go.
Answer:
Explanation:
Multiply the two numbers to get the distance. 240 x 1.2 = 288km