which is a way to express concentration of a solution? parts per billion moles molar mass force per square meter​

The chemist weigh out 35.51 g Na2SO4

Given

0.250 moles of Na2SO4

Required

weight of Na2SO4

Solution

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Moles of a substance can also be determined from its molecular weight

[tex]\tt mol=\dfrac{mass}{MW}[/tex]

For 0.250 moles of Na2SO4, mass =

[tex]\tt mass=mol\times MW\\\\mass=0.25\times 142,04 g/mol\\\\mass=35.51~g[/tex]

Answer:

a. chemical change

Explanation:

A chemical change can cause an odor, however a physical change cannot, and the use of thermal energy will only make an object colder, not give it an odor.

Answer:

This is not a viable question.

Explanation:

Use this formula PV=nRT

Rearrange formula , question want V ,so

V=nRT/P

given

P= 3.00 atm

n=0.450 moles

R is ideal gas constant = 0.08206 L atm mol-¹K-¹

T in Kelvin so , (75 + 273)= 348 Kelvin (K)

Then insert all this information given with that rearranged formula V=nRT/P

Answer:

exothermic reaction

Explanation:

because it occurs in the presence of heat

Answer:

1.12 moles of potassium

6.76x10²³ atoms of potassium

Explanation:

In order to convert g of potassium to moles, we need to use its molar mass (which we can find via the periodic table):

Then, to convert moles into atoms, we use Avogadro's number (6.023x10²³ atoms per mole):

Explanation:

Mole ratio of Ethane to Oxygen = 2 : 7

Moles of O2 needed = 24 moles * (7/2) = 84 moles.

Moles are the ratio of the mass and the molar mass of the substance. 84 moles of oxygen are needed to react with Ethane.

Moles are the unit of the measurement of small entities like molecules, atoms, or particles.

The reaction is shown as:

[tex]\rm 2C_{2}H_{6} +7O_{2} \rightarrow 4CO_{2} + 6H_{2}O[/tex]

From the reaction, it can be said that the mole ratio of ethane [tex](\rm C_{2}H_{6})[/tex] and oxygen [tex](\rm O_{2})[/tex] is 2:7.

Then moles of oxygen will be,

[tex]24 \times \dfrac{7}{2} = 84[/tex]

Therefore, 84 moles of oxygen are needed to react with 24 moles of ethane.

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Answer: Chemical energy

Explanation: In this case plants convert light energy (1) into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.

Answer:

chemical energy

In this case plants convert light energy into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.

Explanation:

The seedlings exerted an upward pushing force on the soil explains why the

seeds emerged from the soil.

Bob watered the soil in which the seed absorbs the water through the coat ,

the seed coat and embryo begins to enlarge and emerge from the soil.

The hydrated enzymes become active thereby increasing metabolic

activities and energy production which is needed for the growth of the plant.

The energy helps the seed exert an upward force on the soil.

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Answer:

[tex]CaS[/tex]

Explanation:

Hello!

In this case, since calcium's oxidation state when forming ionic bonds is +2 and sulfur's oxidation state when bonding those bonds is -2, for the required formula we write:

[tex]Ca^{2+}S^{2-}[/tex]

Now, since they have the same charge number, we infer the ionic compound formed when they bond is calcium sulfide:

[tex]CaS[/tex]

Best regards!

Answer:

Reflecting telescopes take up less space, is the suitable answer.

Answer:

B, or 2: Reflecting telescopes produce clearer images.

Explanation:

Took the test

Answer:

The enthalpy of neutralization and its relation to esterification​ is explained below in details.

Explanation:

The conventional enthalpy variation of neutralization is the enthalpy exchange when extracts of an acid and an alkali respond together under conventional circumstances to generate 1 mole of water. Remark that the enthalpy change of neutralization is always estimated per mole of water produced.

Answer:

84.01 g/mol

Explanation:

Look at your periodic table for the atomic mass for Na, H, and C, and O

Na = 22.99

H = 1.01

C = 12.01

O = 16.00

They are three oxygen atoms. So 16(3) = 48

Now do basic math.

22.99 + 1.01 + 12.01 + 16.00(3) = 84.01 g/mol.

Literally found this in a YouTuube video lol. Hope it helped doe!

The molar mass of sodium bicarbonate (NaHCO₃) is approximately 84.01 grams per mole (g/mol).

To calculate the molar mass of sodium bicarbonate (NaHCO₃), you need to sum the atomic masses of all the atoms in the chemical formula.

The atomic masses:

Sodium (Na) = 22.99 g/mol

Hydrogen (H) = 1.01 g/mol

Carbon (C) = 12.01 g/mol

Oxygen (O) = 16.00 g/mol

Now, let's calculate the molar mass of NaHCO₃:

Molar mass of NaHCO₃ = (1 * Na) + (1 * H) + (1 * C) + (3 * O)

Molar mass of NaHCO₃ = (1 * 22.99 g/mol) + (1 * 1.01 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol)

Molar mass of NaHCO₃ = 22.99 g/mol + 1.01 g/mol + 12.01 g/mol + 48.00 g/mol

Molar mass of NaHCO₃ = 84.01 g/mol

Therefore, the molar mass of sodium bicarbonate (NaHCO₃) is approximately 84.01 grams per mole (g/mol).

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Answer:

Red and Orange

Explanation:

Complementary colors are those colours located across from each other on a color wheel. If we look at the colour wheel attached to this answer, we will see various complementary colours shown.

A good look at the attached colour wheel reveals that blue Cu2+ ions absorbs light around the red and orange portions of the visible spectrum.

Answer:

Suns gravity

Explanation:

Answer: 2021

B

The Sun's gravity

Explanation: Just took the big test

Answer:

I think it's true. But I'm not sure

Answer:

True

Explanation:

1. A radical is a reactive intermediate with a single ____________ electron, formed by ____________ of a covalent bond.

1. A: Unpaired, and homolysis

2. Allylic radicals are stabilized by ____________ , making them ____________ stable than tertiary radicals.

2. A: Resonance, and more

3. A compound that contains an especially weak bond that serves as a source of radicals is called a radical ____________ .

3. A: Initiator

4. Treatment of cyclohexene with N-bromosuccinimide in the presence of light leads to ____________ by ____________ intermediates.

4. A: Allylic substitution by radical

Answer:

(B) -125 kJ

Explanation:

Going by the First Law of Thermodynamics it states that"

"A system can do work and increase it's internal energy provided we supply heat."

ΔU= q+w-----------1

where U= the internal heat

           q= the quantity of heat added or removed from the system

            w= the work done

Given

ΔU= 250kJ

q= 375kJ

from equation 1 make w subject of the formula we have

w= ΔU-q

w= 250-350

w= -125kJ

Answer:

Coefficients represents no of moles while subscripts represent no of atoms.

Answer:

Coefficients came before formula . Example = 4CO means there are 4 molecules of carbonmonooxide.

Subscripts came after and below the formula . Example = Oxygen gas in which 2 is a subscript which means there are 2 atoms of Oxygen in 1 molecule of Oxygen i.e. oxygen gas

Answer:

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the initial volume

[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]

From the question we have

[tex]V_1 = \frac{8.73 \times 18.4}{3.89} = \frac{160.632}{3.89} \\ = 41.293573...[/tex]

We have the final answer as

Hope this helps you

i dont see any processes below

Answer:

Heat and pressure

Explanation:

got it on study island

Answer:

where are the statements?

Explanation:

390 g KNO₃

Atomic Structure

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

2.3 × 10²⁴ formula units KNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

Step 3: Convert

[tex]2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )[/tex] = 386.172 g KNO₃

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

386.172 g KNO₃ ≈ 390 g KNO₃

Answer:

Hydrogen

Explanation:

Helium has an atomic number Z = 2, that is, it has 2 protons. Since it is electrically neutral it also has 2 electrons. Thus, the electron configuration of helium is 1s².

Hydrogen has an atomic number Z = 1, that is, it has 1 proton. Since it is electrically neutral it also has 1 electron. Thus, the electron configuration of hydrogen is 1s¹.

If hydrogen gains a single extra electron to form H¹⁻, it acquires the same electron configuration than helium.

The complete question is attached to this answer

Answer:

2.75 * 10^-5 m

Explanation:

The energy of the absorbed photon = ΔE

ΔE = - Ry (1/n^2 final - 1/n^2initial)

Given that Ry = 2.18 *10^-18 J

nfinal = 9

ninitial =8

ΔE = - 2.18 *10^-18 (1/9^2- 1/8^2)

ΔE = - 2.18 *10^-18 (0.0123 - 0.0156)

ΔE = 7.194 * 10^-21 J

But

ΔE =hc/λ

h = 6.6 *10^-34Js

c= 3 * 10^8 ms-1

λ= the unknown

λ= hc/ΔE

λ= 6.6 *10^-34 * 3 * 10^8/ 7.194 * 10^-21

λ= 2.75 * 10^-5 m

Answer:

Due to "Common ion effect".

Explanation:

Lead chloride and Silver chloride have an ion in common which is Cl-, when these two solutions are dissolved, more chloride reacts with lead which shifts equilibrium position to the right hence precipitating out.

Answer:

12.3 L

Explanation:

Now we have that the rate of diffusion of the saturated hydrocarbon is R1

Rate of diffusion of sulphur dioxide is R2

Molar mass of hydrocarbon is M1

Molar mass of sulphur dioxide is 64 gmol-1

From Graham's law;

R1/R2 = √64/M1

2/1 =√64/M1

(2/1)^2 = (√64/M1)^2

4/1 = 64/M1

4M1 =64

M1 = 16

To obtain the number of moles of the gas;

(n*12) + (2n + 2) 1 = 16

12n + 2n + 2 = 16

14n + 2 = 16

14n = 16 - 2

n = 14/14

n = 1

Hence the hydrocarbon is CH4

Volume occupied by CH4 at STP = 22.4 L

Hence;

P1 = 1 atm

T1 = 273 K

V1 = 22.4 L

T2 = 300 K

P2 = 2 atm

V2 = ?

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1 * 22.4 * 300/2 * 273

V2 = 12.3 L

The volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L

Let the hydrocarbon be initially at standard temperature and pressure (STP)

Thus, we can obtain the new volume of the hydrocarbon by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(1 × 22.4) / 273 = (2 × V₂) / 300

22.4 / 273 = (2 × V₂) / 300

Cross multiply

273 × 2 × V₂ = 22.4 × 300

546 × V₂ = 6720

Divide both side by 546

V₂ = 6720 / 546

V₂ = 12.31 L

Thus, the volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L

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