Answer:
__3__ blood picks up waste products such as carbon dioxide
__2__ carries oxygen and nutrients to the body cell
__1__ moves to right ventricle and to lungs
__4__ blood travels from the lungs to the left atrium
__5__ returns to right atrium
Explanation:
PLS MARK BRAINLEST
Both vena cava passes the deoxygenated blood to the right atrium. Blood from right atrium enters right ventricle and pulmonary arteries carry deoxygenated blood from right ventricle to lungs for oxygenation. Two pulmonary veins come from each lung and pass O2 -rich blood to left atrium. Blood enters left ventricle from the left atrium. The left ventricle pumps blood into the aorta which in turn branches and delivers blood to the major body regions and organs.
What can always be said about a negatively-charged ion?
A negatively-charged ion always has more neutrons than protons
A negatively-charged ion always has more electrons than protons
A negatively-charged ion always has more protons than electrons
A negatively-charged ion always has more protons than neutrons
Answer: A negatively-charged ion always has more electrons than protons
Explanation:
First, we know that the elementary negative charge is the electron, while the positive one is the proton. Such that both have the same charge in magnitude, but a different sign. Such that if we have the same number of electrons and protons in an atom, the charge of this atom will be neutral.
And an ion is an atom with a different number of electrons and protons, so the charge of the atom is not neutral.
Then if we have a negatively-charged ion, the charge of this atom is negative. Then we must have a larger number of electrons (the negative ones) than protons (the positive ones)
Then the correct option is:
A negatively-charged ion always has more electrons than protons
Have you ever noticed that how much electrical energy is consumed by electrical appliances in your home. Make a chart of all of these appliances with their power in kW and an average use on daily, weekly, and monthly basis. Usually the electrical power is written on most of the appliances or on their packing. Calculate the total consumption of electrical energy in kWh in your home for December, 2020. Find the expected electricity bill for this month, if 1 kWh energy costs Rs 10. Which item consumed most energy during the month
Answer:
A. The expected electricity bill for this month is Rs 18,896.2
B. The item which consumed the most energy during the month is the electric cooker with a total consumption of 1,110Kw/Month
Explanation:
Step 1 - Identify electrical appliances
I only have 8 electrical appliances in my home.
Electric Cooker. Its power rating 3000 Watts (that is 3Kw/h)Refrigerator. Its power rating is 150 Watts (that is 0.15Kw/h)Waterheater. Its power rating is 4000 Watts (that is 4Kw/h)Electric Iron. Its power rating is 1000 Watts (that is 1Kw/h)Led TV. Its power rating is 235 watts (that is 0.235Kw/h)13 Energy-saving Light bulbs at 60 watts which is a total of 780 watts (which is 0.78Kw)Electric Standing Fan. Its power rating is 55 watts (that is 0.055Kw)Washing machine. Its power rating 255 watts (that is 0.255Kw)Step 2 - Assign usage per hour and calculate wattage used /month
The Electric Cooker is used an average of 9 hours/day. This is 270hours/month. Total Kw used per month 3Kw * 270hours = 1,110Kw/MonthThe refrigerator is used 24 hours. That is 0.15Kw *24*30days= 108Kw/MonthThe water heater is used 1 hour every day. That is 4Kw *30days = 120Kw/MonthThe electric Iron is used for 20 Minutes every day.That is 1Kw * 0.34hr *30= 10Kw/MonthThe Led Tv is used for 12hours/day. That is 0.235Kw*12*30=84.6Kw/monthThe bulbs are used for about 18hours/day. That is 0.78kw*18*30= 421.2Kw/monthThe electric standing fan is used for about 18 hours/day. That is 0.055kw*18*30=29.7Kw/monthThe washing machine is used for about 6 hours/week. That is 0.255Kw*4*6=6.12Kw/month
Step 3 - Add up all the Kw used per month and multiply by the cost of 1 Kw
Total Kilowatt Consumed/Month = 1110 +108+120+10+84.6+421.2+29.7+6.12
= 1,889.62Kw/Month
Total cost of energy consumed per month = 1889.62 * Rs 10
= Rs 18,896.2
Cheers!
green light has higher refractive index than orange light for the same material medium.explain
Answer:
The index of refraction varies with frequency or color. Frequency does not change as light travels from one medium to another.
Explanation:
Green light has a higher refractive index than orange light for the same material because orange color has a higher wavelength than green light and if the wavelength of light increases the refractive index decreases.
What is Wavelength?The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10-9 m, or angstroms, which are units of 10-10 m, for infrared (IR), visible light (UV), and gamma radiation.
Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.
To get more information about Wavelength :
https://brainly.com/question/13533093
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Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?
element z are isotopes because number of netron are different and number of protons are same
whats the result of rounding 52.8015 into five significant figures
Answer:
52.802
Explanation:
"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.
The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.
Explanation:
five significant of 52.8015=52.801 ..
A boat traveling across a river has a resultant velocity of 10 km/h and travels 34 degrees with respect to the shore. A) What is the boats velocity in m/s?
B) What is the velocity of the river in m/s?
Answer:
a) 1.55 m/s
b) 2.3 m/s
Explanation:
We know that the boat travels across the river, if we define the river as the x-axis, then the velocity of the boat is only on the y-axis.
Then we can write the velocity of the boat in still water as:
S = (0, B)
Now, when the boat is on the river, the velocity of the boat will be equal to the velocity of the boat in still water plus the velocity of the river.
The velocity of the river is:
v = (R, 0).
Then the velocity of the boat in that river is:
V' = (0, B) + (R, 0) = (R, B)
Now, we know that the velocity of the boat is 10km/h, and it travels at an angle of 34° with respect to the shore.
We can use the Pythagoreans theorem to write the components of this velocity as:
x-axis component = 10km/h*cos(34°) = 8.29 km/h
y-axis component = 10km/h*sin(34°) = 5.59 km/h
Then the velocity of the boat can be written in components as:
velocity = ( 8.29 km/h, 5.59 km/h)
And we knew that the velocity of the boat was written as (R, B)
Then we must have:
R = 8.29 km/h
B = 5.59 km/h
a) The speed of the boat in m/s:
We know that the speed of the boat is 5.59 km/h.
First, we know that:
1km = 1000m, then:
5.59 km/h = 5.59*(1000m)h = 5,590 m/h
And we know that:
1h = 3600s
Then we can write:
5,590 m/h = 5,590 m/(3600s) = 1.55 m/s
b) The speed of the river in m/s:
We know that the speed of the river is 8.29 km/h
Using the same reasoning as above, we can do the change of units as follows:
8.29 km/h = 8.29 (1000m)/(3600s) = 2.3 m/s
I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52 m/s at a height of 40 m when the fish wiggles free and fall back toward the ocean. How fast is the fish moving when it hits the water?
Answer:
28.1 m/s
Explanation:
[tex]u_x[/tex] = Initial velocity of the fish = 1.52 m/s
y = Height of the bird = 40 m
[tex]a_y[/tex] = Acceleration in y axis = [tex]9.81\ \text{m/s}^2[/tex]
[tex]u_y[/tex] = Initial velocity in y axis = 0
[tex]y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}[/tex]
[tex]v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}[/tex]
The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction [tex]u_x=v_x=1.52\ \text{m/s}[/tex]
Resultant velocity is given by
[tex]v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}[/tex]
The fish is moving at a velocity of 28.1 m/s when it hits the water.
A 200 kg object is initially at rest on a horizontal frictionless surface. At time t = 0 , a horizontal force of 100 N applied to the object for and then removed. Which of the following is correct about object's motion at time t=2 s?
(A) It is at rest.
(B) It is moving with decreasing acceleration.
(C) it is moving with decreasing speed.
(D)it moving at a constant speed.
(E) It is moving with increasing speed
Answer:
b
Explanation:
Two spheres have a gravitational force between
them of 45 N. If the distance between the masses
is increased to 4.0 times its original distance, what
is the new force?
Answer:
The new force is 2.8125 N
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the original value of the force:
[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]
F' = 2.8125 N
The new force is 2.8125 N
A force of 2 kN is applied to an object to make it move 3.6 m in the direction of the force. Select the correct value of work done on the object.
Answers to choose from:
1.8J
7200J
7.2J
555.6J
Answer:
W= F × d
W= 2kn × 3.6
W= 7.2 J
Work is measured in Joules!
How much work is done if a force of 20 N is used to move an object 6 meters
Explanation:
W=f×d
=20×6
w=120 joule
Select the true statements.
The interquartile range of A is 1 less than the interquartile range of B.
Including the runs allowed in the tenth game does not cause the spread of the data to change
The median of A is the same as the median of B.
The interquartile range of B is greater than the interquartile range of A.
The median of B is 1 run more than the median of A.
M
Answer:
The true statements are;
The median of A is the same as the median of B
The interquartile range of B is greater than the interquartile range of A
Explanation:
The given parameters are;
The set of the number of runs, A = {1, 4, 2, 2, 3, 1, 1, 2, 1}
The number of runs the pitcher allows in the tenth game = 9 runs
The set of the number of runs allowed in 10 games B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}
Rearranging the data, we get
A = 1, 1, 1, 1, 2, 2, 2, 3, 4
B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9
For the set A, we have;
Q₁ = 1, Q₂ = 2, Q₃ = 2
Therefore, the interquartile range of A = Q₃ - Q₁ = 2.5 - 1 = 1.5
For the set B, we have;
Q₁ = 1, Q₂ = 2, Q₃ = 2
Therefore, the interquartile range of A = Q₃ - Q₁ = 3.25 - 1 = 2.25
Therefore, the correct answers with regards to the two data are;
The median of A is the same as the median of B
The interquartile range of B is greater than the interquartile range of A
An object is subject to a 84 Nm torque about a point when a
21 N of force is applied to a second point along the object's
length. How far apart are the two points
Answer:
d = 4[m]
Explanation:
Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.
[tex]T=F*d[/tex]
where:
T = torque [N*m]
F = force [N]
d = distance [m]
Now replacing in the equation above.
[tex]84=21*d\\\\d= 4[m][/tex]
A negative charge of 20 x 10-6C and another charge of 15 x 10-6C are separated by as distance of 0.7 m.
What is the magnitude of the electrical force between the two charges:
answer to the closest 0.1 N
Answer:
Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.
Explanation:
Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.
Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex] and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].
Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].
Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].
By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].
Substitute in the values and evaluate:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].
At the height of 800 meters, a skydiver falls from an airplane flying horizontally at 40 m/sec. What is the horizontal distance of the skydivers travel before they "hit" the ground?
Answer:
The horizontal distance traveled by the skydiver is 510.8 m.
Explanation:
Given;
height of fall, h = 800 m
initial velocity of the airplane, u = 40 m/s
The time to fall to the ground is calculated as;
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \times 800}{9.81} }\\\\t = 12.77 \ s[/tex]
The horizontal distance or range of the motion is calculated as;
R = ut
R = 40 m/s x 12.77 s
R = 510.8 m
Therefore, the horizontal distance traveled by the skydiver is 510.8 m.
Which of these will cause the highest tides? A. when the Sun, Moon and Earth are in a straight line B. when all of the planets are on the same side of the Sun C. when the Sun, Earth, and Moon form a right angle D. when there are high speed winds caused by seasonal changes
Answer:
A. when the Sun, Moon and Earth are in a straight line
Explanation:
The highest tide is formed when the sun, moon, and also the earth are in alignment. This high tide is known as spring tides.
Spring tides happen when we have a new moon or a full moon. With the earth, sun and moon aligning. We have lunar and solar tide forming a reinforcement with each other causing high tides or extreme tides. we have collectively, their gravitational pull on water of the earth to become stronger
What is the formula for Charles Law?
Answer:
Explanation:
V_{1} = first volume
V_{2} = second volume
T_{1} = first temperature
T_{2} = second temperature
A bus travels 50.0 km/hr for 3.80 hours. The distance traveled will be what?
Einstein calculated that ripples of gravity travel at exactly the speed of _____
Answer:
299,792,458 m/s = speed of light
Explanation:
5
A cyclist travels 125 km in 5 hours. How fast is the cyclist moving?
Answer:
25 km/h
Explanation:
speed=distance÷time
125÷5=speed
125÷5=25 (then add units)
Read each of the phrases below. Put the phrases in the correct order to show the path of blood flow in the circulatory system starting with the blood traveling from the lungs.
____ blood picks up waste products such as carbon dioxide
____ carries oxygen and nutrients to the body cells
____ moves to right ventricle and to lungs
____ blood travels from the lungs to the left atrium
____ returns to right atrium
Answer:
blood picks up waste products such as carbon dioxide
returns to right atrium
moves to right ventricle and to lungs
blood travels from the lungs to the left atrium
carries oxygen and nutrients to the body cells
Explanation:
In the circulatory system, the blood carries the carbon dioxide to the right atrium of the heart through superior vena cava, then it move to right ventricle through tricuspid valve. The blood move to lungs following pulmonary artery and from lungs blood travels to the left atrium. From left atrium blood moves to the rest of the body through aorta and carries oxygen and nutrients to the whole body cells through.
Hence, the correct order is as follows:
blood picks up waste products such as carbon dioxide
returns to right atrium
moves to right ventricle and to lungs
blood travels from the lungs to the left atrium
carries oxygen and nutrients to the body cells
The Periodic Table Question 4 of 10 If an element forms a 2+ ion, in which group of the periodic table would you expect to find it? D A. 2 B. 17 O C. 1 D. 18 7
Answer:
B is the difference قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *
The sailboat is initially traveling at velocity of 10km/h. What is the change in velocity if the final velocity is 15.5km/h
Answer:
The change in velocity is 5.5 km/h
Explanation:
The initial velocity with which the sailboat is travelling, v₁ = 10 km/h
The final velocity with which the sailboat is travelling, v₂ = 15.5 km/h
The change in velocity, Δv, is the difference between final velocity, v₂ and the initial velocity, v₁, as follows;
Mathematically, Δv = v₂ - v₁
By substituting the given values, we have;
Δv = 15.5 km/h - 10 km/h = 5.5 km/h
The change in velocity, of the sailboat Δv = 5.5 km/h.
PLEASE ANSWER ILL GIVE YOU BRAIN!!!!
Answer:
I think the first two one is 70 the second on is 14
I hope this helps if I’m wrong I’m sorry
Explanation:
1. A person riding a bicycle on level ground reaches a velocity of 13.4 m/s before
stopping. While braking, the internal energy of the brakes, wheels, and road
increase by 5836 J. What is the mass of the cyclist?
please answerrr asapp tyty Laura goes for cycle from her house to the post office 4km away how long did it take for Laura to reach the post office
Answer:
See the answer below
Explanation:
The time Laura took to reach the post office would depend on the speed of cycling.
We know that;
speed = [tex]\frac{distance}{time}[/tex]
hence,
time = [tex]\frac{distance}{speed}[/tex]
Since the distance from Laura's house to the post office is 4 km, the equation becomes;
time = [tex]\frac{4}{speed}[/tex]
Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.
9ma electric current is flowing through a conducting wire , then the number of electron passing through it in 3 min is
Answer:
1.0125 x 10^19
Explanation:
current flowing through conductive wire= 9mA = 9 x 10^ -3 A
charge passing per 3 min
Q = It
= 9 x 10^ -3 x (3 x 60)
= 1.620 C
no of electrons in charge
Q = ne
1.620 = n x 1.6 x 10 ^ -19
n. = 1.0125 x 10 ^19
Compounds are made from the atoms of two or more______?
Answer:
elements
not really an explanation
What type of wave did you create when you pushed your arm back and forth?
plz help
Answer: It is a transverse wave ^^
Explanation:
the mass of the car is 1400 kg. The car , initially at rest is moved along a level road by a resultant force of 3500N.The car reaches speed of 30m/s ... calculate the average acceleration and use newtons seconds law , F=m×a
Answer:
2.5m/s²
Explanation:
Given parameters:
Mass of car = 1400kg
Resultant force = 3500N
Speed = 30m/s
Unknown:
Average acceleration = ?
Solution:
According to the Newton's second law of motion:
Force = mass x acceleration
Now;
3500 = 1400 x acceleration
Acceleration = [tex]\frac{3500}{1400}[/tex] = 2.5m/s²