A snail moves through a garden and travles 1 1/8 meters in 1 1/2 minutes. What is the snail's rate in minutes per meter? Show your work

Answers

Answer 1

Answer:

4/3mpm

Step-by-step explanation:

(1 1/2)/(1 1/8)

convert to improper fraction

(3/2)/(9/8)

solve

1/(3/4)

4/3


Related Questions

HELP!!! need answers for these questions please. Thank You for anyone who solves atleast one of them!

Answers

5. 4/9 probability

Explanation; You would do (4/13)/(9/13) and that = 4/9.

5b. I don't really get it, it sounds like its asking the same thing.

I gotta go so i will finish later hopefully

plz help!

Find the length for X ​

Answers

Answer:

I think it's x=3 I think that's it

I think the answer is 3 because 4÷2=2. Hence, 6÷2=3



What is the slope of the line below ? [ question 4/0 ]

Answers

Answer:

2/3

Step-by-step explanation:

     [] Since is the line is going up from bottom-left to top-right, we know it will be positive

     [] Because this graph has distinctive coordinate-points, we can use rise over run

     () The other method is to use the change in y divided by the change in x

We start at (-2, 0), then count 2 up and 3 over to get to (2, 1) which gives us a slope of 2/3

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Use exponents to write the prime
factorization of 48.

Answers

Answer:

48=2^4x3

Step-by-step explanation:

48=2x2x2x2x3

48=2^4x3

Hope this helps :)

What is (f•g)(x)?
f(x) = 4x + 6
g(x) = -5x

Answers

(f.g)(x) = (4x + 6)(-5x) = -20x^2 -30x

ok done. Thank to me :>

PLS HELP AMSWER ANYONE PLS ILL GIVE BRAINLKEST THANKS

Answers

Answer:

5. w ≠ 8

Step-by-step explanation:

#1 is the expression for "The amount of water is greater than eight ounces."  This technically means it differs from eight ounces, but it's too specific for what the question is asking.

#2 is the expression for "The amount of water is greater than or equal to eight ounces." It doesn't necessarily differ from eight ounces.

#3 is the expression for "The amount of water is less than eight ounces."  Same issue as #1.

#4 is the expression for "The amount of water is greater than eight ounces."  Same issue as #2.

#5 is the expression for "The amount of water is not equal to eight ounces." This is the correct expression as the only information we know is that it's not eight ounces.

15. (07.05 MC)

What is the solution to the equation 5x + 2(x - 4) = 5x + X - 10?


Answers

Answer:

x = -2

Step-by-step explanation:

5x + 2(x - 4) = 5x + x - 10

→ Expand the brackets

5x + 2x - 8 = 5x + x - 10

→ Collect the x terms

7x - 8 = 6x - 10

→ Minus 6x from both sides

x - 8 = -10

→ Add -8 to both sides

x = -2

Rewrite in simplest terms: -5(3u+1)+10u−5(3u+1)+10u

Answers

Answer:

-10u-10

Step-by-step explanation:

Please answer this question. No links :)

Answers

Step-by-step explanation:

[tex]\frac{rise}{run}[/tex]

Initially, as X increases, Y stays constant.

Then, between x = 3 and x = 5, the graph rises by 4 and runs by 2, or rises by 2 and runs by 1, so the slope is 2.

Between x = 5 and x = 9, the graph "rises" by -1 and runs by 1, so the slope is -1.

The greatest value of y is 4 at x = 5. (5, 4)

Answer:

Initially, as x increases, y remains constant.

Afterward, the slope of the graph of the function is equal to 2 for all x between x = 3 and x = 5.

The slope of the graph is equal to -1 between x = 5 and x = 9.

The greatest value of y = 4, and it occurs when x = 5.

Step-by-step explanation:

Slope = [tex]\frac{rise}{run}[/tex]

The rise is how much it increases by y (up or down), and the run is how much it increases by x (right or left).

From 3-5 the slope = [tex]\frac{4}{2}[/tex] =  2 → it goes up 2 units for every one unit right.

From 5-9 the slope = [tex]\frac{-4}{4}[/tex] = -1 → it goes down (-) 1 unit for every one unit right.

In AFGH, GH = FG and mZF = 10°. Find mZH.

Answers

Answer:

f(x)= 40x

Step-by-step explanation:

Hope this helps, have a nice day/night! :D

The type of sampling method in which a sample frame is divided into groups, which are highly similar to the others is:

Answers

The type of sampling method in which a sample frame is divided into groups, which are highly similar to the other

Simple random sampling.

According to the given question, we are asked to show the name which is given to the type of sampling method in which a sample frame is divided into groups, which are highly similar to the other.

As a result of  this, when a sample frame is divided into groups which are very similar to each other, then this is a simple random sampling.

In this method, we can see that there are different types of random sampling techniques which includes:

Simple random samplingStratified random samplingCluster random samplingSystematic random sampling

Therefore, the correct answer is Simple random sampling.

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The cost of 4 books is $18.00 and the cost of 4 pens is $20.00. Find the cost of six similar
books and six similar pens.

Answers

4 books is 18.00
18/4 is 4.5
$4.50 per book

4 pens is 20.00
20/4 is 5
$5.00 per pen

6 books $4.50 each
6(4.50) = $27

6 pens $5.00 each
6(5) = $30

6 books is $27
6 pens is $30
6 books = $27 and 6 pens = $30
4 books = $18 so divide 18 by 2 get 9 so 2 books are $9 just add $18 to $9 to get $27
4 pens = $20 so divide 20 by 2 get 10 so 2 pens = $10 just add $20 to $10 to get $30

Diagonals of rhombus pqra intersects at o. find (m<opq + m<oqp).​

Answers

Answer:

→ [tex]90°[/tex]

Step-by-step explanation:

Given that

PQRS is a rhombus

The diagonals PR and QS intersects at O

We know that

In a rhombus the diagonals bisects at each other at 90°

So,

In ∆ POQ,

∠ POQ + ∠OPQ + ∠OQP = 180°

➜ 90° + ∠OPQ + ∠OQP = 180°

➜ ∠OPQ + ∠OQP = 180° -90°

➜ ∠OPQ + ∠OQP = 90°

Therefore, the measure of ∠OPQ + ∠OQP is 90°.

Read more:

Similar Questions

In a rhombus ABCD, m∠A = 31°. Point O is a point of intersection of diagonals. Find the measures of the angles of triangle ΔBOC.

https://brainly.com/question/3124169?referrer

I just need help with these 3

Answers

Answer:

1) 11c

2) 9m - 14

3) 4x - 5

-----

4) x = 4

5) x = 2

Step-by-step explanation:

1)

10c + c

11c

2)

5m + 2( 2m - 7 )

5m + 4m - 14

9m - 14

3)

6x - ( 2x + 5 )

6x - 2x - 5

4x - 5

-----

4)

3x + 7 = -5

3x = 12

x = 4

5)

18 = 4x + 10

8 = 4x

2 = x

Hopefully this helps!

Brainliest please?

Answer:

Step-by-step explanation:

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. The bicyclist heading north is riding 4 km/hour faster than the bicyclist heading south. At 10:15, they are 40 km apart. Find the two bicyclists’ rates.

A. northbound bicyclist = 19 km/h; southbound bicyclist = 15 km/h

B. northbound bicyclist = 18 km/h; southbound bicyclist = 13 km/h

C. northbound bicyclist = 16 km/h; southbound bicyclist = 10 km/h

D. northbound bicyclist = 18 km/h; southbound bicyclist = 14 km/h

Answers

Answer:

D Option is the correct one.

Step-by-step explanation:

As,

Distance covered = 40km = 40000m(1k=1000m)

time = 10:15-9:00 = 1:15hours = 75mins

We need to find the rates of the bicyclist in one hour so, for this first we need to calculate the total distance which covered in one hour.

For calculating distance for one hour,

40000/75 = 533.33m/min (means they covered 533.33m distance in one min)

for one hour:

533.33*60= 32000m = 32km

They covered 32km distance in one hour.

Now from the given options D is the correct one because according to give condition north bicyclist covered 4km more that south one. And other reason is we also need to check the sum of distance covered by the both cyclist which must be equal to 32km.

So for A,

Sum = 19 + 15 =34 (wrong not equal to 32)

For B,

Sum = 18 + 13 = 31 (wrong)

For C,

Sum = 16 + 10 = 26(wrong)

For D,

Sum = 18 + 14 = 32 (Right)

And second distance b/w both distance is 4km.

18-14 = 4(Right)

So, D option is the right one.

I hope it will help you.

Find the value of X in the following 3x+4=25

Answers

The answer is 7

Step-by-step explanation:

subtract 4 from 25 which is 21 than divide by 3 getting x =7

Answer:

x=7

Step-by-step explanation:

3x+4=25

3x=25–4

3x=21

X=21÷3

X=7

Sprinters who run 100 yards now often run 100 meters.

How many meters longer to the nearest tenth is 100 meters than 100 yards?

Enter the correct answer in the box.

Answers

Answer:

100 meters is 8.6 meters longer than 100 yards.

Step-by-step explanation:

Conversion of yards to meters.

Each yard has 0.914 meters.

So 100 yards is 100*0.9144 = 91.4 meters.

How many meters longer to the nearest tenth is 100 meters than 100 yards?

100 yards = 91.4 meters

100 - 91.4 = 8.6

So 100 meters is 8.6 meters longer than 100 yards.

among 240 students it was fount three - fourth of the students preferred to play hockey and one-eighth of the students preferred to play cricket the number of students whole prefer to play hockey and cricket respectively are.

a) 180 and 30 b) 40 and 180
c) 180 and 40. d) none of these​

Answers

The answer is d) none

please can someone help me with this question. I will mark as brainliest!​

Answers

Add all the sides
Then add the similar terms
Hope this helps

The two interior angles that are not adjacent to an exterior angle are remote interior angles. TrueFalse

Answers

Answer:

true

Step-by-step explanation:

true

Make n the subject of the formula
m = 5 n - 21

-----------------------------------------------------------
Can someone please help and explain!!
Incorrect or incomplete answers will be reported

Answers

Answer:

[tex] \mathsf{ \frac{m + 21}{5} = n }[/tex]

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

there's a "-21" next to "5n", inverse of subtraction is addition, so add 21 on both sides of the equation.

=> m + 21 = 5n - 21 + 21

=> m+ 21 = 5n

There's also a 5 attached to n, that means the multiplication of n with 5, the inverse of multiplication is division, so dividing both sides of the equation by 5

[tex] \mathsf{ \frac{m + 21}{5} = n }[/tex]

Mallika and Kishore have the same numbser o marbles. To have 100 marbles they must pool their marbles together and then gset 30 more. " which equation represents the above relationship?

Answers

Number of marbles with Mallika = x

Number of marbles with Kishore = x (same number of marbles)

To get 100 marbles = x + x + 30

=》x + x + 30 = 100

2x + 30 = 100

2x = 100 - 30

2x = 70

x = 70/2

x = 35

■ Final answer =》Mallika & Kishore both have 35 marbles each.

■ Equation =》2x + 30 = 100

■ Equation type =》Linear equation in 1 variable

______

Hope it helps ⚜

The equation for the given situation will be;

⇒ 2x + 30 = 100

Where, 'x' is represent the number of marbles.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Mallika and Kishore have the same number of marbles.

And, To have 100 marbles they must pool their marbles together and then get 30 more.

Now,

Since, Mallika and Kishore have the same number of marbles.

Hence, Let the number of marbles = x

So, We can formulate;

⇒ x + x + 30 = 100

⇒ 2x + 30 = 100

⇒ 2x = 100 - 30

⇒ 2x = 70

⇒ x = 35

Thus, Number of marbles each have = 35

And, The equation for the given situation will be;

⇒ 2x + 30 = 100

Where, 'x' is represent the number of marbles.

Learn more about the mathematical expression visit:

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Evaluate.

(−1/3+0.3(−1/3)+1)2

What is the value of the expression?

Enter your answer as a simplified fraction in the box.

Answers

Answer: 1.133333

Step-by-step explanation:

The value of the expression [tex]\frac{17}{15}[/tex] .

What is simplification?

Simplification means simplifying processes involved in work towards consistency of efforts, costs and time. Fraction questions in mathematics frequently require lengthy calculations and complicated sums. Some pupils find it more challenging and require more time to solve. But don't worry—there is a solution for you in this article on math simplification. It will assist you in finding simple ways to simplify fractions. You'll discover what simplification is, how and where to simplify fractions, and the procedures involved in simplifying fractions in this article. Additionally, you'll learn the exact steps to take.

Here, do normal simplification using BODMAS rule.

Hence, the required value is [tex]\frac{17}{15}[/tex]

Learn more about simplification from given link

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I need help please! It’s due tonight and I don’t know.

Answers

Answer:

i think the first question is yes and the second one is no

Step-by-step explanation:

whats the answer for this??

Answers

Step-by-step explanation:

what do you mean "what's the answer for this ?"

you only need to put 3 in place of x (that's what is meant by "x is 3" or x = 3) and then simply calculate.

you know what "squaring" ("something to the power of 2" or x²) means ? it means that you have to multiply that "something" by itself.

y = 3² + 11 = 3×3 + 11 = 9 + 11 = 20

that's all there is to this.

Hello, this is my brother's homework. I'm a little bit confused since I studied this lesson a long time ago..Can someone help me? I am not sure about my answer..​

Answers

Answer:

Length of side of square=25ft

Length of three sides=3(25)=75ft

3ft=1m75ft=15m

Cost per metre=15.00

Total cost:-

[tex]\\ \sf\longmapsto 15(15)=225.00[/tex]

Quadrilateral JKLM with vertices J(2, 10),
K(8,9), L(7,4), and M(3, 4):
J
k = 2, centered at (4,7)

Answers

Given:

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate  quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate  quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate  quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Triangle JKL with vertices /(1, -1), K(2, 3), and
L(3,-2) in the line x = 4.
.ب)J
K'.
L'(_
(

Answers

The reflection of the triangle JKL across the line x = 4 is equivalent to

equivalent to flipping the preimage across the line x = 4.

The correct coordinates are;

[tex]\underline{J'(7, \, -1)}[/tex]

[tex]\underline{K'(6, \, 3)}[/tex]

[tex]\underline{L'(5, -2)}[/tex]

Reasons:

The given transformation is a reflection about the line x = 4

The points of triangle JKL are J(1, -1), K(2, 3), and L(3, -2), in the line x = 4

The coordinates of the triangle JKL following a reflection across the line x = 4, have the same y-coordinates , while the x-coordinates have the same distance magnitude to the line x = 4, but opposite sign.

Distance between x-coordinate of the point J and the line x = 4 is 4 - 1 = 3

Which gives;

Distance between x-coordinate of the point J' and the line x = 4 is 4 + 3 = 7

Therefore, the coordinate of the point J' is [tex]\underline{J'(7, \, -1)}[/tex]

Similarly, we have;

Distance between x-coordinate of the point K and the line x = 4 is 4 - 2 = 2

Distance between x-coordinate of the point K' and the line x = 4 is 4 + 2 = 6

The coordinate of the point K' is [tex]\underline{K'(6, \, 3)}[/tex]

Distance between x-coordinate of the point L and the line x = 4 is 4 - 2 = 2

Distance between x-coordinate of the point L' and the line x = 4 is 4 + 2 = 6

The coordinate of the point L' is  [tex]\underline{L'(5, -2)}[/tex]

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Which equation represents the sentence?

The sum of 10 and a number is 3 times the number.


10 + n = 3n


10 + n = 3 + n


10 + 3n = n


10(n + 3) = n

Answers

Answer:

the first one

10+n = 3n

Step-by-step explanation:

n is the number

and 3n means 3*n

Answer:  the answer the first one 10+n=3n

Step-by-step explanation:

n is the number

and 3n means 3*n

For f(x), evaluate the following: a. f(0), b. f(6) and show all of your work. // I've attached the function below.

Answers

Answer:

a. f(0) = 4

b. f(6) = 8

Step-by-step explanation:

This is a piecewise function, so the actual equation is on the left, and the inequalities are on the right.

If x = 0, this would fall under the first part of the function because x < 5 is the requirement for the first part. Then, evaluating it: f(0) = 0 + 4 = 4.

If x = 6, this would fall under the second part of the function because 5 [tex]\leq[/tex] x < 7 is the requirement. 6 falls under this category, so that means the second part of the function is used. Because it is a constant, 8, this evaluates to f(6) = 8.

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