acetylene c2h2 gas is often used in welding torches because of the very high heat produced when it reacts with oxygen o2 gas, producing carbon dioxide gas and water vapor. calculate the moles of carbon dioxide produced by the reaction of 0.055mol of oxygen. be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits. .083mol

The empirical formula of a sample of a compound that contains 72.0 g of C. 18.0 g of H, and 28.0 g of N is C₃H₉N.

Empirical formula is the notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of a compound can be calculated as follows:

C = 72.0g

H = 18.0g

N = 28.0g

Next, we divide by the atomic mass of each element as follows:

Next, we divide by the smallest mole as follows:

The empirical ratio is 3:9:1, hence, the empirical formula of the compound is C₃H₉N.

The options to the incomplete question are as follows:

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According to the Bohr model, electrons orbit the nucleus at constant energies then the speed of the electron is I = 1.05 mA.

The Bohr model, also known as the Rutherford-Bohr model, was first proposed by Niels Bohr and Ernest Rutherford in 1913 and describes an atomic system with an orbiting system of electrons and a small, dense nucleus that is similar to the Solar System in structure but is attracted by electrostatic forces rather than gravity.

Speed of electron = v = 2.19 × 1[tex]$$0^6[/tex]  m/s

Radius of circular path = [tex]$\gamma[/tex] = 5.29 × 1[tex]0^{11}[/tex] m

The period of electron Pn its orbits is,

T = 2π[tex]\gamma[/tex] / V

To find the current represented by the orbiting electron

I (ΔQ/Δf) = |e|/T = |e|V /2πr

substitute the value in the above equation, we get

[tex]$I=\frac{\left(2.19 \times 10^6\right)\left(1.60 \times 10^{-19}\right)}{2(8.14)\left(5.29 \times 10^{-11}\right)} \\[/tex]

simplifying the equation, we get

I = 1.75 × 10-³  C/s

I = 1.05 mA

Therefore, the speed of the electron is I = 1.05 mA.

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The cloud mist as the number of "dry days” increases and fewer precipitation events contributing to the annual total of cloud mist or the dry days has been increased.​

The main procedure of formation of cyclones is that when hot moist air flows at  the upper surface of the ocean it tries to move in upward direction due to which less amount of air is left at the surface of ocean and hence a lower air pressure is created in this area.

Surrounding air which is at higher air pressure try to push the low pressure air which rises the temperature of low pressure air and again this air moves upward leaving behind less air at the surface of the ocean.

When this high temperature and moist air moves in the upward direction it temperature decreases due to which clouds are formed . This combination of clouds and wind continuously grows and started spinning. When this combination of wind and clouds spin fast,  that time an eye is formed at the center. At this center very low air pressure is there and  air with high pressure flows down into this center.

Therefore, The cloud mist as the number of "dry days” increases and fewer precipitation events contributing to the annual total of cloud mist or the dry days has been increased.​

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According to the data 0.855 moles Mg(OH)₂ has in 0.05 kg from substance.

Add the number of moles to the substance's molecular weight. The molecular weight of a substance determines how many grams there are in a mole and provides a conversion factor from moles to grams for that specific substance. 1 mol H2O x 18.02 g/mol = 18.02 g, or 18.02 grams, is the mass of one mole of water.

1 kg = 1000g

We can convert 0.05 kg to grams

0.05 * 1000 = 50 grams

Then Find moles of Mg(OH)₂

1 grams Mg(OH)₂ is equal to 0.0171 mole

Then 50 grams Mg(OH)₂ is :

50 * 0.0171 = 0.855 moles

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Using significant figures and rounding up, the resulting mass is 80.5 g.

When using addition or subtraction, the total number of significant figures is relevant. Instead, the last significant figure of every number is considered.

In 30.05, the last significant figure is 5, and it is in the hundredths. In 50.0, the last significant figure is 0, and it is in the tenths. Finally, in 0.4006, the last significant figure is 6, and it is in the ten thousandths. Of the three, the 0 from 50.0 is in the "highest" position, and so the last significant figure of the results should also be in the tenths.

If we add the numbers up, we get:

30.05 g + 50.0 g + 0.4006 = 80.4506 g

Because the last significant figure should be in the tenths, we are going to round up 4 to 5, because trailing numbers are greater than 0, so the final mass will be 80.5 g.

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Around the cuts you want the transition to appear on, add in and out points.

You can build a transition from one state in the lifecycle to another state using the new Transition dialog box. You can additionally specify which roles are permitted to move the object through this transition by using this feature.

A solute in a gaseous, liquid, or solid phase can dissolve in a solvent to create a solution through the process of dissolution.

Solubility. The greatest concentration of a solute that may dissolve in a solvent at a specific temperature is known as solubility.

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Precipitation is any liquid or frozen water that forms in the atmosphere and falls back to the Earth.

Acid–base reaction, a type of chemical process typified by the exchange of one or more hydrogen ions, H+, between species that may be neutral

An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species.

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Answer:

Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.

and For jewellery and ornaments, gold, platinum and silver are being used. For building purposes, iron and steel can be used. Iron and aluminium are used as utensils. The thermometer uses mercury and helps to monitor the temperature.

Explanation:

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The value of the equilibrium constant at 627 °C, based on equilibrium pressures, will be 44.1.

First, we write the balanced reaction equation:

2 SO₂(g) + O₂(g) → 2 SO₃ (g)

Based on the reaction equation, the expression for the equilibrium constant (Kp) will look like this:

[tex]K_{p} =\frac{(pSO_{3} )^{2} }{pO_{2}(pSO_{2} )^{2} }[/tex]

pSO₃ - partial pressure of sulfur(VI) oxide

pO₂ - partial pressure of oxygen

pSO₂ - partial pressure of sulfur(IV) oxide

To calculate Kp, we need the equilibrium pressures for all three gasses. We already know the pressure for sulfur(VI) oxide (1.10 atm), but we need to calculate it for oxygen and sulfur(IV) oxide as well.

Because the molar ratio of sulfur(IV) oxide and sulfur(VI) oxide is 1:1, that means that for the formation of 1.10 atm of sulfur(VI) oxide, 1.10 atm of sulfur(IV) oxide was expended, so the equilibrium pressure of SO₂ will be 1.48 atm - 1.10 atm = 0.38 atm.

We apply the same principle for oxygen, but because oxygen:sulfur(VI) oxide ratio is 1:2, only 1.10 atm / 2 = 0.55 atm of oxygen was expended for the formation of sulfur(VI) oxide, leaving us with the oxygen equilibrium pressure of 0.74 atm - 0.55 atm = 0.19 atm.

We plug these values into the expression above:

Kp = (1.10 atm)² / (0.19 atm * (0.38 atm)²) = 44.1

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Answer:

Explanation:

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Answer:

A. 32 g

Explanation:

Density = 2.7 g/cm3

Volume = 2 x 2 x 3 = 12 cm3

Mass = dV = 2.7 x 12 = 32.4 g or 32 g

The air behind a cold front is always cooler than the air in front of it.

The air behind a cold front is much colder and drier than the air in front of it. When a cold front passes the temperature can drop by more than 15 degrees in the first hour. Air masses behind a cold front can be cooler and drier than those in front of the front. When a cold front approaches, precipitation may occur just before or during the passage of the front.

Clear skies cooler temperatures and lower relative humidity behind the front are expected. The answer is the boundary between two different air masses where cold air is retreating and warm air is advancing. A front represents the boundary between two different air masses, such as warm and cold air. A cold front occurs when cold air turns into warm air.

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Answer: Question 1.: B. Question 2.: D. Question 3.: C. Question 4.: A.

The empirical formula of the compound, given it contains 19.3% Na, 26.9% S, and 53.8% O is NaSO₄

The following paameters were obtained from the question:

The empirical formula of the compound can be obtained as follow:

Divide by their molar mass

Na = 19.3 / 23 = 0.839

S = 26.9 / 32 = 0.840

O = 53.8 / 16 = 3.3625

Divide by the smallest

Na = 0.839 / 0.839 = 1

S = 0.840 / 0.839 = 1

O = 3.3625 / 0.839 = 4

Thus, the empirical formula of the compound is NaSO₄

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Complete question:

A compound is 19.3% Na, 26.9% S, and 53.8% O. Its formula mass is 238 g/mol. What is the empirical formula? Show your work in a neat and logical manner.

Plants recycle hydrogen during cellular respiration, as the hydrogen in glucose is recycled as water. The correct option is d.

Food molecules are broken down into energy, water, and carbon dioxide during cellular respiration. In the presence of oxygen, cells respire. Multiple chemical cycles are involved in cell respiration.

In plants, cellular respiration occurs but in a minimum amount, and in this process the hydrogen in combines with oxygen and forms water.

Therefore, the correct option is d. The hydrogen in glucose is recycled as hydrogen gas.

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Answer: Plants recycle hydrogen during cellular respiration, as the hydrogen in glucose is recycled as water. The correct option is d.

Explanation: What is cellular respiration?

Food molecules are broken down into energy, water, and carbon dioxide during cellular respiration. In the presence of oxygen, cells respire. Multiple chemical cycles are involved in cell respiration.

In plants, cellular respiration occurs but in a minimum amount, and in this process the hydrogen in combines with oxygen and forms water.

Therefore, the correct option is d. The hydrogen in glucose is recycled as hydrogen gas.

Answer:

Au, C, K, O

Explanation:

Au = Gold

C = Carbon

K = Potassium

O = Oxegen

H20 = Not an element on the periodic table

CO2 = Not an element on the periodic table

NaCl = Not an element on the periodic table

Milk = Not an element on the periodic table

Mud = Not an element on the periodic table

Air = Not an element on the periodic table

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Answer:

A charged particle is called an ion.

A charged particle is called an ion.

Any atom or group of atoms that bears one or more positive charge is called cation and one or more negative charge is called anion.

High silica content lava flow is thick and viscous and does not flow easily.

Though lava rises upwards toward the surface, it is too thick to pass through the Earth's fissures and crevices. Pressure is increasing as the lava continues to surge upward.

The least dangerous process involved in volcanic eruptions is lava flow. The temperature, silica content, extrusion rate, and slope of the terrain are all factors that affect how far a lava flow travels. A lava flow with a high silica content or one that is chilly will not move very far. Such a flow would be extremely viscous (a high resistance to flow). Low silica content is characteristic of basalt flows like those in Hawaii, OR long-distance flow, and low viscosities.

A MAGMA COMPOSITION AND TYPES OF ROCK

There are various varieties of magmas, ranging from mafic magmas, which have high Fe and Mg contents and relatively little silica, to felsic magmas, which have low Fe and Mg contents and relatively high silica.

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Because the oldest rocks with fossilized evidence of life on earth are at least 3.5 billion years old, life on earth must have started at least then.

According to a study, Earth may have been a "waterworld" without continents 3 billion years ago. Without any continents to divide the oceans, Earth may have been entirely submerged in water about 3 billion years ago, resembling a "waterworld." The 3.5 billion year old "stromatolites," which are hard structures made by microbes, also contain evidence of their presence. Stromatolites are produced when microbe-made sticky mats trap and organize sediments into layers. Even as the microbes disappear, minerals precipitate inside the layers, forming strong structures.

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Answer:

the answer is 0,000423

Explanation:

according to 3SF

The percent of aluminum (Al) by mass in the given mixture of the two powdered oxides is 29%.

The mass percent formula can be expressed by mass of the each element in one mole of the compound. The mass percentage of each component can be calculated as:

Mass percentage = (Mass of an element 1 mole of the compound)/ (molar mass of compound) × 100

Given, the mass of the mixture of the oxides Al₂O₃ and Fe₂O₃ is equal to 10.0 g.

The mass of the Al₂O₃ recovered = 5.5 g

The number of moles of Al₂O₃ = 5.5/101.96 = 0.054 mol

One mole of Al₂O₃ has two moles of aluminum.

0.054 mol Al₂O₃ will have moles of aluminum = 0.054 × 2 = 0.108

The molar mass of the aluminum (Al) = 26.98g/mol

The mass of 0.108 mol of Al = 0.108 × 26.98 = 2.9 g

The percentage by mass of Al in mixture = (2.9/10) × 100 = 29%

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Oxaloacetate contains 4C and is combined with acetyl-CoA which contains 2C in its acetyl group to produce citric acid which contains 6 carbon.

The tricarboxylic acid (TCA) cycle, also known as the Krebs or citric acid cycle, is the main source of energy for cells and a crucial step in aerobic respiration. The cycle transforms the chemical energy of acetyl coenzyme A (acetyl CoA) into nicotinamide adenine dinucleotide's reducing force (NADH).

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The Empirical formula of the compound is C₅H₅O.

and molecular formula of the compound is  C₁₀H₁₀O₂.

mass of C in the compound = (196g CO2)x (12.0 g C/44.0 g CO2) = 53.45g C

mass of H in compound = (40.2 g H2O) x (2.0 g H /18.0 g H2O) = 4.46 g H

mass of O in compound = 72.3 g total - 53.45 g C - 4.46 g H = 14.39 g O

now convert mass of each element to moles

53.45 g C x (1 mole C/12.0 g C) = 4.45 moles C

4.46 g H x (1 mole H/1.0 g H) = 4.46 moles H

14.39 O x (1 mole O/16.0 g O) = 0.899 moles O

Divide each by 0.899 to get C₅H₅O, which has a mass of 81 g

double that to get C₁₀H₁₀O₂ with mass of 162 g.

This is a "classic" example of a combustion analysis problem.

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NO₂  is the example of fewer than eight number of valence electrons due to an odd no. of valence electrons.

N , atomic no. is 7 = 2 , 5

O , atomic no. is 8 = 2, 6

SCl₆ is the example of more than eight valence electrons due to an expanded octet.

S , atomic no. is 16 = 2 , 8 , 6

Cl , atomic no. is 17 = 2 , 8 , 7

BeF₂ is the example of fewer than eight valence electrons due to shortage of valence electrons.

Be, atomic no. is 4 = 2, 2

F , atomic no. is 9 = 2 , 7

These are the examples of odd no. of electrons, expanded octet due to more valence electron and less than eight valence.

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Polypropylene is considered as safe for use. The chemicals found in plastic products are proven to contribute to some cancers.

Its usage in high temperature applications is constrained by its high thermal expansion coefficient.

Heavily resistant to both aromatic and chlorinated solvents. It is vulnerable to UV damage.

It is well known for being challenging to paint because of its low bonding capabilities.

It is highly flammable.

Plastic containers, component parts for machinery and equipment, and even fibers and textiles are only a few applications for polypropylene.

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Citric acid, which has 6 carbons, is created by combining oxaloacetate, which has 4 carbons, with acetyl-CoA, which has 2 carbons in its acetyl group.

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Answer:

D

Explanation:

The heating, rising, cooling, and sinking cycles are called convection currents. 2. A version of this same process, occurring in the mantle, is thought to be the force behind plate tectonics. ... Scientists suggest that differences in density cause the hot, plastic-like rock to be forced upward toward the surface.

In the given condition where the thylakoids are isolated from the chloroplasts to make the pH of the thylakoid space acidic, the isolated thylakoid will form the ATP.

ATP is also referred to as Adenosine Triphosphate and is correctly called as the energy currency of the cell as it is responsible molecule for carrying the energy units in the cell. When the isolated thylakoids are made to transfer in the pH = 8 basic solution, then the acidic lumen of the chloroplast will be having a higher concentration of H⁺ ions. When they are placed in the basic solution then the H⁺ ions will move out because of the occurrence of concentration gradient which is higher in the lumen than the surrounding. The chloroplasts will now bear synthesis of ATP. Therefore, the isolated thylakoid is able to make ATP when the lumen is acidic, and the surroundings are made basic in nature.

Thus, the thylakoid which is isolated will bear the synthesis of ATP.

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Replica plates on medium with glucose or tryptophan as the only energy source. You would look for colonies that can grow only on the plates with glucose

The turns, which separate the RNA transcript from the transcription bubble, are created by complementary base pairing. Genes that are constitutively expressed, or "housekeeping" genes, have the highest frequency of GbM, while genes with the most variable expression have the lowest frequency.

During transcription, the mRNA strand develops a hairpin loop that separates the RNA polymerase from the DNA template strand. The sequences involved in this process are referred to as terminator sequences, and the process is known as rho-independent or intrinsic termination.

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Answer:

Electrons have a negative charge and are found in the area of an atom called Outer Shell

Electrons have a negative charge and are found in the area of an atom called electron shells.