Answer:
Since two angles of the triangle have the same measure, the triangle is an isosceles triangle.
Let one angle be a variable (eg: x) so we can form expressions and solve.
Let the first and second angle be x°.
Form an expression for the third angle using the information given.
Third angle = (x + 21)°
Since sum of angles in a triangle is 180°, we can form an equation.
x + x + (x + 21) = 180
Simplify and solve for x.
3x + 21 = 180
3x = 159
x = 53
Largest angle is the third angle.
Substitute x into the expression to find the value.
Third angle = 53 + 21
= 74°
The graph shows the cost per pound for bananas.
How many pounds of bananas can be purchased for $3.00?
For $3.00, the pounds of bananas that can be bought are 2.
How to derive equation of line from graph using two point form?
A line's equation can take many different shapes in a two-dimensional coordinate plane. The point-slope form, slope-intercept form, and general or standard form of the equation of a line are the three most often used techniques.
The formula of two point form of a equation is given below:
Let (x₁, y₁) and (x₂, y₂) be the two points such that the equation of line passing through these two points is given by the formula:
(y-y₁)/(x-x₁) = (y₂-y₁)/(x₂-x₁) -- (i)
Rearranging (i), we get: y - y₁ = [(y₂-y₁)/(x₂-x₁)] (x-x₁) --(ii)
Given, the graph has y co-ordinate as cost in $ of bananas and the x co-ordinate as pounds in lb.
From graph in question, the two points that can be assumed are (0.5,0.75) and (3,4.5); thus using two point form we get the equation as:
y - 0.75 = [(4.5 - 0.75)/(3 - 0.5)] *(x - 0.5) ⇒ y - 0.75 = 1.5 (x - 0.5)
⇒ y - 0.75 = 1.5x - 0.75 ⇒ y = 1.5x ⇒ x = y/1.5 --(ii)
From (ii),
thus for y = 3, value of x will be x = 3/1.5 = 2
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At one university, the mean distance commuted to campus by students is 19.0 miles, with a standard deviation of 4.2 miles. Suppose that the commutedistances are normally distributed. Complete the following statements.(a) Approximately 95% of the students have commute distances between ? milesand ? miles(b) Approximately ? of the students have commute distances between 6.4 miles and 31.6 miles.
From the given information, we know that the mean and standard deviation are, respectively,
[tex]\begin{gathered} \mu=19 \\ \sigma=4.2 \end{gathered}[/tex]From the 68-95-99 rule, we know that approximately 95% falls between 2 standard deviation of the mean, that is,
[tex]-2=\frac{x-19}{4.2}...(A)[/tex]and
[tex]2=\frac{x-19}{4.2}...(B)[/tex]From equation (A), we have
[tex]x-19=-8.4[/tex]then
[tex]x=10.6[/tex]Now, from equation (B), we get
[tex]\begin{gathered} x-19=8.4 \\ then \\ x=27.4 \end{gathered}[/tex]Therefore, the answer for part a is: Approximately 95% of the students have commute between 10.6 and 27.4 miles
Part b.In this case, we need to find the z score value for 6.4 miles and 31.6 miles and then obtain the corresponding probabilty from the z-table.
For 6.4 miles, the z score is
[tex]z=\frac{6.4-19}{4.2}=-3[/tex]and for 31.6 miles, the z score is
[tex]z=\frac{31.6-19}{4.2}=3[/tex]Now, we need to find the corresponding probability between z=-3 and z=3, which is 0.9973
Therefore, the answer for part b is: Approximately. 0.9973 of the students have commute distances between 6.4 miles and 31.6 miles
The probability is 0.7 that a person shopping at a certain store will spend less than $20. For random samples of 28 customers, find the mean number of shoppers who spend less than $20.
Answer:
approximately 19~20 shopper
Step-by-step explanation:
this case binomial distribution
X~B(n,p)
X: number of shoppers who spend less than 20$
n=28
p=0.7
use mean of binormal distribution E(X)=np
Answer)
E(x) =28*0.7=19.6
thus approximately 19~20 shopper
A chef needs 3/4 of a cup of flour for her recipe, but her 1/4 cup measure is missing. Which method could she use to measure an equivalent amount?
The method that she could use to measure an equivalent amount is to remove 25% from the measurement used.
How to calculate the fraction?From the information, the chef needs 3/4 of a cup of flour for her recipe, but her 1/4 cup measure is missing.
Therefore, the method that she could she use to measure an equivalent amount will be to subtract 25% from whatever value that she is using.
It should be noted that 3/4 to percentage will be:
= 3/4 × 100.
= 75%
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1. Solve the absolute value equation, if possible. If there is no solution, explain why.| 5x + 10| = -7
Answer:
There is no solution.
Step-by-step explanation:
The absolute value of a number is the distance between that number and zero. It doesn't deal with negative numbers. For example, if you were playing a board game and were told to move back 6 spaces, you would be moving -6 spaces, but 6 spaces away from where you were. Absolute value focuses on how far you moved from where you were. So, an absolute value can't be negative.
1. evaluate (a-2b)^3 when a = -3 and b = - 1/2 enter the answer
2. evaluate (jk - 1) ÷ j when j = -4 and k = -0.9 enter as a decimal
3. evaluate -|a+b| /fraction line/ 2-c when a =1 7/8 , b = -1 , and c = -4 enter as a simplified fraction
4. evaluate (w^2 /fraction line/ x - 3) ÷ 10 multiplied by z when w = -9 , x = 2.7 , and z= -2/5 enter as simplified mixed number
5. evaluate (2a - 1/3) ÷ b/15 when a = -2/5 and b = -8.25 enter as simplified mixed number
The corresponding values of expressions 1, 2,3,4 and 5 when evaluated are -2, -0.65, -7/48, 67 1/2 and 2 2/33
How to evaluate algebraic expressions?1. To evaluate (a-2b)^3 when a = -3 and b = - 1/2, put a = -3 and b = - 1/2 into the expression (a-2b)^3:
(a-2b)^3 = ( -3 - 2(-1/2) )
= (-3 + 1) = -2
2. To evaluate (jk - 1) ÷ j when j = -4 and k = -0.9, put j = -4 and k = -0.9 into the expression (jk - 1) ÷ j:
(jk - 1) ÷ j = ( -4(-0.9) - 1) ÷ (-4)
= (3.6 -1) ÷ (-4) = (2.6) ÷ (-4) = -0.65
3. To evaluate -|a+b| / 2-c when a =1 7/8 , b = -1 , and c = -4 , put b = -1 , and c = -4 into the expression -|a+b| / 2-c:
-|a+b| / 2-c = -|1 7/8 + (-1)|/ 2 -(-4)
= -| 7/8 | / 6 = -7/48
4. To evaluate (w^2 / x - 3) ÷ 10 multiplied by z when w = -9 , x = 2.7 , and z= -2/5:
(w^2 / x - 3) ÷ 10z = ((-9)²/ 2.7 -3) ÷ 10(-2/5)
= (81/(-0.3)) ÷ (-4) = -270/-4 = 67 1/2
5. To evaluate (2a - 1/3) ÷ b/15 when a = -2/5 and b = -8.25:
(2a - 1/3) ÷ b/15 = (2(-2/5) - 1/3) ÷ -8.25/15
= (-4/5 - 1/3) ÷ (-11/20) = -17/5 ÷ (-11/20) = 2 2/33
Therefore, the expressions 1, 2,3,4 and 5 evaluate to -2, -0.65, -7/48, 67 1/2 and 2 2/33 respectively
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Can someone please help me with this, it’s geometry by the way
Answer:
congruent: a° and c°; d° and b°
Supplementary: c° and b°; a° and b°; a° and d°; c° and d°
Step-by-step explanation:
On a coordinate plane, a curve goes through (negative 1, 0), (0, negative 60), (2.5, negative 60), and (4, 0).
The real solutions of the equation x4 – 7x3 + 23x2 – 29x – 60 = 0 are shown. What are the nonreal solutions to the equation?
2 + i StartRoot 11 EndRoot, 2 minus i StartRoot 11 EndRoot.
Negative 2 + i StartRoot 11 EndRoot, Negative 2 minus i StartRoot 11 EndRoot.
4 + 2 i StartRoot 11 EndRoot, 4 minus 2 i StartRoot 11 EndRoot.
Negative 4 + 2 i StartRoot 11 EndRoot, Negative 4 minus 2 i StartRoot 11 EndRoot.
The non-real solutions of the polynomial expression are x = 2 + i√11 and x = 2 - i√11
How to determine the non-real solutions?The equation of the polynomial expression is given as:
x^4 – 7x^3 + 23x^2 – 29x – 60 = 0
Also, we have the following points
(-1, 0), (0, -60), (2.5, -60), (4, 0)
Write out the x-intercepts
(-1, 0) and (4, 0)
This means that
x = -1 and x = 4
So, we have
x + 1 = 0 and x - 4 = 0
Multiply
(x + 1)(x - 4) = 0
Divide the polynomial equation x^4 – 7x^3 + 23x^2 – 29x – 60 = 0 by (x + 1)(x - 4) = 0
Using a graphing calculator, we have
x^4 – 7x^3 + 23x^2 – 29x – 60/(x + 1)(x - 4) = x^2 - 4x + 15
So, we have
x^2 - 4x + 15
Next, we solve the quadratic expression using a quadratic formula
So, we have
x = (-b ± √(b² - 4ac))/2a
This gives
x = (4 ± √((-4)² - 4 * 1 * 15))/2 * 1
So, we have
x = (4 ± √-44)/2
This gives
x = (4 ± 2√-11)/2
Divide
x = 2 ± √-11
So, we have
x = 2 ± i√11
Split
x = 2 + i√11 and x = 2 - i√11
Hence, the non-real solutions are x = 2 + i√11 and x = 2 - i√11
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If a dragon can eat an entire cow weighing 500 kilograms in 12 seconds, how long will it take to eat a human weighing 90kilograms
2.16 sec take to eat a human weighing 90kilograms.
What is unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given:
It takes 12 seconds the Dragon eat 500 Kg.
So, to eat 1 Kg the dragon takes
=12/500
=0.024 sec
Now, to eat 90 Kg it will take
=0.024 x 90
= 2.16 sec
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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.9 t 2 + 226 t + 325 .
The rocked was launched at an initial height of 325 meters
How to determine the initial height of the launch?The equation of the function is given as
h ( t ) = − 4.9 t 2 + 226 t + 325 .
Rewrite the above equation properly
So, we have the following equation
h(t) = −4.9t^2 + 226t + 325
At the initial height of the launch, the time is 0
This is represented as
t = 0
Substitute the known values in the above equation
So, we have the following equation
h(0) = −4.9(0)^2 + 226(0) + 325
Evaluate the exponent in the above equation
So, we have the following equation
h(0) = −4.9(0) + 226(0) + 325
Evaluate the product in the above equation
So, we have the following equation
h(0) = 0 + 0 + 325
Evaluate the sum in the above equation
So, we have the following equation
h(0) = 325
Hence, the initial height of the launch is 325 meters
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Possible question
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.9 t 2 + 226 t + 325 .
Calculate the height of launch of the rocket
true or false: when you find the area of a scaled copy, you cube the scale factor.
True, cube the scale factor while finding the area of a scaled copy.
The scale factor is the ratio of two equal lengths in two similar geometric objects. The fundamental formula for calculating the scale factor is the size of the former shape is Scale factor = Dimension of the new shape ÷ Dimension of the original shape. The area of a scaled element is equal to the squared scaling factor. If the scale factor is three, the area of the new item will be nine times, or three times, that of the original object. The area scale factor is equal to the square of the length scale factor. As a result, s2 is the surface scaling factor. If this is reversed, a solution to the situation at hand will be offered. The area has a scale factor of 2.
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Lines A and B are parallelA155°34fB5 67 8m 27 = [ ? ]°
From the diagram we notice that the angle of 55° is vertical opposite to angle 3, hence they are equal.
Also from the diagram we notice that angles 3 and 6 are alternate interior angles and since lines A and B are parallel then they are equal.
Finally angle 6 and angle 7 are vertical opposite, which means they are equal.
Therefore, the value of angle 7 is 55°
How is the graph of the parent function of y=3√x transformed to produce the graph Y=2
-√√√x₂
OIt is horizontally stretched by a factor of 2.
OIt is vertically stretched by a factor of 2.
of 1/1.
1
OIt is translated left by unit.
2
10
1
OIt is translated right by 2 unit.
Using transformations, it is found that the transformation from [tex]y = \sqrt[3]{x}[/tex] to [tex]y = \sqrt[3]{0.5x}[/tex] is:
It is horizontally stretched by a factor of 1/2.
What are transformations on the graph of a function?Transformations in the graph of a function happens when operations such as multiplication/division or sum/subtraction are applied in the definition of the function.
They can be either in the domain of the function, involving values of x, or the range, involving values of y.
For this problem, the change was that x -> x/2, that is, there was a multiplication in the domain, meaning that there was an horizontal stretch to the function.
The fact that the number was multiplied by 1/2 means that the factor of the stretch is of 1/2.
What is the missing information?The transformation is from [tex]y = \sqrt[3]{x}[/tex] to [tex]y = \sqrt[3]{0.5x}[/tex].
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question linked in pic
iven:
heere are given that the population in the year 2000 was 12000 and the growth rate is 7% per year.
xplanation:
ccording to the question:
For t =0 which is the year 2000:
[tex]P(0)=12000[/tex]For t = 1:
[tex]P(1)=12000+7\%(12000)[/tex]If we say r is the rate, then:
[tex]\begin{gathered} P(1)=12000+r(12000) \\ P(1)=12000(1+r) \end{gathered}[/tex]Then,
For t = 2:
[tex]\begin{gathered} P(2)=12000(1+r)(1+r) \\ P(2)=12000(1+r)^2 \end{gathered}[/tex]And,
For t = 3:
[tex]P(3)=12000(1+r)^3[/tex]Therefore our function should be:
(a):
he population function:
[tex]P(t)=12000(1.07)^t[/tex]Now,
(b):
ccording to the question:
2008 is 8 year from year 2000:
Therefore, t = 8:
Then,
Put the value 8 for t into the function (a):
[tex]\begin{gathered} P(8)=12000(1.07)^t \\ P(8)=12000(1.07)^8 \\ P(8)=12000(1.718) \\ P(8)=20616 \end{gathered}[/tex]inal answer:
[tex]P(t)=12000\times(1.07)^{t-2000}[/tex]Represent the quadratic function please help
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: y = x² -14 x + 48[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
The values of x for which the curve cuts/touches the x - axis are roots of that particular polynomial.
So, the values of x, when y = 0 are the roots of the given quadratic function.
that is : x = 6 and x = 8
And it can be represented as :
[tex]\qquad \tt \rightarrow \: (x - h1)(x - h2)= 0[/tex]
[ h1 and h2 represents roots of the quadratic function ]
[tex]\qquad \tt \rightarrow \: (x - 6)(x - 8) = 0[/tex]
It can be further simplified as :
[tex]\qquad \tt \rightarrow \: {x}^{2} -8x - 6x + 48 = 0[/tex]
[tex]\qquad \tt \rightarrow \: x {}^{2} - 14x + 48 = 0[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
graph y=3x-3, its linear graphing
The linear graphing of the given equation y = 3x - 3 is done by plotting a series of points and then tracing a line through them.
What is linear graphing?It is a graph that illustrates how two or more quantities or objects relate to one another. Linear refers to a straight line. To show the relationship between two quantities, a linear graph is a straight-line graph. This graph is useful for showing a result as a series of simple straight lines.Given equation:
y = 3x - 3
Now we will graph this linear equation by plotting points.
We can select input values, evaluate the equation at these input values, and compute output values to determine the respective points. Coordinate pairs are created by the input and output values. The coordinate pairs are then plotted on a grid.
So, the points of the given linear equations are:
x y
-2 -9
-1 -6
0 -3
1 0
2 3
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4th grade elementary question… What is 2,746 divided by 517 =?
Answer:
It's 5.31
Explanation:
what are all the subsets of the set {-3,6}
The subsets of the set {-3, 6}, which are proper subsets is the option;
∅, {-3}, {6}What is a set in mathematics?A set is a model that represents a collection of mathematical objects such as numbers, lines, symbols, points, other sets, variables, or shapes.
In set theory, a set A is a subset of the set B if all the elements or members present in set A can be found in set B. Therefore, set B is said to contain set A or set A is contained in set B.
The above relationships can be expressed using examples as follows;
Let set A = {X, Y} and let set B = {X, Y, Z}, then set A is a subset of set B because the elements, X, Y, contained in set A, are also contained in set B,
Generally, the number of proper subsets of a set that contains n elements is [tex] {2}^{n} - 1[/tex]
Given that the subset of a set which is not a proper subset is the set of itself.
The given set is; {-3, 6}
The number of elements in the set, n = 2
Therefore;
The number of proper subsets = 2² - 1 = 3
All the subsets of {-3, 6} are therefore;
∅, {-3}, {6}
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Mateo fills a 20L jerrycan with gasoline, a volume of gasoline of 1L has a mass of 690 g and the empty jerrycan weighs 2.5 kg
a. calculate the density of gasoline
b. how much will the jerrycan weigh when it is full?
The density of the gasoline is 690 grams per litre.
The mass of the jerrycan when fully filled is 16.3 kg
How to find the density of the gasoline and mass of the jerrycan?He fills a 20 litre jerrycan with gasoline.
A volume of gasoline of 1 litre has a mass of 690 grams and the empty jerrycan weighs 2.5 kg.
Therefore, the density of the gasoline can be calculated as follows:
density = mass / volume
Hence,
mass of the gasoline = 690 grams
volume of the gasoline = 1 litres
density of the gasoline = 690 / 1
density of the gasoline = 690 grams per litre.
The weight of the jerrycan when filled with gas can be calculated as follows:
1 litre of gas = 690 grams
20 litres gas = 13800 grams
Hence,
1000 grams = 1kg
13800 grams = 13.8 kg
Therefore,
weight of the jerry can when filled with gas = 13.8 + 2.5 = 16.3 kg
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(−2, 5), slope = -4 slope intercept form
____________________________________________
Slope-Intercept Form - Solution and Explanation
____________________________________________
Hello! So...
We are given the following to convert:
Convert into Slope-Intercept Form
(-2, 5), slope = -4
____________________________
1. Compute the line equation y = mx + b for slope. In this case, our slope (m) equals -4, and passes through (-2, 5).
____________________________
2. Determine the y-intercept. In this case, b = -3.
____________________________
3. Now, construct the line equation (y = mx + b), where m = -4 and b = -3. Then, you will have your converted solution in Slope-Intercept Form.
Slope-Intercept Form:
[tex]y=-4x-3[/tex]
___________________________________________
Hope this helps! If not, feel free to comment on the matter and I will see what else I can do to assist your further. However, if this does help, lmk! Thanks and good luck!
Using the DMS method to describe an angle, one degree of angle measurement can be divided into how many minutes?
A.100'
B.360'
C.60'
D.90'
Answer: I am 97% sure it's D
Step-by-step explanation:
Given: PQ=PR,(m)/(_(Q))PR=(m)/(_(S))PK,(m)/(_(Q))=(m)/(_(P))RK Prove: PS=PK
Using ASA congruence rule, we have PS = PK.
What does congruence of triangles mean?
Two triangles are said to be congruent if all three corresponding sides and all three corresponding angles have the same size. You can move, flip, twist, and turn these triangles to produce the same effect. When relocated, they are parallel to one another. Mathematics uses the term "congruence" to describe when two figures have similar size and shape. In essence, two triangles are congruent if and only if they follow the four congruence rules. Finding all six dimensions, though, is crucial. As a result, only three of the six variables can be used to evaluate the congruence of triangles. Triangles that are congruent have comparable sides and equivalent angles.
Given, in ΔPQR we have ,
PQ = PR
and ∠PRR = ∠PQR ⇒ 180° - ∠PQR = 180° - ∠PQR ⇒ ∠PQR = ∠PSQ -(i)
Now, in ΔPSQ and ΔPRK;
∠SPQ = ∠RPK
∠Q = ∠R , given
∠SPQ = ∠RPQ
so, by ASA congruence we have , ΔPSQ = ΔPRK
Thus, PS = PK.
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Choose the correct graph to fit the inequality. x2 - y2 9
Trey buys a bag of cookies that contains 4 chocolate chip cookies, 6 peanut butter cookies, 7 sugar cookies and 7 oatmeal cookies.What is the probability that Trey reaches in the bag and randomly selects a sugar cookie from the bag, eats it, then reaches back in the bag and randomly selects an oatmeal cookie? Give your answer as a fraction, or accurate to at least 4 decimal places.
Solution
The total number nof cookies in the bag is:
[tex]4+6+7+7=24\text{ cookies}[/tex]- Thus, we can write the probabilities of choosing any of the cookies are given as:
[tex]\begin{gathered} P(\text{chocolate chip)}=\frac{4}{24} \\ \\ P(\text{Peanut Butter)}=\frac{6}{24} \\ \\ P(\text{Sugar Cookies)}=\frac{7}{24} \\ \\ P(\text{Oatmeal)}=\frac{7}{24} \end{gathered}[/tex]- Now, let us analyze Trey's random choices
Choice 1:
He chose a sugar cookie at first.
- Thus, the probability of this choice is
[tex]P(\text{Sugar Cookies})=\frac{7}{24}[/tex]Choice 2:
- He chose an oatmeal cookie in the second choice.
- But he already had one cookie before this choice, thus, the total number of cookies is one less. That is, 23 not 24.
- Thus, the probability of choosing the oatmeal cookie is given as:
[tex]P(\text{Oatmeal)}=\frac{7}{23}[/tex]- Because these choices do not interfere with one another (i.e. they are mutually exclusive), we can apply the AND probability formula to calculate the probability that Treys chose a Sugar Cookie first, and then an Oatmeal cookie next.
- The AND probability is given as
[tex]P(A\text{ AND }B)=P(A)\times P(B)[/tex]- Thus, we can find the probability that Trey chooses Sugar Cookies first and Oatmeal Cookie next as follows:
[tex]\begin{gathered} P(\text{Sugar Cookies AND Oatmeal)}=\frac{7}{24}\times\frac{7}{23} \\ \\ P(\text{Sugar Cookies AND Oatmeal)}==\frac{49}{552} \end{gathered}[/tex]Final Answer
The answer is
[tex]P(\text{Sugar Cookies AND Oatmeal)}==\frac{49}{552}[/tex]in a triangle, the first angle is three times the measure of the second angle. the measure of the third angle is 70° more than the measure of the second angle. use the fact that the sum of the measures of the three angles of a triangle is 180° to find the measure of each angle
Answer:
Step-by-step explanation:
[tex]3x+x+(x+70)=180[/tex]
[tex]5x+70=180[/tex]
[tex]5x=180-70[/tex]
[tex]5x=110[/tex]
[tex]x=110/5[/tex]
x = 22°
"x" is the second angle: 22°
"3x" is the first angle: 3(22) = 66°
"x + 70" is the third angle: 22 + 70 = 92°
22 + 66 + 92 = 180
Hope this helps
which equation are correct select each other answer
Answer:
A and D (the top one and the bottom one)
Step-by-step explanation:
You do not multiply the exponents when the two terms are be multiplied. Instead, you add the exponents. For example, in the first problem, the terms being multiplied are [tex]5y^4[/tex] and [tex]2y^5[/tex]. The exponents are 4 and 5, and when you add them together, that is the exponent that y should carry in the answer.
Hope this helps you! May I please get a brainliest?
Let f(x) =[tex]2x^2-2x-1[/tex]. At which points does the graph of the f(x) have a horizontal tangent line?
The graph has the horizontal tangent line at the the turning point(stationary point) And we know that at the turning point the gradient is 0. We can find the gradient of f(x0 by the first derivative. As I said the gradient a the turning point is 0 meaning since f'(x) =m and m=0 ∴f'(x)=0
[tex]f'(x)=4x-2\\0=4x-2\\4x=2\\\frac{4x}{4}=\frac{2}{4} \\x=\frac{1}{2}[/tex]
Now we know that in order to find the point where x = [tex]\frac{1}{2}[/tex] we can substitute the value of x in the original equation
[tex]f(\frac{1}{2})=2(\frac{1}{2} )^{2} -2(\frac{1}{2} )-1\\f(\frac{1}{2} )=-\frac{3}{2}[/tex]
The answer is [tex](\frac{1}{2} ,-\frac{3}{2} )[/tex]
Hope I helped.
How many vertical asymptotes does the graph of this function have?A.1B.2C.3D.0
olution
Basically, the number of asymptotes will be the number of solutions the denominator of the function has
We are given the function
[tex]f(x)=\frac{5}{3x(x+1)(x-7)}[/tex]Solving the denominator
[tex]\begin{gathered} 3x(x+1)(x-7)=0 \\ \\ x=0,-1,7 \end{gathered}[/tex]he answer is 3 vertical asymptotes
An investment portfolio is shown below.
Investment Amount Invested ROR
Savings Account $3,200
2.1%
Municipal Bond $4,900
4.5%
Preferred Stock
$940
10.5%
Common Stock A $1,675
-3.5%
Using technology, calculate the weighted dollar amount of the savings account.
O-$58.63
$58.63
O-$67.20
O $67.20
The weighted dollar amount of the savings account as per the an investment portfolio given is equal to $67.20.
As given in the question,
An investment portfolio is shown below.
Investment Amount Invested ROR
Savings Account $3,200 2.1%
Municipal Bond $4,900 4.5%
Preferred Stock $940 10.5%
Common Stock A $1,675 -3.5%
The weighted dollar amount of the savings account is equal to :
= 2.1% of $3200
= ( 2.1 / 100) × $3200
= ($6720) /100
= $ 67.20
Therefore, the weighted dollar amount of the savings account as per the an investment portfolio given is equal to $67.20.
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Answer:
1, 7, 13, 19, 25, 31, 37, 43
Step-by-step explanation:
it is increasing by 6 each time so you add 6 three more times.