Answer:
Voltmeter
Explanation:
Voltmeter is used to measure both terminal potential difference as well as electromotive force (e.m.f.) depending upon the connection state of the battery or cell.
4 – Microwave Miracle Patrick believes that fish that eat food exposed to microwaves will become smarter and would be able to swim through a maze faster. He decides to perform an experiment by placing fish food in a microwave for 20 seconds. He has the fish swim through a maze and records the time it takes for each one to make it to the end. He feeds the special food to 10 fish and gives regular food to 10 others. After 1 week, he has the fish swim through the maze again and records the times for each. 1.What was Patrick’s hypothesis?
2.Which fish are in the control group?
3.What is the independent variable?
4.What is the dependent variable?
5. Look at the results in the charts. What should Patrick’s conclusion be?
The term experiment has to do with the kind of study in which the effect of a dependent variable on an independent variable is undertaken and looked into in dept.
We know that in an experiment there must be an independent variable which is being monitored and changes from time to time and there is the dependent variable which changes as the independent variable changes.
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The following graphs show average temperature data for two locations. Both locations have the same elevation. What is most likely true about the locations?
1080AQ5
A. Location A is farther from the equator than location B.
B. Location A is closer to the equator than location B.
C. Location B is located farther inland than location A.
D. Location A is in the northern hemisphere, and location B is in the southern hemisphere.
The statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )
The average temperature throughout the year is higher in location B then that of location A. The temperature is typically warmer near the equator and is typically cooler near the polar regions.
But some factors such as elevation, precipitation and ocean currents might affect the climate pattern. This change in temperature between equator and polar regions is due to the fact that equatorial regions receive more light and energy from the Sun than the polar regions.
Therefore, the statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )
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a snowboarder glides down a 60-mm-long, 15∘∘ hill. she then glides horizontally for 10 mm before reaching a 26 ∘∘ upward slope. assume the snow is frictionless.
v ^2f-v^2i= 2a Replace the known values,
0-16^2=2 (-4.2)S, S= 256/8.4, S= 30.4m. The maximum distance a snowboarder could travel on a 25o slope was 30.4 meters.
The snowboarder travels a distance of H=50 meters on the hill. The hill slopes at a 15 degree slant. snowboarder's horizontal distance traveled after passing a slope, S=10m Crossing a horizontal distance, there is a 25-degree rising slope.
The snowboarder's initial speed at location A is u = 0 m/s. Let v be the representation of the final velocity. G = 10m/s2 is the acceleration caused by gravity. The snowboarder's acceleration at the incline is = a = 10 sin (15 degree)
The snowboarder moved 10 meters horizontally after reaching the bottom of the hill. Before she reaches the steep slope, as depicted in the illustration, her pace is unchanged. Now, at the top of the hill, where she could go the farthest, S
Vf = 0 m/sec would be the final speed.
To calculate the furthest she could go, write the equation of motion,
v ^2f-v^2i= 2a Replace the known values,
0-16^2=2 (-4.2)S, S= 256/8.4, S= 30.4m. The maximum distance a snowboarder could travel on a 25o slope was 30.4 meters.
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1. A car begins at a speed of 3m/s and accelerates at 2m/s² over a distance of 40m,
calculate the final speed of the car.
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: v = 13 \:\: m/s[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex] \texttt{Initial speed of the car (u) = 3 m/s} [/tex][tex] \texttt{final speed of the car (v) = ??} [/tex][tex] \texttt{acceleration of the car (a)= 2 m/s²} [/tex][tex] \texttt{distance covered in that time (s) = 40 m} [/tex]By third equation of motion :
[tex]\qquad \tt \rightarrow \: {v}^{2} = {u}^{2} + 2as[/tex]
[tex]\qquad \tt \rightarrow \: {v}^{2} = (3) {}^{2} + 2(2)(40) [/tex]
[tex]\qquad \tt \rightarrow \: {v}^{2} = 9 + 160[/tex]
[tex]\qquad \tt \rightarrow \: {v}^{2} = 169[/tex]
[tex]\qquad \tt \rightarrow \: v = 169[/tex]
[tex]\qquad \tt \rightarrow \: v = 13[/tex]
so, speed of the car after that time is : 13 m/s
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
What did you observe about each subsequent for every bounce from every height?
The ball will rise back to a height equal to the initial height multiplied by the amount of kinetic energy it had before it started to ascend again (1-fraction of energy lost).
Why does a ball from a higher height bounce higher?All of the ball’s kinetic energy must be dissipated when it strikes the ground. The bounce increases with potential energy, kinetic energy, and kinetic energy alone, thus the more energy that returns to the ball and gives it more power to spring back into the air, the higher the bounce.
Ball bouncing heightThe height from which a ball is dropped, the material of the ball (and, if it is inflated, the pressure at which it is inflated), and the material of the surface from which the ball bounces determine the height to which it will rebound.
If you are measuring the height of the ball from its bottom to the ground, the radius of the ball doesn't actually matter.
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an object accelerates from rest to a velocity of 4.0 m/s in 8 seconds. what
was its acceleration
Answer:
Acceleration (a) = 0.5 mp[tex]s^{2}[/tex]
Explanation:
Given,
Object starts from rest, hence the initial velocity of the object is said to be 0
Velocity in the next 8 seconds is 4.0 m/s
u = 0 m/s
v = 4 m/s
t = 8 secs
We know,
a = (v-u)/t
=> a = (4-0)/8
=> a = 4/8 = 0.5 m/[tex]s^{2}[/tex]
A 7. 50g-bullet has a speed of 555 m/s as it leaves the muzzle of a rifle. If the barrel of the rifle is 0. 950 m, what is the average force exerted on the bullet by the ammunition?.
The average force exerted on the bullet by the ammunition is 1215.88N
From the question above, It is given that,
Mass of the bullet, m = 7.50 g
Initial speed of the bullet, u = 0
Final speed of the bullet, v = 555 m/s
We need to find the force exerted on the bullet while it was traveling down the 0.950m length of the barrel of the rifle. Let:
a is the acceleration of the bullet. So,
v² - u² = 2ad
v² = 2ad
a = v²/2d
a = 555²/2*0.950
a = 162118.42m/s²
Let F be the force exerted. It is given by:
F = Ma
F = 7.5 * 10⁻³ * 162118.42
F = 1215.88N
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F = 1590.87 N
So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.
5. How long would it take a truck to increase its speed from 10 m/s to 30 m/s if it does so
with uniform acceleration over a distance of 80 m ?
a) 8.0 s
b) 5.0 s
c) 4.0 s
d) 2.0 s
Answer:
C
Explanation:
Average velocity = (10+30) / 2 = 20 m/s
80 m / 20 m/s = 4 seconds
It would take a truck to increase its speed from 10 m/s to 30 m/s in 2.0 s. Option D is the correct answer.
To determine how long it would take for the truck to increase its speed from 10 m/s to 30 m/s, we can use the equations of motion. Option D is the correct answer.
The first equation we will use is: v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial velocity, u = 10 m/s
Final velocity, v = 30 m/s
We need to find the time, t. Since the truck is accelerating uniformly, we can assume a constant acceleration. Next, we use another equation of motion: v² = u² + 2as, where s is the distance traveled.
Given:
Distance, s = 80 m
Initial velocity, u = 10 m/s
Final velocity, v = 30 m/s
Rearranging the equation, we get: s = (v² - u²) ÷ (2a)
Substituting the given values, we have: 80 = (30² - 10²) ÷ (2a)
Simplifying the equation, we find:
80 = (900 - 100) / (2a)
80 = 800 / (2a)
2a = 800 / 80
a = 10 m/s²
Now, we can go back to the first equation: v = u + at
Substituting the known values: 30 = 10 + 10t
Simplifying, we find: 10t = 20
t = 2 seconds
Therefore, it would take the truck 2.0 seconds to increase its speed from 10 m/s to 30 m/s.
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Two point charges are separated by some distance. The first charge is positive. The second charge is negative, with a charge magnitude twice as large as that of the positive charge. Is it possible to find a place to bring a third charge in from infinity without changing the total potential energy of the system?.
No, it is not possible to bring a third charge in from infinity without changing the total potential energy of the system.
Potential energy for the first two charger is,
[tex]U=\frac{1}{4\pi E_{0} } \frac{q_{1}q_{2} }{r_{12} }[/tex]
This will change for adding a third charge no matter I it's sign, given as,
[tex]U=\frac{1}{4\pi E_{0} } [\frac{q_{1}q_{2} }{r_{12} } +\frac{q_{1}q_{3} }{r_{13} }+\frac{q_{2}q_{3} }{r_{23} }][/tex]
Hence not possible to find a place to bring a third charge in from infinity without changing the total potential energy of the system
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. a 7.0-kg box slides along a horizontal frictionless floor at 1.7 m/s and collides with a relatively massless spring that compresses 23 cm before the box comes to a stop. (a) how much kinetic energy does the box have before it collides with the spring? (b) calculate the work done by the spring. (c) determine the spring constant of the spring.
A. The kinetic energy of the box is 10.115 J
B. The work done by the spring is 7.889 J
C. The spring constant of the spring is 298.26 N/m
A. How to determine the kinetic energy
The kinetic energy of the box can be obatined as follow:
Mass (m) = 7 KgVelocity (v) = 1.7 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 7 × 1.7²
KE = 3.5 × 2.89
KE = 10.115 J
Thus, the kinetic energy is 10.115 J
B. How to determine the work done by the spring
Mass (m) = 7 KgAcceleration due to gravity (g) = 9.8 m/s²Force (F) = mg = 7 × 9.8 = 68.6 NCompression (e) = 23 cm = 23 / 100 = 0.23 mWork done (W) =?W = ½Fe
W = ½ × 68.6 × 0.23
W = 7.889 J
Thus, the work done is 7.889 J
C. How to determine the spring constant
Mass (m) = 7 KgAcceleration due to gravity (g) = 9.8 m/s²Force (F) = mg = 7 × 9.8 = 68.6 NCompression (e) = 23 cm = 23 / 100 = 0.23 mSpring constant (K) =?F = Ke
68.6 = K × 0.23
Divide both sides by 0.23
K = 68.6 / 0.23
K = 298.26 N/m
Thus, the spring constant is 298.26 N/m
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Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
The gravitational force between them will change by a factor 1/9.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
R2 = 3R1
By substituting the following parameters, we get
F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²
F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²
F2/F1 = 1/9
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A massless rod is fixed to a wall on one end. A cable is attached to the wall and the center of the rod. The cable makes an angle of 60° to the wall. If the maximum tension of the cable is 10 n, what is the maximum amount of weight that can hang from the end of the rod?.
The most extreme sum of weight that can hang from the conclusion of the pole is 8.66 N.
The most extreme sum of weight that can hang from the conclusion of the bar is calculated as follows.
Apply the equation for pressure utilizing Newton's moment law of movement.
Newton's moment law of movement states that the constrain experienced by a question is specifically relative to the item of the mass and speeding up of the question.
T sinθ = W
Where T is maximum tension in cable
θ is angle of inclination of cable
W is weight of cable
10 sin (60) = W
8.66 N = W
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three people pull simultaneously on a stubborn donkey. jack pulls directly ahead of the donkey with a force of 98.3 n, jill pulls with 62.5 n in a direction 45° to the left, and jane pulls in a direction 45° to the right with 117 n . (since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?)
Jane and Jill are stubborn because they have opposite force directions.
We need to know about force resultant to solve this problem. The force resultant is the total net force applied to the object according to the direction. It can be written as
R = F1 + F2 + ... + Fn
where R is force resultant (net force)
From the question above, we know that
F Jack = 98.3 N
F Jill = 62.5 N
F Jane = 117 N
Assume that the direction
Jack = east
Jill = north east
Jane = south east
The Force to the north direction is
F Jill y = Fjill . cos45
F Jill y = 62.5 . √2/2
F Jane y = -F Jane . cos45
F Jane y = -117 . √2/2
Jane and Jill are stubborn because they have opposite directions.
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The magnitude of the net force the people exert on the donkey is 239 N.
Net force :
[tex]F_{n}[/tex]= [tex]F_{1}+F_{2} +F_{3}[/tex]
Now finding the x and y components of the forces F2 and F3,
[tex]F_{x}[/tex] = F1 + F2cos45°+F3sin45°
[tex]F_{x}[/tex] = 98.5 + 69.3 ×√2/2 + 125 ×√2/2
[tex]F_{x}=235.9N[/tex]
[tex]F_{y}[/tex] = -F2sin45°+F3sin45°
= −69.3 ×√2/2+ 125 ×√2/2
[tex]F_{y}[/tex] = 39.4 N
Now find the magnitude
[tex]F_{n}[/tex] = √235.9^2+39.4^2 = 239 N
The magnitude of the net force the people exert on the donkey is 239 N.
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A roller coaster car, 500 kg, starting at a point 80 m above the lowest point of the track. The car travels from 8 m·s -1 down the steep track. There is no friction.
9.1 What is the total energy of the roller coaster car at the top of the track?
9.2 What is the total energy of the system at the base of the rollercoaster
track?
9.3 What is the velocity of the car at a height of 30 m from
the base of the roller coaster track?
9.4 What is the velocity of the car at the base of the roller coaster track?
The total energy of the roller coaster car at the top of the track is 392,000 J.
The total energy of the system at the base of the rollercoaster track is 392,000 J.
The velocity of the car at a height 30 m above the base is 25.53 m/s.
The velocity of the car at the base of the roller coaster track is 40.4 m/s.
What is the total energy of the roller coaster car?
The total energy of the roller coaster car at the top of the track is calculated as follows;
P.E = mgh
where;
m is mass of the carg is acceleration due to gravityh is heightP.E = (500 kg) x (9.8 m/s²) x (80 m)
P.E = 392,000 J
Based on the law of conservation of energy, the total energy of the rollercoaster at the top of the track is the same as that at the bottom of the track.
Thus, total energy of the system at the base of the rollercoaster track = 392,000 J.
The velocity of the car at a height 30 m above the base is calculated as follows;
v² = u² + 2gh
v² = (8)² + 2(9.8)(30)
v² = 652
v = √652
v = 25.53 m/s
The velocity of the car at the base of the roller coaster track is calculated as follows;
v² = u² + 2gh
v² = (8)² + 2(9.8)(80)
v² = 1632
v = √1632
v = 40.4 m/s
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a baseball is thrown straight upwards from the ground and undergoes a free fall motion as it rises towards its highest point. What changes , if any ,would be observed of the velocity and the acceleration of the baseball as it rises towards its highest point?
The baseball thrown upwards will experience change in its velocity while its acceleration will be constant.
What is upward motion?Upward motion is a type of motion in which an object moves upwards against force of gravity.
During the upward motion of an object, its vertical velocity decreases as the object moves upwards due to opposing force of gravity. The velocity of the object eventually becomes zero when the object reaches maximum height.
As the object begins to move downwards, the velocity begins the increase and eventually become maximum before the object hits the ground.
The acceleration of the object during the upward motion is always point downwards and does not change.
Thus, we can conclude that if an object moving upwards, its velocity will change while the acceleration will not change.
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magnetic effects involving jupiter's moon io results in an effective voltage of about 550 kv that drives a current of about 4.5 ma between io and jupiter.
Effective voltage for the Gi system
V = 550 KV = 550 * 10 3 * v
Current I = 4.5MA = 4.5 * 10 6 *
A The strength of the Lo to Jupiter current
P= VI\s= (550 * 10 ^ 3)(4.5 * 10 ^ 6)
K = Kilo = 10 3 M = Mega = 106
P = 24.75* 10 ^ 7 W
What is magnetic effects?
Moving electric charges and magnetic dipoles combine to form a magnetic field, which acts as a force field on other adjacent moving charges and magnetic dipoles. Given that it has both a magnitude and a direction, the magnetic field is a vector quantity.
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Name the different regions found within the electromagnetic spectrum and describe how the
are similar to and different from, one another.
The electromagnetic (EM) spectrum is the set of all EM radiation types. Electromagnetic radiation includes, for instance, radio waves from a radio station and visible light from a lightbulb in your home. Energy that flows and spreads out as it does is called radiation.
The electromagnetic spectrum is the set of frequencies of electromagnetic radiation and the related photon energies and wavelengths.
The seven regions of the electromagnetic spectrum are often arranged with wavelength decreasing and energy and frequency increasing.
X-rays,gamma rays, visible light, UV light, infrared (IR), microwaves, visible lightare a few of the common names for these energy forms.
Electromagnetic waves have a wide range of useful, everyday applications, including WiFi, cooking, kitchen appliances, eyesight, medical imaging, and cancer treatment.
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A material through which electrons can move easily is a what
Answer:
Electrical conductors
A person on a cruise ship is doing laps on the promenade deck. On one portion of the track the person is moving north with a speed of 3.9 ms relative to the ship. The ship moves east with a speed of 12 ms relative to the water.
The resultant speed of the person on the cruise ship is 12.62 m/s.
What is resultant speed?The resultant speed of an object is the single speed which can effectively represent two or more speed of the object.
The magnitude of the resultant speed of the person on a cruise ship is calculated as follows;
Vr² = Va² + Vb²
where;
Vr is the resultant speed of the personVa is the speed of the person to the northVb is the speed of the person to the eastSubstitute the value of the north speed and east speed to determine the resultant speed of the person on the ship.
Vr = √Va² + Vb²
Vr = √[(3.9 m/s)² + (12 m/s)² ]
Vr = 12.62 m/s
Thus, for a person on a cruise ship is doing laps on the promenade deck at a speed of 3.9 m/s to the north and the speed of the ship 12 m/s to the east, the resultant speed is 12.62 m/s.
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The complete question is below:
person on a cruise ship is doing laps on the promenade deck. On one portion of the track the person is moving north with a speed of 3.9 ms relative to the ship. The ship moves east with a speed of 12 ms relative to the water. Find the resultant speed of the person
the current if 55C of charge pass a particular point in a circuit in 5 seconds.
The current if 55C of charge pass a particular point in a circuit in 5 seconds is 11A.
What's current?One kind of electrical charge carrier that moves as current are electrons. From negative to positive areas, current flows. The ampere is the SI unit used to measure electric current (A). One coulomb of electrical charge travelling over a given region in one second is referred to as an ampere of current.
Similar to how current is widely employed in relation to electronic circuits, voltage is also. Voltage is measured using volts (V). Similar to how current and current are related, voltage and the flow of electrons in a circuit are as well. Current is the flow of electrons, whereas voltage is the amount of force driving the flowing electrons.
At higher voltages, current flows more freely; at lower voltages, current is weaker.
Given,
Electrical charge = 55 C
Time = 5 secs
Therefore current = 55 / 5 A
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An airplane, moving at 375 ms relative to the ground, fires a missile forward at a speed of 790 m/s relative to the planewhat the speed of the relative the ground?
Answer:
1165 m/s relative to ground
Explanation:
(375 + 790 ) = 1165 m/s
Who developed the expression for the line spectrum of hydrogen to include lines in the ultraviolet and infrared portions of the electromagnetic spectrum?.
The expression for the line spectrum of hydrogen to include lines in the ultraviolet and infrared portions of the electromagnetic spectrum was given by Johann Balmer.
It is possible to express the wavelengths of the visible hydrogen lines using a simple formula that was developed by Swiss mathematician Johann Balmer in 1885. The difference between two terms, 1/4 (written as 1/22) and the reciprocal of the square of a variable integer (1/n2), which has sequential values of 3, 4, 5, etc., yields the reciprocal wavelength (1/), which is equal to a constant (R) times the difference between the two terms.
Theodore Lyman, A.H. Pfund, F.S. Brackett, Friedrich Paschen, and Theodore Lyman are all American scientists who discovered the other four spectral line series in addition to the Balmer series. The Lyman series is in the ultraviolet, whereas the Paschen, Brackett, and Pfund series is in the infrared.
The Rydberg formula has been used to determine the wavelengths of several spectral series that have been created from the emission spectrum of atomic hydrogen. These spectral lines that have been seen are the result of electron transitions between two energy levels within an atom. The development of quantum mechanics was greatly aided by the Rydberg formula's classification of the series. In astronomical spectroscopy, the spectral series are crucial for determining redshifts and detecting the existence of hydrogen.
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the following statements are related to household circuits and electrical safety. determine whether each statement is true or false. hint (a) circuit breakers are wired in series with the outlets they protect. true false (b) a circuit breaker rated at 20 a provides a constant current of 20 a to each outlet in the circuit. true false (c) three-wire electrical cords help prevent dangerous electrical shocks by grounding the case of a device. true false
(a) This is true since a circuit breaker is linked in series with the electric device in order to interrupt the circuit if the current flow exceeds a predetermined (rated) limit.
(b) False, because the circuit breaker only permits the maximum current that has been rated for it; when the circuit exceeds that limit, it is broken. There's no issue with continuous current.
(c) The earthing terminal is present.
Circuit breakers: what are they?A circuit breaker is a type of electrical switch used to guard against short circuits, overloads, and over currents that could harm an electrical circuit. Its primary purpose is to halt current flow when protective relays identify a defect.
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each with a mass of 1.5 kg, move toward one another. a). If the cart moving left is traveling at 10 m/s and the cart moving right is traveling at 6 m/s, what is the magnitude and direction of the total momentum of the system? b. What is the total momentum of the system if the two carts have the same speed?
The magnitude and direction of the total momentum of the system is 6 kg m/s to the left.
The total momentum of the system if the two carts have the same speed is 0 kgm/s
What is the total initial momentum of the system?The magnitude and direction of the total momentum of the system is calculated as follows;
Pi = m1u1 + m2u2
where;
Pi is the total initial momentum of the systemm1 is mass of first objectm2 is mass of second objectu1 is initial velocity of the first object'u2 is the initial velocity of the second objectPi = (1.5 x 6) - (1.5 x 10)
Pi = - 6 kg m/s
What is the total momentum of the system at same speed?The total momentum of the system if the two carts have the same speed is calculated as follows;
Pf = (1.5 x 6) - (1.5 x 6)
Pf = 0 kg m/s
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your friend is catching a falling basketball after it has passed through the basket. her hands move straight down while catching the ball. it takes about 0.10 ss for the player to lower her hands to stop the ball. assume the mass of the ball is 0.60 kgkg, and that the ball has fallen a vertical distance of 1.2 mm before reaching the player's hand.
Average force that her hands exert on the ball while catching basketball whose mass is 600g = 29N
Given
clock t=0.1 s
ball mass m=0.6 kilogram
The previous distance traveled (measured in meters) was 1.2.
Net Force Exerted = 29N
Total Force used:
F= △P/△t
F= m△u/△t
F= m√2gd/△t
F= 0.6.√2.9.8.1.2/0.1
F= 0.6.4.849/0.1
F= 2.90/0.1
Force = 29N
What does force mean?
Power is an effect that can physically change the movement of an object. When an object with mass changes speed, it can be accelerated by a force. B. When leaving a stationary state. The obvious way to describe force is pushing or pulling. Force is a vector quantity because it has both magnitude and direction. It is calculated using Newton SI units (N). Force is represented by the letter F (formerly P).
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The question was incomplete. Check below the full question.
Your friend is catching a falling basketball after it has passed through the basket. Her hands move straight down while catching the ball. It takes about 0.10 s for the player to lower her hands to stop the ball. Assume the mass of the ball is 0.60 kg, and that the ball has fallen a vertical distance of 1.2 m before reaching the player's hand. Determine the average force that her hands exert on the ball while catching it.
URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Determine whether each statement describes an atom, a molecule, or both
Answer:
1.A
2.A
3.A
4.A
5.C
6.B
Explanation:
that's
experiment 4: uniform circular motion introduction: in this lab, you will calculate the force on an object moving in a circle at approximately constant speed. to calculate the force you will use newton’s second law combined with the acceleration of an object moving in a circle at constant speed. you will then compare that calculated force with a measured value. you will measure the time t required for 30 revolutions of a hanging object; the object will be held in a circular path of known radius r by a horizontal spring attached to the axis of rotation. the time t for one revolution is then t/30 and the speed v of the moving object is easily calculated from distance (the circumference of the circle 2πr) divided by time: v
This given statement about uniform circular motion and distance is proved.
What is distance?The distance between two points is how long it is.
Okay, so the first three components of this issue include more physics and math. Um Ds equals R. D. Data was thus provided for section A. We have to track down S. Therefore, we just integrate both sides equally using R. D. data. Our data are provided. Therefore, the upon integration over our data is only R 0 Santa + 12 beta zeta squared for part B. We'll make sure S = V T. We combine these two by using the above equation as an equal. In order to allow it to reach its roots once positive, we can see that this is Justin's equation for data. The other drawback, of course, is
Standard units are 247 times zero, therefore switch to the nature radio at a negative six. Additionally, we are given the time, which is 74 minutes, or 4440 seconds. Thus, clogging everything. Injecting R 0 and data mm hmm into the formula for data. Therefore, we enter better Data. V also appears. Everything is therefore known. We may confidently conclude that the data is, hmm, 1.337 x 10-5 bright. or 2.13 x 10 to 4 revolutions, in terms of turns. Okay. We simply re-insert the figures for beta and tr zero V into the earlier formulae for omega and alpha in the last section of the problem. You can take pleasure in utilizing math, even by hand, or perhaps he
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what is the maximum number of 60-w light bulbs you can connect in parallel in a 100-v home circuit without tripping the 30-a circuit breaker? please show solution not only answer.
Answer:
50 sixty watt bulbs max
Explanation:
Watts = amps * volts
30 a * 100 v / 60 w/bulb = 50 bulbs
Proof homogeneity of Einstein's mass energy relation E = mc²
The homogeneity of Einstein’s mass-energy relation E = mc² can be proved by maxwell’s equation of electromagnetism.
According to maxwell’s equation of electromagnetism, light travels at a speed (c) of 3 x [tex]10^8[/tex] m/s.
The momentum(p) of electromagnetic waves is proportional to the energy(E).
So, we can write it as
p = E / c -(i)
By cross multiplication
E = pc -(ii)
As we know
From newton’s second law, momentum (p) is the product of mass (m) and velocity (v)
p = mv -(iii)
since light travels with a speed (c) of 3 x 10^8 m/s
p = mc -(iv)
From the equations (ii) and (iv)
E / c = mc
Hence,
E = mc²
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pls answer the 15a answer i cant understand it
Materials required for the experiment of limiting force borne by string:-
String balanceweightslight stringsweight hanger pan for spring balanceSandSteps of procedure for for the experiment of limiting force borne by string:-
First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.Add additional weight to the hanger again and again. And continue the same until the string is broken.Note down the weight (x) where the string is broken.Suspend spring balance to a support.Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.Now place the weights (x-100 grams) in pan.Observe the reading in the spring balance.Add a small amount of sand in the pan by observing the readings.same is to be done till the string is broken.Learn more about limiting force here:- https://brainly.com/question/11371672
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