Which of the following are equivalent to 1 Newton?

Hi there!

A)

The angle that will produce the same range is the compliment of 35°.

Thus, kicking the ball at 55° will result in the same range.

We can prove this by using the derived range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

An angle of 35° yields:

[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]

An angle of 55° yields:

[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]

Both are the same, thus indicating that 55° produces the same range.

B)

The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.

sin(55) > sin(35)

C)

The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.

We can prove this using:

vf = vi + at

0 = vy - 9.8t

vy/9.8 = t

Greater vy (vertical component of velocity) ⇒ greater time taken.

D)

The angle that would result in the furthest range is 45°.

We can prove this using calculus. Recall the above range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

We can take the derivative and use the first-derivative test to find its critical point:

[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]

Evaluate:

[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]

A. The angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.

For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.

In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.

The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.

Therefore, the angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

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Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

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Answer:

C. Mechanical Energy

Explanation:

The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Answer:

Oh its fine i am not in college but its still fine

Explanation:

Answer:

its atmospheric pressure decreases

When the temperature of an air mass increases, its atmospheric pressure drops

ok done. Thank to me :>

Temperature inversion leads to an increase in temperature as altitude increases.

The term temperature inversion refers to a situation in which a layer of warm air lies over a layer of cool air. This is also referred to as thermal inversion. This occurs when the air below to loose heat rapidly.

One of the effects of temperature inversion is reduction in visibility. So, thermal inversion leads to an increase in temperature as altitude increases.

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Answer:

if your saying can it? then yes or if you are asking what type of magnetic force  then its fr its actual self magnetic force

Explanation:

this is my attachment answer hope it's helpful to you

Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 25 × 10 × 4 = 1000

We have the final answer as

Hope this helps you

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 50 × 9.8 × 600 = 294,000

We have the final answer as

Hope this helps you

Answer:

"work against the force of the air in the tire"

The air in the tire provides a force opposing the force of the air provided by the plunger.

Answer:

Answer → Distance is 5 × 10⁴ km

Explanation:

Gravitational formular

[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]

For the first case;

[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]

For the second case;

[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]

but F2 = ½F1

Therefore, F1 = 2F2

Hence:

[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]

Answer: Distance is 5 × 10⁴ km

Explanation:

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The initial velocity of the runner is 5.25 m/s.

You've probably seen that when there's a lot of traffic and there are more bikes blocking us, we tend to slow down the speed of our bikes.

Therefore, deceleration is defined as a reduction in speed as the body moves away from the beginning location. The opposite of acceleration is deceleration.

Given parameters:

Deceleration of the runner: a = 0.25 m/s².

Time interval: t = 5 second.

Final velocity: v = 4 m/s.

We have to find initial velocity of the runner: u = ?

From definition of deceleration, it can be written that:

deceleration = (initial velocity - final velocity) time interval

0.25 = (u -4)/5

u =  5.25 m/s.

Hence, initial velocity of the runner is 5.25 m/s.

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Answer:

3,900m³

Explanation:

Answer:

the bird has 550J of potential energy

Explanation:

PEtotal=PE+KE

1000J=PE+450J

subtracting the kinetic energy from the total we get:

1000J-450J=PE

550J=PE

Let the ball at the ground be A and that at the top be B.

Assume that you see the motion of A while sitting at B.

You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.

Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.

Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.

Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.

Since B falls freely, he covers a distance of  1/2(g)(1²)=5  (assuming g = 10m/s²)

Thus, they meet at a height of (20–5)m = 15m from the ground.

Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:

a) El periodo de la pelota es 1.43 segundos.

b) La velocidad lineal de la pelota es 3.3 m/s.

a) El periodo de la pelota está dado por:

[tex] T = \frac{2\pi}{\omega} [/tex]

En donde:

ω: es la velocidad angular

Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:

[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]

Entonces, el periodo es:

[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]

b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:

[tex] v = \omega r [/tex]

En donde:

r: es el radio de la circunferencia = longitud del cordón = 0.75 m

[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]

Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.

Puedes encontar mas aquí:

Espero que te sea de utilidad!

Convert km to meters:

1km = 1000 m

1.5 km x 1000 = 1500 m

1500m / 4.8 m/s = 312.5 seconds

312.5 seconds / 60 seconds per minute =5.2 minutes = 5 minutes 12.5 seconds

Hi there!

[tex]\large\boxed{F_{A} = -5000N}}[/tex]

For an object to be moving at constant velocity:

∑F = 0 (The sum of the forces acting on the object MUST be 0 N)

We can do a summation of forces for this helicopter in the HORIZONTAL direction:

∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0

Thus, if we substitute in the given value for Ft:

Ft = -Fa

5000N = -Fa

Fa = -5000N

Answer:

Molar mass of NH3=14+3=17g

[tex]mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65[/tex]

BRAINLIST

Answer:

Speed can be defined in (C) distance / time.

I hope this helped at all.

Answer:

carbon dioxide

Explanation:

its common sense

[tex] \huge \bf༆ Answer ༄[/tex]

The given terms in the question are : -

We have been given the task to find out time (t)

The formula that can be used to find time is : -

[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]

Rearrange the formula,

[tex] \sf \: t = \dfrac { Q}{I }[/tex]

Solve for time (t)

[tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]

Answer: beta particles

Explanation:

that's the answer

Answer: I think it's larger

Explanation:  man im just trying to help you

The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

The given parameters;

The radius of the circular path when spring is stretched is calculated as;

R = l₁ + x

R = 0.201 + 0.0176

R = 0.2186 m

The spring constant is calculated as follows;

[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]

The extension of the spring when the ball is allowed to hang straight down, motionless;

[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]

Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

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Hi there!

We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.

(A)

The system will flow in the direction of the hanging block's movement downwards.

(B)

Summation of forces of block on incline:

∑F = -M₁gsinФ + T

Summation of forces of hanging block:

∑F = M₂g - T

Sum both summations:

∑F =  -M₁gsinФ + T + M₂g - T

∑F = M₂g -M₁gsinФ

According to Newton's Second Law:

∑F = ma

Thus:

(M₁ + M₂)a = M₂g -M₁gsinФ

[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]

Plug in the values:

[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]

(C)

Calculate the rope's tension using one of the above equations:

∑F₂ = M₂g - T

Rearrange for T:

T = M₂g - m₂a

Plug in values:

T = 5(9.8) - 5(0.754) = 45.23 N

Answer:

Explanation:

The gravitational force = G * m1 * m2 / r^2

That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.

Answer:

the answer is A

Explanation: