No, it is not possible to bring a third charge in from infinity without changing the total potential energy of the system.
Potential energy for the first two charger is,
[tex]U=\frac{1}{4\pi E_{0} } \frac{q_{1}q_{2} }{r_{12} }[/tex]
This will change for adding a third charge no matter I it's sign, given as,
[tex]U=\frac{1}{4\pi E_{0} } [\frac{q_{1}q_{2} }{r_{12} } +\frac{q_{1}q_{3} }{r_{13} }+\frac{q_{2}q_{3} }{r_{23} }][/tex]
Hence not possible to find a place to bring a third charge in from infinity without changing the total potential energy of the system
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a 1.83 kg book is placed on a flat desk. suppose the coefficient of static friction between the book and the desk is 0.562 and the coefficient of kinetic friction is 0.305 .
Answer: the force required to begin moving the book is 7.93 N.
Explanation:The concepts required to solve this problem is forces.
Initially, calculate the force required to begin moving the book by using the expression for the static frictional force. Later, calculate the force required to keep the book moving by using the expression for the kinetic friction.
Here,
is the coefficient of static friction and N is the normal force.
Here,
is the coefficient of kinetic friction and N is the normal force.
Step: 1
The expression for the force required to begin moving the book is,
The normal force acting on the book ,
Substitute mg for N in the equation
.
Substitute 0.442 for
, 1.83 kg for m,
for g in the above equation.
Therefore, the force required to begin moving the book is 7.93 N.
Explanation:
The external force is required to move the book on the surface of the desk is known as static frictional force.
The forces acting on the book along the y direction is,
By using Newton’s second law of motion the net forces acting along y direction is,
As the book is along the x direction means that there is no motion of the book along the y direction. Hence the acceleration of the book is equal to zero.
Now the normal force is equal to the weight of the book.
Hint:
Calculate the force required to keep the book moving by using the expression for the kinetic friction.
Step: 2
The force required to keep the book moving ,
The normal force acting on the book ,
Substitute mg for N in the equation
.
Substitute 0.240 for
, 1.83 kg for m,
for g in the above equation.
Therefore, the force required to keep the book moving is 4.30 N.
The kinetic frictional force acts on the object if the object is in motion.
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If a 1.83 kg book is placed on a flat desk, 10.089 N of force is required to start moving the book. If the book and desk experience static friction of 0.442 and kinetic friction of 0.240, respectively.
A force that acts between moving surfaces is referred to as kinetic friction. A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficient of kinetic friction will determine how much force is applied.
The book needs force to move
Ff = N * s Ff = (1.83 kg)(9.81 m/s2)(0.562)=10.089 N
The book needs force to continue.
Ff = (1.83 kg) (9.81 m/s2) (0.305) = 5.47 N
The force that prevents a sliding object from moving is known as friction. Everything has kinetic friction, which prevents two or more objects from moving in unison. In contrast to how an object would like to slide, the force operates in that direction. When a car needs to stop by kinetic friction, we engage the brakes, and that's when friction is created. Again, friction is to blame when one wishes to stop abruptly while walking. however, when we are forced to stop in the middle of a puddle.
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first find the direction of the magnetic field at wire 2 due to wire 1 (using the right-hand rule). next, find the direction of the force on wire 2 due to this magnetic field. the force on a particle with charge qqq moving with velocity v⃗ v→v vec in a magnetic field b⃗ b→b vec is f⃗
1) Magnitude of the magnetic field equals (permeabilityoffrespace) (currentmagnitude)
2π(distance)
B = μ02πr
Developing the Formula
B = denotes the strength of the magnetic field in Tesla (T)
The permeability of open space (4107Tm/A) is shown by the symbol 0
Electric current strength is expressed as I in terms of amperes (A)
R stands for the meters-long distance (m)
2) the magnetic force per unit length of wire in a uniform field is
F/l =IB sinθ .
force on a length l
current I
uniform magnetic field B ,
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A girl runs at 10m/sec for 6 seconds, and then walks at 5 m/sec for 4 seconds. What is the average speed of the girl for the entire trip?
The average speed of the girl for the entire trip is 8m/s
Firstly we have to find the total distance that the girl covered.
As formula says
Distance = speed * time
So according to the question;
Total Distance = 10×6 + 5×4
= 60+20
= 80
And the total time taken by the girl = 6+4
= 10
Therefore, by Putting the values in the formula:
Average speed = 80÷10
=8m/s
Hence, the average speed of the girl is 8m/s.
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Describe how the womans nervous system coordinates the reflex action
The nervous system in a woman can coordinate the reflex action due skin receptors sense a stimulus, sensory neurons transmits the electrical impulses, motor neurons address it to the effect, and finally producing a response.
What is the reflex action?Reflex action can be defined as an involuntary response to different environmental conditions, which are collectively called stimuli. These conditions may lead to a change in the body temperature and they are useful to adapt to a changing environment, which is a fundamental issue in adaptive responses.
The nervous system may manage reflex actions in this system by using specific cell receptors located at the epidermis (skin cells).
Therefore, we can conclude that the reflex action is a coordinated response of the nervous system associated with the detection of environmental stimuli that lead to the activation of effector cells and sensory neurons.
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in coming to a stop, an old truck leaves skid marks 45 m long on the highway. assuming a deceleration of 6m/s2 , estimate the speed of the truck just before braking.
Deceleration is the slowing down of the body as it moves away from its starting place. Negative acceleration is a common term for deceleration.
The kinematic equation was used to get the truck's estimated speed right before braking as
v2 = u2 + 2*acceleration *displacement.
Consequently,
[2*(45.0 m)*(6 m/s)]
= √540 = 23.24 m/s
The velocity, or v, of an object is the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.
The rates at which an object's velocity with respect to time changes are known as accelerations and are stated as constants. Whenever a force is operating on an object, it will always accelerate in a direction that is parallel to that force.
The length of a displacement vector is the smallest distance between the starting and ending coordinates of a moving point P.
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A simple machine is a machine that does work with only |two movements| of the machine
true or false
If false write the true answer
Answer:
hope it helps
Explanation:
a rabbit is moving in the positive x-direction at 1.50 m/s when it spots a predator and accelerates to a velocity of 10.9 m/s along the negative y-axis, all in 1.80 s. determine the x-component and the y-component of the rabbit's acceleration. (enter your answers in m/s2. indicate the direction with the signs of your answers.)
x-component of the rabbit's acceleration ax = -0.833m/s
y-component of the rabbit's acceleration ay = -6.06m/s
How does acceleration work?Acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is always shifting, motion on a circle accelerates even while the speed is constant.
Along x axis
Vox = velocity along the positive x-direction = 1.50 m/s
Vfx = 0m/s
ax = (Vfx-Vox)/T
ax=(0-1.5)/(1.8)
ax=-0.833m/s
x-component of the rabbit's acceleration ax = -0.833m/s
Along y axis
Voy = 0 m/s
Vfy = velocity along the negative y-axis -10.9m/s
ay=(Vfy-Voy)/T
ay= (-10.9-0)/(1.8)
ay = -6.06m/s
y-component of the rabbit's acceleration ay = -6.06m/s
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NEED ANSWER BADLY
the strength of a gravitational pull ______ as the distance between two objects ______.
The strength of a gravitational pull increases as the distance between two objects decreases. This is why you experience less gravity at Everest mountain than the sea level.
What is gravity?Gravity is an attractive force between two different objects, which is based n the weight and mass (i.e. physical features) of such objects. Newton developed the law of Gravity by observing the movement of different objects such as apples when they down to the ground from trees.
The attractive gravity forces are also inversely proportional to the distance square between the object subject to this force, thereby gravity is a force that decreases in longer distances regardless of other physical features of such objects and or celestial bodies.
Therefore, we can conclude that gravitational forces are well known to increase as the distance is minor and therefore this value is associated with the separation between objects.
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please answer this question! i am new to physics and i need help please. thanks!!!
Numerous optical devices, including telescopes, microscopes, binoculars, spectroscopes, and periscopes, among others, employ the phenomenon of complete internal reflection of light.
A diamond's brilliance results from complete internal reflection.
Why is it crucial to fully reflect within?Total internal reflection, which is used in polarising prisms, is significant in fibre optics. Portion of the incoming light will be transmitted and part will be reflected at any incidence angle below the critical angle. The indices of refraction can be used to compute the normal incidence reflection coefficient.
Total internal reflection is a widely used technique in fibre optics. It is used in communications to carry cable TV, internet, and telephone signals. The use of light transmission through fibres is known as fibre optics.
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9. Twelve identical 2 W light bulbs are connected in series to a 240 V mains supply. The current in ampere through each lamp is (A) 0,05 (B) 0,1 (C) 6 (D) 10
Since they are connected in series, the current in ampere through each lamp will be 0.01 A approximately. None of the options is correct.
What is Electrical Power ?Electrical power is the rate at which electrical work (or electrical energy) is done. It is measured in Watt.
Given that twelve identical 2 W light bulbs are connected in series to a 240 V mains supply. The current in ampere through all the lamp will be the same because they are connected in series.
Power P = IV
Where
P = 2 WV = 240 VI = ?Substitute all the parameters into the formula.
2 = I × 240
I = 2 / 240
I = 0.0083 A
Therefore, the current in ampere through each lamp is 0.0083 A
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Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 1.54 m away from a
waterfall 0.643 m in height, at what minimum
speed must a salmon jumping at an angle of
35.5° leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s².
Answer in units of m/s.
The minimum speed that a salmon jumps at an angle of 35.5 degree is 43.3 m/s to leave the water to continue upstream.
What is speed and how it calculated out to be 43.3 m/s ?
First draw the picture of initial velocity , Looking at the x direction x = vxt but vx= vcos 35.4 degree, so x = vcos(31.4 degree) .t= 2.73/ vcos(35.4 deg) is the time to reach and continue to upstream, given acceleration due to gravity 9.8m/s^2.In the y direction del y = Vyt + 1/2 at^2 but Vyi = Vsin(35.4 deg) (2.73/vcos(31.4 deg).So using the equation V^2 = 43.1765 or we can get the final answer as 43.3 m/s to be the speed that the salmon jumps at angle of 35.5 degree leave the water to continue upstream.Speed is a quantity which represents distance per unit time.To know more about speed visit:
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1. If the odometer on a car reads 100 km at the start and 155 km at the end of a trip, what
distance did the car travel on the trip?
2. What would be the average speed of the car in the question above if the trip took half an
hour (30 minutes)?
1. 55 km is distance the car travel on the trip.
Net distance = final distance - initial distance = 155 - 100 = 55km.
2. 110 km/hr is would be the average speed of the car in the question above if the trip took half an hour.
Average speed = distance travelled/ time = 55km/0.5hr
Hence, average speed = 110km/hr
The average speed is the full distance traveled with the aid of the object in a particular time interval. The average speed is a scalar quantity. it is represented via the significance and does not have path. average pace is calculated by way of dividing distance through time.
Speed is the directional pace of a object in movement as a demonstration of its price of alternate in role as discovered from a selected frame of reference and as measured by way of a particular trendy of time.
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
A liquid has a mass of 25 grams (g) and a volume of 10 milliliters (mL). What is the density of the liquid?
A. 4.0 g/ml
B. 0.4 g/ml
C. 2.5 g/ml
D. 250 g/ml
Answer:
C. 2.5 g/ml
Explanation:
Divide mass by volume
A ball was kicked horizontally off a cliff at 14m / s. how high was the cliff if the ball landed 83 m from the base of the cliff?
The height of the cliff from which the ball fell is 172.3 m.
What is the time of motion of the ball?
The time of motion of the ball is the time taken for the ball to travel from its initial position to the final position.
X = Vt
where;
X is the horizontal distance travelled by the ballV is the horizontal velocity of the ballt is the time of motion of the ballt = X/V
t = (83 m) / (14 m/s)
t = 5.93 s
The height of fall of the ball is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity = 0g is acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
h = ¹/₂(9.8)(5.93)²
h = 172.3 m
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A 1.4-kg physics textbook is initially at rest on a steel table. The textbook is then pushed with a constant force of 6.0 N. Friction with a magnitude of 3.0 N is exerted on the moving book by the surface of the table. Determine the final velocity of the textbook after it has been pushed 1.0 meter across the table.
The final velocity of textbook upon being pushed is 0.64 m/s. Thus, [tex]v_{f} = 0.64 m/s[/tex].
Given mass of the textbook, m = 1.4 kg
External force applied to push textbook, F = 6.0 N
Frictional force exerted on book, f = 3.0 N
Initial velocity of textbook, u = 0
Since, The external force applied on the object is more than the total limiting friction exerted on book. Hence, the object moves and friction become Kinetic Friction.
Therefore, F-f = ma
6 - 3 = 1.4 * a
[tex]a= \frac{3}{1.4}[/tex]
[tex]a = 2.1 m/s^{2}[/tex]
Now, to find final velocity of textbook
[tex]v^{2} = u^{2} + 2as[/tex]
where v = final velocity
u = initial velocity
a = acceleration
s = distance travelled by textbook
[tex]v^{2} = 0 + 2*2.1*0.1[/tex]
[tex]v^{2} = 0.42[/tex]
v = 0.64 m/s
Hence, Final velocity of textbook after crossing 1.0m of distance is 0.64m/s.
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why you cannot use the acceleration equation for an object that changes direction
Answer: The proportionalities expressed by Newton's universal law of gravitation are represented graphically by the following illustration. Observe how the force of gravity is directly proportional to the product of the two masses and inversely proportional to the square of the distance of separation.
Explanation: I hope this helps : )
A dropped object reaches 88.2m/s in its fall. How long did it take to reach this speed?
The time taken for the object to reach its highest speed is 9 seconds.
What is time of motion?The time of motion of an object is the time taken for the object to travel from its initial position to the final position.
The time taken for the object to reach its maximum or highest speed is calculated as follows;
v = u + gt
where;
v is the final velocity of the rock at the highest pointu is the initial velocity of the rockg is acceleration due to gravityt is time of motionThe initial velocity of the object is zero, u = 0
v = u + gt
v = 0 + gt
v = gt
t = v/g
t = (88.2 m/s) / (9.8 m/s²)
t = 9 seconds
Thus, we can conclude that time from the initial position of the object to the final position of the object is 9 seconds.
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shows three ropes tied together in a knot. one of your friends pulls on a rope with 3.0 units of force and another pulls on a second rope with 5.0 units of force.
According to the parallelogram rule, if two vectors are placed with the same initial point and then completed into a parallelogram, the directed diagonal that begins at the same position as the vectors equals the sum of the two individual vectors.
What is a parallelogram, exactly?A quadrilateral with opposite sides that are parallel and equal is known as a parallelogram. The interior opposite angles of it are equal. Additionally, the transverse angles on the same side must add up to 180 degrees or be complementary to one another.
What do formula and parallelogram mean?A unique variety of quadrilateral in which the opposing sides are parallel and equal is known as a parallelogram. The length of each side added together makes up a parallelogram's perimeter, which may be computed using the following formula: Perimeter is equal to 2(a + b), where a and b are the parallelogram's two sides.
What is a parallelogram's primary characteristic?In a parallelogram, the opposing sides are parallel to one another and have equal measurements. In a parallelogram, the opposing angles are equal. A parallelogram's internal angles add up to 360 degrees. A parallelogram's subsequent angles must be supplementary (180°).
What are the parallelogram theorems?There are several related theorems, such as opposite sides are congruent, opposite angles are congruent, a parallelogram's diagonals bisect one another, and rectangles are parallelograms with congruent diagonals.
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on an icy day your worry about parking your car in a driveway
When we rolled carts down a ramp, we measured the length of the ramp, the height of the lower part of the ramp, the height of the upper part of the ramp, and how long it took for the cart to reach the bottom of the ramp. Then we changed the height of the upper part of the ramp and measured how long it took for the cart to reach the bottom of the ramp.
Which variable was the Independent Variable in that situation?
How do you know it's the Independent Variable?
The force of gravity can more easily overcome the force of friction if the ramp is steep. Obviously, gravity causes an object on an incline to move faster down the slope than an object on a flat slope. Because of the increased height, falling takes longer.
What exactly is an independent variable?In mathematical modeling, statistical modeling, and experimental sciences, dependent and independent variables are variables. Dependent variables are so named because their values are studied in an experiment under the assumption or demand that they are dependent on the values of other variables due to some law or rule. In research, the best way to identify dependent and independent variables is to use the sentence "The Independent variable causes a change in the Dependent variable.Multiple independent variables are frequently included in experiments by researchers. The factorial design is the most common approach, in which each level of one independent variable is combined with each level of the others to generate all possible conditions.Hence, The force of gravity can more easily overcome the force of friction if the ramp is steep.
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4) Free fall is a situation in which the only force acting upon an object is gravity. Why do all objects in free fall have the same acceleration?
A) their masses are always the same
B) acceleration due to gravity is always the same
C)
the distance between two objects is always the same
D) the gravitational force between two objects are always the same
All objects in free fall have the same acceleration because acceleration due to gravity is always the same. So option B is correct.
What is gravity?Gravity can be referred to as the force by which a planet or other body draws objects toward its center.
Gravity is one of the universe's fundamental forces and dominates every moment of our conscious experience which helps keeps us close to the ground.
All objects in free fall have the same acceleration because acceleration due to gravity is always the same.
Free fall is a special type of motion in which the only force acting upon an object is gravity which will make all objects with the same rate of acceleration, regardless of their mass.
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A hoop of radius 0.06m starts from rest and rolls down a slope without sliding. find its linear and angular speed when it reaches sa point of 0.50m vertically lower than the starting point
The linear speed is √5 m/s and the angular speed is √5/0.06 rad/s.
We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as
Ei = Ef
where Ei is initial energy and Ef is the final energy
From the question above, we know that
R = 0.06 m
h = 0.5 m
The playground slide is converting the potential energy from height to kinetic energy. Hence,
Ei = Ef
PE = KE trans + KE rot
m . g . h = 1/2 . m . v² + 1/2 I . ώ²
m . 10 . 0.5 = 1/2 . m . v² + 1/2 m.R² . ώ²
5 = 1/2(v² + R² . ώ²)
10 = (v² + R² . v²/R²)
2v² = 10
v = √5 m/s
v = ώ . R
√5 = ώ . 0.06
√5 = ώ . 0.06
ώ = √5/0.06 rad/s
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a 7li nucleus with a charge of 3e and a mass of 7 u and a proton with a charge of e and a mass of 1 u are both moving in a plane perpendicular to a magnetic field . the two particles have the same monentum. the ratio of the radius of curvature of the path of the proton (rp) to that of the 7li nucleus (rli) is
Kinetic energy is transformed into potential energy. The charges on the nuclei of lithium and thorium, which have Z=3 and Z=90, respectively, are 3e and 90e.
Potential energy is created by converting kinetic energy (we use the classical formula since v is significantly less than c). Lithium has a Z=3 and thorium has a Z=90, meaning that the charges on each of those nuclei are 3e and 90e, respectively. The "e" in the kinetic energy unit MeV is removed by manipulating the terms, and the other factor of e is set to be 1.610 19 C.
We note that K= 1/4π0 can be written as 8.99*109V. m/C. Thus, from energy conversation, we have
Kinetic Energy=U = r=kq1q2/K=
(8.99x10^9 v.m/C)(3x1.6x10^-19)(90e)/3.00x10^6ev
which yields r= 1.3x10^-13 m (or about 130 fm).
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a 1.45 kg falcon catches a 0.159 kg dove from behind in midair. what is their velocity (in m/s) after impact if the falcon's velocity is initially 23.4 m/s and the dove's velocity is 9.33 m/s in the same direction? (enter the magnitude.)
The velocity of the falcon and dove in m/s after the impact is 21.95 m/s.
Using the data given,
Mass of falcon m₁ = 1.45kg
Mass of dove m₂ = 0.159kg
Initial speed of the falcon x₁ = 23.4m/s
Initial speed of the dove, x₂ = 9.3m/s
It is necessary to find the final velocity after the impact. When the falcon catches the dove, it will becomes the case of inelastic collision. The conservation of momentum will be :
m₁x₁ + m₂x₂ = (m₁ + m₂)V
V = m₁x₁ + m₂x₂/(m₁ + m₂)
V = 1.45*23.4 + 0.159*9.33/1.45+0.159
V = 33.93 + 1.483/1.613
V = 35.413/1.613
V = 21.95
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The figure shows a steady electric current passing through a wire with a narrow region. What happens to the drift velocity of the moving charges as they go from region a to region b and then to region c ?.
The drift velocity increases from A to B and decreases from B to C.
A drift velocity in physics is the average speed that charged particles—like electrons—achieve within a material as a result of an electric field. An electron will typically move randomly across a conductor at the Fermi velocity, producing an average velocity of zero. Applying an electric field causes a little net flow in one direction to be added to this random motion; this is the drift. Free electrons gain velocity in the direction opposite the electric field between collisions when a potential difference is applied across a conductor (and lose velocity when moving in the direction of the field), acquiring a velocity component in that direction in addition to their random thermal velocity.
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6.0-μf capacitor is connected in series with a 5.0 mω resistor, and this combination is connected across an ideal 15-v dc battery. what is the current in the circuit when the capacitor has reached 20% of its maximum charge?
Applied voltage across the capacitor is , Vo = 15 v
Capacitance , C = 6 × 10-6 F
Resistance in the circuit , R = 5 M.ohm = 5 × 106 ohm.
• Maximum charge in the capacitor is,
Q = CVo = (6×10-6 F)×(15 v) = 90 × 10-6 c
20% of maximum charge Q is, q = 0.2 ×(90×10-6) c
q =18×10-6 c.
when charge is 20% of maximum charge , voltage across the capacitor is,
V = q/C
V = (18 × 10-6 c)/(6 × 10-6 F) = 3 v
• At that time , voltage of the battery is Vo = 15 v
Voltage across the capacitor is , V = 3 v
Resistance in the circuit, R = 5 × 106 ohm
So, applying ohm's law :
Current in the circuit, I = (Vo - V)/R
> I = (15 - 3)/(5×106) A
> I = 2.4 × 10-6 A = 2.4 \muA
The current in the circuit is 2.4 \muA .
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A bicycle moves at an initial velocity of 5m/s accelerating constantly at 2.5m/s^2, what would be the displacement of the bicycle after 6.5 seconds?
The displacement of the bicycle is 85.3125m
Displacement of the bicycle may be defined as the change in position of the bicycle. It is a vector quantity so that it has direction and magnitude.
We are given that,
The initial velocity of the bicycle = u = 5m/s
The acceleration of the bicycle is = a = 2.5 m/s²
The time taken by the bicycle = t = 6.5 seconds
Therefore, to get the value of displacement of the bicycle by the equation of motion which is written as,
S = ut + (1/2) at²
Where, S is displacement, u is initial velocity, a is acceleration and t is time taken by the bicycle.
Since , putting the values in above equation then we get,
S = {5m/s × 6.5sec} +{ (1/2) × 2.5m/s² × (6.5 sec)²}
S = 32.5 m + 52.8125m
S = 85.3125m
Therefore, the bicycle would be moves 85.3125m
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a 1160 kg car traveling south at 24.0 m/s with respect to the ground collides with and attaches to a 2590 kg delivery truck traveling east at 16.0 m/s .
V=1160*24S/3750 + 2590*16E/3750 is the final velocity.
How to find the final velocity?Given,
An 1160 kg car traveling south at 24.0 m/s
A 2590 kg delivery truck traveling east at 16.0 m/s gets collided and attached to the car.
Solution:
The momentum is conserved here
1160*24 S + 2590*16 E =(1160+2590)V
V = 1160*24 S + 2590*16 E/3750
V=1160*24S/3750 + 2590*16E/3750
The final velocity is V=1160*24S/3750 + 2590*16E/3750.
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what force does a trampoline have to apply to a 45.0-kg gymnast to accelerate her straight up at 7.50 m/s2 ? note that the answer is independent of the velocity of the gymnast—she can be moving either up or down, or be stationary.
The force required will be 337.5 N
We have given the mass of the gymnast m = 45 kg
We have to find the force applied to the gymnast so that he can accelerate with the acceleration of 7.50m/sec^2
According to newtons law force on any object is given by F = ma, where m is mass and a is acceleration
So the force on the gymnast will be equal to F = 45×7.50 337.50 N
For acceleration of 7.50m/sec^2, we have to apply a force of 337.5 N
Acceleration is defined in mechanics as the rate of change of an object's velocity with respect to time. The orientation of an object's net force determines the orientation of its acceleration. Newton's Second Law states that the magnitude of an object's acceleration is the result of two causes:
the net balance of all external forces acting on that object — the magnitude of this net resulting force is related to its sizeThe magnitude is inversely related to the mass, depending on the materials used to make the thing.The rate of acceleration is expressed in meters per second squared.
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find the ratio of the masses m1/m2 . express your answer in terms of some or all of the variables a , μ , and θ , as well as the magnitude of the free-fall acceleration g .
The ratio of the masses is m1/m2.In terms of some or all of the variables a, μ, and θ, as well as the magnitude of the free-fall acceleration g.
m1/m2 = a+g(sinθ+μcosθ)/g−a
Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or points traveling straight forward. Due to the constant change in direction, motion on a circle accelerates even while the speed is constant.
To be a vector quantity, acceleration must have both a magnitude and a direction. As a vector quantity, velocity is also. A time interval's velocity vector change divided by that interval's duration is the definition of acceleration. The limit of the ratio of the change in velocity over a certain period to that period as that period approaches zero is used to determine instantaneous acceleration.
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