If there are six water molecules, the following applies;
There are 12 atoms of hydrogenThere are 6 atoms of oxygenWhat is a molecule?A molecule is the smallest particle of a specific element or compound that retains the chemical properties of that element or compound i.e. two or more atoms held together by chemical bonds.
Atoms of an element are usually shown in the chemical or molecular formula, which is a notation indicating the number of atoms of each element present in a compound.
According to this question, six water molecules are given as follows: 6H₂O
This means that there are 6 × 2 = 12 atoms of hydrogen and 6 × 1 = 6 atoms of oxygen in the 6 molecules of water.
Electrolysis is the chemical change produced by passing an electric current through a conducting solution or a molten salt.
If six molecules of water undergoes electrolysis, there would be 12 atoms of hydrogen and 6 atoms of oxygen.
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Pls explain ........................
Option A that is 8.6 x 10^4 volt is the potential difference between a point 0.79 mm from a charge of 7.6nC and a point of infinity.
What is potential difference how it is calculated out to be so?Potential difference can be stated as the difference of electrical potential between two points stated.Here in this question is given the charge 7.6 nC that is 7.6 x 10^-9 and the radius 0.79 mm that is 0.79 x 10^-3 m.Here the potential difference can be calculated out to be by the equation V = k x Q /R , where k is proportionality constant given in equation.V= 8.99 x 10^9 x 7.6x 10^-9 / 0.79 x 10^-3 , putting all the values in the equation.Finally the potential difference is calculate out to be 8.65 x 10^4 volts.To know more about potential difference visit:
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Fig. 3.1 shows a house brick of dimensions 21.0 cm x 10.0 cm x 7.00 cm.
21.0 cm
10.0 cm
7.00 cm
Fig. 3.1
The brick is held under water with its largest surfaces horizontal. The density of water is 1000 kg/m3
(a) Calculate the difference in pressure between the top and the bottom surfaces of the brick.
pressure difference
Given:
Lenght = 21 cm
Width = 10 cm
Height = 7 cm
Density = 1000 kg/m^3
Gravity = 9.8 m/s^2
Apply the formula:
Pressure = depth x density x gravity
Depth = Height = 7 cm = 0.07 m
Replacing:
P = 0.07 x 1000 x 9.8 = 686 Pa
I need help with question 5
uestion 5.
iven:
Mass, m = 25 kg
Tension = 47 N
Let's find the maximum acceleration the truck can have before the crate breaks.
Let the magnitude of the force be expressed as:
= m x a
efore the cord breaks , the maximum tension, T, in the string is:
= ma
Where:
T is the maximum tension
m is the mass
a is the maximum acceleration
ence, to findt he maximmum acceleration, rewrite the equation for a.
We have:
[tex]a=\frac{T}{m}[/tex]Now, input 47N for T and 25 kg for m to solve for a:
[tex]\begin{gathered} a=\frac{47\text{ N}}{25\operatorname{kg}} \\ \\ a=1.88m/s^2 \end{gathered}[/tex]herrefore, the maximum acceleration of the truck before the cord breakes is 1.88 m/s²
Find the velocity of a 1000kg car with 50,000J of KE.
Answer:
10 m/2²
Explanation:
v=t/d
blah blah blah
Answer:
10 m/s
Explanation:
Kinetic Energy = 1/2 m v^2
KE / ( 1/2 m) = v^2
then v = sqrt ( KE / (1/2 m ) = 10 m/s
air around us exerts ____________
Philippe, Maurice’s draft horse, is pulling his 6000N cart using a 745N force on a bridle that is at a 15o angle. If the friction force on the cart is 100N, how long will it take Philippe to go 1000m?
The time taken for Philippe to go 1000 m is 44.5 s.
What is the net force on cart?The net force on the cart is calculated as follows;
F(net) = F - Ff
where;
F is the applied forceFf is the frictional forceF(net) = 745 cos(15) - 100
F(net) = 619.6 N
The mass of the cart is calculated as follows;
W = mg
m = W/g
m = (6000) / (9.8)
m = 612.24 kg
The acceleration of the cart is calculated as follows;
a = F(net) / m
a = (619.6) / (612.24)
a = 1.01 m/s²
The time taken for Philippe to go 1000 m is calculated as follows;
s = vt + ¹/₂at²
s = 0 + ¹/₂at²
2s = at²
t² = 2s/a
t = √(2s/a)
t = √(2 x 1000 / 1.01)
t = 44.5 seconds
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Car A runs a red light and crashes into Car B, which is waiting to make a left turn. Car A has a mass of 2,000 kg. Car B has a mass of 1,500 kg. After the impact, the cars stick together and slide away at a speed of 9.1m/s. How fast was Car A going when it hit Car B? Show all of your work. (Law of Conservation of Momentum)
Answer:
The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:
mA vA + mB vB = m v
where, m is the mass in kg, v is the velocity in m/s
since m is the total mass, m = mA + mB, we can write the equation as:
mA vA + mB vB = (mA + mB) v
furthermore, car B was at a stop signal therefore vB = 0, hence
mA vA + 0 = (mA + mB) v
1800 (vA) = (1800 + 1500) (7.1 m/s)
vA = 13.02 m/s
Explanation:
Using energy considerations, calculate the average force (in N) a 70.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 8.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him.
The average force a 70.0 kg sprinter exerts backward on the track is 84 N.
What is law of conservation of energy?
The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
E = Fd
where;
F is the applied forced is the displacement of the objectThe average force exerted by the sprinter is calculated as follows;
F = ma
where;
a is the acceleration of the sprinterm is mass of the sprinterThe acceleration of the sprinter is calculated as follows;
v² = u² + 2as
where;
v is the final velocityu is the initial velocitys is the distance(8)² = (2)² + (2x25)a
64 = 4 + 50a
60 = 50a
a = 60/50
a = 1.2 m/s²
Average force exerted by the sprinter;
F = ma
F = 70 kg x 1.2 m/s²
F = 84 N
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7. Conceptual 03 04 10 pts possible Someone in a car going past you at the speed of 41 m/s drops a small rock from a height of 1.6 m. How far from the point of the drop will the rock hit the ground? The acceleration due to gravity is 9.8 m/s². Answer in units of m.
Answer:
See below
Explanation:
Find out how long the vertical velocity and accel cause the rock to ground out....then multiply this time by the horizontal speed....then use pythag theorem for the TOTAL distance
df = do + vo t + 1/2 a t^2 df = final height = 0 do = original = 1.6 m
v o = original velocity = 0 accel = - 9.81 m/s^2
0 = 1.6 + 0 + 1/2 ( - 9.8)(t^2) shows t = .5714 seconds to hit the ground
horizontal distance = .5711 seconds * 41 m/s = 23.43 m
vertical distance = 1.6 m
TOTAL distance = sqrt (( 23.42)^2 + (1.6)^2 ) = 23.48 m
If questioner wants horizontal disance <=====use first answer
if Q wants TOTAL distance <====== use second answer
When solving projectile motion problems where the projectile is launched at an angle, the first step is to find the x- and y-component of the initial velocity. Why is this helpful in solving these types of problems?
The projectile motion is a 2-D motion. Therefore, if we make the component of the given velocity into x- and y-component, we can solve each component by using all 1-D motion equations. Now it will become very easy to solve projectile motion problems.
Projectile movement is a shape of movement experienced by an object or particle this is projected close to Earth's surface and moves along a curved path under the movement of gravity handiest.
Projectile movement is the movement of an item thrown (projected) into the air. After the preliminary pressure that launches the item, it best reviews the force of gravity. The object is called a projectile, and its direction is known as its trajectory.
A projectile is any object that is cast, fired, flung, heaved, hurled, pitched, tossed, or thrown. you throw the ball directly upward, or you kick a ball and provide it a pace at an attitude to the horizontal otherwise you just drop matters and lead them to lose fall; most of these are examples of projectile movement.
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Gravity causes a ball to fall is an example of which Newton law?
Answer:
Newton's 2nd Law
Explanation:
First law concerns balanced forces, which result in either static equilibrium or dynamic equilibrium, where there is no acceleration. Gravity causes the ball to accelerate so it can't be the first law.
Second Law deals with unbalanced forces (F=ma).
Third law relates to "action-reaction" which is unrelated to the scenario.
if Ms. Avari is carrying a stack of books weighing 12 N up a flight of starts that is 10 meters high. How much work does Ms. Avari need to do to take the stack of books up the stairs? ( W = F x d )
F = force = 12 N
d = distance = 10 m
W= work
Apply:
W = F x d
Replacing:
W= 12 x 10 = 120 J
A m= 25.7 kg object is released from rest at a distance h= 0.523059 R above the earth's surface. the acceleration of gravity is 9.8 m/s^2. for the earth, RE= 6.38 x 10^6 m, M= 5.98 x 10^24 kg. the gravitational acceleration at the surface of the earth is g =9.8 m/s^2. find the speed of the object when it strikes the earth's surface. neglect any atmospheric friction.
caution: you must take into account that the gravitational acceleration depends on distance between the object and the center of the earth. answer in units of m/s
The speed of the object when it strikes the earth's surface is 8087.45 m/s
We'll begin by obtainig the time taken for the object to strike the earth's surface. This can be obtained as follow:
Initial velocity (u) = 0 m/sRadius of earth (R) = 6.38×10⁶ mHeight (h) = 0.523059R = 0.523059 × 6.38×10⁶ = 3337116.42 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
3337116.42 = ½ × 9.8 × t²
3337116.42 = 4.9 × t²
Divide both side by 4.9
t² = 3337116.42 / 4.9
Take the square root of both side
t = √(3337116.42 / 4.9)
t = 825.25 s
Finally, we shall determine the speed the object used in striking the earth's surface. This can be obtained as follow:
Time (t) = 825.25 sAcceleration due to gravity (g) = 9.8 m/s²Speed (v) =?v = gt
v = 9.8 × 825.25
v = 8087.45 m/s
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Determine the velocity of car A with respect to car B. Responses
A 20, km/hr
B -20, km/hr
C 80, km/hr
D -80 km/hr
A. The velocity of car A with respect to car B is 20 km/h
What is relative velocity?The velocity of an object A relative to another object B is the velocity that object A would appear to have to an observer moving with B.
The velocity of car A with respect to car B is calculated as follows;
Va/b = Va - Vb
where;
Va/b is the velocity of car A with respect to car BVa is the velocity of car AVb is the velocity of car BSubstitute the given parameters and solve for the the velocity of car A with respect to car B.
Va/b = 50 km/h - 30 km/h
Va/b = 20 km/h
Thus, we can conclude that the velocity of car A with respect to car B will appear to decrease since they are moving in the same direction.
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The rate at which goods and services can be produced is called
a)capital investment.
b)productivity.
c)producer price output.
d)human capital.
Answer:
productivity
Explanation:
it's the efficiency of production of goods or services
Answer:
Explanation:
The rate at which goods and services can be produced is called
b) productivity.
4. What is stellar parallax?
Answer:
I don't k own what it is dad fjf f fjff
Answer:
Explanation:
Stellar parallax is the apparent shift of position of any nearby star against the background of distant objects
what are chemical properties of acid
What does the amount of refraction of a wave depend on?
A. change in wave speed
B. Location of normal line
C. Size of the object
D. Size of the opening between objects
plsss 15 pointsss!
A) change in wave speed
Option A is correct
What is the mass of an airplane accelerating at 35 m/s2 if 27,000N of force is being applied?
ill give brainleist
Answer:
771 .4 kg
Explanation:
Remember F = ma so F/a = m
m = 27000 N / 35 m/s^2 = 771 .4 kg
How many measures are there until the next part enters in Kookaburra?
A. 2
B. 1
C. 3
D. 4
Option C) 3. There are about 3 measures until the next part enters in Kookaburra through the expression in Australian countryside.
What is the meaning of the Kookaburra song?The expression probably first appeared because of how many bushes and scrub there are in the Australian countryside. Gay — Up until the middle of the 1950s, the word gay denoted happiness and carelessness.
It therefore signified “happy and carefree” during the time this song was penned.
Do kookaburras make good pets?The state has issued them licenses and permits. For authorized and permitted educational initiatives, both kookaburras serve as educational ambassadors. Kookaburras are not recommended as pets by anyone.
They may be very unpredictable, demand a lot of space, must be maintained in a pack, are very loud, and need a special diet.
What food does a kookaburra consume?They consume insects, beetles, worms, frogs, small animals, snakes, lizards, and lizards.
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module 2 question 17
Figure 4.25
(a) What is the mass of the child and basket if a scale reading of 100 N is observed?
kg
(b) What is the tension T in the cord attaching the child to the scale?
N
(c) What is the tension T' in the cord attaching the scale to the ceiling, if the scale has a mass of 0.300 kg?
N
(d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible. (Do this on paper. Your instructor may ask you to turn in this work.)
a ) The mass of the child and basket = 5.61 kg
b ) The tension T in the cord attaching the child to the scale = 55 N
c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N
a ) The mass of the child and basket,
[tex]W_{b}[/tex] = 55 N
g = 9.8 m / s²
W = m g
[tex]m_{b}[/tex] = [tex]W_{b}[/tex] / g
[tex]m_{b}[/tex] = 55 / 9.8
[tex]m_{b}[/tex] = 5.61 kg
b ) In the cord attaching the child to the scale,
∑ [tex]F_{y}[/tex] = 0
T - W = 0
T = W
T = 55 N
c ) In the cord attaching the scale to the ceiling,
[tex]m_{s}[/tex] = 0.3 kg
[tex]W_{s}[/tex] = [tex]m_{s}[/tex] * g
[tex]W_{s}[/tex] = 0.3 * 9.8
[tex]W_{s}[/tex] = 2.94 kg
∑ [tex]F_{y}[/tex] = 0
T - [tex]W_{s}[/tex] - [tex]W_{b}[/tex] = 0
T = 2.94 + 55
T = 57.94 N
Therefore,
a ) The mass of the child and basket = 5.61 kg
b ) The tension T in the cord attaching the child to the scale = 55 N
c ) The tension T' in the cord attaching the scale to the ceiling = 57.94 N
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Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica.
Answer:
The frictional force between the wall and the ball
********
A student investigates whether a spring obeys Hooke's law
She uses the apparatus shown in the photograph
(a) Which additional measuring instrument does the student need for the investigation?
1
(b) Explain how the student can investigate whether the spring obeys Hooke's law.
(1)
(5)
The answers include the following below:
The additional measuring instrument the student needs for the investigation is a ruler or measuring tape.The student can investigate whether the spring obeys Hooke's law by adding masses to a spring and measuring the length of the spring when the weight of the masses is increased.What is Hooke's law?
This law states that the force which is needed to extend a spring is directly proportional to the distance in which the spring is extended from its rest or initial position.
The distance gotten is measured with the use of a ruler or a measuring tape so as to obtain an accurate result during the experimental procedures. Hooke'slaw is performed by adding some masses to a spring and taking note of the effect by measuring the length of the spring when the weight of the masses is increased.
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The diagram above shows the angle of an sentence from a light source what will be the angle of reflection?
A 1
B 2
C 3
D 4
Answer:
B 2
Explanation:
Angle of reflection is the measure of the angle taken from the normal.
Question 8 of 10
Which change to a circuit is most likely to decrease its electrical power?
OA. Increase its voltage and increase its current.
о B. Decrease its voltage and decrease its current.
O C. Decrease its voltage and increase its current.
OD. Increase its voltage and decrease its current.
Decrease its voltage and decrease its current change to a circuit is most likely to decrease its electrical power.
The correct option is B.
What is voltage explain?When charged electrons (current) are forced through a conducting loop by the pressure of an electric circuit's power source, they may perform tasks like lighting a lamp. In a nutshell, voltage equal pressure and is expressed in volts.
What is the basic voltage unit?Electric potential difference, often referred to as voltage, is measured in units called volts. According to official definitions, a volt is the difference in potential between two locations on a wire that's also conveying a current of one ampere and dissipating one watt of power.
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7. The initial temperature of a jar of a juice is 80°C and the mass of the juice is 2kg. Susan adds ice cubes into jar in order to cool down the juice to 20°C. What is the minimum number of ice cubes at 0°C required? (Neglect the heat capacity of the jar and assume there is no heat exchange with the surrounding.) Given: Mass of each ice cube = 0.15Kg Specific heat capacity of juice = 4700 J kg¹ °C¹ Specific heat capacity of water = 4200 J kg-¹ °C-¹ Specific heat capacity of fusion of ice = 3.34 x 105 J kg E A. 9 B. 10 C. 11 D. 12
The minimum number of ice cubes at 0°C required to cool down the juice is 11 ice cubes (Option C)
We'll begin by obtainig the heat released by the juice. This can be obtained by
Initial temperature (T₁) = 80 °CFinal temperature (T₂) = 20 °CMass of juice (M) = 2KgChange in temperature (ΔT) = 20 - 80 = -60 °CSpecific heat capacity of juice (C) = 4700 J/KgºC Heat released (Q) =?Q = MCΔT
Q = 2 × 4700 × -60
Q = -564000 J
Next, we shall determin the mass of the total ice. This can be obtained as follow:
Heat capacity of fusion of ice (ΔHf) = 3.34×10⁵ J/kgHeat released = -564000 JHeat absorbed (Q) = 564000 JTotal mass of ice (M) = ?Q = m × ΔHf
564000 = m × 3.34×10⁵
Divide both sides by 3.34×10⁵
m = 564000 / 3.34×10⁵
m = 1.69 Kg
Finally, we shall determine the number of ice cubes. This can be stained as follow:
Total mass of cube = 1.69 KgMass of one cube = 0.15 KgNumber of ice =?Number of ice = total mass / mass of one cube
Number of ice = 1.69 / 0.15
Number of ice = 11 ice cubes
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We will be changing one variable at a time to see how it affects the value of the forces. Set the variables listed in the table and document the force and determine if the charges are attracted to each other or repelled.
Answer:
Explanation:
The coulombs law is expressed as
F = kq1q2/r^2
where
F is the force
k is the coulomb constant and its value is 9 x 10^9 N/m^2C^2
q1 and q2 are the magnitude of the charges
r is the distance between them
From the information given,
r = 4 cm = 4/100 = 0.04m
For trial 1,
q1 = - 2μC
q2 = 8μC
Recall,
1 μC = 1 x 10^- 9 C
q1 = - 2 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 2 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 9 x 10^-5 N
There is an attraction
For trial 2,
q1 = - 4μC
q2 = 8μC
q1 = - 4 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 4 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 1.8 x 10^-4N
There is an attraction
For trial 3,
q1 = - 6μC
q2 = 8μC
q1 = - 6 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 2.7 x 10^-4N
There is an attraction
For trial 4,
q1 = - 8μC
q2 = 8μC
q1 = - 8 x 1 x 10^- 9 C
q2 = 8 x 1 x 10^- 9 C
F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2
F = 3.6 x 10^-4N
There is an attraction
The change in the value of the charge is proportional to the force
You have three identical, uniform, square pieces of wood, each with
side length L. You stack the three pieces of wood at the edge of
the horizontal top of a table. The first block extends a distance L/4
past the edge of the table. The next block extends a distance L/4
past the edge of the first block, so a distance L/2 past the edge of
the table. The third block extends a distance L/4 past the edge of
the block beneath it, so 3L/4 past the edge of the table. The stack
is unstable if the center of mass of the stack extends beyond the
edge of the table.
Centre of mass of the square piece at the middle of the stack is at x = 0 centre of mass of the bottom most square piece in the stack is at{ (l/4)^2 + (l/4)^2}^1/2 .
What is centre of mass and how it is calculated in the stack?Centre of mass in physics is a phenomenal discovery which states that the overall weight of the body distributed sums up to zero at the point central relative to other points.The point of centre of mass is the point where we may apply force and the linear acceleration will be on action but no angular acceleration would be seen.Here is given three identical square pieces of wood, each with length L . Now we are stacking the block three pieces at the edge of the horizontal.The centre of mass of the bottom most square piece in the stack is at {(l/4)^2 +(l/4)^2}^1/2= L/2(2)^1/2.To know more about centre of mass visit:
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You have a parallel‑plate 5.13×10−6 F capacitor that is charged to 0.00967 C. While the capacitor is isolated, you change the plate separation so that the capacitance becomes 1.27×10−6 F. How much work do you perform in this process?
The work done to separate the plates of the parallel plate capacitor that's charged to a 0.00967 C is 2864.5 J
U = 1 / 2 C V²
U = Initial energy
C = Capacitance
V = Electric Potential
Q = Charge
C[tex]_{i}[/tex] = 5.13 μ F
Q[tex]_{i}[/tex] = 9.67 m C
C[tex]_{f}[/tex] = 1.27 μ F
As the capacitor is isolated, there'll be no further current flow and charge will remain constant.
Q[tex]_{f}[/tex] = Q[tex]_{i}[/tex] = 9.67 m C
Q = C V
Q² = ( C V )²
U[tex]_{i}[/tex] = 1 / 2 * C[tex]_{i}[/tex] * V[tex]_{i}[/tex]²
U[tex]_{i}[/tex] = 0.5 * ( C[tex]_{i}[/tex] * [tex]V_{i}[/tex] )² / C[tex]_{i}[/tex]
U[tex]_{i}[/tex] = 0.5 * Q[tex]_{i}[/tex]² / C[tex]_{i}[/tex]
U[tex]_{i}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 5.13 * [tex]10^{-6}[/tex] )
U[tex]_{i}[/tex] = 942.5 J
U[tex]_{f}[/tex] = 1 / 2 * C[tex]_{f}[/tex] * [tex]V_{f}[/tex]²
U[tex]_{f}[/tex] = 0.5 * ( C[tex]_{f}[/tex] * [tex]V_{f}[/tex] )² / C[tex]_{f}[/tex]
U[tex]_{f}[/tex] = 0.5 * Q[tex]_{f}[/tex]² / C[tex]_{f}[/tex]
U[tex]_{f}[/tex] = 0.5 * ( 9.67 * [tex]10^{-3}[/tex] / 1.27 * [tex]10^{-6}[/tex] )
U[tex]_{f}[/tex] = 3807 J
W = U[tex]_{f}[/tex] - U[tex]_{i}[/tex]
W = 3807 - 942.5
W = 2864.5 J
Therefore, the work done to separate the plates of the parallel plate capacitor is 2864.5 J
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Find the resultant of the following vectors:
ASAPPPP
(7) The resultant vector is middle line which is the longest line representing the single effect of the two vectors at both ends.
(8) The resultant vector is any of the lines at the end of the vectors, since any of this line will effectively complete triangle formed by the vectors.
What is resultant vector?A resultant vector is defined as a single vector that produces the same effect as the two or more vectors combined together.
A resultant vector is usually, drawn to join the head of the first vector to the tail of the second in a triangle method of vector addition.
Also, a resultant vector can be determined by applying parallelogram law of vector addition.
Mathematically, a resultant vector can be determined using this formula,
R² = a² + b² - 2ab cosθ
where;
a is the first vectorb is the second vectorθ is the angle between vector a and vector bA resultant vector is always bigger than the two vectors acting together.
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