Y varies directly as x, y = 35 when x = 5. Find y when x = 12

Answers

Answer 1
I don’t know if this is correct or makes sense but I think it would be y=84
If 5:35
Which means when x=1 y=5
Soo..you multiply x•5 to get y
IE; 12•5=84
Answer 2

The value of y when (x = 12) is 84 and this can be determined by forming the linear equation with the help of the given data.

Given :

y varies directly as xy = 35 when x = 5

The following steps can be used to determine the value of y when x = 12:

Step 1 - Given that y varies directly as x, that means:

[tex]\rm y \; \alpha \; x[/tex]

Step 2 - The above expression becomes:

y = kx   ----- (1)

Step 3 - Given that y = 35 when x = 5, that implies:

35 = 5k

k = 7

Step 4 - Put the value of k in equation (1).

y = 7x

Step 5 - Now, the value of y when x = 12 is:

y = 7(12)

y = 84

So, the value of y when (x = 12) is 84.

For more information, refer to the link given below:

https://brainly.com/question/2263981


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Step-by-step explanation:

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The cost to manufacture a product is proportional to the quantity produced, with a cost of $35000 dollars per day when 700 items are produced. The cost to store n items is proportional to the square of n, with a daily storage cost of $3430 dollars when 700 items are stored. In addition, there is a fixed daily cost of $7000. The total daily cost, T when producing and storing n items is the sum of production, storage and fixed costs.

Write a formula for T as a function of n.

Answers

Solution :

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35000 = k . 700

k = [tex]$\frac{35000}{700}$[/tex]

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[tex]$P = \frac{3430}{490000}$[/tex]

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[tex]$T_2=\frac{7}{1000}n^2$[/tex]

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Total, [tex]$T=T_1+T_2+T_3$[/tex]

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Given that ,

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When producing and storing n items is the sum of production, storage and fixed costs.

The manufacturing cost of a product when 700 items produced = $35000 dollars per day.

Daily storage cost of when 700 items are stored = $3430 dollars

We have write the formula in terms of total daily cost T and n stored items.

According to the question,

The cost to manufacture a product is proportional to the quantity produced, with a cost of $35000 dollars per day when 700 items are produced.

Where ,total daily cost T and n stored items.

[tex]T_1 = k . n[/tex]

$35000 =  k.700

[tex]k = \frac{35000}{700}[/tex]

k = $50

The cost to store n items is proportional to the square of n, with a daily storage cost of $3430 dollars when 700 items are stored.

[tex]T_2 = pn^{2}[/tex]

$3430 = P [tex](700)^{2}[/tex]

$3430 = P 490000

[tex]P = \frac{3430}{490000} \\\\P = \frac{7}{1000}[/tex]

There is a fixed daily cost of $7000.

[tex]T_3 = 7000[/tex]

Combine all the equation ,

Where T = [tex]T_1 = T_2 = T_3[/tex] and p = k =n

T = 0.000[tex]n^{2}[/tex] + 50 n +7000

Hence,  The required formula in terms of T and n is T = 0.000[tex]n^{2}[/tex] + 50 n +7000.

For the more information about  System of equations click the link given below.https://brainly.com/question/14418346

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