The equation used to calculate required fastener torque as a function of desired preload and bolt size is τ = K D [tex]F_{i}[/tex].
τ = K D [tex]F_{i}[/tex]
[tex]F_{i}[/tex] = σ[tex]_{t}[/tex] * A[tex]_{t}[/tex]
σ[tex]_{t}[/tex] = 0.9 * σ[tex]_{y}[/tex]
τ = Torque
K = Torque co-efficient
D = Nominal bolt diameter
[tex]F_{i}[/tex] = Desired preload
σ[tex]_{t}[/tex] = Tensile stress
A[tex]_{t}[/tex] = Tensile stress area
σ[tex]_{y}[/tex] = Ultimate yield strength
As the fastener grade increases, the required preload also increasesAs the TPI ( Threads per Inch ) increases, the required preload also increasesTherefore, the equation used to calculate required fastener torque as a function of desired preload and bolt size is τ = K D [tex]F_{i}[/tex].
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a sonar system can use sound waves wih a frequency of 120kHz or 200kHz. A. what is the wavelength of each of these waves when they are sent through sea water?
B. What are their wavelengths in freshwater?
C. The ship operating these sonar systems is in sea water with a depth of 3km.
How long will it take an echo to return to the ship after a ‘ping’
(A) The wavelength of each of these waves when they are sent through sea water is 0.0126 m and 0.0076 m respectively.
(B) The wavelength of each of these waves when they are sent through freshwater is 0.012 m and 0.0074 m respectively.
(C) The time taken for the echo to return to the ship is 3.97 seconds.
What is the wavelength of the sound wave in sea water?
The wavelength of the sound wave in sea water depends on the speed of sound in seawater and frequency of the wave.
The speed of sound in seawater, v = 1,510 m/s
λ = v/f
when the frequency, f = 120 kHz
λ = 1510 / 120,000
λ = 0.0126 m
when the frequency, f = 200 kHz
λ = 1510 / 200,000
λ = 0.0076 m
The speed of sound in freshwater, v = 1481 m/s
when the frequency, f = 120 kHz
λ = 1481 / 120,000
λ = 0.012 m
when the frequency, f = 200 kHz
λ = 1481 / 200,000
λ = 0.0074 m
The time taken for the echo to return is calculated as follows
v = 2d/t
t = 2d/v
t = (2 x 3,000 m) / (1510 m/s)
t = 3.97 s
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Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The center of mass of the three mass system is at 83cm.
What is center of mass?The center of mass of an object or a collection of objects is known. It represents the system's average location by weighing the mass of each component. For straightforward rigid structures with uniform densities, the center of mass is located at the centroid.
What is the calculation of the above problem?Given the mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
So the center of mass of the three mass system is at 83cm.
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You push a book across a table. The book moves at a constant speed, but you do not move. Identiffy all the forces on you. Then identify all of the forces on the book
The forces acting on me are static frictional force and reaction force of the book. The forces acting on the book moving with a constant speed are Applied force and Kinetic frictional force.
Forces acting on me are
Static frictional forceReaction force of the bookThe book at rest, will have a static frictional force. So when I push the book, these forces will act on me. According to Newton's third law of motion, when I apply a certain amount of force on the book, the book will exert the equal amount of force on me.
Forces acting on the book are
Applied forceKinetic frictional forceThe book when moving at constant velocity will have zero net force, because according to Newton's second law of motion, force is directly proportional to acceleration. If the velocity is constant, acceleration will be zero and net force will also be zero. Since the book is moving on a table, a kinetic frictional force will act on the book to resist the movement of the book.
Therefore,
The forces acting on me are Static frictional force and Reaction force of the book.The forces acting on the book are Applied force and Kinetic frictional forceTo know more about Newton's second law of motion
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In the United States, most people measure temperature in ______.
Celsius
Kelvin
Fahrenheit
Answer: Fahrenheit
Explanation:
Marco and his sister are rummaging through a large box of books. Their younger brother also wants to see what’s inside the box. Marco pulls the box away from his brother, applying a force of 38 N to the left. His sister helps him by applying an additional force of 36 N to the left. Their brother applies a force of 35 N to pull the box in the opposite direction. The box weighs 22 kg. Determine the acceleration of the box.
By applying net force formula, the acceleration of the box is 1.8 m/s²
What is Acceleration ?Acceleration is the velocity change per time taken. It is a vector quantity and it is measured in m/s²
Given that Marco pulls the box away from his brother, applying a force of 38 N to the left. His sister helps him by applying an additional force of 36 N to the left. Their brother applies a force of 35 N to pull the box in the opposite direction. The box weighs 22 kg.
F = ma
Where
F = Net force = sum of the left forces - sum of the right forces m = 22 Kga = ?To determine the acceleration of the box, substitute all the parameters into the formula
(38 + 36) - 35 = 22 a
74 - 35 = 22a
39 = 22a
a = 39/22
a = 1.77 m/s²
Therefore, the acceleration of the box is 1.8 m/s² approximately.
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A sample of a gas is in a container. The temperature of the gas is decreased. Based on the relationship between temperature and pressure, what must have happened to the pressure?
If the temperature of the gas is decreased then the pressure will also decrease.
The molecules of a gas receive more energy when heated, causing them to move more quickly. This results in increased pressure and more impacts on the container's walls. On the other hand, cooling the molecules will cause them to slow down and reduce pressure.
This is more explained by Gay Lussac's Law which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.
P1/T1 = P2/T2
Thus, with decrease in temperature the pressure will decrease as the move of molecules will be slow now.
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A wheel spins with constant angular acceleration on an axis through its center, the ratio of
the tangential speed of a point on the rim to the tangential speed of a point halfway between
the center and the rim is:
A. 1
B. 2
C.1/2
D. 4
The ratio of the tangential speed of a point on the rim to the tangential speed of a point halfway between the center and the rim is 2.
The correct option is B.
Briefing:The wheel's angular velocity The rate at which the angular displacement changes over time is known as the wheel's angular velocity. Because the angular velocity is constant, a point just on rim will have constant tangential velocity.
What does angular velocity?The angular velocity of a body refers to the pace at which it revolves or circumambulates an axle. Sometimes, the Greek letter omega symbolizes angular velocity. Due to the fact that it is expressed as an angle every unit of time, the angular velocity in the SI was measured in radians per second.
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Based on properties of elements in the periodic table, which element is the best conductor of thermal energy?
A. argon(Ar)
B. germanium (Ge)
C. polonium(Po)
D. vanadium(V)
Answer:A. argon(Ar)
Argon is commonly considered to be a chemical by most people
What is the total translational kinetic energy of 1.6 mol of N₂ molecules at 27°C?
The total translational kinetic energy of 1.6 mol of N₂ molecules at 27°C is calculated as 9673 J as pern the Kinetic energy formula with Boltzmann Constant.
How is translational kinetic energy calculated?Remember that the mass of the item multiplied by the square of its linear velocity (around its center of mass) yields translational kinetic energy, which is then divided by two.
What is the kinetic energy of translation?The energy of motion of a body is equivalent to the work it would perform if it were brought to rest, according to general physics.
For a rigid body with constant mass, the translational kinetic energy is dependent on motion through space and is calculated as the product of the square of the speed and the product of the mass divided by half.
N2 is an adiatomic molecule
Total translational Kinetic energy of adiatomic gas
E = 5/2 NKT
1 mol = 6.022 x [tex]10^{23}[/tex]
1.6 mol = 1.6 x (6.022 x [tex]10^{23}[/tex])
= 9.635 x [tex]10^{23}[/tex]
Boltzmann constant K = 1.38 x [tex]10^{-23}[/tex] J/K
Temperature = 18° C
= (18 + 273) K
= 291 K
Putting the values,
E = 5/2 x (9.635 x [tex]10^{23}[/tex] ) x (1.38 x [tex]10^{23}[/tex]) x 291 K
= 9673 J
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If Rico pulls on a 30 kg box of supplies with a force of 200 N towards the nearest firefight and Ace pulls on the box with a force of -56 N in the opposite direction, what is the net force (in Newtons) on the box of supplies?
The net force (in Newton) on the box of supplies, given that Rico pulled it with a force of 200 N is 256 N
How do I determine the net force?From the question given above, the following data were obtained:
Mass of box = 30 KgForce of pull = 200 NOpposite force = -56 NNet force =?The net force on the box of supplies can be obtained as illustrated below:
Net force = force of pull - opposite force
Net force = 200 - (-56)
Net force = 200 + 56
Net force = 256 N
Thus, the net force on box is 256 N
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The international Agreed system of Units (SI) for physical measurement, are! (A) lb, fl, s (b) g,m, s (c) kg, m,s (d) cm,g,s ( e ) kg,cm,s
Answer:
Option (c) - Kg, m, s
Explanation:
The internationally agreed system of units for physical quantities is based on the fact that kg(kilogram) is the unit of mass, m(meter) is the unit of length and (second) is the unit of Time.
A boy is running to the east and jumps into a stationary boat in a lake. once the boy lands in the boat, the boat moves to the east. which best compares the initial momentum of the boy with the final momentum of the boy/boat system? the initial momentum of the boy is zero because the velocity cancels with the mass of the boy. the initial momentum of the boy is greater than the boy/boat because the boy has a greater velocity than the boat. the initial momentum of the boy is less than the boy/boat because the boy has less mass than the boat. the initial momentum of the boy is equal to the boy/boat because the final velocity of the boat is less than the initial velocity of the boy.
Due to the boat's final velocity being lower than the kid's initial velocity, the boy's initial momentum is equal to that of the boy and the boat.
A moving object's velocity is gauged by its momentum. The momentum increases with velocity. The momentum of an item increases with its mass. Using Newton's second law of motion, it may also be connected to force. The sum of an object's mass and velocity is its linear momentum, often known as translational momentum or just momentum. It has a magnitude and a direction, making it a vector quantity. The measurement of an object's kinetic energy is what is commonly referred to as its momentum. Simply put, momentum is the result of multiplying mass by velocity.
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Answer: D
Explanation: precise, concise answer
the combined force that you and your friends exert has magnitude 8.00×102n , and starting from rest the car reaches a speed of 1.40 m/s after you have pushed it 5.00 m . find the magnitude of the constant friction force that acts on the car.
The magnitude of the constant frictional force that acts on the car is 574.6
What is frictional force?The frictional force is the force that acts to oppose the relative motion of an object over another.
Friction is a contact force that acts at the surface of contact between two bodies.
The frictional force acting on an object depends on the following:
the coefficient of friction between the surfaces- the coefficient of friction between the two surfaces is a constant ad depends on the nature of the surfaces.the weight of the object moving over another. The greater the weight of the object moving over another surface, the greater the frictional force, and vice versa.The total force exerted by the friends = 800 N
Force on the car as it moves will be = mass * acceleration
acceleration, a = v² - u² / 2 * s
a = 1.40² - 0² / 2 * 5
a = 0.196 m/s²
force = 1.15×10³ kg * 0.196 m/s²
force = 225.4 N
Frictional force = 800 - 225.4
Frictional force = 574.6 N
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Complete question:
A car of mass 1.15×10^3kg is stalled on a horizontal road. You and your friends give the car a constant, forward, horizontal push. There is friction between the car and the road.
the combined force that you and your friends exert has magnitude 8.00×102n , and starting from rest the car reaches a speed of 1.40 m/s after you have pushed it 5.00 m . find the magnitude of the constant friction force that acts on the car.
calculate the percent efficiency of a motor that lifts a 50 n weight, 5 meters in 10 seconds. the motor is run by a 9v battery with 3 amperes of current.
The efficiency of the motor is 92.6%
The input energy comes from the motor.
W_in = P . t
Where:
P = V. i
= 9 volt. 3 A = 27 Watt
Hence,
W = 27 watt . 10 seconds = 270 Joules.
The output work is the potential energy.
W_out = F . s
= 50 . 5 = 250 Joule.
The efficiency is calculated as:
Efficiency = W_out / W_in x 100%
= 250/270 x 100% = 92.6%
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a uniform cube of mass m and edge a moves on a horizontal surface along the positive x-axis, with initial velocity v0: (a) during motion, n>mg (b) during motion, normal reaction acts on the centre of mass (c) during motion, the normal reaction shifts towards positive x-axis from the centre of mass (d) during motion, normal reaction shifts in the direction of the forces of friction
Option C about friction is correct statement with initial velocity v0.
What is friction?
friction is a force that opposes motion between any surfaces that are touching. Friction can work for us yet against of us .
It is the action of one surface or object rubbing against another .
Solution -
According to the given question in this case force of friction has a tendency to rotate the cube in anticlock wise direction.
So normal reaction will shift in forword direction to balance the force due to torque of friction.
Thus,
During motion the normal reaction shift towards posetive x- axis from the centre of mass is correct.
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Convert 5 x 105 into normal notation.
50,000
500,000
.00005
5,000,000
Answer:
5 * 10^5 = 5E5 = 500,000
What was the kelly-bessemer process used for? reducing the speed for laying rail tracks mass producing train cars monopolizing the iron industry making high-quality steel
The kelly - bessemer process used for converting the iron metal to molten steel by injecting air into molten pig iron.
Molten steel (from an oxygen or electric arc furnace) is poured into a ladle that is brought to the inlet of a continuous casting machine, raised onto a turret, and poured into a tundish. This is a large vessel that ensures the continuous flow of hot metal through a submerged entry nozzle and into a water-cooled and vertical copper mould, where the solidification starts as an outer shell starts encasing a liquid core. Hydrogen is highly soluble in molten steel, including weld metal.
The partial pressure or concentration of hydrogen above the molten steel determines the equilibrium solubility. It is a really difficult process.
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What electric field e′ would have been required to create a current of 30. 0 amperes in a copper gauge 10 wire with diameter d equal to 0. 259 centimeters?.
The required electric field is 9.58 × 10⁻² N/C
We know that the electric field, E is a product of resistivity and current density
∴ E=jρ ......(i)
Where ρ⇒ Resistivity
j ⇒ Current density
j = I/A
Now, as per the question,
Resistivity of copper, ρ = 1.68 × 10⁻⁸ Ωm
Current, I = 30 ampere
Diameter = 0.259 cm = 0.00259 m
So, Radius, r = Diameter/2
= 1.295 × 10 ⁻⁴m
Now, Cross-sectional area, A = πr²
= 3.14 × (0.001295)²
= 5.26 × 10⁻⁶ m²
Putting the values in equation (i), we get:
[tex]E = 1.68 \times 10^{-8} \times\frac{30}{5.26 \times 10^{-6} }[/tex]
[tex]E= 9.58 \times 10^{-2} N/C[/tex]
Therefore, the required electric field is 9.58 × 10⁻² N/C
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how does a coal-fired power plant use the energy in coal to produce electricity? burning coal heats wires to very high temperatures, which then generate electricity. burning coal generates light that is converted into electricity. burning coal heats water and creates steam that turns the blades of a turbine and generates electricity. burning coal heats air that spins the blades of a turbine and produces electricity.
Coal is burned to create steam, which is then used to generate electricity at coal-fired power stations. Under extreme pressure, the steam generated enters a turbine, which turns a generator to provide power. In order to restart the process, the steam is then cooled, condensed back into water, and fed back into the boiler.
For example, the Kingston Fossil Plant near Knoxville, Tennessee, uses coal to heat its boilers to around 1,000 degrees Fahrenheit in order to produce high-pressure steam as a practical illustration of this.
How is energy generated by burning coal?
Whether bituminous, subbituminous, or lignite, they are all burned in coal-fired power plants. The heat generated by coal combustion is utilized to turn water into high-pressure steam, which drives a turbine and generates electricity.
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pdf a ball thrown vertically upward continues upward until it reaches a certain position, and then falls downward. the ball's velocity is instantaneously zero at that highest point. is the ball accelerating at that point. describe an experiment to prove or disprove your answer.
When the ball is thrown upward, gravity takes control as soon as it is removed from the hand. The ball will only be under its control.
The ball is moving downward at a rate of 9.8 meters per second squared as it approaches the dot-com point. Using a second camera and the gadget, you can perform an experiment where you can observe that the velocity is 0.0 at the top, but varies somewhat before and after it moves.
The ball is accelerating, as can be shown if you take the difference in velocities and calculate acceleration of the ball.
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i need help with this lab. i have to answer the lab questions 4-10. i will upload the graphs u need to use. someone please answer these questions. i will upload the pictures in different questions because it won’t let me upload 3…
The speed of an object is the rate of change of its position, and the object's velocity includes its speed as well as its direction of motion. The rate of change of the object's velocity gives the acceleration.
Explain Speed,Velocity and Acceleration?When an object's reference frame is chosen, its motion can be precisely characterized. The pace at which an object's position changes while it is moving is referred to as speed. The object's speed indicates how quickly or slowly it is going. But which way is the item traveling? The velocity of an object includes information about its direction of motion. The rate of change of an object's velocity, or the change in velocity per unit of time, is known as its acceleration.
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A ball is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s. Calculate the vertical component of the velocity on getting to the ground
A ball when is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s, the vertical component of the velocity on getting to the ground is 28.3 m/s.
What is motion under gravitational field?When any object moves, it can be said to be in motion under gravity because gravity has an impact on the object’s vertical motion. Gravity is also called as the force that pulls things downward. In actuality, gravity pulls objects toward the Earth’s center.
What is the motion under gravity equation?The particle’s initial velocity is 0 during free fall. Consequently, this v=gt is the equation of motion.
An object launched into the air may also experience a shift in upward velocity due to gravity, which causes it to slow down and return to Earth’s surface. The Moon is kept in orbit by the force of Earth’s gravity, which also causes the Moon to rotate constantly.
Initial horizontal velocity = 20[tex]ms^{-1}[/tex]
Initial vertical velocity = 0
Vy= Uy + gt
Vy= gt {Uy= 0}
Vy= 10 × 2.83= 28.3m/s
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A ball is launched with initial speed v from ground level up a frictionless slope. The slope makes an angle θ with the horizontal. Using conservation of energy, find the maximum vertical height hmax to which the ball will climb.
The maximum vertical height hmax to which the ball will climb by the law of conservation of energy is, hmax = (1/2g)ν² cos θ
What is conservation of energy?
The law of conservation of energy states that the total amount of energy of an isolated system remain constant. Also for energy to be conserved, the sum of initial kinetic energy and the potential energy of the system is equal to the sum of final kinetic energy and the potential energy of the system. i.e.
Ki + Ui = Kj + Uj
where K represent Kinetic energy and U represents potential energy.
Since the ball is launched with initial speed v from ground level up a frictionless slope, it means the ball slides up the slope without rolling. The initial kinetic energy of the ball is given as:
Ki = 1/2mv²
The slope makes an angle θ with the horizontal. This means that velocity will be equal to zero in y-direction and velocity in x-direction is:
Ki = 1/2mv²cos θ
Potential energy of the max height is Uf = mghmax
The final potential energy the ball posses will be equal to the intial kinetic energy of it at the maximum height. Thus by the conservation of energy:
mghmax = 1/2mv²cos θ
hmax = 1/2gmv²cos θ
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What is the point on an object where the force of gravity is considered to act?
The Centre of gravity is the point on an object where the force of gravity is considered to act.
Every object that exists on the earth has weight and because of that weight, certain gravity acts on it. When we calculate the total weight of the object, mainly center is taken as the point where the whole weight of the object is accumulated.
for instance, in the seesaw, the middle portion of it acts as a center of gravity which balances out both sides.
It plays a very important role in calculating big and complex problems of gravitation. It simplifies calculations to treat the mass of an object as if it is concentrated at one point only. It is an imaginary point that stable the object.
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what is the coefficient of static friction between m1 and m2 (call this s1) and between m2 and the wall (call this s2) if the minimum force fmin required to keep the blocks from breaking loose and sliding under the influence of gravity is fmin
The static coefficient of friction between m1 and m2 and m2 and the wall (designated as s1 and s2, respectively) if the minimum force F minimum necessary to prevent the blocks from separating and sliding under the action of gravity is F minimum.
What is static friction coefficient?
The ratio of limiting friction to the usual reaction between the surfaces is known as the coefficient of static friction.
This equation yields the minimum coefficient of static friction:
When the radius of curvature R = 190 m and the vehicle's speed V is 72 km/h (20 m/s), the smallest value of the coefficient of static friction Typically, it is represented by the Greek letter mu ().
In terms of math, is equal to F/N, where F stands for frictional force and N for normal force. The coefficient of friction has no dimensions because both F and N are measured in units of force (such as newtons or pounds). friction equals 0.21.
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When a football player catches a football. Time interval or a time instant? (Please give me the right answer)
You throw a ball straight up into the air. the ball starts from rest and has a speed of 7.60 m/s when it leaves your hand. in the process of throwing the ball, you move your hand through a vertical distance of 1.02 m. if the ball has a mass of 0.150 kg and undergoes constant acceleration during the throw, calculate the magnitude of the force that you exert on the ball during the throwing process. hint: remember newton's 2nd law - an object's acceleration is due to the net force acting on it.
The force exerted on the ball is 28.88 N.
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
vo = 0 m/s
vt = 7.6 m/s
s = 1.02 m
m = 0.15 kg
Find the acceleration
vt² = vo² + 2as
7.6² = 0² + 2.a.0.15
a = 57.76 / 0.3
a = 192.53
Find the force exerted
F = m .a
F = 0.15 . 192.53
F = 28.88 N
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A person on a cruise ship is doing laps on the promenade deck. On one portion of the track the person is moving north with a speed of 3.9 ms relative to the ship. The ship moves east with a speed of 12 ms relative to the water.
The resultant speed of the person on the cruise ship is 12.62 m/s.
What is resultant speed?The resultant speed of an object is the single speed which can effectively represent two or more speed of the object.
The magnitude of the resultant speed of the person on a cruise ship is calculated as follows;
Vr² = Va² + Vb²
where;
Vr is the resultant speed of the personVa is the speed of the person to the northVb is the speed of the person to the eastSubstitute the value of the north speed and east speed to determine the resultant speed of the person on the ship.
Vr = √Va² + Vb²
Vr = √[(3.9 m/s)² + (12 m/s)² ]
Vr = 12.62 m/s
Thus, for a person on a cruise ship is doing laps on the promenade deck at a speed of 3.9 m/s to the north and the speed of the ship 12 m/s to the east, the resultant speed is 12.62 m/s.
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The complete question is below:
Find the resultant speed of the person
A bullet is accelerated in the muzzle of a gun from rest to 150 m/s in 0.50sec. What is the acceleration?
Answer:
Bullets are cylindrical metal projectiles shot from firearms. Their main function is to kill or otherwise incapacitate. They come in numerous varieties for use in handguns, rifles, and machine guns. There is also special ammunition capable of penetrating armor, firing underwater, or firing "silently" at subsonic speeds. However, their designs are all basically the same. A typical cartridge consists of four components: the cartridge case, primer, propellant charge and bullet. When a gun trigger is pulled, the primer is struck, igniting the propellant. This causes a rapid expansion of gas, which forces the bullet forward and ejects the casing. Contrary to popular belief, guns are not loaded with bullets, but cartridges, and they fire bullets (since bullets are a more common term and the actual objects responsible for harm, they receive the recognition).
While small in size (the most popular handgun bullet is 9 mm in diameter) bullets posses enough kinetic energy to cause serious damage. Using a kinematics formula, it is possible to determine the acceleration of a bullet when the muzzle velocity and barrel length of a gun are known.
v2 = vo2 + 2as
Where
v is the muzzle velocity
vo is the initial velocity of the bullet, which is zero
a is the acceleration
s is the barrel length
Since acceleration is the desired value, the derived formula is this:
equation
When fired from a Beretta 92S, the standard issue US Army pistol, a 9 mm Parabellum bullet has a muzzle velocity of 335 m/s. With its 127 mm barrel length, the bullet's acceleration is calculated to be 4.4 × 105 m/s2.
The acceleration of a bullet depends largely on the gun from which it is fired, along with the intent of the user. Pistol bullets generally feature a lower acceleration than rifles or machine guns. Also, individuals involved with clandestine operations may use firearms with silencers, which suppress bullet speed and require special subsonic ammunition.
Remember, guns don't kill people. Bullets do. To paraphrase Chris Rock in Bigger, Blacker and Uncut, if bullet prices were raised to $5,000 each, there would be a drastic decrease in murders [mp3].
a large air-filled 0.211-kg plastic ball is thrown up into the air with an initial speed of 10.9 m/s. at a height of 3.49 m, the ball's speed is 3.03 m/s. what fraction of its original energy has been lost to air friction?
Initial energy equals (M/2)*Vo2 = 12.80 J.
At 4.7 m and V = 5 m/s, total energy equals (M/2)
*5^2 + M*g*4.7 = 1.25 + 4.61 J
a portion of the energy in a ball LOST = (12.80-5.86)/12.80 \s= 0.542
We are informed that a plastic ball with a mass of 0.1 kg is tossed into the air as an example of energy conservation. It starts off at a height of three meters and a speed of 10 meters per second. Now moving at three meters per second. We are interested in learning how much of its initial energy has been lost through friction. We now know that the total mechanical energy is constant for an isolated system. Thus, the change in gravitational potential energy descends to you along with the change in kinetic energy data K. additionally the data on N. G. Lost to air friction Zero is equal to E. F. Keep in mind that the gravitational potential energy you I is zero at the beginning.
It follows that either their energy changes or that the energy lost to friction belt E. F. is equal to minus daughter. Kay, without a doubt, which is without uh-huh. Mm. V squared divided by the starting speed is the final speed. M. G. H. plus V not squared Additionally, the ball's initial energy is entirely kinetic. Since this is a half-squared north, the lost energy delta E. F. is the proportion of the original energy that is reflected and lost.
This therefore equals half of M. Squared into the not minus V squared into the not minus to G. H. multiplied by half. squared M Vinod Thus, this fraction becomes the square of the starting speed. We not squared minus the final speed squared square V squared minus twice the acceleration brought on by gravity, G times the height of the ball. H centered over Vinod. Therefore, if we enter our numbers here, this becomes 10 m/s squared times three m/s squared times two, or 9.81 m/km2 times. three meters tall times 10 meters per second squared.
As a result, 32 321 the amount of energy that is lost when there is an uncertainty about e f over e I This is the percentage that is lost due to air friction, or 32.1 percent.
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