question 1 options: calculate the overall speedup of a system that spends 55% of its time on i/o with a disk upgrade that provides for 50% greater throughput. enter integer number with no % sign as the answer.

To assess the effect of class attendance on student performance, you could conduct a regression analysis with attendance as the independent variable and student performance as the dependent variable.

The coefficients obtained from the analysis would provide information on the relationship between attendance and performance. For instance, if the coefficient for attendance is positive, it would suggest that as attendance increases, so does student performance. The values of 0, 1, 2, and 3 in the question may represent different levels of attendance, which could be used to determine the specific effect of attending more or fewer classes on student performance.
Based on your question, it seems you are interested in the relationship between class attendance and student performance. Here's an answer incorporating the terms you provided:

Class attendance can be a significant factor in student performance. As attendance increases (represented by the values 0, 1, 2, 3, with 0 being no attendance and 3 being full attendance), there is a likelihood that student performance will improve. This is because attending class allows students to engage with the material, participate in discussions, and receive guidance from teachers.

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The answers that are true about the graph that represents y = 2x(x - 11) are:

         [tex]\sf y = a(x - h)^2 + k[/tex]

         Vertex of the parabola will be (h, k)

Given in the question,

Convert the equation in the vertex form,

[tex]\sf y = 2x^2 - 22x[/tex]

[tex]\sf y = 2(x^2 - 11x)[/tex]

[tex]\sf y = 2[x^2 - 2(5.5x) + (5.5)^2 - (5.5)^2][/tex]

[tex]\sf y = 2[(x - 5.5)^2 - 30.25][/tex]

[tex]\sf y = 2(x - 5.5)^2 - 60.5[/tex]

  Vertex of the parabola will be (5.5, -60.5).

For x-intercepts,

Substitute y = 0,

[tex]\sf 0 = 2x(x - 11)[/tex]

[tex]\sf \rightarrow x = 0, 11[/tex]

   Therefore, x-intercepts of the parabola will be (0, 0) and (11, 0).

Hence, x-intercepts of the parabola are (0, 0) and (11, 0)

           x-coordinate of the vertex is x = 5.5

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Since y_1(0) = 1, it satisfies the initial condition. However, y_2(0) = 0 does not satisfy the initial condition, as it should be y(0) = 1. Therefore, only y_1(t) is a solution of the initial value problem.

To verify that both y_1(t) = 1 - t and y_2(t) = -t^2/4 are solutions of the initial value problem, we first need to understand what the problem is. An initial value problem is a differential equation that includes an initial condition. In this case, we can assume that the initial condition is y(0) = 1.
Now, let's substitute both y_1(t) and y_2(t) into the differential equation and see if they satisfy the initial condition. The differential equation is not provided, but assuming it is y'(t) = -t/2, we have:
y_1'(t) = -1
y_2'(t) = -t/2
Substituting y_1(t) and y_2(t) into the differential equation gives:
y_1'(t) = -1

= -t/2 (when t = 2)
y_2'(t) = -t/2

= -t/2 (for all t)
Thus, both y_1(t) and y_2(t) satisfy the differential equation. Now, let's check if they satisfy the initial condition.
y_1(0) = 1 - 0

= 1
y_2(0) = -0^2/4

= 0
In conclusion, y_1(t) = 1 - t is the only solution that satisfies the differential equation and initial condition, while y_2(t) = -t^2/4 is not a solution since it does not satisfy the initial condition.

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The solutions are x = -4 and x = 1/2 and the solutions are not extraneous

From the question, we have the following parameters that can be used in our computation:

(x + 2)/x = (3 -x)/(2 - 3x)

Cross multiply

So, we have

x(3 - x) = (x + 2)(2 - 3x)

When the equation is expanded, we have

3x - x² = 2x - 6x + 4 - 3x²

Evaluate the like terms

2x² + 7x - 4 = 0

Evalaute

x = -4 and x = 1/2

Hence, the solutions are x = -4 and x = 1/2 and the solutions are not extraneous

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5.5 hours pass as Ping flies before the two ducks are 493 miles apart.

The distance traveled by Ping can be calculated as the product of its speed (52 mph) and time:

Distance_Ping = 52t

The distance traveled by Pong can be calculated as the product of its speed (46 mph) and time:

Distance_Pong = 46(t - 1)

Distance_Ping + Distance_Pong = 493

52t + 46(t - 1) = 493

Simplifying the equation:

52t + 46t - 46 = 493

98t = 539

Dividing both sides by 98:

t = 5.5

Therefore, Ping flies for 5.5 hours before the two ducks are 493 miles apart.

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To find the integral of ln(ln(x^2)), we can use the technique of integration by substitution. Let's go through the steps:

Let u = ln(x^2).

Differentiating both sides with respect to x:

du/dx = (1/x^2) * 2x = 2/x.

We can rewrite the integral as:

∫ ln(ln(x^2)) dx = ∫ (1/u) * (1/x) * (2/x) dx

                   = ∫ (2/(x^2u)) dx.

Now, substituting u = ln(x^2), we get:

du = (2/x^2) dx,

which can be rewritten as:

dx = (x^2/2) du.

Substituting the values into the integral, we have:

∫ (2/(x^2u)) dx = ∫ (2/(x^2 * ln(x^2))) * (x^2/2) du

                      = ∫ (1/ln(x^2)) du

                      = ∫ (1/2ln(x))^2 du.

Simplifying further, we get:

∫ (1/2ln(x))^2 du = ∫ (1/4ln^2(x)) du

                         = (1/4) ∫ (1/ln^2(x)) du.

Now, integrating (1/ln^2(x)) with respect to u gives us:

(1/4) ∫ (1/ln^2(x)) du = (1/4) (-1/ln(x)) + C

                                = -1/(4ln(x)) + C.

Therefore, the integral of ln(ln(x^2)) is equal to -1/(4ln(x)) + C, where C is the constant of integration.

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To determine figures can be shown to have the same volume using Cavalieri's principle need to consider if every plane parallel to the height intersects the figures in cross-sections with equal areas is only A and B. A.

Cavalieri's principle states that if two solids have the same height and every plane parallel to the height intersects both solids in cross-sections with equal areas, then the two solids have the same volume.

Based on the given information, we have three figures A, B, and C with the same height and the same base area.

Looking at the figures, we can observe that for any plane parallel to the height, both figures A and B will have cross-sections with equal areas because they have the same shape.

Figure C has a different shape compared to A and B, so it is not possible to find cross-sections with equal areas when considering planes parallel to the height.

Cavalieri's principle, two solids have the same volume if their heights are identical and any plane parallel to their height crosses them in cross-sections with the same area.

Using the information provided, we can create three figures with the same height and base area:

A, B, and C.

By examining the pictures, we can see that because figure A and figure B have the same form, they will both have cross-sections with equal areas for any plane parallel to the height.

When examining planes parallel to the height, it is impossible to locate cross-sections with similar areas for Figure C due to its distinct form from that of Figures A and B.

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Therefore, the Fourier series representation of f(x) = π - x on the interval -π < x < π is: f(x) = π/2 + Σ((2/π^2) * [(-1)^n - 1.

To find the Fourier series of the function f(x) = π - x on the interval -π < x < π, we can use the standard Fourier series formulas for periodic functions.

The Fourier series representation of f(x) can be expressed as:

f(x) = a₀/2 + Σ(aₙcos(nx) + bₙsin(nx))

where a₀, aₙ, and bₙ are the Fourier coefficients.

To determine the Fourier coefficients, we need to calculate the following integrals:

a₀ = (1/π) * ∫[-π, π] f(x) dx

aₙ = (1/π) * ∫[-π, π] f(x) * cos(nx) dx

bₙ = (1/π) * ∫[-π, π] f(x) * sin(nx) dx

Let's calculate these coefficients step by step:

a₀:

a₀ = (1/π) * ∫[-π, π] (π - x) dx

= (1/π) * [πx - (x^2/2)] | from -π to π

= (1/π) * [ππ - (π^2/2) - (-ππ + (π^2/2))]

= (1/π) * [π^2 - π^2/2 + π^2 - π^2/2]

= π

aₙ:

aₙ = (1/π) * ∫[-π, π] (π - x) * cos(nx) dx

= (1/π) * ∫[-π, π] πcos(nx) - xcos(nx) dx

= (1/π) * [π * (sin(nx)/n) - ∫[-π, π] xcos(nx) dx]

= (1/π) * [π * (sin(nx)/n) - [x * (sin(nx)/n^2) + (cos(nx)/n^2)] | from -π to π

= (1/π) * [π * (sin(nx)/n) - [π * (sin(nx)/n^2) + (cos(nx)/n^2) - (-π * (sin(nx)/n^2) + (cos(nx)/n^2))]]

= 0

bₙ:

bₙ = (1/π) * ∫[-π, π] (π - x) * sin(nx) dx

= (1/π) * ∫[-π, π] πsin(nx) - xsin(nx) dx

= (1/π) * [-π * (cos(nx)/n) - ∫[-π, π] xsin(nx) dx]

= (1/π) * [-π * (cos(nx)/n) - [-x * (cos(nx)/n^2) + (sin(nx)/n^2)] | from -π to π

= (1/π) * [-π * (cos(nx)/n) - [-π * (cos(nx)/n^2) + (sin(nx)/n^2) - (-π * (cos(nx)/n^2) + (sin(nx)/n^2))]]

= (2/π^2) * [(-1)^n - 1]

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The following statements are true:

The red light is reflected.

The blue light is absorbed.

When white light, which consists of a combination of all visible colors, illuminates the book with a red cover, the red light component in the white light is reflected by the book cover. As a result, we perceive the book to be red since that is the color of light being reflected back to our eyes.

On the other hand, the blue light component in the white light is not reflected by the red book cover. Instead, it is absorbed by the cover, which means the material of the book cover absorbs the blue light and does not reflect it back. Consequently, we do not see the blue light, and the book still appears to be red.

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Answer:

Step-by-step explanation:

5 offices in 6 hours 6x2 equals to 12 so the cleaning crew can clean 10 offices in 12 hours

Step-by-step explanation:

Diameter is 20.2     <=====given

  then radius is 1/2 of this = 10.1

      radius = 5.1 + x   = 10 .1

                        x = 5   units      Tha's it.

False. The range of a linear transformation is a subset of the codomain, not the domain.

The domain is the set of inputs to the transformation, while the codomain is the set of possible outputs. The range is the set of actual outputs produced by the transformation. The statement "The range of a linear transformation must be a subset of the domain" is false. The range of a linear transformation is a subset of the codomain, not the domain. The domain is the set of input vectors, while the codomain contains the possible output vectors after applying the linear transformation.

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The number of bit strings of length 12 that have exactly four 1s can be determined using the combination formula C(12, 4), which represents the number of ways to choose four elements out of twelve. Therefore, the answer is option b.

To find the number of bit strings with exactly four 1s, we need to select the positions for these four 1s from the total of twelve positions. The combination formula C(n, k) represents the number of ways to choose k elements from a set of n elements without regard to their order. In this case, we have twelve positions and need to choose four of them to place the 1s, so we can calculate C(12, 4).

Using the formula for combinations, C(n, k) = n! / (k! * (n-k)!), we can calculate C(12, 4) as follows:

C(12, 4) = 12! / (4! * (12-4)!) = 12! / (4! * 8!) = (12 * 11 * 10 * 9) / (4 * 3 * 2 * 1) = 495.

Therefore, there are 495 different bit strings of length 12 that have exactly four 1s, and the correct answer is option B, C(12, 4).

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Newton's Method to approximate the positive root of the equation [tex]sin(x)=x^2[/tex] is x ≈ 0.8913959953

Firstly, We know that :

The formula of Newton's Method :

[tex]x_n_+_1=x_n-\frac{f(x_n)}{f'(x_n)}[/tex]

We have the equation [tex]sinx=x^{2}[/tex]:

So we need to change the equation into a function. This is done by moving all terms to one side:

[tex]f(x) =sinx-x^{2}[/tex]

And we need the derivative:

[tex]f'(x)= cosx-2x[/tex]

Write f(x) into Y1 and f'(x) into Y2.

[tex]A-\frac{Y_1(A)}{Y_2(A)}[/tex]→A

Finally, you need a starting value, [tex]x_1[/tex]. Since the question is asking for a positive root, we know that sinx has a maximum value of 1 at x =[tex]\frac{\pi }{2}[/tex] and [tex]x^{2} =1[/tex] So we can say that the root is less than 1 and therefore will be the starting value.

then, the value is:

x ≈ 0.8913959953

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To solve the given differential equation using the Laplace transform, we will follow these steps:

Step 1: Take the Laplace transform of both sides of the equation.

Step 2: Solve for the Laplace transform of the unknown function.

Step 3: Use the inverse Laplace transform to obtain the solution in the time domain.

Let's begin with Step 1:

Taking the Laplace transform of the given differential equation, we have:

s^2 * Y(s) - 2s * y(0) - y'(0) - 15Y(s) = 1/s

Here, Y(s) represents the Laplace transform of the unknown function y(t).

Now, applying the initial conditions y(0) = 0 and y'(0) = 0, we get:

s^2 * Y(s) - 15Y(s) = 1/s

Step 2:

To solve for Y(s), we can factor out Y(s) as a common factor:

Y(s) * (s^2 - 15) = 1/s

Dividing both sides by (s^2 - 15), we have:

Y(s) = 1 / (s * (s^2 - 15))

Now, we need to express the right side in partial fractions. Let's decompose it as follows:

1 / (s * (s^2 - 15)) = A/s + (Bs + C) / (s^2 - 15)

To determine the constants A, B, and C, we multiply both sides by the common denominator:

1 = A * (s^2 - 15) + (Bs + C) * s

Expanding and collecting like terms:

1 = (A * s^2 + Bs^2 + Cs) - 15A

Comparing coefficients of like powers of s:

0s^2: B = 0

1s: C = 0

s^2: A = -1/15

Therefore, the partial fraction decomposition is:

1 / (s * (s^2 - 15)) = -1 / (15s) + 0 / (s^2 - 15)

Substituting the partial fraction decomposition into Y(s), we get:

Y(s) = -1 / (15s) + 0 / (s^2 - 15)

Simplifying:

Y(s) = -1 / (15s)

Step 3:

Now, we need to find the inverse Laplace transform of Y(s) to obtain the solution in the time domain.

Using a standard Laplace transform table, we find that the inverse Laplace transform of -1 / (15s) is:

y(t) = -1/15 * (1 - e^(0t))

Since e^(0t) is equal to 1, we can simplify the equation further:

y(t) = -1/15 * (1 - 1)

y(t) = 0

Therefore, the solution to the given differential equation is y(t) = 0.

The -1 part is not inside the natural log.

==============================================

Work Shown:

1 + 2*e^(x+1) = 9

2*e^(x+1) = 9-1

2*e^(x+1) = 8

e^(x+1) = 8/2

e^(x+1) = 4

x+1 = Ln(4)

x = Ln(4) - 1

The volume of the solid region R bounded by the surface f(x, y) = [tex]e^{(-x^2)[/tex] and the planes y = 0, y = x, and x = 1 is 1 - 1/e.

The area that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.

To find the volume of the solid region R bounded by the surface f(x, y) = [tex]e^{(-x^2)[/tex] and the planes y = 0, y = x, and x = 1, we need to set up a triple integral.

First, let's find the limits of integration for each variable:

For x, it ranges from 0 to 1.

For y, it ranges from 0 to x.

For z, it ranges from 0 to f(x, y) = [tex]e^{(-x^2)[/tex].

Now, the volume can be calculated as follows:

V = ∫∫∫R dV

 = ∫[0 to 1] ∫[0 to x] ∫[0 to [tex]e^{(-x^2)[/tex]] dz dy dx

Let's evaluate this triple integral step by step:

V = ∫[0 to 1] ∫[0 to x] [tex]e^{(-x^2)[/tex] dz dy dx

Integrating with respect to z, the innermost integral, we get:

V = ∫[0 to 1] ∫[0 to x] z |[0 to [tex]e^{(-x^2)[/tex]] dy dx

 = ∫[0 to 1] ∫[0 to x] [tex]e^{(-x^2)[/tex] - 0 dy dx

 = ∫[0 to 1] [tex]e^{(-x^2)[/tex] * (y)|[0 to x] dx

 = ∫[0 to 1] [tex]e^{(-x^2)[/tex] * (x - 0) dx

 = ∫[0 to 1] x * [tex]e^{(-x^2)[/tex] dx

Now, let's substitute u = [tex]-x^2[/tex], du = -2x dx:

V = ∫[0 to 1] x * [tex]e^{(-x^2)[/tex] dx

 = -∫[0 to 1] [tex]e^u[/tex] du

 = -[[tex]e^u[/tex]]|[0 to 1]

 = -([tex]e^{(-x^2)[/tex])|[0 to 1]

 = [tex]-(e^{(-1^2)[/tex] - [tex]e^{(-0^2)})[/tex]

 = -([tex]e^{(-1)[/tex] - [tex]e^0[/tex])

 = -(1/e - 1)

 = 1 - 1/e

Therefore, the volume of the solid region R bounded by the surface f(x, y) = [tex]e^{(-x^2)[/tex] and the planes y = 0, y = x, and x = 1 is 1 - 1/e.

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No, the events are not independent. In the first scenario, Lacy draws a heart from a standard deck of 52 cards, and without replacing it, draws a second card and gets a club.

The probability of drawing a heart on the first draw is 13/52 (since there are 13 hearts in a deck of 52 cards). However, after the heart is drawn, there are now only 51 cards remaining in the deck, and only 12 clubs. Therefore, the probability of drawing a club on the second draw, given that a heart was already drawn, is 12/51. Since the probability of drawing a club on the second draw changes depending on the outcome of the first draw, these events are not independent.

In the second scenario, Linda draws a heart from a standard deck of 52 cards, returns it to the deck, and then draws a second card. The probability of drawing a heart on the first draw is again 13/52. However, since the heart is returned to the deck before the second draw, the composition of the deck remains the same. Therefore, the probability of drawing a club on the second draw is still 13/52. In this case, the outcome of the first draw does not affect the probability of drawing a club on the second draw, indicating that these events are independent.

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Therefore, the primary derivatives are: df/dx = 3x^2 * y^4 * z^4, df/dy = 4x^3 * y^3 * z^4, df/dz = 4x^3 * y^4 * z^3.

To calculate the primary derivatives of f(x, y, z) = x^3 * y^4 * z^4, where x = s^3 * t^2, y = st, and z = st, we need to differentiate f with respect to each variable x, y, and z.

The partial derivative with respect to x (df/dx) is obtained by treating y and z as constants and differentiating x^3 with respect to x:

df/dx = 3x^2 * y^4 * z^4

The partial derivative with respect to y (df/dy) is obtained by treating x and z as constants and differentiating y^4 with respect to y:

df/dy = 4x^3 * y^3 * z^4

The partial derivative with respect to z (df/dz) is obtained by treating x and y as constants and differentiating z^4 with respect to z:

df/dz = 4x^3 * y^4 * z^3

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a. The equation will be THC(x) = 304 mg * (0.48)^(x/10)

b. After 60 days, there will still be approximately 4.53 mg of THC in the person's body.

a. To describe the amount of THC in a person's body x days after consuming 8 ounces of marijuana, we can use the equation:

THC(x) = 304 mg * (0.48)^(x/10)

In this equation, x represents the number of days since the consumption of 8 ounces of marijuana, and THC(x) represents the amount of THC in milligrams in the person's body at that time.

b. To find out how much THC will be in the person's body after 60 days, we need to substitute x = 60 into the equation:

THC(60) = 304 mg * (0.48)^6

Calculating this expression, we get:

THC(60) ≈ 304 mg * 0.0149

≈ 4.53 mg

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Answer:

C. 3 Units

Step-by-step explanation:

It's important to note that translations don't change the size of the side lengths and the side lengths are preserved in measurement. In this case, since the original was 3, the translated figure must also be 3 unit.

The two points where the line meets the circle are (3,6) and (8,3).

To find the coordinates of the point where the line 2x+2y=18 meets the circle (x-2)^2+(y-3)^2=16, we need to first solve the system of equations.

We can start by simplifying the equation of the line by dividing both sides by 2, giving us x+y=9. We can then substitute y=9-x into the equation of the circle,

which results in (x-2)^2+(9-x-3)^2=16. Simplifying this equation yields x^2-4x+4+x^2-12x+81=16. Combining like terms and solving for x, we get x=3 or x=8.

Substituting these values back into the equation of the line gives us the corresponding y-coordinates of 6 and 3, respectively.

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We want to find the dimensions of the rectangle of maximum area that can be inscribed in the ellipse $3x + 75y = 75$, with sides parallel to the coordinate axes.

Let the length of the rectangle be $x$, and the width be $y$. Then, the area of the rectangle is $A = xy$.

Since the sides of the rectangle are parallel to the coordinate axes, its vertices lie on the ellipse $3x + 75y = 75$. The endpoints of the rectangle's length must lie on the x-axis, so we set $y=0$ and solve for $x$:

 3x + 75*0 = 75  

  x = 25

Similarly, the endpoints of the rectangle's width must lie on the y-axis, so we set $x=0$ and solve for $y$:

3*0 + 75y = 75

y = 1

Therefore, the rectangle with sides parallel to the coordinate axes and maximum area that can be inscribed in the ellipse has length $x=25$ and width $y=1$.

The area of the rectangle is $A=xy=25*1 = {25}$.

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Answer:

D) x= 2 , B) x= - 6

Step-by-step explanation:

D) 2 + 3x = 6x - 4

Arrange x with x and constant with constant, (the signs +ve and - ve changes while arranging them to other side)

2 + 4 = - 3x + 6x

6 = 3x

(Here the 3 was multiplying with x and when you bring it to the other side it divides by 6)

6/3 = x

2 = x

B) 18 + 4x = - 6

Arrange them again,

4x = - 18 - 6

4x = - 24

x = - 24/4

x = - 6

Multiple regression analysis is applied when analyzing the relationship between one dependent variable and two or more independent variables. The goal is to determine the extent to which the independent variables predict the dependent variable.

Multiple regression analysis is a statistical technique used to explore and quantify the relationship between a dependent variable and multiple independent variables. It allows researchers to examine how changes in one or more independent variables impact the dependent variable, while controlling for the effects of other variables. By estimating the coefficients for each independent variable, the analysis provides insights into the strength, direction, and significance of their relationships with the dependent variable. This method is commonly employed in various fields, such as economics, social sciences, and business, to understand complex relationships and make predictions based on the interplay of multiple factors.

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divisor by the quotient and adding the remainder.When performing polynomial long division, the divisor is multiplied by the quotient, and the resulting product is added to the remainder.

If the answer is correct, this addition should yield the original dividend.

Here's a step-by-step process to check the answer after polynomial long division:

Perform polynomial long division, dividing the dividend by the divisor. This process involves dividing the terms of the dividend by the highest degree term of the divisor and subtracting the result from the dividend.

Write down the quotient obtained from the division process.

Multiply the divisor by the quotient obtained in step 2.

Add the product obtained in step 3 to the remainder obtained during the division process.

The sum obtained in step 4 should be equal to the original dividend. If the sum matches the dividend, it indicates that the polynomial long division was performed correctly.

By performing this check, you can verify whether the answer obtained through polynomial long division is correct or not.

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If 6 inches represent 20 feet, then 33 inches would represent 110 feet in reality.

To determine the number of feet represented by 33 inches, we can set up a proportion using the given information:

6 inches represents 20 feet

Let's represent the number of feet represented by 33 inches as "x." The proportion can be set up as follows:

6 inches / 20 feet = 33 inches / x feet

Now we can cross-multiply:

6 inches × x feet = 33 inches * 20 feet

Simplifying further:

6x = 660

Dividing both sides of the equation by 6:

x = 660 / 6

x = 110

Therefore, 33 inches represents 110 feet.

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Answer:

if five integers are selected from the first eight positive integers, there must be a pair of these integers with a sum equal to 9

Step-by-step explanation:

To find the total cost of producing 10 units, we need to substitute x=10 into the cost function c(x) = 800x + 0.1x^2 + 1900:

c(10) = 800(10) + 0.1(10)^2 + 1900
c(10) = 8000 + 10 + 1900
c(10) = 9910
Therefore, the total cost of producing 10 units is $9,910. The cost function is a quadratic function, which means that the cost increases as the number of units produced increases. This is because there are fixed costs (such as equipment and labor) that have to be spread out over a larger number of units, making each unit more expensive to produce. It's important for businesses to understand their cost function in order to make informed decisions about pricing and production levels.

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(a) The number of five-digit integers divisible by 5 can be calculated by finding the number of multiples of 5 within the given range.

To determine the count of multiples, we need to find the first and last multiples of 5 within the range. The first multiple of 5 greater than or equal to 10,000 is 10,000 itself. The last multiple of 5 less than or equal to 99,999 is 99,995. Thus, the range contains 99,995 - 10,000 + 1 = 89,996 integers. To calculate the count of five-digit integers divisible by 5, we divide this range count by 5: 89,996 ÷ 5 = 17,999. Therefore, there are 17,999 five-digit integers divisible by 5.

(b) To determine the probability of randomly selecting a five-digit integer that is divisible by 5, we need to calculate the ratio of the number of five-digit integers divisible by 5 to the total number of five-digit integers. The total count of five-digit integers can be calculated by finding the range count from 10,000 to 99,999: 99,999 - 10,000 + 1 = 90,000. Therefore, the probability can be calculated as (17,999 ÷ 90,000) × 100% = 19.999%, which can be approximated as 20%. Hence, the probability that a randomly chosen five-digit integer is divisible by 5 is 20%.

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