If you have a rocket that has a mass of 20kg and is accelerating at 25 m/s what force
would that rocket experience?
a . 20N
b . 40000N
c. 500N
d. 25N
The gravitational field strength on Mars is 3. 7 N/kg. Kai has a mass of 55 kg. What would Kai weigh on Mars? Give your answer to 1 decimal place.
Hi there!
Weight = mass × acceleration due to gravity (or gravitational field strength)
We can write this as:
W = mg
Plug in the given values:
W = 55 × 3.7
W = 203.5 N
What average force magnitude is required to stop a 15,000 kg train in 12.1 s if the train is traveling at 86 km/hr
Answer:
Explanation:
Givens
m = 15000 kg
t = 12.1 seconds
vi = 86 km / hr
vf =0
Formula
F = m*a
a = (vf - vi)/ t
vi has to be converted to m/s
86 km/hr [1000 m / 1 km] * [1 hour / 3600 seconds]
86 * 1000 / 3600 = 23.89 m/s
Solution
a = (vf - vi) / t
a = (0 - 23.89)/12.1
a = - 1.97 m/s^2 The minus means that the trains is slowing down.
F = 15000 kg * - 1.97 m/s^2
F = -29615.7 Newtons.
Arthur (mass 79 kg) and Violet (mass 50 kg) are trying to play on a seesaw. If Violet sits 4 m from the fulcrum, at what distance from the fulcrum should Arthur sit
Hi there!
There are two torques acting on the system:
τ (Arthur) = RW = R(790N)
τ (Violet) = RW = 4(500N) = 2000N
∑τ = 0 = τ(Violet) - τ(Arthur)
Thus:
τ(Violet) = τ(Arthur)
2000 = 790R
R ≈ 2.53m
If someone were to be researching and studying similarities between our sun and a neighboring star, what kind of scientific investigation would they be conducting
Answer:
a
Explanation:
because there both in the solar system
There are billions of galaxies in the universe and each contains trillions of stars which are different in size, distance from the earth, brightness etc.When we scientifically investigate about this we can obtain the stars of similarity to sun in brightness and size.
What is galaxies?Galaxies are a group of stars, dust and dark matter joined together by the force of gravitation. Three trillions of stars in each galaxies. Some stars forms a group of certain size and shape and number also they are called constellations.
Sun is the closest star to earth. Thus sunlight is the major source of energy in earth. Sunlight reaches the earth surface within a time of 8 minute and 6 seconds.
The star which nearest to sun is named proximacentory which far from the earth and we can see it as spot of light in the sky. There are many more stars which are giants are more brighter than sun.
The brightness and luminosity is determined based on the distance from the earth. Which can be calculated in terms of light years. Each star has an age and length of life. After that the star may die still their light energy can be seen in sky because their light takes more years to reach here.
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5. SEP Construct Explanations If the line on
a distance-versus-time graph and the line on
a speed-versus-time graph are both straight
lines going through the origin, can the two
graphs be displaying the motion of the same
object? Explain.
Answer:
If and only if the object has 0 speed. Any other case is a no.
Explanation:
In increasing math complexity:
If the graph of a distance/time is a straight line with a non-zero slope it means that the velocity-time graph is an horizontal line where every point has the same second coordinate, equal to the value of the slope of the first line (ie, if the first line has equation [tex]y=2t[/tex] the second line will have equation [tex]y=2[/tex] - I'm using y to denote either the distance or the speed, read it as "the non-time variable")
If the graph of a speed/time is a straight line, the graph of the distance/time is the area of the region of space beneath the straight line in the first graph, ie a triangle. And as you increase the sides of that triangle keeping the angles fixed, you get a parabolic curve.
Bonus case: if [tex]v(t)= 0; d(t) = 0[/tex], they are both straight lines, they both pass through the origin, and they are the exact same line.
With calculus (or: math becomes fun after you add the alphabet to it)
You are asking if the answer of the IVP
[tex]\left \{ {{x'=x} \atop {x(0)=0}} \right.[/tex]
is a linear function. The answer is: besides the obvious [tex]x(t)'=x(t)=0 \ \forall t[/tex] there are no other solutions, linear or otherwise.
Hãy giải thích sự phát âm của cái sáo khi thổi vào nó
The best evidence for dark matter in the milky way comes from the observation that the rotation curve
An object's inertia causes it to come to a rest position.
Answer:
no
Explanation:
the inertia of an object does not make it to come to rest, this is normally caused by friction
a box takes 350 N to start moving the coefficient of static friction is 0.35. what is the weight of the box?
Answer:
101.937 kg
Explanation:
The force needed to get the box moving must just cancel the static friction force:
F = µsmg = 0.35•m•9.81 = 350 ---> m = 350 / (0.35•9.81) = 101.937 kg
Again, with units shown, and using 1 N = 1 kg•m/s2:
0.35•m•9.81(m/s2) = 350 N
solving for m:
m = 350 N / (0.35•9.81 m/s2) = (350 kg•m/s2) / (3.434 m/s2 ) = 101.937 kg
______________________
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najah, a management researcher, conducted an experiment with the goal of confirming or contradicting the behavioral leadership approach. najah spent many days following managers around while they worked. like the ohio state university and university of michigan studies, najah’s data showed that most managers focus on
Based on the information that is depicted from the question, the data from Najah showed that most managers focus on consideration and inspiration.
The behavioral leadership theory simply focuses on how leaders behave. The theory also assumes that other leaders copy each other's traits.
Based on the complete information, the data illustrated that most managers focus on consideration and inspiration. Managers inspire their subordinates in order to accomplish a goal.
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how long does it take saturn to revolve around the sun
Answer: about 29.4 Earth years
Orbit and Rotation
One day on Saturn takes only 10.7 hours (the time it takes for Saturn to rotate or spin around once), and Saturn makes a complete orbit around the Sun (a year in Saturnian time) in about 29.4 Earth years (10,756 Earth days).
test questions!!!!!!!!
Answer:
B. surface wave
A person makes a loud sound and hears the echo of this sound 1.2s later .calculate how far the person is from the object causing the echo assume that the speed of sound is 330m/s calculate the distane
Answer:
198m
Explanation:
Distance = speed x time
. d = 330m/s x 1.2s = 396m
This is the distance travelled by the sound from the person to the object and then back to the person. To get the distance from the person to the object, we would have to divide by 2.
. distance = 396 / 2 = 198m
An object has an acceleration of 12.0 m/s/s. If the NetForce was tripled and the mass was doubled, then the new acceleration would be _____ m/s/s
Answer: that would be New acceleration would be 12 m/s²
Explanation:
mars one mission essay
so bassicly Mars is a planet
Explanation:
planet
Alejandro Kirk is the catcher for the Blue Jays’ baseball team. He exerts a forward force on the 0.145-kg baseball to bring it to rest from a speed of 38.2 m/s. During the process, his hand recoils a distance of 0.135 m.
Determine is the acceleration of the ball.
Determine the force applied by Alejandro.
Answer:
a= -5404.6 [m/s²]; F=785.75 [N].
Explanation:
1. Determine is the acceleration of the ball:
equation of the distance (0.135m) is:
[tex]S=-\frac{at^2}{2} +v_0t,[/tex] where S=0.135[m]; a - required acceleration; t - elapsed time; v₀ - initial velocity (38.2 m/s);
also the required acceleration is:
[tex]a=\frac{v-v_0}{t}, where[/tex] V - the end velocity (0 m/s), t - elapsed time, ₀ - initial velocity (38.2 m/s).
Using the equations of reqruired acceleration and the distance it is possible to make up and solve the next system:
[tex]\left \{ {{a=-\frac{38.2}{t} } \atop {S=-\frac{at^2}{2}+38.2t }} \right. \ => \ \left \{ {{a=-\frac{38.2}{t} } \atop {0.5at^2-38.2t=0.135}} \right. \ => \ \left \{ {{a=-\frac{38.2}{t} } \atop {19.1t-38.2t=0.135}} \right. \ => \ \left \{ {{a=-5404.6} \atop {t=0.007}} \right.[/tex]
finally, a≈-5404.6 [m/s²].
2. Determine the force applied by Alejandro.
the energy is:
[tex]E=\frac{mv^2}{2}; \ or E=FS, where \ m-the \ mass; \ v-velocity; \ F-required \ force; S-distance;[/tex]
According to these two equations, the required force is:
[tex]F=\frac{E}{S}=\frac{mv^2}{2S};[/tex]
F=0.145*38.8²/2/0.135≈785.75 [N].
note, the suggested way is not the shortest one and not the only one.
P.S. if it is possible, check the arithmetic operations and the provided answers in other sources.
A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall returns 0.9 s later while the echo from the farther wall returns 1.10 s later. If the air temperature is -10 C, how wide is the valley?
OK I have tried answering this for a while but im not very good at this so, how many waves will pass in 1 second if it has a frequency of 10 Hz?
foetus grows by receiving nutriens and oxygen from the mother. How does the foetus receive these nutriens and oxygen?
Answer:
From the very beginning, the developing cells need oxygen and nutrients. The fetus receives its nutrition from the mother through the placenta and the umbilical cord.
Explanation:
A 455 kg cannon fires a 21 kg cannonball at 26 m/s. If the cannon is on wheels, at what velocity does it move backward?
Answer:
A cannon ball of mass 4.0 kg is fired from a stationary 96 kg cannon at 120 m/s. Calculate the velocity of the cannon immediately after firing.
total momentum of cannon and cannon ball before = 0 kg m/s - because neither object is moving
total momentum of cannon and cannon ball after collision = 0 kg m/s - because momentum is conserved
Momentum of cannon ball after firing = 4.0 × 120 = 480 kg m/s.
Momentum of cannon after firing = -480 kg m/s (because it recoils in the opposite direction and 480 - 480 = 0 kg m/s, the total momentum after collision).
Rearrange p = m v to find v:
v = p/m
v = 480 divided by 96
v = 5.0 m/s
Note that the forward velocity of the cannon ball was given a positive value. The negative value for the cannon's velocity shows that it moved in the opposite direction.
Power of an electric motor is 1 h.p. what does it mean ?
Answer: HP = Horse Power.
Explanation: it is the unit given to tell the motor's particular power and 1hp = 746 watts.
. The gas in a piston (defined as the system) warms and absorbs 655 J of heat. The expansion performs 344 J of work on the surroundings. What is the change in internal energy for the system
The change in the internal energy for the system is 311 J
The change in internal energy for the system will be the difference between the heat absorbed and the work expansion from the surroundings.
i.e.
ΔU = Q + W
where;
internal energy = Uheat absorbed = Qworkdone on surroundings = -WΔU = ( 655 J + ( - 344 J) )
ΔU = 311 J
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the thermodynamic processes that occur in nature ____________.
Answer:
The thermodynamic processes that occur in nature convert thermal energy into mechanical energy.
The thermodynamic processes that occur in nature are according to the law of thermodynamics.
The thermodynamics processes seen in nature are guided by the law of thermodynamics. The role of energy and heat transmission in physical systems is guided by these laws.
The laws are:
(1) Energy cannot be created nor destroyed in a system, according to the first law of thermodynamics, Also, referred to as the law of energy conservation. Only from one form to another, the energy can be transmitted or altered. Energy is conserved through natural processes, keeping the overall amount constant.
(2) Second law of thermodynamics: states that the overall entropy of an isolated system tends to increase over time in any natural process. This suggests that processes progress towards a state of increasing disorder.
Hence, the thermodynamic processes are guided by the law of thermodynamics.
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This Constitutional right forbids Congress from sending a person to prison__
Explain what this Constitutional right is:___
The formation and operation of prisons, as well as inmates' rights, are governed by federal and state regulations. Although prisoners may not have full constitutional rights, the Eighth Amendment's restriction on cruel and unusual punishment protects them.
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Many farmers harvest their crops in the fall and then let the leftover plant material stay on the ground over winter. How does this help prevent erosion?
Answer:
it grabs unto soil and keeps it clamped together it prevents this makes the soil harder to wash away
Answer:
When the leftovers are left in the autumn, they have two purposes:
- Preventing erosion; the roots remain in the ground, so they hold it tightly till the next planting of the crops.
- Fertilizing the soil with natural material; the roots will not rot quickly in the colder period of the year, but will start rotting much faster in the spring, thus they will enrich the soil.
A 1,000 kg truck is traveling at 3 m/s. Suddenly, the driver sees a herd of cows on the road ahead and applies the brakes. The truck's tires could fail after doing 5,000 J of work to slow the vehicle. Can the truck stop before the tires fail?
A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J.
B. Yes, the tires do not do any work, it is only the brakes that do work.
C. No, the truck had to stop suddenly and the quick change in KE will cause the tires to fail.
D. No, the total KE the tires need to transfer out of the system is more than 5,000 J.
This question involves the concepts of the law of conservation of energy and kinetic energy.
The correct option is "A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J".
According to the law of conservation of energy:
Loss in Kinetic Energy = Work done by the tires
[tex]\frac{1}{2}mv^2=W[/tex]
where,
W = work done by tires = ?
m = mass of the truck = 1000 kg
v = speed of the truck = 3 m/s
Therefore,
[tex]W=\frac{1}{2}(1000\ kg)(3\ m/s)^2[/tex]
W = 4500 J
Since the failure limit of work done by the tire is 5000 J, which is greater than the actual work done by the tire in this scenario. Hence, the tire will not fail in this case.
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The attached picture explains the law of conservation of energy.
consider an air-filled balloon weighted so that it is on the verge of sinking. now, if you push it beneath the surface, it will
Given our understanding of physics, we can conclude that once the balloon is pushed under the surface, it will sink.
One key factor to take into account here is to remember that the density of a ballon can change when exposed to a higher pressure. This is due to the elastic nature of the material that makes up the ballon, and the nature of gas atoms that allow them to be compressed.
Therefore, when the balloon is pushed underwater, the surrounding water will squeeze the balloon, thus incrementing its density. Once the density of the balloon rises, this, in addition to the weight to which it is attached, will make it heavier than the water it is in, and the balloon will sink.
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An object of mass of 2.0 kg rotates at constant speed in a horizontal circle of radius 5.0 m. The time
for one complete revolution is 3.0 s. What is the magnitude of the resultant force acting on the object.
Explanation:
follow the above attachment to get the answer.
If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest? Solve this problem using conservation of energy. initial speed is 5.3 m/s
Hi there!
We know that:
Ei = Ef
There is work being done on the object, so:
W = Force · displacement = F · d ⇒ work due to friction
KEi - Fd = KEf (0)
KEi = Fd
Input variables:
1/2mv² = μmgd
Cancel out the mass:
1/2v² = μgd
Solve for d:
1/2(5.3²)/(0.05 · 9.81) = 28.63 m