Which object would have the highest gravitational attraction?
A. compact car
B. bicycle
C. semi truck

As a spaceship travels from Earth to the moon, which value never changes?
A. velocity
B. weight
C. acceleration
D. mass​

Answer:

B

Explanation:

Answer:

5.3 hours

Explanation:

(3180 km) / (600 km/h) = 5.3 hours

Answer:

According to Newton, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration."

Force = mass x acceleration

Answer: According to Newton’s Second Law of physics, the force is equal to the mass of the object times the acceleration. The force acting on an object would be equal to the mass of an object times its acceleration... This means the more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration

The change in the height of the object is 5.1 m.

The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.

The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;

P.E = K.E

[tex]mg \Delta h = \frac{1}{2} mv^2\\\\g \Delta h = \frac{1}{2}v^2\\\\\Delta h = \frac{v^2}{2g} \\\\\Delta h = \frac{(10)^2}{2(9.8)} \\\\\Delta h = 5.1 \ m[/tex]

Thus, the change in the height of the object is 5.1 m.

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Answer:

48,000 J

Explanation:

m = 60.0 kg

v = 40.0 m/s

kinetic energy = mv^2/2 = 60*40^2/2 = 48,000 J

Answer:

429.424

Explanation:

Trust :)

The wavelength of the light passing through the single slit is approximately 429 nanometers.

To calculate the wavelength of the light passing through a single slit, we can use the formula for the diffraction of light:

w × sin(θ) = m ×λ

Where:

w is the width of the slit

θ is the angle of the diffraction minimum

m is the order of the diffraction minimum

λ is the wavelength of the light

Given:

Width of the slit (w) = 8.77 × 10^(-6) m

Angle of the diffraction minimum (θ) = 5.62º = 5.62° = 5.62 × π/180 radians

Order of the diffraction minimum (m) = 2

To solve for the wavelength (λ),  rearrange the formula:

λ = (w × sin(θ)) / m

Substituting the given values:

λ = (8.77 × 10^(-6) m × sin(5.62° × π/180)) / 2

Calculating this expression:

λ ≈ (8.77 × [tex]10^{(-6)[/tex] m × sin(0.098)) / 2

λ ≈ (8.77 ×[tex]10^{(-6)[/tex] m × 0.098) / 2

λ ≈ 4.29 ×[tex]10^{(-7)[/tex] m

To convert the wavelength to nanometers, we multiply by[tex]10^9[/tex]:

λ = 4.29 × [tex]10^{(-7)[/tex] m × 10^9 nm/m

λ ≈ 429 nm

Therefore, the wavelength of the light passing through the single slit is approximately 429 nanometers.

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Answer:

5,920 J

Explanation:

Lowest temperature T₂ = 293 K

Highest temperature T₁ = 495 K

Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408

Input heat Q₁ = 10,000 J

Find output heat Q₂

e = 1 - Q₂/Q₁

0.408 = 1 - Q₂/10,000

Q₂/10,000 = 1 - 0.408 = 0.592

so

Q₂  = 10,000 x 0.592 = 5,920 J

Answer:

354875 J

Explanation:

The equation for Work is:

[tex]Work=Force*Distance[/tex]

We can plug in the given values into the equation:

[tex]Work=4250N*83.5m=354875J[/tex]

Answer:

The noble gases are located in the 18th group of the periodic table.

Hi there!

We can use the following equation for the period of a pendulum:

[tex]\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}[/tex]

T = Period (s)
L = length of simple pendulum (.75 m)

g = acceleration due to gravity (9.8 m/s²)

Plug in the values:

[tex]T = 2\pi \sqrt{\frac{.75}{9.8}} = \boxed{1.738 s}[/tex]

Answer: car 1 is going how fast

Explanation: no need to answer without speed I won't know distance.

Answer:

because they have opposite charges

Explanation:

If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.

Charged particles interact with each other because they have opposite charges.

When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.

So we can conclude that Charged particles interact with each other because they have opposite charges.

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Answer:

A friction is very much desirable to stop the body from its moving condition. ... If the friction is more between the block and inclined surface then a large force is required to push the block on the plane.

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

[tex]kai6417[/tex]

Answer:

What is the effect of clouds on the "output" of a Solar PV module?

Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!

Explanation:

I hope it will help you...

#carryonleraning

Answer:

160 kg

Explanation:

f = ma

100 = m * a

a = v/t

v = distanc/time

dist = 40m

time = 8 sec

v = 40/8

a = 40/(64)= 5/8

m = 100*8/5= 160 kg

Answer:

150 watts

Explanation:

300/2 = 150 watts

Answer:

150 watts

Explanation:

The explanation is in the picture

PLEASE MARK BRAINLIEST

In celestial mechanics, escape velocity or escape speed is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a primary body, thus reaching an infinite distance from it.

PLEASE MARK AS BRAINLIEST

A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.

The change of displacement with respect to time is defined as the velocity.  velocity is a vector quantity.

Given data;

t = 0 ,u=16 m/s

acceleration = −0.50t m/s²

v=0,t=?

The acceleration is found as;

[tex]\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt[/tex]

Intregating both sides we get;

[tex]\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec[/tex]

Hence, the car stops at t=8sec. Option D is correct.

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Answer:

so you have your boxes go by tens on the x-axis okay which is the one going straight up then the second number goes by 5's is your y-axis. 30,6 so 30 is your x and 6 is your y. start at 0,0 which is the little corner piece. find 30 on x and then go over 6 and that's it!

Explanation:

When you double the speed of your car, your braking distance quadruples. every time you double your speed, you multiply your braking distance by four.

The stopping distance of a vehicle is the sum of breaking distance and thinking distance. The stopping distance of a vehicle when we increase the velocity from 10mph to 30 mph, increases from30 feet to 90 feet.

Stopping distance is the distance covered by a vehicle when we stops. Distance is the product of time and velocity. As the velocity increases then, the time taken to cover the distance will be lower.

Stopping distance mathematically is the sum of breaking distance and thinking distance .Thinking distance is simply the speed and it is in fact means how long it takes on average to think for a break.

Breaking distance is means how long the driver takes to break or stop in actual. In general, the breaking distance is speed multiplied by 2.

Thus, for 10 mph, the thinking distance is 10 feet and breaking distance is 10 × 2 = 20 feet and therefore, the stopping distance is 10 + 20 =30 feet.

Similarly for 30 mph, breaking distance is 60 feet and thinking distance is 30 feet thus, having 60 + 30 = 90 feet of stopping distance.

Therefore, when the speed increased from 10 mph to 30 mph, stopping distance increases from 30 feet to 90 feet.

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The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s

the speed of the plane wave defined by sin(ωt−kx) is v = ω/k where

Now ω = 3376.7 Thz = 3376.7 × 10¹² Hz and k = 11.79μm⁻¹ = 11.79 × 10⁶ m⁻¹

So, substituting the values of the variables into v, we have

v = ω/k

v = 3376.7 × 10¹² Hz/11.79 × 10⁶ m⁻¹

v = 286.4 × 10⁶ m/s

v = 2.864 × 10⁸ m/s

The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s

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Answer:

b

Explanation:

Answer:

10m-2m = 8m

8

Hope this helps!

We have that the  force between  the two charged objects is mathematically given as

F=2.349N

Question Parameters:

Two spheres carry a charge of 1x10^-7 C.

Their centers are separated by 0.7m.

Generally the equation for the Force  is mathematically given as

[tex]F=\frac{q1q2}{4*\pi e*r}[/tex]

Therefore

[tex]F=\frac{(1e-7)^2}{9e9*0.7}[/tex]

F=2.349N

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Answer:

B

Explanation:

From Kepler's Third Law, T^2 is proportional to r^3.

Now r of B is larger than r of A,

so T of B is larger than T of A.

Then B takes the longest time.

Dwarf Galaxy B takes the longest time to orbit the large galaxy. This can be explained using Kepler's Third Law of Planetary Motion, also known as the Law of Periods.

Kepler's Third Law states that the square of the orbital period (T) of a celestial body is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit. Mathematically, it can be expressed as:

[tex]\[ T^2 \propto a^3 \][/tex]

Where:

T is the orbital period (time taken for one complete orbit), and

a is the semi-major axis of the elliptical orbit.

In the case of dwarf galaxies A and B revolving around the large galaxy, we can use the distances from the large galaxy to each of the dwarf galaxies as the semi-major axes (a) of their orbits.

Let's compare the values of [tex]\( a^3 \)[/tex] for the two dwarf galaxies:

For Dwarf Galaxy A:

[tex]\( a_{\text{A}} = 70,000 \)[/tex] light years

For Dwarf Galaxy B:

[tex]\( a_{\text{B}} = 500,000 \)[/tex] light years

Now, let's calculate [tex]\( a^3 \)[/tex] for each galaxy:

For Dwarf Galaxy A:

[tex]\( a_{\text{A}}^3 = (70,000)^3 = 343,000,000,000 \)[/tex] cubic light years

For Dwarf Galaxy B:

[tex]\( a_{\text{B}}^3 = (500,000)^3 = 125,000,000,000,000,000 \)[/tex] cubic light years

Since [tex]\( a_{\text{B}}^3 \)[/tex] is significantly larger than [tex]\( a_{\text{A}}^3 \)[/tex], it means that Dwarf Galaxy B has a larger a value and therefore a longer orbital period according to Kepler's Third Law. In other words, Dwarf Galaxy B takes the longest time to orbit the large galaxy.

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Explanation:

a) to allow for the metal tracks to expand on hot days.

reason:- as you have seen in summer the sunlight fall on these tracks and make the metal expand and fill that gaps.

hope this helps you

have a great day :)