Hello! Can you, please, explain how to solve this kind of equation "Find m+n, if P(x) = (2m-4)x^2+(5-n)x+13 is constant polynomial".

The ordered pair at which the function f(x) = √(x - 4) + 7 would begin on the coordinate plane is (4, 7).

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

An ordered pair can be defined as a pair of two elements that are typically written in a fixed order within parentheses as (x, y), which represents the x-axis (abscissa) and the y-axis (ordinate) on a coordinate plane.

By critically observing the graph of this function (see attachment), the ordered pair would begin at (4, 7) on the cartesian coordinate.

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Complete Question:

At which ordered pair will the function f(x) = √(x - 4) + 7 begin on the

coordinate plane?

The given point were reflected about the line y = x and the coordinates the reflected point (-5 , 3)  is (3, - 5)

According to the question, given that

point reflected line y =x,

Reflected point coordinates of (-5, 3), then find the coordinates of the point after in the line of symmetry :

(-5, 3) →  (3, - 5)

A reflection is referred to as a twist in geometry. A reflection is the mirror image of shape . A line, called the line of reflection, will agree an image to reflect without change it. When all of the points in a figure are evenly spaced apart from one another, the two figures are said to reflect each other. The reflected picture should have the same size and shape as the original, but it faces the opposite way. Changes in position during contemplation may also result in translation. Pre-image and image are terms used to refer to the same thing in this context. ABC and A'B'C are used to represent the pre-image and image, respectively.

A reflection point is similar to staring at a flipped mirror picture of yourself.

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It is True to state that Arcs AB, BC, CD, DE, EF, FA in the circumscribed hexagon are all equal. See the explanation below.

In geometry, a hexagon is a six-sided polygon. A regular hexagon is one in which the lengths of all the sides and the measurements of all the angles are identical. The sides of a regular hexagon are therefore equivalent.

Allow point P to be the hexagon's and circle's center.

The dimension of arc AB is the same as the measure of central angle APB, which are both 360/6 = 60 degrees. This also applies to the other arc measurements. The whole 360-degree circle is divided into six equal parts, each measuring 60 degrees.

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Full Question:

Although the question seems incomplete you may have been referring to this:


A circle P is circumscribed about a regular hexagon ABCDEF

Arcs AB, BC, CD, DE, EF, FA are all equal

Select one:

a. False

b. True

Answer:

C. x ≥ 11 or x ≤ 1

Step-by-step explanation:

x - 6 + 6 ≥ 5 + 6

x ≥ 11

x - 6 ≤ -5

x - 6 + 6 ≤ -5 + 6

x ≤ 1

Hope this helps! :)

The equivalent to the complex number i²⁷ is -i.

Every complex number may be represented in the form a + bi, where a and b are real numbers. A complex number is an element of a number system that extends the real numbers with a specific element labeled I sometimes known as the imaginary unit, and satisfying the equation

i² = 1.

Given that,

i²⁷ is a complex number

i²⁷ = i²⁴⁺³

i²⁷ = i²⁴ ₓ i³

i²⁷ = i⁴⁽⁶⁾ ₓ i²⁺¹

i²⁷ = (i⁴)⁶ . i².i

Here, we know that i² = -1

so, i⁴ = (i²)²

i⁴ = 1

Hence, 1⁶(-1)(i) = -i

Therefore, the equivalent to the complex number i²⁷ is -i.

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Answer:

picture pls

Step-by-step explanation:

I need clearer pic pls

In a case whereby  two members of the math competition team solve at the rate  13 problems in 1 hour, the members that are needed to solve 39 problems in 1 hour is 6 member of the team.

Since two members solve 13 problems in 1 hour, which implies that

2 members= 13 problem/ hr

Then if we want to calculate the number of the team that will be able to solve the problem at the rate of 39 problems in 1 hour, we can represent the number required as X.

Then X = 39 problems/hr.

2 members= 13 problem/ hr

Then in this case we can cross multiply as follows:

13 problem/ hr * X =  39 problems/hr * 2

Then we can make X the subject of the formular as X =( 78 /13)

= 6 member of the team.

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The area of the trapezoid is given as 100. See the explanation for the same below.

A trapezoid is a quadrilateral with at least one set of parallel sides in American and Canadian English. A trapezoid is known as a trapezium in British and other varieties of English.

To find the length of each side of the trapezoid, you need to use the distance formula.

AB = (-1,5) and (3,2)

BC = (3,2) and (0,-2)

CD =  (0,-2) and (-13, -11)

AD or DA =  (-1,5) and(-13, -11)

Now, just use the distance formula for each line.

The Distance Formula is given as: d=√((x2 – x1)² + (y2 – y1)²).

Distance AB = √((3 – (-1))² + (2 – 5)²).
= √(4)² + (-3)²
= √(16+9)
= √25
AB = 5

lets us repeat this for the other section we will get:

Doing so gives us for all the points:

AB = 5

BC = 5

CD = 15.811388300842

DA or AD = 20

Note that:

The height is AD, the first base is AB and the second base is BC. We can plug the values for these sides into the trapezoid area formula, which is:

A = (base 1 + base 2) /  2 x height.

A = (5+5)/2 x 20

A = 5 x 20

A = 100.

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Answer:

k = 53.13°

Step-by-step explanation:

[tex]{ tan (k) = \dfrac{\text{side opposite k}}{\text{side adjacent k}}}[/tex]

[tex]= \dfrac{35}{JK}\\\\\textrm{Since JK is a right triangle, by the Pythagorean theorem }\\JK = \sqrt{IK^2 - IJ^2}}\\\\= \sqrt{35^2 - 28^2}\\\\\\ =\sqrt{1225 - 784}\\\\= \sqrt{441}\\\\= 21[/tex]

[tex]\tan(k) = \dfrac{28}{21} = 1.333\\\\k = \tan^{-1}(1.333)\\\\= 53.13^\circ[/tex]

The value of the expression is 74 - 12x

Expressions are mathematical statements that are represented by variables, coefficients and operators

The expression is given as

-3[10+4(x-2)] all subtracted from 20

When represented as an expression, we have the following mathematical representation

20 - (-3[10+4(x-2)])

Open the brackets in the above expression

So, we have

20 - (-3[10+4(x-2)]) = 20 - (-30+12(x-2)])

Open the brackets in the above expression

So, we have

20 - (-3[10+4(x-2)]) = 20 - (-30 + 12x - 24)

Open the last brackets in the above expression

So, we have

20 - (-3[10+4(x-2)]) = 20 + 30 - 12x + 24

Evaluate the like terms in the above expression

So, we have

20 - (-3[10+4(x-2)]) = 74 - 12x

Hence, the equivalent expression of the expression "-3[10+4(x-2)] all subtracted from 20" is 74 - 12x

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Answer:

69

Step-by-step explanation:

15*3=45

12*2=24

45+24= 69

Answer: 114

Step-by-step explanation:

15×3+12×2

15×3=45

45+12=57

57×2=114

Answer:710.48 miles

Step-by-step explanation:

look it up

As per given data of end of the season , ratio of teams win to losses is 3:5 and no ties, then percentage of game win by team is equal 37 1/2%.

As given in the question,

For the given dat of end of season,

Ratio of teams win to losses is equal to 3:5

Let x be the percentage of game

As per given ratio we have,

3x+ 5x =100%

⇒ 8x = 100

⇒x =100/ 8

⇒ x= 12.5

Percentage of winning the game by team = 3x

                                                                   = 3(12.5)

                                                                   = 37.5%

                                                                   = 37 1/2%

Therefore, for given data of end of the season , ratio of teams win to losses is 3:5 and no ties, then percentage of game win by team is equal 37 1/2%.

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Point M has the same distance from point A and point B (option d).

Given,

Line segment CD is the  perpendicular bisector of line segment  AB

AB ⊥ CD

Assume the conjecture that the set of  points equidistant from A

and B is the  perpendicular bisector of AB is true

Here,  line segment CD intersect line segment AB at M

Then, M is the mid-point of line segment AB

So, the length of  line AM = the length of line MB

That is, Point M has the same distance from both point A and point B.

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Answer:

GREAT question i have no idea

Step-by-step explanation:

Answer:

question tho??

Answer:

see explanation

Step-by-step explanation:

1

1 + [tex]\frac{x-5}{2}[/tex] - [tex]\frac{x+3}{5}[/tex] ≤ 0

multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions

10 + 5(x - 5) - 2(x + 3) ≤ 0 ← distribute parenthesis on left side and simplify

10 + 5x - 25 - 2x - 6 ≤ 0

3x - 21 ≤ 0 ( add 21 to both sides )

3x ≤ 21 ( divide both sides by 3 )

x ≤ 7

2

[tex]\frac{6x}{5}[/tex] - [tex]\frac{2}{3}[/tex] ≥ 4

multiply through by 15 ( the LCM of 5 and 3 ) to clear the fractions

18x - 10 ≥ 60 ( add 10 to both sides )

18x ≥ 70 ( divide both sides by 18 )

x ≥ [tex]\frac{70}{18}[/tex] , that is

x ≥ [tex]\frac{35}{9}[/tex]

3

[tex]\frac{x}{10}[/tex] - [tex]\frac{2}{8}[/tex] ≥ 1

multiply through by 40 ( the LCM of 10 and 8 ) to clear the fractions

4x - 10 ≥ 40 ( add 10 to both sides )

4x ≥ 50 ( divide both sides by 4 )

x ≥ [tex]\frac{50}{4}[/tex] , that is

x ≥ [tex]\frac{25}{2}[/tex]

Answer:

[tex]\textsf{1.} \quad x \leq 7[/tex]

[tex]\textsf{2.} \quad x \geq \dfrac{35}{9}[/tex]

[tex]\textsf{3.} \quad x \geq \dfrac{25}{2}[/tex]

Step-by-step explanation:

Given inequality:

[tex]1+\dfrac{x-5}{2}-\dfrac{x+3}{5} \leq 0[/tex]

[tex]\textsf{Add \; $\dfrac{x+3}{5}$ \; to both sides}:[/tex]

[tex]\implies 1+\dfrac{x-5}{2}-\dfrac{x+3}{5} +\dfrac{x+3}{5}\leq 0+\dfrac{x+3}{5}[/tex]

[tex]\implies 1+\dfrac{x-5}{2}\leq \dfrac{x+3}{5}[/tex]

[tex]\textsf{Rewrite $1$ as $\dfrac{2}{2}$}:[/tex]

[tex]\implies \dfrac{2}{2}+\dfrac{x-5}{2}\leq \dfrac{x+3}{5}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]

[tex]\implies \dfrac{2+x-5}{2}\leq \dfrac{x+3}{5}[/tex]

[tex]\implies \dfrac{x-3}{2}\leq \dfrac{x+3}{5}[/tex]

Cross multiply:

[tex]\implies 5(x-3)\leq 2(x+3)[/tex]

[tex]\implies 5x-15\leq 2x+6[/tex]

Subtract 2x from both sides:

[tex]\implies 5x-15-2x\leq 2x+6-2x[/tex]

[tex]\implies 3x-15\leq 6[/tex]

Add 15 to both sides:

[tex]\implies 3x-15+15\leq 6+15[/tex]

[tex]\implies 3x\leq 21[/tex]

Divide both sides by 3:

[tex]\implies \dfrac{3x}{3}\leq \dfrac{21}{3}[/tex]

[tex]\implies x \leq 7[/tex]

---------------------------------------------------------------------------------------

Given inequality:

[tex]\dfrac{6x}{5}-\dfrac{2}{3} \geq 4[/tex]

[tex]\textsf{Add \; $\dfrac{2}{3}$ \; to both sides}:[/tex]

[tex]\implies \dfrac{6x}{5}-\dfrac{2}{3} +\dfrac{2}{3}\geq 4+\dfrac{2}{3}[/tex]

[tex]\implies \dfrac{6x}{5}\geq \dfrac{12}{3}+\dfrac{2}{3}[/tex]

[tex]\implies \dfrac{6x}{5}\geq \dfrac{12+2}{3}[/tex]

[tex]\implies \dfrac{6x}{5}\geq \dfrac{14}{3}[/tex]

Cross multiply:

[tex]\implies 3(6x) \geq 14(5)[/tex]

[tex]\implies 18x \geq 70[/tex]

Divide both sides by 18:

[tex]\implies \dfrac{18x}{18} \geq \dfrac{70}{18}[/tex]

[tex]\implies x \geq \dfrac{70}{18}[/tex]

Reduce the fraction by dividing the numerator and the denominator by 2:

[tex]\implies x \geq \dfrac{70 \div 2}{18 \div 2}[/tex]

[tex]\implies x \geq \dfrac{35}{9}[/tex]

---------------------------------------------------------------------------------------

Given inequality:

[tex]\dfrac{x}{10}-\dfrac{2}{8} \geq 1[/tex]

[tex]\textsf{Add \; $\dfrac{2}{8}$ \; to both sides}:[/tex]

[tex]\implies \dfrac{x}{10}-\dfrac{2}{8} +\dfrac{2}{8}\geq 1+\dfrac{2}{8}[/tex]

[tex]\implies \dfrac{x}{10}\geq \dfrac{8}{8}+\dfrac{2}{8}[/tex]

[tex]\implies \dfrac{x}{10}\geq \dfrac{8+2}{8}[/tex]

[tex]\implies \dfrac{x}{10}\geq \dfrac{10}{8}[/tex]

Cross multiply:

[tex]\implies 8(x) \geq 10(10)[/tex]

[tex]\implies 8x \geq 100[/tex]

Divide both sides by 8:

[tex]\implies \dfrac{8x}{8} \geq \dfrac{100}{8}[/tex]

[tex]\implies x \geq \dfrac{100}{8}[/tex]

Reduce the fraction by dividing the numerator and the denominator by 4:

[tex]\implies x \geq \dfrac{100 \div 4}{8 \div 4}[/tex]

[tex]\implies x \geq \dfrac{25}{2}[/tex]

The value of  u + xy, if u = 18, x = 10, and y = 8​ is 98

Algebraic expressions are defined as mathematical expressions that are made up of constants, variables, coefficients, terms and factors.

These algebraic expressions are also composed of arithmetic operations, such as;

Given the expression;

u + xy

Where;

Now, substitute the values into the expression;

18 + 10(8)

expand the bracket

18 + 80

Add the values

98

Hence, the value is 98

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Answer: Where P is.

Step-by-step explanation

Answer:

(2,2) and (6,6) would be the other two points to the square.

Step-by-step explanation:

Answer:

(2,2) or (6,6)

Step-by-step explanation:

looking at the graph you can see the diagonal of a square and I just followed the points if that make sense please tell me if you need more

Answer:

ishbekshbrishdhtjekdhhfjeid

The given composition as a single translation is (x,y)→(x+1,y+2) .

In the question,

two translation are given , we have to write the composition of two translation in a single translation ,

we choose arbitrary points (x,y) in the tile , and find the horizontal and vertical shift in the coordinates of point after both translations .

let A(x,y) be an arbitrary point in the tile

So , by the first translation

"move 2 tiles right and 3 tiles up" ,

after first translation, the coordinates are  A'(x+2,y+3)

The second translation "you move 1 tile left and 1 tile down" ,  will map A'(x+2,y+3) to

A"(x+2-1 , y+3-1)

= A"(x+1 , y+2)

Therefore , the single translation rule for the composition is (x,y)→(x+1,y+2)    .

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Answer: x=21

Step-by-step explanation:

2x-8=34 (change the -8 into a positive since it doesn't have a variable)

34+8=42 (divide 34 by 2)

42/2=21

Check your answer

2 x 21 = 42

42-8=34

x=21

Answer:

y - intercept = 14

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 10x + 14 ← is in slope- intercept form

with y- intercept c = 14